MySQL table is like this (VoteID is PK):
VoteID VoteValue CommentID
1 -1 1
2 -1 1
3 1 1
4 -1 1
5 1 2
6 1 2
7 -1 2
I need a result:
CommentID Plus Minus
1 1 3
2 2 1
Sum of "Pluses", Sum of "Minuses" groupped by CommentID
Is it possible to get desired in one SQL expression?
SELECT
CommentID,
SUM(CASE WHEN VoteValue > 0 THEN 1 ELSE 0 END) AS PLUS,
SUM(CASE WHEN VoteValue < 0 THEN 1 ELSE 0 END) AS MINUS
FROM
mytable
GROUP BY
CommentID
You need a query in the lines of:
SELECT CommentID,
SUM(IF(VoteValue > 0, 1, 0)) AS Plus,
SUM(IF(VoteValue < 0, 1, 0)) AS Minus
FROM yourTable
GROUP BY CommentID
ORDER BY CommentID
Related
I have a series of Ids, some of them activate a product on certain month and that product remains activated for an X period of time, while others do not activate the product.
I want to create a column which indicates in which month the user activates the product or a NULL if the user doesn't activate it.
I've tried using a partition like the following:
SELECT id, fl_testdrive, month_dt,
CASE WHEN fl_testdrive = 1 then min(month_dt) OVER(PARTITION BY id ORDER BY month_dt ROWS UNBOUNDED PRECEDING) else 0 end as month_testdrive
FROM Table_1
However, when I try this solution, in the column month_testdrive, I do not obtain the first month in which the user appears, indepently of if he/she activated that product in that month or on a later one.
This is what I get with my query
Id flag_testdrive month_dt month_testdrive
1 0 1 1
1 0 2 1
1 1 3 1
1 1 4 1
2 0 2 0
2 0 3 0
3 1 4 4
3 1 5 4
What I'd expect:
Id flag_testdrive month_dt month_testdrive
1 0 1 3
1 0 2 3
1 1 3 3
1 1 4 3
2 0 2 0
2 0 3 0
3 1 4 4
3 1 5 4
This solution is a second best but is also fine:
Id flag_testdrive month_dt month_testdrive
1 0 1 0
1 0 2 0
1 1 3 3
1 1 4 3
2 0 2 0
2 0 3 0
3 1 4 4
3 1 5 4
You want CASE expression inside MIN():
MIN(CASE WHEN fl_testdrive = 1 THEN month_dt ELSE 0 END) OVER(PARTITION BY id, flag_testdrive ORDER BY month_dt ROWS UNBOUNDED PRECEDING)
Here's an option for you:
DECLARE #Testdate TABLE(
id INT
,flag_testdrive INT
,month_dt INT
)
INSERT INTO #Testdate (
[id]
, [flag_testdrive]
, [month_dt]
)
VALUES(1,0,1)
,(1,0,2)
,(1,1,3)
,(1,1,4)
,(2,0,2)
,(2,0,3)
,(3,1,4)
,(3,1,5)
SELECT
*
,COALESCE((SELECT MIN([aa].[month_dt]) FROM #Testdate aa
WHERE aa.[id] = a.id
AND aa.[flag_testdrive] = 1), 0) AS month_testdrive
FROM #Testdate a
Return the minimum month_dt for a given id only if flag_testdrive=1, wrapped in coalesce to return 0 instead of NULL.
I have this table
SECTION
Which consist of field called
Semester
2
1
1
1
2
1
1
2
2
2
1
2
I need sql to count how many 1's and how many 2's are there
And out put like this
semester 1 | semester 2
6 | 6
Demo here:After testing
select
sum(Case when semester=1 then 1 else 0 end) as 'Semester1',
sum(Case when semester=2 then 1 else 0 end) as 'Semester2'
from section
Try out this:
Select sum(case when semster =1 then 1 else 0 end) as semster1 ,
sum(case when semster =2 then 1 else 0 end) as semster2
from section;
Assuming there are more values than 1 and 2, and that the values are integers:
SELECT semester, count(*)
FROM section
WHERE semester = 1 OR semester = 2
GROUP BY semester
Lets say I have a table Tbl (Represents simple timelogs for work made on different customers)
Five columns
Id: int
TimeUse: float
IdCustomer: int
Created: DateTime
TimeCalc: float
I have a number of records in this table, (TimeCalc is initialized to value = 0)
What I want my SQL to do is:
when TimeUse for all foregoing records on a specific customer accumulates to a value < 10 then the value in TimeCalc should be 0
when TimeUse for all foregoing records on a specific customer accumulates to a value >= 10 then the value in TimeCalc should be = TimeUse for the record...
I have messed around with Case routines with subqueries, but can't get it working.
BEFORE
Id TimeUse IdCustomer Created TimeCalc
1 2 1 14/09/09 0
2 5 2 14/09/10 0
3 2 1 14/09/11 0
4 5 2 14/09/12 0
5 4 1 14/09/13 0
6 2 2 14/09/14 0
7 4 1 14/09/15 0
8 1 1 14/09/16 0
9 3 2 14/09/17 0
10 2 1 14/09/18 0
11 4 2 14/09/19 0
AFTER
Id TimeUse IdCustomer Created TimeCalc
1 2 1 14/09/09 0
2 5 2 14/09/10 0
3 2 1 14/09/11 0
4 5 2 14/09/12 0
5 4 1 14/09/13 0
6 2 2 14/09/14 2
7 4 1 14/09/15 0
8 1 1 14/09/16 1
9 3 2 14/09/17 3
10 2 1 14/09/18 2
11 4 2 14/09/19 4
Can this be solved in an SQL update?
In SQL Server 2012+, you can do this with a cumulative sum:
select Id, TimeUse, IdCustomer, Created,
(case when sum(timeuse) over (partition by idcustomer order by id) < 10 then 0
else timeuse
end) as timecalc
from table t;
You can do the same thing in earlier versions using outer apply or a subquery.
If you want an update, just use a CTE:
with toupdate as (
select t.*,
(case when sum(timeuse) over (partition by idcustomer order by id) < 10 then 0
else timeuse
end) as new_timecalc
from table t
)
update toupdate
set timecalc = new_timecalc;
EDIT:
The following will work in any version of SQL Server:
with toupdate as (
select t.*,
(case when (select sum(t2.timeuse)
from table t2
where t2.idcustomer = t.idcustomer and
t2.id <= t.id
) < 10 then 0
else timeuse
end) as new_timecalc
from table t
)
update toupdate
set timecalc = new_timecalc;
I have the following Result from Select statement
UnitId UnitType GroupId
1 1 1
2 1 1
3 1 2
4 2 2
5 2 2
6 2 2
7 2 2
I need the following result for each group Id
GroupId CountBasedOnUnitType1 CountBasedOnUnitType2
1 2 0
2 1 4
Thanks in advance.
Try this
SELECT * FROM
(
SELECT GroupId,
UnitType
FROM Table1
) x
Pivot
(
Count(UnitType)
For UnitType in ([1], [2])
) p
Fiddle Demo
Output
GroupId 1 2
1 2 0
2 1 4
Does in necessarily need to have OVER?
select
GroupID,
sum(case when UnitType = 1 then 1 else 0 end) CountBasedOnUnitType1,
sum(case when UnitType = 2 then 1 else 0 end) CountBasedOnUnitType2
from table
group by GroupID
I have a table AssignmentMaster in that I have following columns with data
AssignmentID PaidAmount RefundAmount UserID
1 20 0 1
2 10 5 1
3 30 7 2
4 25 0 3
5 35 15 3
6 10 3 1
7 5 0 3
8 10 0 3
Now I want to find out the TotalNumberofAssignment with respect to userID, i.e. result should be:
UserID TotalAssignment TotalAssignmentofRefundAmount TotalPaidAmount TotalRefundAmount
1 3 2 40 8
2 1 1 30 7
3 4 1 75 15
How I can get above given result in MSSQL.
your any help will help me lot.
SELECT
UserID,
COUNT(AssignmentID) AS TotalAssignment,
SUM(SIGN(RefundAmount)) AS TotalAssignmentofRefundAmount,
SUM(PaidAmount) AS TotalPaidAmount,
SUM(RefundAmount) AS TotalRefundAmount
FROM
MyTable
GROUP BY
UserID
Note:
SIGN(RefundAmount) works if RefundAmount is always >= 0.
If not, change to
SUM(CASE WHEN RefundAmount <> 0 THEN 1 ELSE 0 END) AS TotalAssignmentofRefundAmount
Select UserID,
count(1) as TotalAssignment,
sum( case when RefundAmount = 0 then 0 else 1 end) as TotalAssignmentofRefundAmount,
sum(PaidAmount) as TotalPaidAmount ,
sum(RefundAmount) as TotalRefundAmount
From AssignmentMaster
Group by UserID
To show how to do this using nested SQL:
Select UserTotals.UserID, UserTotals.TotalAssignment,
Refunds.TotalAssignmentofRefundAmount,
UserTotals.TotalPaidAmount, UserTotals.TotalRefundAmount
From (select UserID,
Count(AssignmentID) [TotalAssignment],
Sum(PaidAmount) [TotalPaidAmount],
sum(RefundAmount) [TotalRefundAmount]
From #AssignmentMaster
Group By UserID
) [UserTotals] Left Join
(Select UserID,
Count(AssignmentID) [TotalAssignmentofRefundAmount]
From #AssignmentMaster
Where RefundAmount > 0
Group By UserID
) [Refunds] On Refunds.UserID = UserTotals.UserID
select UserId, count (AssignmentID) as TotalAssignment,
sum(case when RefundAmount = 0 then 0 else 1 end) as TotalAssignmentofRefundAmount,
sum(PaidAmount) as TotalPaidAmound,
sum(RefundAmount) as TotalRefundAmount
from AssignmentMaster
group by UserID;