SELECT User, COUNT(*) as count FROM Tests WHERE Release = '1.0' GROUP by User;
Above query will return distinct numbers, however, I would like to convert count to percents in relation to total number of records. Total number of records considering WHERE clause.
SELECT R1.user, COUNT(*)/R2.COUNT_ALL AS Expr1
FROM Releases R1,
(SELECT COUNT(*) As COUNT_ALL FROM Releases WHERE Release = '1.0') R2
WHERE R1.Release = '1.0'
GROUP BY R1.user, R2.COUNT_ALL
Here's another approach that uses a single SELECT:
SELECT
Tests.User,
Count(IIf([Tests].[Release]='1.0', 1, Null)) / Count(*) AS Percentage
FROM
Tests
GROUP BY
Tests.User
Unlike the approaches suggested earlier, this one will, for better or worse, return records for users having no records in Tests where Release is "1.0". If you don't want these records, you could add a HAVING clause to eliminate them.
Hope this helps.
Like Brian's answer but in standard SQL instead of MS Access only. (One can also use COUNT instead of SUM with NULL where I have 0.)
SELECT
Tests.User,
Sum(CASE WHEN Release='1.0' THEN 1 ELSE 0 END) / Count(*) AS Percentage
FROM
Tests
GROUP BY
Tests.User
Related
I am new to SQL and have had pretty good luck figuring things out thus far but I am missing something in this query:
The question is how to return a distinct count from two columns using another column and the criteria if the value is greater than 0.
I have tried IF and AND operators (My current query returns a 0 not an error, and it works when only using one .shp criteria)
select count (distinct ti.TO_ADDRESS)
from ti
where ti.input_id = 'xxx_029_01z_c_zzzzbab_ecrm.shp'
and ti.input_id = 'xxx_030_01z_c_zzzzbab_ecrm.shp'
and ti.OPENED>0;
Thanks so much!!
I think you want two levels of aggregation:
select count(*)
from (select ti.TO_ADDRESS
from ti
where ti.input_id in ('xxx_029_01z_c_zzzzbab_ecrm.shp', 'xxx_030_01z_c_zzzzbab_ecrm.shp') and
ti.OPENED > 0
group by ti.TO_ADDRESS
having count(distinct ti.input_id) = 2 -- has both of them
) ti;
I using this website to practice SQL. I've got this query:
SELECT DISTINCT maker
FROM Product
GROUP BY maker
HAVING COUNT(type) = 1
AND COUNT(model) > 1
For some reason both count aggregates return the same value--as if they were COUNT(*)--but this isn't what I'm expecting. Please explain why and, if it's not too much trouble, what the correct approach is.
Your having clause is:
HAVING COUNT(type) = 1 AND COUNT(model) > 1
Each component is counting the number of non-NULL rows with a value in that column. So, if type contained 200 NULLs and 100 '1's, the value would be 100. Count(*), in this case, would return the number of rows, or 300.
Perhaps you want to count the number of distinct values in each column. In that case, you can use:
HAVING COUNT(DISTINCT type) = 1 AND COUNT(DISTINCT model) > 1
In practice, though, COUNT(DISTINCT) usually uses more resources than other aggregation functions. The following does the same thing and often performs better:
HAVING min(type) = max(type) and min(model) < max(model)
Count() aggregate function, counts the number of records of the table you are query. (Product Table)
There is no difference that which column you give it as input.
It will return the same output as you said.
And it's completely normal.
I have two subquerys both calculating sums. I would like to do an Artithmetic Minus(-) with the result of both Querys . eg Query1: 400 Query2: 300 Result should be 100.
Obvious a basic - in the query does not work. The minus works as MINUS on sets. How can I solve this? Do you have any ideas?
SELECT CustumersNo FROM Custumers WHERE
(
SELECT SUM(value) FROM roe WHERE roe.credit = Custumers.CustumersNo
-
SELECT SUM(value) FROM roe WHERE roe.debit = Custumers.CustumersNo
)
> 500
Using Informix - sorry missed that point
To get the original syntax to work, you would need to surround the sub-selects in parentheses:
SELECT CustumersNo
FROM Custumers
WHERE ((SELECT SUM(value) FROM roe WHERE roe.credit = Custumers.CustumersNo)
-
(SELECT SUM(value) FROM roe WHERE roe.debit = Custumers.CustumersNo)
) > 500
Note that aggregates are defined to ignore nulls in the values they aggregate in standard SQL. However, the SUM of an empty set of rows is NULL, not zero.
You can get inventive and devise ways to always have a value for each customer listed in the roe table, such as:
SELECT CustomersNo
FROM (SELECT CustomersNo, SUM(value) AS net_credit
FROM (SELECT credit AS CustomersNo, +value
UNION
SELECT debit AS CustomersNo, -value
) AS x
GROUP BY CustomersNo
) AS y
WHERE net_credit > 500;
You can also do that with an appropriate HAVING clause if you wish. Note that this avoids issues with customers who have credit entries but no debit entries or vice versa; all the entries that are present are treated appropriately.
Your misspelling (or unorthodox spelling) of 'customers' is nearly as good as 'costumers'.
Something like what you tried should work. It may be a syntax problem, and it may depend on what type of SQL you are using. However, an approach like this would be more efficient:
Update: I see you were having a problem with nulls, so I updated it to handle nulls properly.
select CustumersNo from (
select CustumersNo,
sum(coalesce(roecredit.value,0)) - sum(coalesce(roedebit.value,0))
as balance
FROM Custumers
join roe roecredit on roe.credit = Custumers.CustumersNo
join roe roedebit on roe.debit = Custumers.CustumersNo
group by CustumersNo
)
where balance > 500
Caveat: I don't have experience with Informix specifically.
I have an performance heavy query, that filters out many unwanted records based on data in other tables etc.
I am averaging a column, and also returning the count for each average group. This is all working fine.
However, I would also like to include the percentage of the TOTAL count.
Is there any way of getting this total count without rerunning the whole query, or increasing the performance load significantly?
I would also prefer if I didn't need to completely restructure the sub query (e.g. by getting the total count outside of it), but can do if necessary.
SELECT
data.EquipmentId,
AVG(MeasureValue) AS AverageValue,
COUNT(data.*) AS BinCount
COUNT(data.*)/ ???TotalCount??? AS BinCountPercentage
FROM
(SELECT * FROM MultipleTablesWithJoins) data
GROUP BY data.EquipmentId
See Window functions.
SELECT
data.EquipmentId,
AVG(MeasureValue) AS AverageValue,
COUNT(*) AS BinCount,
COUNT(*)/ cast (cnt as float) AS BinCountPercentage
FROM
(SELECT *,
-- Here is total count of records
count(*) over() cnt
FROM MultipleTablesWithJoins) data
GROUP BY data.EquipmentId, cnt
EDIT: forgot to actually divide the numbers.
Another approach:
with data as
(
SELECT * FROM MultipleTablesWithJoins
)
,grand as
(
select count(*) as cnt from data
)
SELECT
data.EquipmentId,
AVG(MeasureValue) AS AverageValue,
COUNT(data.*) AS BinCount
COUNT(data.*)/ grand.cnt AS BinCountPercentage
FROM data cross join grand
GROUP BY data.EquipmentId
I need to calculate the net total of a column-- sounds simple. The problem is that some of the values should be negative, as are marked in a separate column. For example, the table below would yield a result of (4+3-5+2-2 = 2). I've tried doing this with subqueries in the select clause, but it seems unnecessarily complex and difficult to expand when I start adding in analysis for other parts of my table. Any help is much appreciated!
Sign Value
Pos 4
Pos 3
Neg 5
Pos 2
Neg 2
Using a CASE statement should work in most versions of sql:
SELECT SUM( CASE
WHEN t.Sign = 'Pos' THEN t.Value
ELSE t.Value * -1
END
) AS Total
FROM YourTable AS t
Try this:
SELECT SUM(IF(sign = 'Pos', Value, Value * (-1))) as total FROM table
I am adding rows from a single field in a table based on values from another field in the same table using oracle 11g as database and sql developer as user interface.
This works:
SELECT COUNTRY_ID, SUM(
CASE
WHEN ACCOUNT IN 'PTBI' THEN AMOUNT
WHEN ACCOUNT IN 'MLS_ENT' THEN AMOUNT
WHEN ACCOUNT IN 'VAL_ALLOW' THEN AMOUNT
WHEN ACCOUNT IN 'RSC_DEV' THEN AMOUNT * -1
END) AS TI
FROM SAMP_TAX_F4
GROUP BY COUNTRY_ID;
select a= sum(Value) where Sign like 'pos'
select b = sum(Value) where Signe like 'neg'
select total = a-b
this is abit sql-agnostic, since you didnt say which db you are using, but it should be easy to adapat it to any db out there.