I have the following code in my msbuild script:
<?xml version="1.0" encoding="utf-8"?>
<Project xmlns="http://schemas.microsoft.com/developer/msbuild/2003" ToolsVersion="4.0" InitialTargets="Build">
<PropertyGroup>
<Configuration Condition=" '$(Configuration)' == '' ">Debug</Configuration>
<SolutionName>CommTrac.Web\CommTrac.Web</SolutionName>
<SolutionFileName>$(SolutionName).csproj</SolutionFileName>
</PropertyGroup>
<Target Name="Build">
<Message Text="Building the solution"/>
<MSBuild Projects="$(SolutionFileName)" ContinueOnError="false" Properties="Configuration=$(Configuration)" />
</Target>
<Target Name="CopyOutput" DependsOnTargets="Build">
<ItemGroup>
<BinFolder Exclude="*.pdb" Include="$(ProjectDir)bin\**\*.*"/>
<BuildOutputFolder Include="C:\BuildOutput" />
</ItemGroup>
<Message Text="Copying from directory: $(BinFolder)"/>
<Copy SourceFiles="$(BinFolder)" DestinationFolder="$(BuildOutputFolder)"/>
</Target>
</Project>
For some reason, it will not copy the files to my output directory. I have tried all the similar
solutions with other questions that I have seen similar to this issue. Anyone have any ideas?
BindFolder and BuildOutputFolder are items, not properties. So you need to reference them using #(BindFolder) and #(BuildOutputFolder) instead of using '$'.
Related
I have a .proj file which is configured to execute a solution file which in turn build all the projects in the solution.
I want to add an XCopy operation which should copy the .dll files of all projects to another location only after all the projects build is completed.
I have tried with below, but it is not copying the dlls.
I am newbie in writing MSBuild tags, so it could be that I may be wrong in choosing this approach to write the task in this way.
Please provide a solution, if anyone knows.
<?xml version="1.0" encoding="utf-8"?>
<Project ToolsVersion="Current" DefaultTargets="Build" xmlns="http://schemas.microsoft.com/developer/msbuild/2003">
<PropertyGroup>
<Configuration Condition="'$(Configuration)' == 'Release|Debug'"/>
<Platform Condition="'$(Platform)' == ''">x64</Platform>
</PropertyGroup>
<ItemDefinitionGroup>
<SolutionToBuild>
<Properties>Configuration=$(Configuration);Platform=$(Platform)</Properties>
<Targets>Clean;Build</Targets>
</SolutionToBuild>
</ItemDefinitionGroup>
<ItemGroup>
<SolutionToBuild Include="..\Seg\Algorithms.sln" />
</ItemGroup>
<Target Name="Build" >
<MSBuild Projects="#(SolutionToBuild)" Targets="%(SolutionToBuild.Targets)" Properties="%(SolutionToBuild.Properties)" BuildInParallel="false" ContinueOnError="false" />
</Target>
<Target Name="Clean">
<MSBuild Projects="#(SolutionToBuild)" Targets="Clean" Properties="%(SolutionToBuild.Properties)" BuildInParallel="false" ContinueOnError="false" />
</Target>
<PropertyGroup>
<CopyDestination>..\Extern\Algo\bin\$(Configuration)\</CopyDestination>
<CopySource>..\Seg\Algorithms\$(Configuration)\DoBin\</CopySource>
</PropertyGroup>
<ItemGroup>
<FilesToCopy Include="$(CopySource)*.dll"/>
</ItemGroup>
<ItemGroup>
<CustomBuildStep Include ="#(FilesToCopy)">
<Message>Copying..</Message>
<Command> XCOPY %(Identity) $(CopyDestination) /f /y </Command>
</CustomBuildStep>
</ItemGroup>
<PropertyGroup>
<CustomBuildAfterTargets>Build</CustomBuildAfterTargets>
</PropertyGroup>
</Project>
Think of Targets as methods that are called. They run in sequence, so you just need to put your copy after the solution build:
<Target Name="Build">
<MSBuild Projects="#(SolutionToBuild)" Targets="%(SolutionToBuild.Targets)" Properties="%(SolutionToBuild.Properties)" BuildInParallel="false" ContinueOnError="false" />
<ItemGroup>
<FilesToCopy Include="..\Seg\Algorithms\$(Configuration)\DoBin\*.dll" />
</ItemGroup>
<Copy SourceFiles="#(FilesToCopy)" DestinationFolder="..\Extern\Algo\bin\$(Configuration)\" SkipUnchangedFiles="true" />
</Target>
I have a property GroupProj storing a full path name. How can I extract the directory of the property?
I have the following code, but it doesn't work as expected:
<PropertyGroup>
<GroupProj>C:\development\project\default.groupproj</GroupProj>
</PropertyGroup>
<Target Name="Default">
<Message Text="Echo: $(GroupProj->'%(RootDir)')" />
</Target>
I will describe my actual intention of doing so. Perhaps there is a way to do the job that I am not aware of.
I have a Delphi groupproj (MSBuild project) file, C:\development\project\default.groupproj:
<Project xmlns="http://schemas.microsoft.com/developer/msbuild/2003">
<ItemGroup>
<Projects Include="project1.dproj">
<Dependencies/>
</Projects>
<Projects Include="project2.dproj">
<Dependencies/>
</Projects>
<Projects Include="project3.dproj">
<Dependencies/>
</Projects>
</ItemGroup>
...
</Project>
There are other 3 MSBuild files (project1.dproj, project2.dproj and project3.dproj) stored in same folder as default.groupproj.
I create a MSBuild project file (c:\test.targets):
<Project xmlns="http://schemas.microsoft.com/developer/msbuild/2003" DefaultTargets="Build" ToolsVersion="3.5">
<Import Project="$(GroupProj)" />
<Target Name="Build">
<MSBuild BuildInParallel="True" Projects="project1.dproj;project2.dproj;project3.dproj"/>
</Target>
</Project>
And execute as:
c:\> msbuild /p:GroupProj="C:\development\project\default.groupproj" test.targets
The execution shall fail as MSBuild can't find projectN.dproj file. The issue shall be the working directory isn't set to default.groupproj.
One straight solution come into my mind is to extract directory of $(GroupProj) and concat to there projectN.dproj file.
That's the whole story of my question.
Try something like this:
<?xml version="1.0" encoding="utf-8"?>
<Project DefaultTargets="Build" xmlns="http://schemas.microsoft.com/developer/msbuild/2003">
<PropertyGroup>
<GroupProj>C:\development\project\default.groupproj</GroupProj>
</PropertyGroup>
<Target Name="Build">
<CreateItem Include="$(GroupProj)">
<Output TaskParameter="Include" ItemName="ItemFromProp"/>
</CreateItem>
<Message Text="1. #(ItemFromProp -> '%(RootDir)%(Directory)')"/>
<Message Text="2. %(ItemFromProp.RootDir)%(ItemFromProp.Directory)"/>
<Message Text="3. %(ItemFromProp.Identity)"/>
<Message Text="4. %(ItemFromProp.FullPath)"/>
<Message Text="5. %(ItemFromProp.FileName)"/>
<Message Text="6. %(ItemFromProp.Extension)"/>
</Target>
</Project>
EDIT:
To build the projects in parallel try this:
<?xml version="1.0" encoding="utf-8"?>
<Project ToolsVersion="4.0" DefaultTargets="Build" xmlns="http://schemas.microsoft.com/developer/msbuild/2003">
<Target Name="GetGroupProjPath">
<ItemGroup>
<GroupProj Include="$(GroupProj)" />
<GroupProjPath Include="#(GroupProj->'%(Directory)')" />
</ItemGroup>
<PropertyGroup>
<GroupProjPath>#(GroupProjPath->'%(RootDir)%(Identity)')</GroupProjPath>
</PropertyGroup>
</Target>
<Import Project="$(GroupProj)" />
<Target Name="GetDProjs" DependsOnTargets="GetGroupProjPath">
<ItemGroup>
<DProjs Include="#(Projects->'$(GroupProjPath)%(FileName)%(Extension)')" />
</ItemGroup>
</Target>
<Target Name="Build" DependsOnTargets="GetDProjs">
<Message Text="#(DProjs)" />
</Target>
</Project>
I saw this S.O question and have a similar requirement. This is what I have in a .targets file -
<Project xmlns="http://schemas.microsoft.com/developer/msbuild/2003">
<PropertyGroup Condition="$(TeamBuildOutDir) != '' ">
<OutputPath>$(TeamBuildOutDir)\Assemblies</OutputPath>
</PropertyGroup>
How can I output to multiple folders?
e.g.- $(TeamBuildOutDir)\Assemblies2
TIA
Thanks Nick, The copy/paste mucked it up. This is what I tried -
<Project xmlns="http://schemas.microsoft.com/developer/msbuild/2003">
<PropertyGroup Condition="$(TeamBuildOutDir) != '' ">
<OutputPath>$(TeamBuildOutDir)\Assemblies</OutputPath>
</PropertyGroup>
<Target Name="AfterBuild">
<Copy SourceFiles="$(OutputPath)\**\*.*" DestinationFolder="$(TeamBuildOutDir)\Assemblies2" />
</Target>
</Project>
I've also tried -
<Copy SourceFiles="$(OutputPath)\***\*.*" DestinationFolder="$(TeamBuildOutDir)\Assemblies2" />
and -
<Copy SourceFiles="$(OutputPath)\***\*.*" DestinationFolder="$(TeamBuildOutDir)\" />
in case the directory not being present caused an issue but still no luck.
Updated 7/28. Tried this but doesn't work still (no errors but the files are not present in the output directory. They are present in the Assemblies folder so I know the targets file is being triggered.) -
<Project xmlns="http://schemas.microsoft.com/developer/msbuild/2003">
<PropertyGroup Condition="$(TeamBuildOutDir) != '' ">
<OutputPath>$(TeamBuildOutDir)\Assemblies</OutputPath>
</PropertyGroup>
<Target Name="AfterBuild">
<CreateItem Include="$(OutputPath)\**\*.*">
<Output ItemName="Outfiles" TaskParameter="Include" />
</CreateItem>
<Copy SourceFiles="#(Outfiles)" DestinationFiles="#(Outfiles->'$(TeamBuildOutDir)\%(relativedir)%(Filename)%(Extension)')" SkipUnchangedFiles="false" />
</Target>
</Project>
You create an AfterBuild target with a copy task the contents of $(OutputPath) to $(TeamBuildOutDir)\Assemblies2.
<Target Name="AfterBuild">
<Copy SourceFiles="$(OutputPath)\**\*.*" DestinationFolder="$(TeamBuildOutDir)\Assemblies2" />
</Target>
Edit, updating this to include a test message, and include a "DependsOnTarget" attribute to see if we can get this to occur after the build process...
<Target Name="AfterBuild" DependsOnTarget="Build">
<Message Text="**** TEST **** " Importance="high" />
<Copy SourceFiles="$(OutputPath)\**\*.*" DestinationFolder="$(TeamBuildOutDir)\Assemblies2" />
</Target>
I am trying to create a simple build process for a quite complex (many projects) vs2010 solution.
I wish for a folder structure such as this
-Build
-Proj1
-proj1.exe
-proj1.dll
-Proj2
-proj2.exe
-proj2.dll
......
-Projn
-projn.exe
-projn.dll
What I am getting from my attempts below is
-Build
-proj1.exe
-proj1.dll
-proj2.exe
-proj2.dll
-projn.exe
-projn.dll
I currently have this as a .proj file. (see below)
This builds things fine, however it puts everything in the "build" folder that I specify. I want each project to be in its own seperate folder within that 'build' folder. How can I achive this?
<?xml version="1.0" encoding="utf-8"?>
<Project DefaultTargets="Build" xmlns="http://schemas.microsoft.com/developer/msbuild/2003">
<PropertyGroup>
<BuildOutputDir>C:\Projects\BuildScripts\Build</BuildOutputDir>
<SolutionToCompile>PathToSolution.sln</SolutionToCompile>
</PropertyGroup>
<Target Name="Clean">
<RemoveDir Directories="$(BuildOutputDir)" />
</Target>
<Target Name="Compile">
<MakeDir Directories="$(BuildOutputDir)" />
<MSBuild Projects="$(SolutionToCompile)"
properties = "OutputPath=$(BuildOutputDir)" Targets="Rebuild" />
</Target>
<Target Name="Build" DependsOnTargets="Clean;Compile">
<Message Text="Clean, Compile"/>
</Target>
</Project>
I call the .proj with a simple bat
"%windir%\Microsoft.NET\Framework\v4.0.30319\MSBuild.exe" /nologo externalBuild.proj /m:2 %*
pause
I have also tried a more complex version (copy and paste!) that looks more like it should work, but still puts things in a single folder.
<?xml version="1.0" encoding="utf-8"?>
<Project DefaultTargets="BuildAll" xmlns="http://schemas.microsoft.com/developer/msbuild/2003">
<ItemGroup>
<ProjectsToBuild Include="path to solution folder\**\*proj" Exclude="$(MSBuildProjectFile)"/>
</ItemGroup>
<PropertyGroup>
<Configuration>CI</Configuration>
</PropertyGroup>
<Target Name="CoreBuild">
<MSBuild Projects ="#(ProjectsToBuild)"
ContinueOnError ="false"
Properties="Configuration=$(Configuration)">
<Output ItemName="OutputFiles" TaskParameter="TargetOutputs"/>
</MSBuild>
</Target>
<PropertyGroup>
<DestFolder>Build\</DestFolder>
</PropertyGroup>
<Target Name="CopyFiles">
<Copy SourceFiles="#(OutputFiles)"
DestinationFiles="#(OutputFiles->'$(DestFolder)%(RecursiveDir)%(Filename)%(Extension)')" />
</Target>
<Target Name="CleanAll">
<!-- Delete any files this process may have created from a previous execution -->
<CreateItem Include="$(DestFolder)\**\*exe;$(DestFolder)\**\*dll">
<Output ItemName="GeneratedFiles" TaskParameter="Include"/>
</CreateItem>
<Delete Files="#(GeneratedFiles)"/>
<MSBuild Projects="#(ProjectsToBuild)" Targets="Clean" Properties="Configuration=$(Configuration);"/>
</Target>
<PropertyGroup>
<BuildAllDependsOn>CleanAll;CoreBuild;CopyFiles</BuildAllDependsOn>
</PropertyGroup>
<Target Name="BuildAll" DependsOnTargets="$(BuildAllDependsOn)"/>
</Project>
Using devenv.com to build from the command line will do what you want. It will use the output directories specified in the project files. This is what we're using, because at the moment we don't need more control over the build mechanism.
What i want to do is to copy all files and subfolders from the OutputPath to the daily folder. For example i have project called Clock, i have msbuild script for it:
<?xml version="1.0" encoding="utf-8" ?>
<Project xmlns="http://schemas.microsoft.com/developer/msbuild/2003">
<PropertyGroup>
<ProjectPath>C:\Clock</ProjectSolutionName>
<ProjectSolutionName>Clock</ProjectSolutionName>
</PropertyGroup>
<Target Name="ReleaseBuild">
<Message Text="Building $(ProjectSolutionName) Release Build" />
<MSBuild Projects="$(ProjectPath)\$(ProjectSolutionName).sln" Targets="Clean" Properties="Configuration=Release" />
<MSBuild Projects="$(ProjectPath)\$(ProjectSolutionName).sln" Targets="Build" Properties="Configuration=Release" />
<Message Text="$(ProjectSolutionName) Release Build Complete!" />
</Target>
</Project>
Now when i run the script it compiles the solution and the files will be stored to a Release folder. How could i copy all the files and subfolders from the Release folder to folder named as the date, as for today for example: C:\Clock_Builds\20110803
This should do most of what you ask (its msbuild 4):
<Project DefaultTargets="DateCopy" xmlns="http://schemas.microsoft.com/developer/msbuild/2003" ToolsVersion="4.0">
<Target Name="DateCopy">
<ItemGroup>
<Release Include="d:\Build\**\**"/>
</ItemGroup>
<PropertyGroup>
<StringDate>$([System.DateTime]::Now.ToString('yyyyMMdd'))</StringDate>
</PropertyGroup>
<MakeDir Directories="D:\Release\$(StringDate)"/>
<Message Text="$(StringDate)" Importance="High"/>
<Copy SourceFiles="#(Release)"
DestinationFolder="D:\Release\$(StringDate)\%(RecursiveDir)"/>
</Target>
</Project>
Hope that helps