I have a datevariable, I would like to have convert it to first day of its monh,
Eg: 10/10/2010 -> 01/10/2010
Eg: 31/07/2010 -> 01/07/2010
According to http://psoug.org/reference/date_func.html, this should work a dandy...
SELECT TRUNC(yourDateField, 'MONTH') FROM yourTable
SQL> select to_date('31/07/2010', 'DD/MM/YYYY') from dual;
TO_DATE('
---------
31-JUL-10
SQL> select trunc(to_date('31/07/2010', 'DD/MM/YYYY'), 'MM') from dual;
TRUNC(TO_
---------
01-JUL-10
SQL>
select trunc(sysdate, 'mm') from dual;
try this one
select trunc(sysdate, 'MM')firstday , trunc(last_DAY(sysdate)) lastday from dual;
SELECT trunc(to_date('22-AUG-03'), 'MON') FROM dual;
More in the manual.
About Oracle needing a dummy FROM: Select without a FROM clause in Oracle
Here is a good example:
select trunc(to_date('15.11.2019', 'DD.MM.YYYY'), 'MONTH') from dual;
Related
I run these two statements in sql and the dates are two days apart. This ruins my query. Why are they not both 10/13/2015?
select sysdate from dual
-- 10/13/2015 5:09:43 PM
select trunc(sysdate, 'DAY') from dual
-- 10/11/2015
trunc 'DAY' returns the starting day of the week. Use 'DDD', 'DD' or 'J' to truncate to a day.
I assume you want to truncate the time. So you can just remove the second parameter if you want to truncate the time to midnight.
SELECT to_char(SYSDATE,'mm/dd/yyyy hh24:mi:ss') FROM dual;
/
SELECT to_char(trunc(SYSDATE),'mm/dd/yyyy hh24:mi:ss') FROM dual;
Output:
TO_CHAR(SYSDATE,'MM/DD/YYYYHH24:MI:SS')
---------------------------------------
10/14/2015 07:35:24
TO_CHAR(TRUNC(SYSDATE),'MM/DD/YYYYHH24:MI:SS')
----------------------------------------------
10/14/2015 00:00:00
I am using oracle 11g and I have normal timestamps (starttime) which produce an output as follows:
23.09.14 05:15:00,000000000
Now I want an output like
23.09.14 05
Also ok would be:
23.09.14 05:00:00,000000000
but when I use something like
round(starttime, 'HH') or trunc(starttime ,'HH24') I always get
23.09.14
with no hours at all.
Looking around here at stackoverflow I found
substr(TO_CHAR(starttime),0,LENGTH(TO_CHAR(starttime))-13)
which produces the correct output as char but when I want to sort dates it wont work because it sorts alphabetically. (so for example, 1.3., 1.4, 1.5.... instead of 1.3., 2.3., 3.3,...),
Any idea how I can get a timestamp which is rounded to the full hour?
I will have to use the statement in a group by clause. The complete statement would look like:
select round(starttime, 'HH24'), sum(counter) from wmsconsolidationorderdwct group by round(starttime, 'HH24') order by round(starttime, 'HH24') desc;
So I cannot display the rounded time and sort by the full timestamp since this would violate the group by clause.
This will truncate to the hour:
trunc(SYSTIMESTAMP) + extract(hour from SYSTIMESTAMP)/24
Edit:
I just tried it and
SELECT TRUNC(SYSTIMESTAMP ,'HH24') FROM DUAL;
returns the correct result.
Fiddle
If your purpose is to display, then use TO_CHAR with desired format model.
For example,
SQL> SELECT TO_CHAR(SYSTIMESTAMP, 'DD.MM.YY HH24') FROM dual;
TO_CHAR(SYS
-----------
28.05.15 15
SQL>
If your purpose is to do date arithmetic then you need to leave the data type as date.
For example,
SQL> alter session set nls_date_format='DD-MM-YYYY HH24:MI:SS'
2 /
Session altered.
SQL> SELECT TRUNC(SYSTIMESTAMP ,'HH24') FROM DUAL
2 /
TRUNC(SYSTIMESTAMP,
-------------------
28-05-2015 15:00:00
SQL>
If you have a timestamp object:
select my_number from(
SELECT TO_NUMBER(TO_CHAR(TO_DATE (TO_CHAR (SYSTIMESTAMP, 'DD.MM.YY HH24:MI'),
'DD.MM.YY HH24:MI'
),'HH24')) AS my_number
FROM DUAL)
order by 1
This could be simplified to:
select my_number from(
SELECT TO_NUMBER(TO_CHAR(SYSTIMESTAMP, 'HH24')) AS my_number
FROM DUAL)
order by 1
When i executed the below query in Oracle
select TO_CHAR((CURRENT_DATE),'DD-Mon-YYYY HH24:MI:SS') from dual;
O/P : 04-Mar-2014 14:25:14
I would like to select current date only without current time as below
select TO_CHAR(trunc(CURRENT_DATE),'DD-Mon-YYYY HH24:MI:SS') from dual;
O/P : 04-Mar-2014 00:00:00
To achieve the only way is to apply function trunc() on the query? Is there any another way?
Edit : Thanks for your ans.Can it be done without any function?(wihout using to_char or trunc)
{sorry for missing this info}
The answer is simply no, there is no function that only gets the date part of the date / time (even current_date or sysdate are functions after all).
You should always use trunc to get the current date, without the time.
It isn't necessary to do a trunc and a to_char together. Keep to_char and don't specify the time part.
This is sufficient:
To get the date as varchar:
select TO_CHAR(CURRENT_DATE,'DD-Mon-YYYY') from dual
To get the date as date, with the time part as 00:00:00:
select trunc(CURRENT_DATE) from dual
You can do this:
select TO_CHAR(CURRENT_DATE,'DD-Mon-YYYY')||' 00:00:00' from dual;
there is also EXTRACT function which can be used like that:
SELECT extract(DAY FROM sysdate)
||'-' ||
extract(MONTH FROM sysdate)
|| '-' || extract(YEAR FROM sysdate)
FROM dual;
result: 4-3-2014
Use This Query...
select (TO_CHAR(TRUNC(CURRENT_DATE),'DD-Mon-YYYY HH24:MI:SS')) from dual
I have table that has date field. When I run a query, I see this:
01/10/2009 22:10:39
How can I retrieve only the time (IE: 22:10:39)
you can try this:
SELECT TO_CHAR(yourval, 'DD-MON-YYYY HH:MI:SS') FROM yourtable;
SELECT TO_CHAR(yourval, 'HH:MI:SS') FROM yourtable;
Edit:
as #steven pointed out, to have 24 hours style use
SELECT TO_CHAR(yourval, 'HH24:MI:SS') FROM yourtable;
You need the format HH24, since HH is only a 12 hour date.
select to_char(SYSDATE, 'HH24:MI:SS') from dual
select to_char(YourDateColumn, 'HH24:MI:SS') from YourTable
SELECT TO_CHAR (SYSDATE, 'hh:mi:ss')
FROM DUAL
SELECT TO_CHAR(DATE_COLUMN,'HH24:MI:SS') from TABLE;
I need to add the current year as a variable in an SQL statement, how can I retrieve the current year using SQL?
i.e.
BETWEEN
TO_DATE('01/01/**currentYear** 00:00:00', 'DD/MM/YYYY HH24:MI:SS')
AND
TO_DATE('31/12/**currentYear** 23:59:59', 'DD/MM/YYYY HH24:MI:SS')
Using to_char:
select to_char(sysdate, 'YYYY') from dual;
In your example you can use something like:
BETWEEN trunc(sysdate, 'YEAR')
AND add_months(trunc(sysdate, 'YEAR'), 12)-1/24/60/60;
The comparison values are exactly what you request:
select trunc(sysdate, 'YEAR') begin_year
, add_months(trunc(sysdate, 'YEAR'), 12)-1/24/60/60 last_second_year
from dual;
BEGIN_YEAR LAST_SECOND_YEAR
----------- ----------------
01/01/2009 31/12/2009
Another option is:
SELECT *
FROM TABLE
WHERE EXTRACT( YEAR FROM date_field) = EXTRACT(YEAR FROM sysdate)
Use extract(datetime) function it's so easy, simple.
It returns year, month, day, minute, second
Example:
select extract(year from sysdate) from dual;
Yet another option would be:
SELECT * FROM mytable
WHERE TRUNC(mydate, 'YEAR') = TRUNC(SYSDATE, 'YEAR');
Since we are doing this one to death - you don't have to specify a year:
select * from demo
where somedate between to_date('01/01 00:00:00', 'DD/MM HH24:MI:SS')
and to_date('31/12 23:59:59', 'DD/MM HH24:MI:SS');
However the accepted answer by FerranB makes more sense if you want to specify all date values that fall within the current year.
Why not use YEAR function?
SELECT * FROM table WHERE YEAR(date_field)=YEAR(SYSDATE);
To display the current system date in oracle-sql
select sysdate from dual;