I have a table whose data is in this manner.
A B C
---------
0 6 2
0 3 4
1 0 2
1 1 4
I wrote a SQL query -
select A
from Table
where (B = 6 and C = 2) AND (B = 3 and C = 4).
Obviously it returned zero results since this query would search in the same row. Please help me with writing a better one to produce results such that it can check two rows with a single statement.
EDIT:
I am not looking for 'OR' statement. I need to find an element of A such that it has two corresponding rows AND each of the rows has elements 6,2 and 3,4 present in columns B,C correspondingly.
PS.
(I don't have the option of writing two queries and then finding the common elements of two set.)
Many thanks in advance
I guess you want something like this
select A
from YourTable
where (B = 6 and C = 2) or
(B = 3 and C = 4)
group by A
having count(distinct B) >= 2
Try here:
https://data.stackexchange.com/stackoverflow/q/123711/
Use OR instead of AND
select A from Table where (B=6 and C=2) OR (B=3 and C=4).
If you want the onlu result use DISTINCT
select DISTINCT A from Table where (B=6 and C=2) OR (B=3 and C=4).
If you need to check the equality of A, use this:
select t1.A
from Table t1
JOIN Table t2 ON t1.A = t2.A
where T1.B=6 and t1.C=2 AND t2.B=3 and t2.C=4
As you see - using AND again
Are you trying to get this??
SELECT A
FROM Table
WHERE (B = 6 AND C = 2) OR (B = 3 AND C = 4)
This would return the A column for all four rows again.
If not: WHAT exactly are you trying to select?
IF you want just two rows, one with A = 0, one with A = 1, then use DISTINCT:
SELECT DISTINCT A
FROM Table
WHERE (B = 6 AND C = 2) OR (B = 3 AND C = 4)
Maybe:
select A
from Table
where (B = 6 and C = 2)
INTERSECT
select A
from Table
(B = 3 and C = 4)
Related
I have what should be simple (maybe) and I am just struggling with it.
Here is the scenario:
TABLE 1 contains all the data
TABLE 2 contains only a subset
I need a query that will look at table 1 and give a list of items that are not in table 2. Below is what I have but I know its not performing as such.
SELECT c.[DOC_ID], d.[DOCID]
FROM [dbo].[Custom_SUAM_Docuware] d
LEFT JOIN [dbo].[Custom_SUAM_Content] c ON (c.[DOC_ID] = d.[DOCID])
WHERE c.[DOC_ID] IS NULL
OR d.[DOCID] IS NULL
You are describing a not exists scenario.
You can't expect to return data from c since by definition what you want doesn't exist:
select d.DOCID
from dbo.Custom_SUAM_Docuware d
where not exists(
select * from dbo.Custom_SUAM_Content c
where c.DOC_ID = d.DOCID
);
you can use EXCEPT
SELECT c.[DOC_ID]
FROM [dbo].[Custom_SUAM_Content] c
EXCEPT
SELECT d.[DOC_ID]
FROM [dbo].[Custom_SUAM_Docuware] d ;
that would show all ids from c that are not in d
In a large database, is it faster to perform a query such as
select * from table where a = 1 and b = 2 or b = 3 or b = 4;
or
select * from table where a = 1 and b = 2;
select * from table where a = 1 and b = 3;
select * from table where a = 1 and b = 4;
You should rely on the DBMS to do the optimisation for you. If the second were quicker, then the DBMS would do it that way anyway.
Go with the first (but put parentheses round the b conditions, as Tommy suggests).
As others have pointed out, the queries are not equivalent. I assume the first query should read:
select * from table where a = 1 and (b = 2 or b = 3 or b = 4);
For clarity I would suggest:
select * from table where a = 1 and b in (2, 3, 4);
In general this will perform better than asking three different queries as in the second alternative.
my question is, is it possible to select certain rows in a table according to a comparison rule without removing anything from the result. To clarify what i want to to imagine following example.
i have a table with two values,
A | B | C
1 0 hey
1 1 there
2 1 this
3 0 is
3 1 a
4 0 test
now i want to select the rows that have a 0 in the B column, and an a in the C column without removing the results that don't have a 0 in column B but the same value in column A.
For that i could do a
select C from T where A in (select A from T where B = 0);
but isn't it possible to select all C values where column B contains a 0 and that match column A with those?
I'd gladly stand by if more information is needed since it is a quite fuzzy question, but SQL can be confusing sometimes.
Tough to tell without your example result set; but maybe something like this:
SELECT A, B, C
FROM myTable
WHERE (B = 0 AND C LIKE '%A%')
OR (B <> 0 AND B = A)
I think you just want an or condition:
select C
from MyTable
where b = 0 or A in (select A from T where B = 0)
Is this the version you want:
select C
from MyTable
where C = 'a' or A in (select A from T where B = 0)
Suppose I have this statement:
SELECT * FROM MyTable WHERE a = 1 or b = 2 and c = 3
Does that mean: (a = 1) OR (b = 2 AND c = 3) or does it mean (a = 1 or b = 2) AND c = 3? Can I change what it means, i.e. execute the OR before the AND or is this not possible?
From Technet:
When more than one logical operator is used in a statement, AND
operators are evaluated first. You can change the order of evaluation
by using parentheses.
So yes, it means (a = 1) OR (b = 2 AND c = 3).
You can force the behavior you want by writing the parentheses as you did above: (a = 1 OR b = 2) AND c = 3
I have table TABLE1 with columns A, B and C. I need to get all rows from the table where columns A, B and C are not all equal to 1, e.g.,
WHERE NOT (A = 1 AND B = 1 AND C = 1)
This works. However, I need to do this in a fashion that only uses AND and OR statements. I had expected this to work:
WHERE A != 1
AND B != 1
AND C != 1
However, this only returns rows where no row = 1, i.e, too few rows.
Using MS SQL 2008.
WHERE (A <> 1 OR B <> 1 OR C <> 1)