I always seem to trip myself up during these types of SQL Statements. Here is what I'm attempting to accomplish.
My Example Table
Name Date Type
Bob 9/28/11 1
Bob 9/27/11 1
Bob 9/28/11 2
Debra 9/28/11 1
I'm trying to write a SQL Statement that would give me all the names, their total count occured, and then a Date Filter. I'll write a rought statement with completely wrong syntax, but I think it'll convey what I'm attempting to do...I think.
SELECT Name, Count(*) As Total
FROM Table
GROUP BY Name, Total
WHERE Date = Today (I'm aware you can't do a WHERE in a GROUP BY) AND Type = 1
Essentially, I would like to get back a set of data that would show the Name, how many instances of Type 1 for today.
I don't think I'm searching for the proper question to actually be able to effectively research this on my own as well, probably because I'm wording it improperly.
Any help would be appreciated!
Your WHERE was in the wrong place:
SELECT Name, Count(*) As Total
FROM Table
WHERE Date = Today AND Type = 1
GROUP BY Name
You just need to move your WHERE after your FROM.
SELECT Name, Count(*) As Total
FROM Table
WHERE [Date] = CAST(getdate() as Date) -- or 'Jan 1 1990'
AND [Type] = 1
GROUP BY Name
WHERE comes before GROUP
SELECT Name, Count(*) As Total
FROM Table
WHERE Date >= #Today --assuming your date passed in has no time
AND Date < DATEADD(d,1,#Today)
AND Type = 1
GROUP BY Name, Total
example you can run
SELECT LEFT(name,1) FROM sysobjects
WHERE name < 'p'
GROUP BY LEFT(name,1)
Related
I have a table with the follow structure
ID ReportDate Object_id
What I need to know, is the count of new and count of old (Object id's)
For example: If I have the data below:
I want the following output grouped by ReportDate:
I thought a way doing it using a Where clause based on date, however i need the data for all the dates I have in the table. To see the count of what already existed in the previous report and what is new at that report. Any Ideas?
Edit: New/Old definition- New would be the records that never appeared before that report run date and appeared on this one, whereas old is the number of records that had at least one match in previous dates. I'll edit the post to include this info.
managed to do it using a left join. Below is my solution in case it helps anyone in the future :)
SELECT table.ReportRunDate,
-1*sum(table.ReportRunDate = new_table.init_date) as count_new,
-1*sum(table.ReportRunDate <> new_table.init_date) as count_old,
count(*) as count_total
FROM table LEFT JOIN
((SELECT Object_ID, min(ReportRunDate) as init_date
FROM table
GROUP By OBJECT_ID) as new_table)
ON table.Object_ID = new_table.Object_ID
GROUP BY ReportRunDate
This would work in Oracle, not sure about ms-access:
SELECT ReportDate
,COUNT(CASE WHEN rnk = 1 THEN 1 ELSE NULL END) count_of_new
,COUNT(CASE WHEN rnk <> 1 THEN 1 ELSE NULL END)count_of_old
FROM (SELECT ID
,ReportDate
,Object_id
,RANK() OVER (PARTITION BY Object_id ORDER BY ReportDate) rnk
FROM table_name)
GROUP BY ReportDate
Inner query should rank each occurence of object_id based on the ReportDate so the 1st occurrence of certain object_id will have rank = 1, the next one rank = 2 etc.
Then the outer query counts how many records with rank equal/not equal 1 are the within each group.
I assumed that 1 object_id can appear only once within each reportDate.
I am using SQL Server and wondering if it is possible to iterate through time series data until specific condition is met and based on that label my data in other table?
For example, let's say I have a table like this:
Id Date Some_kind_of_event
+--+----------+------------------
1 |2018-01-01|dsdf...
1 |2018-01-06|sdfs...
1 |2018-01-29|fsdfs...
2 |2018-05-10|sdfs...
2 |2018-05-11|fgdf...
2 |2018-05-12|asda...
3 |2018-02-15|sgsd...
3 |2018-02-16|rgw...
3 |2018-02-17|sgs...
3 |2018-02-28|sgs...
What I want to get, is to calculate for each key the difference between two adjacent events and find out if there exists difference > 10 days between these two adjacent events. In case yes, I want to stop iterating for that specific key and put label 'inactive', otherwise 'active' in my other table. After we finish with one key, we start with another.
So for example id = 1 would get label 'inactive' because there exists two dates which have difference bigger that 10 days. The final result would be like that:
Id Label
+--+----------+
1 |inactive
2 |active
3 |inactive
Any ideas how to do that? Is it possible to do it with SQL?
When working with a DBMS you need to get away from the idea of thinking iteratively. Instead you need to try and think in sets. "Instead of thinking about what you want to do to a row, think about what you want to do to a column."
If I understand correctly, is this what you're after?
CREATE TABLE SomeEvent (ID int, EventDate date, EventName varchar(10));
INSERT INTO SomeEvent
VALUES (1,'20180101','dsdf...'),
(1,'20180106','sdfs...'),
(1,'20180129','fsdfs..'),
(2,'20180510','sdfs...'),
(2,'20180511','fgdf...'),
(2,'20180512','asda...'),
(3,'20180215','sgsd...'),
(3,'20180216','rgw....'),
(3,'20180217','sgs....'),
(3,'20180228','sgs....');
GO
WITH Gaps AS(
SELECT *,
DATEDIFF(DAY,LAG(EventDate) OVER (PARTITION BY ID ORDER BY EventDate),EventDate) AS EventGap
FROM SomeEvent)
SELECT ID,
CASE WHEN MAX(EventGap) > 10 THEN 'inactive' ELSE 'active' END AS Label
FROM Gaps
GROUP BY ID
ORDER BY ID;
GO
DROP TABLE SomeEvent;
GO
This assumes you are using SQL Server 2012+, as it uses the LAG function, and SQL Server 2008 has less than 12 months of any kind of support.
Try this. Note, replace #MyTable with your actual table.
WITH Diffs AS (
SELECT
Id
,DATEDIFF(DAY,[Date],LEAD([Date],1,0) OVER (ORDER BY [Id], [Date])) Diff
FROM #MyTable)
SELECT
Id
,CASE WHEN MAX(Diff) > 10 THEN 'Inactive' ELSE 'Active' END
FROM Diffs
GROUP BY Id
Just to share another approach (without a CTE).
SELECT
ID
, CASE WHEN SUM(TotalDays) = (MAX(CNT) - 1) THEN 'Active' ELSE 'Inactive' END Label
FROM (
SELECT
ID
, EventDate
, CASE WHEN DATEDIFF(DAY, EventDate, LEAD(EventDate) OVER(PARTITION BY ID ORDER BY EventDate)) < 10 THEN 1 ELSE 0 END TotalDays
, COUNT(ID) OVER(PARTITION BY ID) CNT
FROM EventsTable
) D
GROUP BY ID
The method is counting how many records each ID has, and getting the TotalDays by date differences (in days) between the current the next date, if the difference is less than 10 days, then give me 1, else give me 0.
Then compare, if the total days equal the number of records that each ID has (minus one) would print Active, else Inactive.
This is just another approach that doesn't use CTE.
I have what seems to be a common business request but I can't find no clear solution. I have a daily report (amongst many) that gets generated based on failed criteria and gets saved to a table. Each report has a type id tied to it to signify which report it is, and there is an import event id that signifies the day the imports came in (a date column is added for extra clarification). I've added a sqlfiddle to see the basic schema of the table (renamed for privacy issues).
http://www.sqlfiddle.com/#!3/81945/8
All reports currently generated are working fine, so nothing needs to be modified on the table. However, for one report (type 11), not only I need pull the invoices that showed up today, I also need to add one column that totals the amount of consecutive days from date of run for that invoice (including current day). The result should look like the following, based on the schema provided:
INVOICE MESSAGE EVENT_DATE CONSECUTIVE_DAYS_ON_REPORT
12345 Yes July, 30 2013 6
54355 Yes July, 30 2013 2
644644 Yes July, 30 2013 4
I only need the latest consecutive days, not any other set that may show up. I've tried to run self joins to no avail, and my last attempt is also listed as part of the sqlfiddle file, to no avail. Any suggestions or ideas? I'm quite stuck at the moment.
FYI: I am working in SQL Server 2000! I have seen a lot of neat tricks that have come out in 2005 and 2008, but I can't access them.
Your help is greatly appreciated!
Something like this? http://www.sqlfiddle.com/#!3/81945/14
SELECT
[final].*,
[last].total_rows
FROM
tblEventInfo AS [final]
INNER JOIN
(
SELECT
[first_of_last].type_id,
[first_of_last].invoice,
MAX([all_of_last].event_date) AS event_date,
COUNT(*) AS total_rows
FROM
(
SELECT
[current].type_id,
[current].invoice,
MAX([current].event_date) AS event_date
FROM
tblEventInfo AS [current]
LEFT JOIN
tblEventInfo AS [previous]
ON [previous].type_id = [current].type_id
AND [previous].invoice = [current].invoice
AND [previous].event_date = [current].event_date-1
WHERE
[current].type_id = 11
AND [previous].type_id IS NULL
GROUP BY
[current].type_id,
[current].invoice
)
AS [first_of_last]
INNER JOIN
tblEventInfo AS [all_of_last]
ON [all_of_last].type_id = [first_of_last].type_id
AND [all_of_last].invoice = [first_of_last].invoice
AND [all_of_last].event_date >= [first_of_last].event_date
GROUP BY
[first_of_last].type_id,
[first_of_last].invoice
)
AS [last]
ON [last].type_id = [final].type_id
AND [last].invoice = [final].invoice
AND [last].event_date = [final].event_date
The inner most query looks up the starting record of the last block of consecutive records.
Then that joins on to all the records in that block of consecutive records, giving the final date and the count of rows (consecutive days).
Then that joins on to the row for the last day to get the message, etc.
Make sure that in reality you have an index on (type_id, invoice, event_date).
You have multiple problems. Tackle them separately and build up.
Problems:
1) Identifying consecutive ranges: subtract the row_number from the range column and group by the result
2) No ROW_NUMBER() functions in SQL 2000: Fake it with a correlated subquery.
3) You actually want DENSE_RANK() instead of ROW_NUMBER: Make a list of unique dates first.
Solutions:
3)
SELECT MAX(id) AS id,invoice,event_date FROM tblEventInfo GROUP BY invoice,event_date
2)
SELECT t2.invoice,t2.event_date,t2.id,
DATEDIFF(day,(SELECT COUNT(DISTINCT event_date) FROM (SELECT MAX(id) AS id,invoice,event_date FROM tblEventInfo GROUP BY invoice,event_date) t1 WHERE t2.invoice = t1.invoice AND t2.event_date > t1.event_date),t2.event_date) grp
FROM (SELECT MAX(id) AS id,invoice,event_date FROM tblEventInfo GROUP BY invoice,event_date) t2
ORDER BY invoice,grp,event_date
1)
SELECT
t3.invoice AS INVOICE,
MAX(t3.event_date) AS EVENT_DATE,
COUNT(t3.event_date) AS CONSECUTIVE_DAYS_ON_REPORT
FROM (
SELECT t2.invoice,t2.event_date,t2.id,
DATEDIFF(day,(SELECT COUNT(DISTINCT event_date) FROM (SELECT MAX(id) AS id,invoice,event_date FROM tblEventInfo GROUP BY invoice,event_date) t1 WHERE t2.invoice = t1.invoice AND t2.id > t1.id),t2.event_date) grp
FROM (SELECT MAX(id) AS id,invoice,event_date FROM tblEventInfo GROUP BY invoice,event_date) t2
) t3
GROUP BY t3.invoice,t3.grp
The rest of your question is a little ambiguous. If two ranges are of equal length, do you want both or just the most recent? Should the output MESSAGE be 'Yes' if any message = 'Yes' or only if the most recent message = 'Yes'?
This should give you enough of a breadcrumb though
I had a similar requirement not long ago getting a "Top 5" ranking with a consecutive number of periods in Top 5. The only solution I found was to do it in a cursor. The cursor has a date = #daybefore and inside the cursor if your data does not match quit the loop, otherwise set #daybefore = datediff(dd, -1, #daybefore).
Let me know if you want an example. There just seem to be a large number of enthusiasts, who hit downvote when they see the word "cursor" even if they don't have a better solution...
Here, try a scalar function like this:
CREATE FUNCTION ConsequtiveDays
(
#invoice bigint, #date datetime
)
RETURNS int
AS
BEGIN
DECLARE #ct int = 0, #Count_Date datetime, #Last_Date datetime
SELECT #Last_Date = #date
DECLARE counter CURSOR LOCAL FAST_FORWARD
FOR
SELECT event_date FROM tblEventInfo
WHERE invoice = #invoice
ORDER BY event_date DESC
FETCH NEXT FROM counter
INTO #Count_Date
WHILE ##FETCH_STATUS = 0 AND DATEDIFF(dd,#Last_Date,#Count_Date) < 2
BEGIN
#ct = #ct + 1
END
CLOSE counter
DEALLOCATE counter
RETURN #ct
END
GO
I am trying to write a query that brings up the details (invoiceNumber, name, phone & email) from a table but only where the entries match these specific requirements:
Return the rows where the email address appears only once in the whole table from any date
AND
Return the rows where the email address multiple times WHERE the email has only been entered ONCE within the last 3 months.
I am fairly sure that this requires nested statements but I have no idea how to go about setting it up.
Any help would be greatly appreciated!
Approach this by thinking about the email addresses. You can determine the frequency of appearance by doing a group by:
select emailaddress, count(*) as TotalCnt,
sum(case when invoicedate >= sysdate - 90 then 1 else 0 end) as LastThreeMonths
from t
group by emailaddress;
This gives you the information you need. The following query joins this back to the original table to get the rows you are looking for:
select t.*
from t join
(select emailaddress, count(*) as TotalCnt,
sum(case when invoicedate >= sysdate - 90 then 1 else 0 end) as LastThreeMonths
from t
group by emailaddress
) e
on t.emailaddress = e.emailaddress
where e.TotalCnt = 1 or e.LastThreeMonths = 1
I'm trying to add the counts together and output the one with the max counts.
The question is: Display the person with the most medals (gold as place = 1, silver as place = 2, bronze as place = 3)
Add all the medals together and display the person with the most medals
Below is the code I have thought about (obviously doesn't work)
Any ideas?
Select cm.Givenname, cm.Familyname, count(*)
FROM Competitors cm JOIN Results re ON cm.competitornum = re.competitornum
WHERE re.place between '1' and '3'
group by cm.Givenname, cm.Familyname
having max (count(re.place = 1) + count(re.place = 2) + count(re.place = 3))
Sorry forgot to add that were not allowed to use ORDER BY.
Some data in the table
Competitors Table
Competitornum GivenName Familyname gender Dateofbirth Countrycode
219153 Imri Daniel Male 1988-02-02 Aus
Results Table
Eventid Competitornum Place Lane Elapsedtime
SWM111 219153 1 2 20 02
From what you've described it sounds like you just need to take the "Top" individual in the total medal count. In order to do that you would write something like this.
Select top 1 cm.Givenname, cm.Familyname, count(*)
FROM Competitors cm JOIN Results re ON cm.competitornum = re.competitornum
WHERE re.place between '1' and '3'
group by cm.Givenname, cm.Familyname
order by count(*) desc
Without using order by you have a couple of other options though I'm glossing over whatever syntax peculiarities sqlfire may use.
You could determine the max medal count of any user and then only select competitors that have that count. You could do this by saving it out to a variable or using a subquery.
Select cm.Givenname, cm.Familyname, count(*)
FROM Competitors cm JOIN Results re ON cm.competitornum = re.competitornum
WHERE re.place between '1' and '3'
group by cm.Givenname, cm.Familyname
having count(*) = (
Select max( count(*) )
FROM Competitors cm JOIN Results re ON cm.competitornum = re.competitornum
WHERE re.place between '1' and '3'
group by cm.Givenname, cm.Familyname
)
Just a note here. This second method is highly inefficient because we recalculate the max medal count for every row in the parent table. If sqlfire supports it you would be much better served by calculating this ahead of time, storing it in a variable and using that in the HAVING clause.
You are grouping by re.place, is that what you want? You want the results per ... ? :)
[edit] Good, now that's fixed you're almost there :)
The having is not needed in this case, you simply need to add a count(re.EventID) to your select and make a subquery out of it with a max(that_count_column).