I'm writing a Mac application which needs to check whether a given driver has been installed or not.
How can I go about checking this?
BR,
S.
The simplest way is to grep output of kextstat for its name, knowing that grep returns nonzero exit code when nothing is found:
if (0 == system("/usr/sbin/kextstat | /usr/bin/grep -qF com.company.KextName"))
{
// it is loaded
}
If you need to do that directly, check kextstat source code, you'll find it's using kmod_get_info API, however I can't find any documentation on it right now. I see no serious disadvantages in using system() call, so I'd stick with it.
Related
I am using Python's Paramiko library to SSH a remote machine and fetch some output from command-line. I see a lot of junk printing along with the actual output. How to get rid of this?
chan1.send("ls\n")
output = chan1.recv(1024).decode("utf-8")
print(output)
[u'Last login: Wed Oct 21 18:08:53 2015 from 172.16.200.77\r', u'\x1b[2J\x1b[1;1H[local]cli#BENU>enable', u'[local]cli#BENU#Configure',
I want to eliminate, [2J\x1b[1;1H and u from the output. They are junk.
It's not a junk. These are ANSI escape codes that are normally interpreted by a terminal client to pretty print the output.
If the server is correctly configured, you get these only, when you use an interactive terminal, in other words, if you requested a pseudo terminal for the session (what you should not, if you are automating the session).
The Paramiko automatically requests the pseudo terminal, if you used the SSHClient.invoke_shell, as that is supposed to be used for implementing an interactive terminal. See also How do I start a shell without terminal emulation in Python Paramiko?
If you automate an execution of remote commands, you better use the SSHClient.exec_command, which does not allocate the pseudo terminal by default (unless you override by the get_pty=True argument).
stdin, stdout, stderr = client.exec_command('ls')
See also What is the difference between exec_command and send with invoke_shell() on Paramiko?
Or as a workaround, see How can I remove the ANSI escape sequences from a string in python.
Though that's rather a hack and might not be sufficient. You might have other problems with the interactive terminal, not only the escape sequences.
You particularly are probably not interested in the "Last login" message and command-prompt (cli#BENU>) either. You do not get these with the exec_command.
If you need to use the "shell" channel due to some specific requirements or limitations of the server, note that it is technically possible to use the "shell" channel without the pseudo terminal. But Paramiko SSHClient.invoke_shell does not allow that. Instead, you can create the "shell" channel manually. See Can I call Channel.invoke_shell() without calling Channel.get_pty() beforehand, when NOT using Channel.exec_command().
And finally the u is not a part of the actual string value (note that it's outside the quotes). It's an indication that the string value is in the Unicode encoding. You want that!
This is actually not junk. The u before the string indicates that this is a unicode string. The \x1b[2J\x1b[1;1H is an escape sequence. I don't know exactly what it is supposed to do, but it appears to clear the screen when I print it out.
To see what I mean, try this code:
for string in output:
print string
We have published several different versions of an app. They have similar names – Foo Basic, Foo Deluxe, Foo Retro, etc. Similar but different bundle identifiers too. (It wasn't my idea!) Some users have more than one of these apps installed, but only one can be running.
All apps support the same AppleScript dictionary. I need an AppleScript to script the currently-running version of our app to do stuff. How can I do this?
I got it working. It required several pieces:
Get the name of the running app. You can do this with either processes of System Events or else do shell script "ps …", whichever you think will be more reliable in your situation.
Then, using terms from one of the apps on your Mac, you can
*tell application appName…, provided that you have
saved your script as an Application, so it is already compiled.
Here is some code. The script I'm working on has not yet resorted to System Events, so to spare new users the pain of a trip to System Preferences, I chose to use /bin/ps instead…
set appName to runningAppWithBaseName("Foo")
using terms from application "Foo Deluxe" -- an app on your Mac
tell application appName
(* whatever code you want here *)
end tell
end using terms from
on runningAppWithBaseName(baseName)
set command to "/bin/ps -eo args | grep " & baseName & " | grep -v grep"
(* The "grep -v grep" is to exclude the grep process itself from the results. *)
try
set fullPathOfRunningApp to do shell script command
end try
(* Here, given the fullPathOfRunningApp and your list of candidate app names, *)
(* insert code to determine the name of the running app. *)
return nameOfRunningApp
end runningAppWithBaseName
I want to lock the user-facing command line API of my golang program by writing few anti-regression tests that would focus on testing my binary as a whole. What testing "binary as a whole" means is that go-test should:
be able to feed STDIN to my binary
be able to check that my binary produces correct STDOUT
be able to ensure that error cases are handled properly by binary
However, it is not obvious to me what is the best practice to do that in go? If there is a good go test example, could you point me to it?
P.S. in the past I have been using autotools. And I am looking for something similar to AT_CHECK, for example:
AT_CHECK([echo "XXX" | my_binary -e arg1 -f arg2], [1], [],
[-f and -e can't be used together])
Just make your main() single line:
import "myapp"
func main() {
myapp.Start()
}
And test myapp package properly.
EDIT:
For example, popular etcd conf server uses this technique: https://github.com/coreos/etcd/blob/master/main.go
I think you're trying too hard: I just tried the following
func TestMainProgram(t *testing.T) {
os.Args = []string{"sherlock",
"--debug",
"--add", "zero",
"--ruleset", "../scripts/ceph-log-filters/ceph.rules",
"../scripts/ceph-log-filters/ceph.log"}
main()
}
and it worked fine. I can make a normal tabular test or a goConvey BDD from it pretty easily...
If you really want to do such type of testing in Go, you can use Go os/exec package https://golang.org/pkg/os/exec/ to execute your binary and test it as a whole - for example, executing go run main.go command. Essentially it would be an equivalent of a shell script done in Go. You can use StdinPipe https://golang.org/pkg/os/exec/#Cmd.StdinPipe and StdouPipe/StderrPipe (https://golang.org/pkg/os/exec/#Cmd.StdoutPipe and https://golang.org/pkg/os/exec/#Cmd.StderrPipe) to feed the desired input and verify output. The examples on the package documentation page https://golang.org/pkg/os/exec/ should give you a good starting point.
However, the testing of compiled programs goes beyond the unit testing so it is worth to consider other tools (not necessarily Go-based) that more typically used for functional / acceptance testing such as Cucumber http://cucumber.io.
I am writing a macro to check for cython on the system my program is about to be compiled.
i can use AC_PATH_PROG all right to find cython when it is in the path, but if the user want to specifiy it in the configure line like this:
./configure CYTHON=/home/user/cythonFoo
I just can't find the right way to check for it.
This is not working, it always pass the test whatever the value of CYTHON is:
AC_PATH_PROG( CYTHON, $CYTHON,"" )
This is kinda working, but not really usable, because it would require me to extract filename and filepath beforehand:
AC_PATH_PROG( CYTHON, cythonFoo,"", /home/user/ )
So i've wrote my own test, but i think there may be a standard way to do it
AC_MSG_CHECKING([Checking Cython path $CYTHON is correct])
AS_IF($CYTHON -V > /dev/null 2>&1, , CYTHON="")
if test -z $CYTHON; then
AC_MSG_RESULT([ no ])
else
AC_MSG_RESULT([ yes ])
fi
You're observing the expected behavior of AC_PATH_PROG. If the user sets CYTHON, AC_PATH_PROG is going to treat it as the cython to use, even if it's bogus. As the first line of the linked page states
If you need to check the behavior of a program as well as find out whether it is present, you have to write your own test for it
So what you've done is the "standard way".
I'm just switch to zsh and now adapting the alias in which was printing some text (in color) along with a command.
I have been trying to use the $fg array var, but there is a side effect, all the command is printed before being executed.
The same occur if i'm just testing a echo with a color code in the terminal:
echo $fg_bold[blue] "test"
]2;echo "test" test #the test is in the right color
Why the command print itself before to do what it's supposed to do ? (I precise this doesn't happen when just printing whithout any wariable command)
Have I to set a specific option to zsh, use echo with a special parameter to get ride of that?
Execute the command first (keep its output somewhere), and then issue echo. The easiest way I can think of doing that would be:
echo $fg[red] `ls`
Edit: Ok, so your trouble is some trash before the actual output of echo. You have some funny configuration that is causing you trouble.
What to do (other than inspecting your configuration):
start a shell with zsh -f (it will skip any configuration), and then re-try the echo command: autoload colors; colors; echo $fg_bold[red] foo (this should show you that the problem is in your configuration).
Most likely your configuration defines a precmd function that gets executed before every command (which is failing in some way). Try which precmd. If that is not defined, try echo $precmd_functions (precmd_functions is an array of functions that get executed before every command). Knowing which is the code being executed would help you search for it in your configuration (which I assume you just took from someone else).
If I had to guess, I'd say you are using oh-my-zsh without knowing exactly what you turned on (which is an endless source of troubles like this).
I don't replicate your issue, which I think indicates that it's either an option (that I've set), or it's a zsh version issue:
$ echo $fg_bold[red] test
test
Because I can't replicate it, I'm sure there's an option to stop it happening for you. I do not know what that option is (I'm using heavily modified oh-my-zsh, and still haven't finished learning what all the zsh options do or are).
My suggestions:
You could try using print:
$ print $fg_bold[red] test
test
The print builtin has many more options than echo (see man zshbuiltins).
You should also:
Check what version zsh you're using.
Check what options (setopt) are enabled.
Check your ~/.zshrc (and other loaded files) to see what, if any, options and functions are being run.
This question may suggest checking what TERM you're using, but reading your question it sounds like you're only seeing this behaviour (echoing of the command after entry) when you're using aliases...?