T-SQL AND logic - sql

I have table TABLE1 with columns A, B and C. I need to get all rows from the table where columns A, B and C are not all equal to 1, e.g.,
WHERE NOT (A = 1 AND B = 1 AND C = 1)
This works. However, I need to do this in a fashion that only uses AND and OR statements. I had expected this to work:
WHERE A != 1
AND B != 1
AND C != 1
However, this only returns rows where no row = 1, i.e, too few rows.
Using MS SQL 2008.

WHERE (A <> 1 OR B <> 1 OR C <> 1)

Related

sql function case returns more than one row

Going to use this query as a subquery, the problem is it returns many rows of duplicates. Tried to use COUNT() instead of exists, but it still returns a multiple answer.
Every table can only contain one record of superRef.
The below query I`ll use in SELECT col_a, [the CASE] From MyTable
SELECT CASE
WHEN
EXISTS (SELECT 1 FROM A WHERE
A_superRef = myTable.sysno AND A_specAttr = 'value')
THEN 3
WHEN EXISTS (SELECT 1 FROM B
INNER JOIN С ON С_ReferenceForB = B_sysNo WHERE C_superRef = myTable.sysno AND b_type = 2)
THEN 2
ELSE (SELECT C_intType FROM C
WHERE C_superRef = myTable.sysno)
END
FROM A, B, C
result:
3
3
3
3
3
3...
What if you did this? Because Im guessing you are getting an implicit full outer join A X B X C then running the case statement for each row in that result set.
SELECT CASE
WHEN
EXISTS (SELECT 1 FROM A WHERE
A_superRef = 1000001838012)
THEN 3
WHEN EXISTS (SELECT 1 FROM B
INNER JOIN С ON С_ReferenceForB = B_sysNo AND C_superRef = 1000001838012 )
THEN 2
ELSE (SELECT C_type FROM C
WHERE C_superRef = 1000001838012)
END
FROM ( SELECT COUNT(*) FROM A ) --This is a hack but should work in ANSI sql.
--Your milage my vary with different RDBMS flavors.
DUAL is what I needed, thanks to Thorsten Kettner
SELECT CASE
WHEN
EXISTS (SELECT 1 FROM A WHERE
A_superRef = 1000001838012)
THEN 3
WHEN EXISTS (SELECT 1 FROM B
INNER JOIN С ON С_ReferenceForB = B_sysNo AND C_superRef = 1000001838012 )
THEN 2
ELSE (SELECT C_type FROM C
WHERE C_superRef = 1000001838012)
END
FROM DUAL

How to set nulls the values of column B and column C if they already exist on column A sql?

Select BillName as A, ConsigneeName as B, ShipperName as C
from Sum_Orders
where (OrderStatus in ('Complete','Invoiced')
)
and
OrderPeriodYear IN (
(
YEAR(GETDATE())-1
)
)
Group by billname,ConsigneeName,ShipperName
I'm having duplicates in A, B, C (which is expected)
I'm trying to make a condition to
keep the value in A and set to nulls the values that repeat in B OR C
IF A = B or C then keep A and SET B or C to NULLS
Thank you, guys, :D
Is this what you want?
update t
set B = (case when B <> A then B end),
C = (case when C <> A then C end)
where B <> A or C <> A;
If you have to do this inline the perhaps a case will help.
Select Billname AS A,
CASE WHEN ConsigneeName = Billname THEN NULL ELSE ConsigneeName END,
CASE WHEN ShipperName = Billname THEN NULL ELSE ShipperName
from Sum_Orders etc ...
If the table is big, this maybe expensive on the query and pushing this logic into the query itself might be better.
If a,b and c has same value, b and c should set null, so:
Update tablename
Set B = if(A=B, null, B) , C=if(A=C, null, C)
-- where A=B or A=C
You can use 'where' if optimization is interesting!
If you're going to 'Select' value:
Select A, if(A=B, null, B) as B , if(A=C, null, C) as C from tablename

sql query with comparison but without removing without subquerying

my question is, is it possible to select certain rows in a table according to a comparison rule without removing anything from the result. To clarify what i want to to imagine following example.
i have a table with two values,
A | B | C
1 0 hey
1 1 there
2 1 this
3 0 is
3 1 a
4 0 test
now i want to select the rows that have a 0 in the B column, and an a in the C column without removing the results that don't have a 0 in column B but the same value in column A.
For that i could do a
select C from T where A in (select A from T where B = 0);
but isn't it possible to select all C values where column B contains a 0 and that match column A with those?
I'd gladly stand by if more information is needed since it is a quite fuzzy question, but SQL can be confusing sometimes.
Tough to tell without your example result set; but maybe something like this:
SELECT A, B, C
FROM myTable
WHERE (B = 0 AND C LIKE '%A%')
OR (B <> 0 AND B = A)
I think you just want an or condition:
select C
from MyTable
where b = 0 or A in (select A from T where B = 0)
Is this the version you want:
select C
from MyTable
where C = 'a' or A in (select A from T where B = 0)

Order of operations for SQL?

Suppose I have this statement:
SELECT * FROM MyTable WHERE a = 1 or b = 2 and c = 3
Does that mean: (a = 1) OR (b = 2 AND c = 3) or does it mean (a = 1 or b = 2) AND c = 3? Can I change what it means, i.e. execute the OR before the AND or is this not possible?
From Technet:
When more than one logical operator is used in a statement, AND
operators are evaluated first. You can change the order of evaluation
by using parentheses.
So yes, it means (a = 1) OR (b = 2 AND c = 3).
You can force the behavior you want by writing the parentheses as you did above: (a = 1 OR b = 2) AND c = 3

Searching Multiple Rows at a time through a single SQL query

I have a table whose data is in this manner.
A B C
---------
0 6 2
0 3 4
1 0 2
1 1 4
I wrote a SQL query -
select A
from Table
where (B = 6 and C = 2) AND (B = 3 and C = 4).
Obviously it returned zero results since this query would search in the same row. Please help me with writing a better one to produce results such that it can check two rows with a single statement.
EDIT:
I am not looking for 'OR' statement. I need to find an element of A such that it has two corresponding rows AND each of the rows has elements 6,2 and 3,4 present in columns B,C correspondingly.
PS.
(I don't have the option of writing two queries and then finding the common elements of two set.)
Many thanks in advance
I guess you want something like this
select A
from YourTable
where (B = 6 and C = 2) or
(B = 3 and C = 4)
group by A
having count(distinct B) >= 2
Try here:
https://data.stackexchange.com/stackoverflow/q/123711/
Use OR instead of AND
select A from Table where (B=6 and C=2) OR (B=3 and C=4).
If you want the onlu result use DISTINCT
select DISTINCT A from Table where (B=6 and C=2) OR (B=3 and C=4).
If you need to check the equality of A, use this:
select t1.A
from Table t1
JOIN Table t2 ON t1.A = t2.A
where T1.B=6 and t1.C=2 AND t2.B=3 and t2.C=4
As you see - using AND again
Are you trying to get this??
SELECT A
FROM Table
WHERE (B = 6 AND C = 2) OR (B = 3 AND C = 4)
This would return the A column for all four rows again.
If not: WHAT exactly are you trying to select?
IF you want just two rows, one with A = 0, one with A = 1, then use DISTINCT:
SELECT DISTINCT A
FROM Table
WHERE (B = 6 AND C = 2) OR (B = 3 AND C = 4)
Maybe:
select A
from Table
where (B = 6 and C = 2)
INTERSECT
select A
from Table
(B = 3 and C = 4)