Query assistance please - sql

Question

Given the following table (much simplified for the purposes of this question):
id perPeriod actuals createdDate
---------------------------------------------------------
1 14 22 2011-10-04 00:00:00.000
2 14 9 2011-10-04 00:00:00.000
3 14 3 2011-10-03 00:00:00.000
4 14 5 2011-10-03 00:00:00.000
I need a query that gives me the average daily "actuals" figure. Note, however, that there are TWO RECORDS PER DAY (often more), so I can't just do AVG(actuals).
Also, if the daily "actuals" average exceeds the daily "perPeriod" average, I want to take the perPeriod value instead of the "average" value. Thus, in the case of the first two records: The actuals average for 4th October is (22+9) / 2 = 15.5. And the perPeriod average for the same day is (14 + 14) / 2 = 14. Now, 15.5 is greater than 14, so the daily "actuals" average for that day should be the "perPeriod" average.
Hope that makes sense. Any pointers greatly appreciated.
EDIT
I need an overall daily average, not an average per date. As I said, I would love to just do AVG(actuals) on the entire table, but the complicating factor is that a particular day can occupy more than one row, which would skew the results.

Answer 1

Is this what you want?
First, if the second payperiod average needed to be the average across a different grouping (It doesn't in this case), then you would need to use a subquery like this:
Select t.CreatedDate,
Case When Avg(actuals) < p.PayPeriodAvg
Then Avg(actuals) Else p.PayPeriodAvg End Average
From table1 t Join
(Select CreatedDate, Avg(PayPeriod) PayPeriodAvg
From table1
Group By CreatedDate) as p
On p.CreatedDate = t.CreatedDate
Group By t.CreatedDate, p.PayPeriodAvg
or, in this case, since the PayPeriod Average is grouped on the same thing, (CreatedDate) as the actuals average, you don't need a subquery, so even easier:
Select t.CreatedDate,
Case When Avg(actuals) < Avg(PayPeriod)
Then Avg(actuals) Else Avg(PayPeriod) End Average
From table1 t
Group By t.CreatedDate
with your sample data, both of these return
CreatedDate Average
----------------------- -----------
2011-10-03 00:00:00.000 4
2011-10-04 00:00:00.000 14

Answer 2

SELECT DAY(createdDate), MONTH(createdDate), YEAR(createdDate), MIN(AVG(actuals), MAX(perPeriod))
FROM MyTable
GROUP BY Day(createdDate, MONTH(createdDate), YEAR(createdDate)

Answer 3

Try this out:
select createdDate,
case
when AVG(actuals) > max(perPeriod) then max(perPeriod)
else AVG(actuals)
end
from SomeTestTable
group by createdDate