I am having recods as below
---------------------------------------------------------------------
| AcnttNo | Date1 | Balance1 | Date2 | balance3 | date4 | balance4 |
|--------------------------------------------------------------------
| 123 | 50282 | 3456 | 45465 | 56557 | 4556 | 324235 |
| 123 | 56757 | 23434 | 234235 | 344324 | 56476 | 5676 |
| 123 | 435 | 2434 | 2343 | 234545 | 24245 | 2423424 |
---------------------------------------------------------------------
For example:
for each AcnttNo there will be several rows of data for balance and date.
I need to get the balance for largest date.
I'm using PL/SQL developer and an oracle database
If you want the row with the greatest date:
select
*
from
YourTable y
where
greatest(y.date1, y.date2, y.date3) =
(select max(greatest(yx.date1, yx.date2, yx.date3))
from
YourTable yx)
If you do actually need the balance matching the greatest date on that row:
select
greatest(y.date1, y.date2, y.date3) as GreatestDate,
case greatest(y.date1, y.date2, y.date3)
when y.Date1 then
y.balance1
when y.date2 then
y.balance2
when y.date3 then
y.balance3
end as GreatestDateBalance
from
YourTable y
where
greatest(y.date1, y.date2, y.date3) =
(select max(greatest(yx.date1, yx.date2, yx.date3))
from
YourTable yx)
But I think what you really need, is to reconsider your table design. :)
I'm not sure why you've multiple dates / balances in your table, however, the below should get you something interesting that you can work on...
SELECT *
FROM YourTable T
WHERE NOT EXISTS (
SELECT *
FROM YourTable T2
WHERE T2.AcntNo = T.AcntNo
AND T2.Date1 > T.Date1
)
Related
Write a SQL query to find all dates' id with a higher temperature compared to its previous dates (yesterday).
Try out if you want: https://leetcode.com/problems/rising-temperature/
Input:
Weather table:
+----+------------+-------------+
| id | recordDate | temperature |
+----+------------+-------------+
| 1 | 2015-01-01 | 10 |
| 2 | 2015-01-02 | 25 |
| 3 | 2015-01-03 | 20 |
| 4 | 2015-01-04 | 30 |
+----+------------+-------------+
Output:
+----+
| id |
+----+
| 2 |
| 4 |
+----+
Here's my code:
SELECT w_2.id AS "Id"
FROM Weather w_1
JOIN Weather w_2
ON w_1.id + 1 = w_2.id
WHERE w_1.temperature < w_2.temperature
But my code won't be accepted even if it looks exactly like the expected output.
I know the answer is:
SELECT w2.id
FROM Weather w1, Weather w2
WHERE w2.temperature > w1.temperature
AND DATEDIFF(w2.recordDate, w1.recordDate) = 1
But I tried to not use DATEDIFF because this function is not available in PostgreSQL.
The queries are not compatible. You should join the table on recordDate, not on Id.
SELECT w_2.id AS "Id"
FROM Weather w_1
JOIN Weather w_2
ON w_1.recordDate + 1 = w_2.recordDate
WHERE w_1.temperature < w_2.temperature
Do not assume that Id is sequential and ordered in the same way as recordDate, although the sample data may suggest this.
I am sure this is easy to accomplish but after spending the whole day trying I had to give up and ask for your help.
I have a table that looks like this
| PatientID | VisitId | DateOfVisit | FollowUp(Y/N) | FollowUpWks |
----------------------------------------------------------------------
| 123456789 | 2222222 | 20180802 | Y | 2 |
| 123456789 | 3333333 | 20180902 | Y | 4 |
| 234453656 | 4443232 | 20180506 | N | NULL |
| 455344243 | 2446364 | 20180618 | Y | 12 |
----------------------------------------------------------------------
Basically I have a list of PatientIDs, each patient can have multiple visits (VisitID and DateOfVisit). FollowUp(Y/N) specifies whether the patients has to be seen again and in how many weeks (FollowUpWks).
Now, what I need is a query that extracts PatientsID, DateOfVisit (the most recent one and only if FollowUp is YES) and the FollowUpWks field.
Final result should look like this
| PatientID | VisitId | DateOfVisit | FollowUp(Y/N) | FollowUpWks |
----------------------------------------------------------------------
| 123456789 | 3333333 | 20180902 | Y | 4 |
| 455344243 | 2446364 | 20180618 | Y | 12 |
----------------------------------------------------------------------
The closest I could get was with this code
SELECT PatientID,
Max(DateOfVisit) AS LastVisit
FROM mytable
WHERE FollowUp = True
GROUP BY PatientID;
The problem is that when I try adding the FollowUpWks field to the SELECT I get the following error: "The query does not include the specified expression as part of an aggregate function." However, if I add FollowUpWks to the GROUP BY statement than I get all visits, not just the most recent ones.
You need to match back to the most recent visit. One method uses a correlated subquery:
SELECT t.*
FROM mytable as t
WHERE t.FollowUp = True AND
t.DateOfVisit = (SELECT MAX(t2.DateOfVisit)
FROM mytable as t2
WHERE t2.PatientID = t.PatientID
);
Say I have a MoneyIN and a MoneyOUT column. I wish to total these entire columns up so I have a sum of each, then I wish to subtract the total of the MoneyOUT column from the total of the MoneyIN column. I also want to display a DateOF column and possibly a description (I think I can do that by myself).
This would be the original database where I get my information from:
+-------------+------------------+---------+----------+-----------+
| Location ID | Location Address | Date Of | Money In | Money Out |
+-------------+------------------+---------+----------+-----------+
| 1 | blah | date | 10.00 | 0.00 |
| 2 | blah | date | 2,027.10 | 27.10 |
| 2 | blah | date | 0.00 | 2000.00 |
| 1 | blah | date | 0.00 | 10.00 |
| 3 | blah | date | 5000.00 | 0.00 |
+-------------+------------------+---------+----------+-----------+
I would like to be able to type in a location ID and then have results show up (in this example I type 2 for the location)
+---------+----------+-----------+------+
| Date Of | Money In | Money Out | |
+---------+----------+-----------+------+
| date | 2027.10 | 27.10 | |
| date | 0 | 2000 | |
| Total: | 2027.10 | 2027.10 | 0 |
+---------+----------+-----------+------+
I have tried other solutions (One of which was pointed out below), however, they don't show the sum of each entire column, they simply subtract MoneyOUT from MoneyIN for each row. As of now, I am trying to do this in a query, but if there is a better way, please elaborate.
I am extremely new to SQL and Access, so please make the explanation understandable for a beginner like me. Thanks so much!
This is a table referred to below.
+-------------+-------+----------+-----------+-----------+
| Location ID | Date | Money IN | Money Out | Total Sum |
+-------------+-------+----------+-----------+-----------+
| 1 | date | 300 | 200 | |
| 1 | date | 300 | 200 | |
| 1 | date | 300 | 200 | |
| 1 | total | 900 | 600 | 300 |
+-------------+-------+----------+-----------+-----------+
The following should give you what you want:
SELECT DateOf, MoneyIn, MoneyOut, '' AS TotalSum FROM YourTable
UNION
SELECT 'Total', SUM(MoneyIn) AS SumIn, SUM(MoneyOut) AS SumOut,
SUM(MoneyIn - MoneyOut) AS TotalSum FROM YourTable
Edit:
You do not need to alter very much to achieve what you want. In order to get Access to prompt for a parameter when running a query, you give a name for the parameter in square brackets; Access will then pop-up a window prompting the user for this value. Also this parameter can be used more than once in the query, without Access prompting for it multiple times. So the following should work for you:
SELECT DateOf, MoneyIn, MoneyOut, '' AS TotalSum
FROM YourTable
WHERE LocationID=[Location ID]
UNION
SELECT 'Total', SUM(MoneyIn) AS SumIn, SUM(MoneyOut) AS SumOut,
SUM(MoneyIn - MoneyOut) AS TotalSum FROM YourTable
WHERE LocationID=[Location ID];
However, looking at your table design, I strongly encourage you to change it. You are including the address on every record. If you have three locations, but 100 records, then on average you are unnecessarily repeating each address more than 30 times. The "normal" way to avoid this would be to have a second table, Locations, which would have an ID and an Address field. You then remove address from YourTable, and in its place create a one-to-many relationship between the ID in Locations and the LocationID in YourTable.
It's a little unclear exactly what you expect without sample data, but I think this is what you want:
SELECT DateOf, SUM(MoneyIN) - SUM(MoneyOut)
FROM YourTable
GROUP BY DateOf
This will subtract the summed total of MoneyOut from MoneyIn at each distinct DateOf
Updated Answer
A UNION will let you append a 'Totals' record to the bottom of your result set:
SELECT *
FROM (
SELECT CAST(DateOf as varchar(20)) as DateOf, MoneyIn, MoneyOut, '' as NetMoneyIn
FROM YourTable
UNION
SELECT 'Total:', SUM(MoneyIn), SUM(MoneyOut), SUM(MoneyIN) - SUM(MoneyOut)
FROM YourTable
) A
ORDER BY CASE WHEN DateOf <> 'Total:' THEN 0 ELSE 1 END, DateOf
Some notes.. I used a derived table to ensure that the 'Total' record is last. Also casted DateOf to a string (assuming it is a date), otherwise you will have issues writing the string 'Total:' to that column.
Is it possible to join these tables:
Log table:
+--------+---------------+------------+
| name | ip | created |
+--------+---------------+------------+
| 408901 | 178.22.51.168 | 1390887682 |
| 408901 | 178.22.51.168 | 1390927059 |
| 408901 | 178.22.51.168 | 1390957854 |
+--------+---------------+------------+
Orders table:
+---------+------------+
| id | created |
+---------+------------+
| 8563863 | 1390887692 |
| 8563865 | 1390897682 |
| 8563859 | 1390917059 |
| 8563860 | 1390937059 |
| 8563879 | 1390947854 |
+---------+------------+
Result table would be:
+---------+--------------+---------+---------------+------------+
|orders.id|orders.created|logs.name| logs.ip |logs.created|
+---------+--------------+---------+---------------+------------+
| 8563863 | 1390887692 | 408901 | 178.22.51.168 | 1390887682 |
| 8563865 | 1390897682 | 408901 | 178.22.51.168 | 1390887682 |
| 8563859 | 1390917059 | 408901 | 178.22.51.168 | 1390887682 |
| 8563860 | 1390937059 | 408901 | 178.22.51.168 | 1390927059 |
| 8563879 | 1390947854 | 408901 | 178.22.51.168 | 1390927059 |
+---------+--------------+---------+---------------+------------+
Is it possible?
Espessialy, if first table is result of some query.
UPDATE
Sorry for this mistake. I want found in log who make order. So orders table relate to logs table by created field, i.e.
first row with condition (orders.created >= log.created)
This will result in a non-equi join with a horrible performance:
SELECT *
FROM t2 JOIN t1
ON t1.created =
(
SELECT MAX(t1.created)
FROM t1 WHERE t1.created <= t2.created
)
You might better go with a cursor based on a UNION like this (you probably need to add some type casts to get a working UNION):
SELECT *
FROM
(
SELECT NULL AS name, NULL AS ip, NULL AS created2, t2.*
FROM t2
UNION ALL
SELECT t1.*, NULL AS id, NULL AS created
FROM t1
) AS dt
ORDER BY COALESCE(created, created2)
Now you can process the rows in the right order and remember the rows from the last t1 row.
There is nothing to bind these 2 together.
No ID or other column exists in both tables.
If this were the case, you could join these 2 tables in a stored procedure.
At the moment you ask the first query, store the data in a newly created table, use it in the join to get your results and delete it afterwards.
Kind regards
simply you can use union
select id, created from table_2
union all
select name, ip, created from table_1
my table name is tbl1. The fileds are id,name,txdate.
| ID | NAME | TXDATE |
| 1 | RAJ | 1-1-2013 |
| 2 | RAVI | |
| 3 | PRABHU | 25-3-2013 |
| 4 | SAT | |
Now i want to use select query for check txdate < 2-2-2013 in which rows have txdate not empty and the select also retrun which rows have txdate empty.
The Result is like this
| ID | NAME | TXDATE |
| 1 | RAJ | 1-1-2013 |
| 2 | RAVI | |
| 4 | SAT | |
Any feasible solution is there?.
With out using union it is possible?.
Assuming that the TXDATE is of data type DATE then you can use WHERE "TXDATE" < '2013-2-2' OR "TXDATE" IS NULL. Something like:
SELECT *
FROM table1
WHERE "TXDATE" < '2013-2-2'
OR "TXDATE" IS NULL;
See it in action:
SQL Fiddle Demo
I don't now what database your are using and what data type the TXDATE is.
I just tried on my postgreSQL 9.2, with a field "timestamp without time zone".
I have three rows in the table , like:
ac_device_name | ac_last_heartbeat_time
----------------+-------------------------
Nest-Test1 |
Nest-Test3 |
Nest-Test2 | 2013-04-10 15:06:18.287
Then use below statement
select ac_device_name,ac_last_heartbeat_time
from at_device
where ac_last_heartbeat_time<'2013-04-11';
It is ok to return only one record:
ac_device_name | ac_last_heartbeat_time
----------------+-------------------------
Nest-Test2 | 2013-04-10 15:06:18.287
I think you can try statement like:
select * from tbl1 where TXDATE<'2-2-2013' and TXDATE is not NULL
this statement also works in my environment.