SQL - Limit results - sql

I was wondering if you could do something like this is Microsoft SQL Server 2k8 R2
Say I have a query which returns 100 rows of data.
Is their a way I can pass in some variables for example #lower_limit and #upper_limit.
Then I want the query to record the rows between the lower and upper limit
For example:
#lower_limit = 5
#upper_limt 10
Would return me rows 5 - 10 from the 100 records.

You can assign a ROW_NUMBER() over your result set and then use the BETWEEN statement to limit the rows.
A contrived example:
WITH data AS
(
SELECT
ID
,YourColumn
,ROW_NUMBER() OVER (ORDER BY ID) AS RowNum
FROM
YourTable
)
SELECT
*
FROM
data
WHERE
RowNum BETWEEN 5 AND 10
EDIT: For standard paging, here's exactly the technique I use in all the applications I develop:
DECLARE #PageNumber int = /* The page number you want */
DECLARE #PageSize int = /* The number of records per page */
WITH paged AS
(
SELECT
ROW_NUMBER() OVER(ORDER BY [OrderByColumns]) AS RowNum
,*
FROM
[YourSource]
)
SELECT
[Column1]
,[Column2]
,...
FROM
paged
WHERE
RowNum BETWEEN (#PageNumber - 1) * #PageSize + 1 AND #PageNumber * #PageSize
ORDER BY
[OrderByColumns] -- Same as used in ROW_NUMBER()

select *
from
(
select *, row_number() over(order by someColToOrderBy) RowNum
from yourTable
) a
where RowNum between #lower_limit and #uppder_limit

Something like this should work:
SELECT ID, Foo, Bar
FROM (
SELECT ROW_NUMBER() OVER (ORDER BY ID ASC) AS Row, ID, Foo, Bar
FROM SomeTable
)
tmp
WHERE Row >= #RowRangeStart AND Row <= #RowRangeEnd

Related

Applying LIMIT and OFFSET to MS SQL server 2008 queries

I need to apply LIMIT and OFFSET to original query (without modifying it) in MSSQL server 2008.
Let's say the original query is:
SELECT * FROM energy_usage
(But it can be any arbitrary SELECT query)
That's what I came up with so far:
1. It does what I need, but the query generates extra column row_number which I don't need.
WITH OrderedTable AS
(
SELECT ROW_NUMBER() OVER (ORDER BY (SELECT 1)) AS row_number, * FROM energy_usage
)
SELECT * FROM OrderedTable WHERE row_number BETWEEN 1 AND 10
2. This one doesn't work for some reason and returns the following error.
SELECT real_sql.* FROM (
SELECT ROW_NUMBER() OVER (ORDER BY (SELECT 1)) AS row_number, * FROM (SELECT * FROM energy_usage) as real_sql) as subquery
WHERE row_number BETWEEN 1 AND 10
More common case is:
SELECT real_sql.* FROM (
SELECT ROW_NUMBER() OVER (ORDER BY (SELECT 1)) AS row_number, * FROM (real sql query) as real_sql) as subquery
WHERE row_number BETWEEN {offset} + 1 AND {limit} + {offset}
Error:
The column prefix 'real_sql' does not match with a table name or alias
name used in the query.
Simply do not put it on SELECT list:
WITH OrderedTable AS
(
SELECT ROW_NUMBER() OVER (ORDER BY (SELECT 1)) AS row_number, *
FROM energy_usage
)
SELECT col1, col2, col3 FROM OrderedTable WHERE row_number BETWEEN 1 AND 10;
SELECT * is common anti-pattern and should be avoided anyway. Plus ORDER BY (SELECT 1) will not give you guarantee of stable sort between executions.
Second if you need only ten rows use:
SELECT TOP 10 *
FROM energy_usage
ORDER BY ...
Unfortunately you won't get something nice as Selecting all Columns Except One
WITH OrderedTable AS
(
SELECT ROW_NUMBER() OVER (ORDER BY (SELECT 1)) AS row_number, *
FROM energy_usage
)
SELECT * EXCEPT row_number FROM OrderedTable WHERE row_number BETWEEN 1 AND 10;
This would solve the problem.
DECLARE #offset INT = 1;
DECLARE #limit INT = 10;
WITH Filtered AS (
SELECT TOP (#offset + #limit) *
FROM energy_usage
ORDER BY 1 ASC
), Results AS (
SELECT TOP (#limit) *
FROM Filtered
ORDER BY 1 DESC
)
SELECT *
FROM Results
ORDER BY 1 ASC;

SQL Server Row_number in ORDER BY CASE

EDITED THE WHOLE TOPIC.
I need to create a view that sort article per type.
If I only have the type : *VALUE -> I need to show this line only.
If I have the type : *VALUE & 2 -> Still showing row accordingly to *VALUE type only.
If I only have the type : 2 -> Showing this one.
I already did somethink like this :
VALUE* is a value that should come from an another table with a Join.
SELECT Id_item ,Name_item , Type_item , Id_type_item FROM ITEM
WHERE Name_item = 'Gillette' AND (Id_Type_item = VALUE* OR Id_Type_item ='10')
ORDER BY CASE
WHEN row_number() OVER(ORDER BY Id_item DESC , Id_Type_Item DESC) <= 1 THEN 0
ELSE 1
END;
But it does that in the case where we've got both row for the types(*VALUE & 10):
Id_item / Name_item / Type_item / Id_Type_Item
1 Gillette 45 30 (*VALUE)
1 Gillette 2 10
So I think that the order by on the Over() could be useful to always sort by *VALUE (which are in reality another column from another table)
I always want to select 1 row of data only ! :)
I'm guessing, that what you want is the "first" row returned from each SELECT? There's no need to use a separate SELECT statement for each variable on the same table, you can use a window function to do so. I believe this is what you might be after.
WITH CTE AS(
--The following assumes table A and B have the same DDL (which begs the question, why are they different tables?)
SELECT *,
ROW_NUMBER() OVER (PARTITION BY var
ORDER BY (SELECT NULL)) AS RN --Replace SELECT(NULL) with your actual ordering criteria
FROM A
WHERE var IN (1,2)
UNION --ALL(?)
SELECT *
ROW_NUMBER() OVER (PARTITION BY var
ORDER BY (SELECT NULL)) AS RN --Replace SELECT(NULL) with your actual ordering criteria
FROM B
WHERE var IN (3))
SELECT *
FROM CTE
WHERE RN = 1;
Here is a possible solution. In this case ROW_NUMBER, RANK and DENSE_RANK would all work. However, ROW_COUNT is not a valid window function in sql server.
DECLARE #A TABLE(ID INT, Value INT)
DECLARE #B TABLE(ID INT,Value INT)
INSERT INTO #A VALUES (1,1),(2,1),(3,2),(4,3),(5,2),(6,1),(7,3)
INSERT INTO #B VALUES (1,1),(2,1),(3,1),(4,2),(5,3),(6,2),(7,1),(8,3)
;WITH D AS
(
SELECT ID,Value FROM #A WHERE Value IN(1,2)
UNION ALL
SELECT ID,Value FROM #B WHERE Value IN (3)
)
SELECT * FROM
(
SELECT
ID, Value,
ValueRankInSet = DENSE_RANK() OVER(PARTITION BY VALUE ORDER BY ID) -- <-- If you do not have an ID field you can subst ID with NEWID() as order is not important
FROM D
)AS X
WHERE ValueRankInSet = 1
Assign the priority within your Select(s) and then order by it in the row_number:
with cte as
(
SELECT *,
row_number()
over (-- partition by ???
order by prio) as Position
FROM
(
SELECT 1 as prio, * FROM A WHERE var = 1
UNION -- probably a more efficient UNION ALL
SELECT 2 as prio, * FROM A WHERE var = 2
UNION -- probably a more efficient UNION ALL
SELECT 3 as prio, * FROM B WHERE var = 3
)
)
select *
from cte
WHERE Position = 1

Oracle: I need to select n rows from every k rows of a table

For example:
My table has 10000 rows. First I will divide it in 5 sets of 2000(k) rows. Then from each set of 2000 rows I will select only top 100(n) rows.
With this approach I am trying to scan some rows of table with a specific pattern.
Assuming you are ordering them 1 - 10000 using some logic and want to output only rows 1-100,2001-2100,4001-4100,etc then you can use the ROWNUM pseudocolumn:
SELECT *
FROM (
SELECT t.*,
ROWNUM AS rn -- Secondly, assign a row number to the ordered rows
FROM (
SELECT *
FROM your_table
ORDER BY your_condition -- First, order the data
) t
)
WHERE MOD( rn - 1, 2000 ) < 100; -- Finally, filter the top 100 per 2000.
Or you could use the ROW_NUMBER() analytic function:
SELECT *
FROM (
SELECT t.*,
ROW_NUMBER() OVER ( ORDER BY your_condition ) AS rn
FROM your_table
)
WHERE MOD( rn - 1, 2000 ) < 100;
Is it possible to increase the set of sample data exponentially. Like 1k, 2k, 4k,8k....and then fetch some rows from these.
Replace the WHERE clause with:
WHERE rn - POWER(
2,
TRUNC( CAST( LOG( 2, CEIL( rn / 1000 ) ) AS NUMBER(20,4) ) )
) * 1000 + 1000 <= 100
This solution uses the analytic ntile() to split the raw data into five buckets. That result set is labelled using the analytic row_number() which provides a filter to produce the final set:
with sq1 as ( select id, col1, ntile(5) over (order by id asc) as quintile
from t23
)
, sq2 as ( select id, col1, quintile
, row_number() over ( partition by quintile order by id asc) as rn
from sq1 )
select *
from sq2
where rn <= 200
order by quintile, rn
/
use partition by and order by with row_number. it will look like following:
row_number()over(partition by partition_column order by order_column)<=100
partition_column will be your condition to divide set.
order_column will be your condition to select top 100.

Returning a certain number of results from the top

How do I return a certain number of rows, that are a certain number of rows from the top of a SELECT query?
What I mean is, suppose I had a table with 1000 rows. Suppose I want the first 50 rows, then I want the second 50 rows, then the third 50 rows, and so on. I know that TOP or LIMIT will limit the number of rows that are returned, but I am unsure how to tell SQL to get me the rows from a certain point in the returned table.
In Sql server you can make use of ROW_NUMBER() function to do thing you want
SELECT ROW_NUMBER() OVER(ORDER BY col3 DESC) AS Row,
col1, col2, col3
FROM tablename
in short
WITH ctetable AS
(
SELECT ROW_NUMBER() OVER(ORDER BY col3 DESC) AS RowNumber ,
col1, col2, col3
FROM tablename
)
SELECT *
FROM ctetable
WHERE RowNumber BETWEEN 1 AND 50;
SELECT TOP 50 * FROM
(
SELECT ROW_NUMBER() OVER(ORDER BY ID DESC) AS [Index], * FROM MyTable
) AS A
WHERE A.[Index] BETWEEN #StartIndex AND #EndIndex
;With CTE as(SELECT ROW_NUMBER() OVER(ORDER BY (select 0)) AS rno, * FROM MyTable)
select * from CTE where rno between start and end;

Select top and bottom rows

I'm using SQL Server 2005 and I'm trying to achieve something like this:
I want to get the first x rows and the last x rows in the same select statement.
SELECT TOP(5) BOTTOM(5)
Of course BOTTOM does not exist, so I need another solution. I believe there is an easy and elegant solution that I'm not getting. Doing the select again with GROUP BY DESC is not an option.
Using a union is the only thing I can think of to accomplish this
select * from (select top(5) * from logins order by USERNAME ASC) a
union
select * from (select top(5) * from logins order by USERNAME DESC) b
Check the link
SQL SERVER – How to Retrieve TOP and BOTTOM Rows Together using T-SQL
Did you try to using rownumber?
SELECT *
FROM
(SELECT *, ROW_NUMBER() OVER (Order BY columnName) as TopFive
,ROW_NUMBER() OVER (Order BY columnName Desc) as BottomFive
FROM Table
)
WHERE TopFive <=5 or BottomFive <=5
http://www.sqlservercurry.com/2009/02/select-top-n-and-bottom-n-rows-using.html
I think you've two main options:
SELECT TOP 5 ...
FROM ...
ORDER BY ... ASC
UNION
SELECT TOP 5 ...
FROM ...
ORDER BY ... DESC
Or, if you know how many items there are in the table:
SELECT ...
FROM (
SELECT ..., ROW_NUMBER() OVER (ORDER BY ... ASC) AS intRow
FROM ...
) AS T
WHERE intRow BETWEEN 1 AND 5 OR intRow BETWEEN #Number - 5 AND #Number
Is it an option for you to use a union?
E.g.
select top 5 ... order by {specify columns asc}
union
select top 5 ... order by {specify columns desc}
i guess you have to do it using subquery only
select * from table where id in (
(SELECT id ORDER BY columnName LIMIT 5) OR
(SELECT id ORDER BY columnName DESC LIMIT 5)
)
select * from table where id in (
(SELECT TOP(5) id ORDER BY columnName) OR
(SELECT TOP(5) id ORDER BY columnName DESC)
)
EDITED
select * from table where id in (
(SELECT TOP 5 id ORDER BY columnName) OR
(SELECT TOP 5 id ORDER BY columnName DESC)
)
No real difference between this and the union that I'm aware of, but technically it is a single query.
select t.*
from table t
where t.id in (select top 5 t2.id from table t2 order by MyColumn)
or
t.id in (select top 5 t2.id from table t2 order by MyColumn desc);
SELECT *
FROM (
SELECT x, rank() over (order by x asc) as rown
FROM table
) temp
where temp.rown = 1
or temp.rown = (select count(x) from table)
Then you are out - doing the select again IS the only option, unless you want to pull in the complete result set and then throwing away everything in between.
ANY sql I cna think of is the same way - for the bottom you need to know first either how many items you have (materialize everything or use count(*)) or a reverse sort order.
Sorry if that does not suit you, but at the end.... reality does not care, and I do not see any other way to do that.
I had to do this recently for a very large stored procedure; if your query is quite large, and you want to minimize the amount of queries you could declare a #tempTable, insert into that #tempTable then query from that #tempTable,
DECLARE #tempTable TABLE ( columns.. )
INSERT INTO #tempTable
VALUES ( SELECT.. your query here ..)
SELECT TOP(5) columns FROM #tempTable ORDER BY column ASC -- returns first to last
SELECT TOP(5) columns FROM #tempTable ORDER BY column DESC -- returns last to first