I've two column data as:
9 17.52
11 29.77
7 62.75
11 36.15
7 30.46
7 52.5
9 65.26
9 90.05
14 101.87
12 86.88
15 74.78
And want that first column be plotted as histogram according to index of y2, and second column be plotted as line according to index of y1. Anyone has ideas?
Maybe I didn't understand your question correctly, but are you possibly looking for something like this:
set style fill solid border -1
set boxwidth 0.4
plot "Data.dat" u 2 w boxes t "boxes", "" u (column(0)):1 t "lines" w l
?
Related
I have a simple line graph, but the xticks are overlapping. Therefore I want to display only every 2nd xtick. I implemented this answer which worked for me in another graph. As you can see below it stops working after the 6th tick and I can't wrap my head around why.
My code is the following:
data = pf.cum_perc
fig, ax = plt.subplots(figsize=(10, 6))
ax.set_xlabel("Days", size=18)
ax.set_ylabel("Share of reviews", size = 18)
for label in ax.xaxis.get_ticklabels()[1::2]:
label.set_visible(False)
ax.plot(data)
pf.cum_perc is a column of a data frame (therefore a series) with the following data:
1 0.037599
2 0.089759
3 0.203477
4 0.302451
5 0.398169
6 0.486392
7 0.533514
8 0.538183
9 0.539411
10 0.550040
11 0.550716
12 0.553050
13 0.553726
14 0.654789
15 0.681084
16 0.706211
17 0.731462
18 0.756712
19 0.781594
20 0.807766
21 0.873687
(and so on)
The resulting graph:
Any help is greatly appreciated :)
As user #ImportanceOfBeingErnest suggested:
Solution 1:
Convert the x-axis data to numbers, so matplotbib takes care of the ticks automatically. In my case this is done by
pf.index = pf.index.map(int)
Solution 2:
Remove the ticks, after the graph is plotted, otherwise the objects don't exist yet and therefore can't be set invisible.
The new code would look like this:
data = pf.cum_perc
fig, ax = plt.subplots(figsize=(10, 6))
ax.set_xlabel("Days", size=18)
ax.set_ylabel("Share of reviews", size = 18)
ax.plot(data)
for label in ax.xaxis.get_ticklabels()[1::2]:
label.set_visible(False)
I've got next script to plot dots from file "puntos"
set title "recorrido vehiculos"
set term png
set output "rutasVehiculos.png"
plot "puntos" u 2:3:(sprintf("%d",$1)) with labels font ",7" point pt 7 offset char 0.5,0.5 notitle
file "puntos" has next format:
#i x y
1 2.1 3.2
2 0.2 0.3
3 2.9 0.3
in another file called "routes" i have the routes that joins the points, for example:
2
1 22 33 20 18 14 8 27 1
1 13 2 17 31 1
Route 1 joins points 1, 22, 33, etc.
Route 2 joins points 1, 13, 12, etc.
Is there a way that perform this with gnuplot?
PS: sorry for my English
Welcome to stackoverflow. This is an interesting task. It's pretty clear what to do, however, to my opinion not very obvious how to do this gnuplot.
The following code seems to work, probably with room for improvements. Tested in gnuplot 5.2.5
Tested with the files puntos.dat and routes.dat:
# puntos.dat
#i x y
1 2.1 3.2
2 0.2 0.3
3 2.9 0.3
4 1.3 4.5
5 3.1 2.3
6 1.9 0.7
7 3.6 1.7
8 2.3 1.5
9 1.0 2.0
and
# routes.dat
2
1 5 7 3 6 2 9
6 8 5 9 4
and the code:
### plot different routes
reset session
set title "recorrido vehiculos"
set term pngcairo
set output "rutasVehiculos.png"
POINTS = "puntos.dat"
ROUTES = "routes.dat"
# load routes file into datablock
set datafile separator "\n"
set table $Routes
plot ROUTES u (stringcolumn(1)) with table
unset table
# loop routes
set datafile separator whitespace
stats $Routes u 0 nooutput # get the number of routes
RoutesCount = STATS_records-1
set print $RoutesData
do for [i=1:RoutesCount] {
# get the points of a single route
set datafile separator "\n"
set table $Dummy
plot ROUTES u (SingleRoute = stringcolumn(1),$1) every ::i::i with table
unset table
# create a table of the coordinates of the points of a single route
set datafile separator whitespace
do for [j=1:words(SingleRoute)] {
set table $Dummy2
plot POINTS u (a=$2,$2):(b=$3,$3) every ::word(SingleRoute,j)-1::word(SingleRoute,j)-1 with table
print sprintf("%g %s %g %g", j, word(SingleRoute,j), a, b)
unset table
}
print "" # add empty line
}
set print
print sprintf("%g different Routes\n", RoutesCount)
print "RoutesData:"
print $RoutesData
set colorsequence classic
plot \
POINTS u 2:3:(sprintf("%d",$1)) with labels font ",7" point pt 7 offset char 0.5,0.5 notitle,\
for [i=1:RoutesCount] $RoutesData u 3:4 every :::i-1::i-1 w lp lt i title sprintf("Route %g",i)
set output
### end code
which results in something like:
I have a pretty simple dataframe as seen below. I am trying to manipulate the x-axis(dates) so it starts at 1996-31-12 and ends at 2016-31-12 on increments of 365 days.
Datafame:
Date A B
1996-31-12 10 3
1997-31-03 5 6
1997-31-07 7 5
1997-30-11 3 12
1997-31-12 4 10
1998-31-03 5 8
.
.
.
2016-31-12 3 9
#change date string to datetime variable
df12.Date = pd.to_datetime(df12.Date)
fig, ax = plt.subplots()
ax.plot_date(df12.Date,df12.A)
ax.plot_date(df12.Date,df12.B)
ax.xaxis.set_major_locator(mdates.YearLocator())
ax.xaxis.grid(True, which="major")
ax.yaxis.grid()
ax.xaxis.set_major_formatter(mdates.DateFormatter('%b\n%Y''))
plt.tight_layout()
plt.show()
I am getting an error message when i try and run the above code that I am not sure what it means-OverflowError: Python int too large to convert to C long. ANy one know what this means? If not, is there another way to do what i want to do?
Please, i have a question about gnuplot.
Here is the file i work on:
1 129 130
2 129 129
3 129 130
4 129 129
5 129 ---
As you see the last line has no value in the third column.
Here is my command:
plot "mesuresSecondscen.txt" using 1:2 with linespoints lt 26 pt 26 tit 'Kernel of 129s' axis x1y1, "mesuresSecondscen.txt" using 1:3 with linespoints lt 21 pt 13 tit 'With-My-Approach' axis x1y1
Example: http://tinyurl.com/p2rfde9
I'd like to set the symbol 'X' in red in the place of the absent value
Is that possible please ?
Thank you so much for answer.
Kind regards.
There is a fundamental problem with your question, which is that you want to place a red "X", but where? If the value is missing you need to provide the coordinate value in some other way to know where you want to place the symbol. Anyway, for demonstration purposes I will assume you want to place it where the second column value lies. The function valid(n) can test if the value in column n is valid (returns 1) or not (returns 0). Using a conditional expression we can ask gnuplot to place a big red "X" at y = column(2) every time it encounters non-valid data:
plot "mesuresSecondscen.txt" using 1:2 with linespoints lt 26 pt 26 tit 'Kernel of 129s' axis x1y1, \
"mesuresSecondscen.txt" using 1:3 with linespoints lt 21 pt 13 tit 'With-My-Approach' axis x1y1, \
"mesuresSecondscen.txt" u 1:(valid(3) == 1 ? 1/0 : $2) pt 2 lc 1 ps 3 lw 3
The last line tests if the third column's value is valid, if it is valid (valid(3) = 1) it ignores that point, if it is not valid (valid(3) = 0) it places a big red "X" at y = column(2).
I am trying plot data sets consisting of 3 coordinates:
X-coordinate, x-coordinate and the number of occurrences.
example:
1 2 10
3 1 2
3 2 1
I would like to draw for every line a dot at x,y with a diameter which is depending on the third value.
Is that possible with Gnuplot?
Create a 2D plot with variable point size. See the demo.
Example:
plot 'dataFile.dat' u 1:2:3 w points lt 1 pt 10 ps variable
This is basically equivalent to the existing answer, just shorter:
plot 'dataFile.dat' with circles
Credit: Gnuplot: plot with circles of a defined radius