SQL Query: finding the 'day' value from a SQL DateTime - sql

I have a table with the fields timeout and timein. I need to return a list of records where timeout is on a different day to timein. How can I achieve this?

If both dates are in the same month, then:
select *
from table
where DAY(timeout) <> DAY(timein0)
or
select *
from table
where DATEPART(day,timeout) <> DATAPART(day,timein) or
will work..
If, however, they can be in different months, then you need to compare the full dates. This should do that for you:
select *
from table
where DATEDIFF(day,timeout,timein) <> 0

select *
from table_name
where datediff(dd,timein,timeout) > 0 (for day in greater then today)
if want next day time out then
select *
from table_name
where datediff(dd,timein,timeout) =1

How about this :
select *
from table
where day(timeout) != day(timein);

Related

select specific records using IN

I need to select records that has ID = 10,23,30 so I wrote this SQL
Select * from mytable where position(id in '10,23,30') > 0
But the problem I get additional records where ID = 1 and 2
Any ideas how to select only what I need ?
No need for position, just do IN:
Select * from mytable
where id in (10,23,30)
Use IN operator:
Select * from mytable where id in (10,23,30)

postgresql if else select query

I am trying to make a query that will compare first
first condition was to compare
the year now and
get the maximum year of view view_delinquency_allquarter
then, it will execute the first query
else second query
BEGIN
IF
select max(ctaxyear) as ctaxyear,
(select cast ( (SELECT EXTRACT(QUARTER FROM TIMESTAMP 'now()')) as int ) as yearnow) as yearnow
from view_delinquency_allquarter
where ctaxyear > year_next
THEN
select * from view_delinquency_allquarter;
ELSE
select * from view_delinquency;
END IF;
END
There are plenty of answers as well as documentation use declare var and then assignment var := (your query result)

SQL Server check if where clause is true for any row

I'm going to select those provinces which intersects any railroad. So I do it like this (Using SQL Spatial):
SELECT * FROM ProvinceTable
WHERE (
SELECT count(*)
FROM RailroadTable
WHERE ProvinceTable.Shape.STIntersects(RailroadTable.Shape) > 1
) > 0
But it is not efficient because it has to check the intersection between every single railroad geometry and province geometry in order to calculate the count. However it is better to stop the where clause as soon as every first intersection detected and there is no need to check others. Here is what I mean:
SELECT * FROM ProvinceTable
WHERE (
--return true if this is true for any row in the RailroadTable:
-- "ProvinceTable.Shape.STIntersects(RailroadTable.Shape) > 1"
)
So is there a better way to rewrite this query for such a goal?
EDIT
Surprisingly This query takes the same time and returns no row:
SELECT * FROM ProvinceTable
WHERE EXISTS (
SELECT *
FROM RailroadTable
WHERE ProvinceTable.Shape.STIntersects(RailroadTable.Shape) > 1
)
You want to use exists:
SELECT pt.*
FROM ProvinceTable pt
WHERE EXISTS (SELECT 1
FROM RailroadTable rt
WHERE pt.Shape.STIntersects(rt.Shape) = 1
);

return a default record from a sql query

I have a sql query that I run against a sql server database eg.
SELECT * FROM MyTable WHERE Id = 2
This may return a number of records or may return none. If it returns none, I would like to alter my sql query to return a default record, is this possible and if so, how? If records are returned, the default record should not be returned. I cannot update the data so will need to alter the sql query for this.
Another way (you would get an empty initial rowset returned);
SELECT * FROM MyTable WHERE Id = 2
IF (##ROWCOUNT = 0)
SELECT ...
SELECT TOP 1 * FROM (
SELECT ID,1 as Flag FROM MyTable WHERE Id = 2
UNION ALL
SELECT 1,2
) qry
ORDER BY qry.Flag ASC
You can have a look to this post. It is similar to what you are asking
Return a value if no rows are found SQL
I hope that it can guide you to the correct path.
if not exists (SELECT top 1 * FROM mytable WHERE id = 2)
select * from mytable where id= 'whatever_the_default_id_is'
else
select * from mytable where id = 2
If you have to return whole rows of data (and not just a single column) and you have to create a single SQL query then do this:
Left join actual table to defaults single-row table
select
coalesce(a.col1, d.col1) as col1,
coalesce(a.col2, d.col2) as col2,
...
from (
-- your defaults record
select
default1 as col1,
default2 as col2,
...) as d
left join actual as a
on ((1 = 1) /* or any actual table "where" conditions */)
The query need to return the same number of fields, so you shouldn't do a SELECT * FROM but a SELECT value FROM if you want to return a default value.
With that in mind
SELECT value FROM MyTable WHERE Id = 2
UNION
SELECT CASE (SELECT count(*) FROM MyTable WHERE Id = 2)
WHEN 0 THEN 'defaultvalue'
END

How to find the average time difference between rows in a table?

I have a mysql database that stores some timestamps. Let's assume that all there is in the table is the ID and the timestamp. The timestamps might be duplicated.
I want to find the average time difference between consecutive rows that are not duplicates (timewise). Is there a way to do it in SQL?
If your table is t, and your timestamp column is ts, and you want the answer in seconds:
SELECT TIMESTAMPDIFF(SECOND, MIN(ts), MAX(ts) )
/
(COUNT(DISTINCT(ts)) -1)
FROM t
This will be miles quicker for large tables as it has no n-squared JOIN
This uses a cute mathematical trick which helps with this problem. Ignore the problem of duplicates for the moment. The average time difference between consecutive rows is the difference between the first timestamp and the last timestamp, divided by the number of rows -1.
Proof: The average distance between consecutive rows is the sum of the distance between consective rows, divided by the number of consecutive rows. But the sum of the difference between consecutive rows is just the distance between the first row and last row (assuming they are sorted by timestamp). And the number of consecutive rows is the total number of rows -1.
Then we just condition the timestamps to be distinct.
Are the ID's contiguous ?
You could do something like,
SELECT
a.ID
, b.ID
, a.Timestamp
, b.Timestamp
, b.timestamp - a.timestamp as Difference
FROM
MyTable a
JOIN MyTable b
ON a.ID = b.ID + 1 AND a.Timestamp <> b.Timestamp
That'll give you a list of time differences on each consecutive row pair...
Then you could wrap that up in an AVG grouping...
Here's one way:
select avg(timestampdiff(MINUTE,prev.datecol,cur.datecol))
from table cur
inner join table prev
on cur.id = prev.id + 1
and cur.datecol <> prev.datecol
The timestampdiff function allows you to choose between days, months, seconds, and so on.
If the id's are not consecutive, you can select the previous row by adding a rule that there are no other rows in between:
select avg(timestampdiff(MINUTE,prev.datecol,cur.datecol))
from table cur
inner join table prev
on prev.datecol < cur.datecol
and not exists (
select *
from table inbetween
where prev.datecol < inbetween.datecol
and inbetween.datecol < cur.datecol)
)
OLD POST but ....
Easies way is to use the Lag function and TIMESTAMPDIFF
SELECT
id,
TIMESTAMPDIFF('MINUTES', PREVIOUS_TIMESTAMP, TIMESTAMP) AS TIME_DIFF_IN_MINUTES
FROM (
SELECT
id,
TIMESTAMP,
LAG(TIMESTAMP, 1) OVER (ORDER BY TIMESTAMP) AS PREVIOUS_TIMESTAMP
FROM TABLE_NAME
)
Adapted for SQL Server from this discussion.
Essential columns used are:
cmis_load_date: A date/time stamp associated with each record.
extract_file: The full path to a file from which the record was loaded.
Comments:
There can be many records in each file. Records have to be grouped by the files loaded on the extract_file column. Intervals of days may pass between one file and the next being loaded. There is no reliable sequential value in any column, so the grouped rows are sorted by the minimum load date in each file group, and the ROW_NUMBER() function then serves as an ad hoc sequential value.
SELECT
AVG(DATEDIFF(day, t2.MinCMISLoadDate, t1.MinCMISLoadDate)) as ElapsedAvg
FROM
(
SELECT
ROW_NUMBER() OVER (ORDER BY MIN(cmis_load_date)) as RowNumber,
MIN(cmis_load_date) as MinCMISLoadDate,
CASE WHEN NOT CHARINDEX('\', extract_file) > 0 THEN '' ELSE RIGHT(extract_file, CHARINDEX('\', REVERSE(extract_file)) - 1) END as ExtractFile
FROM
TrafTabRecordsHistory
WHERE
court_id = 17
and
cmis_load_date >= '2019-09-01'
GROUP BY
CASE WHEN NOT CHARINDEX('\', extract_file) > 0 THEN '' ELSE RIGHT(extract_file, CHARINDEX('\', REVERSE(extract_file)) - 1) END
) t1
LEFT JOIN
(
SELECT
ROW_NUMBER() OVER (ORDER BY MIN(cmis_load_date)) as RowNumber,
MIN(cmis_load_date) as MinCMISLoadDate,
CASE WHEN NOT CHARINDEX('\', extract_file) > 0 THEN '' ELSE RIGHT(extract_file, CHARINDEX('\', REVERSE(extract_file)) - 1) END as ExtractFile
FROM
TrafTabRecordsHistory
WHERE
court_id = 17
and
cmis_load_date >= '2019-09-01'
GROUP BY
CASE WHEN NOT CHARINDEX('\', extract_file) > 0 THEN '' ELSE RIGHT(extract_file, CHARINDEX('\', REVERSE(extract_file)) - 1) END
) t2 on t2.RowNumber + 1 = t1.RowNumber