I have a couple of queries, detailed below. I'd like to be able to run one SQL query which returns both counts, is this possible?
1.
select nvl(count(rowid), 0) from tablename where OPP = 'FOO' and date = 'BAZ';
2.
select nvl(count(rowid), 0) from tablename where OPP = 'BAR' and date = 'BAZ';
I've only found MSSQL specific solutions in my searches so far.
If you need them in a single row:
SELECT
COUNT(CASE OPP WHEN 'FOO' THEN 1 END),
COUNT(CASE OPP WHEN 'BAR' THEN 1 END)
FROM tablename
WHERE OPP IN ('FOO', 'BAR') AND date = 'BAZ'
(The GROUP BY approach by Thilo is a better generic solution anyway.)
Edit: I've removed NVL(). I had forgotten why I never use it.
If the condition really looks like that (same table, only one field different in the groups):
select opp, count(*) from tablename
where date = 'BAZ'
group by opp
having opp in ('FOO', 'BAR');
For arbitrary queries:
select 'A', count(*) from tableA
union all
select 'B', count(*) from tableB
You could use a with statement:
with
count1 as (
select ...
),
count2 as (
select ...
)
select tot1, tot2
from count1, count2
Related
I have a table like below and I want 'Y' in front of Ref 345 and 789 in the result-set on basis of count(Ref) = 1 where the amount is less than 0. I am using this query to get the desired output. My question is, is there any other (and more efficient) way to do it in Teradata?
SELECT T.Ref,T.AMOUNT, R.Refund_IND as Refund_IND
FROM Table1 t
LEFT JOIN (select 'Y' as Refund_IND, Ref from Table1 where Ref in
(select Ref from Table1 where amount < 0)
group by Ref having count(Ref) = 1) R on t.Ref = R.Ref
You can use window functions to test these conditions:
SELECT
Ref,
Amount,
CASE WHEN COUNT(*) OVER (PARTITION BY REF) = 1 AND Amount < 0 THEN 'Y' ELSE '' END AS Refund_Ind
FROM Table1
I have a huge query and I am wondering if it is in Oracle possible
to get the result of a case-when-statement and use it for comparison? My CASE-STATEMENT is declared in the Select-Statement and it looks like this.
SELECT........
(CASE
WHEN (Select 1 from DUAL) = 1 THEN 'TEST'
ELSE 'TEST2'
END) AS TEST;
Now I want to get the result of this case-statement and use it in the where part? Is it possible? (Sry this may be a dumb question)
If you define your CASE statement in either an inline-view or a common table expression (aka WITH clause), you can refer to it by whatever alias you give it.
For example (inline-view):
SELECT ...
FROM ( SELECT .....
(CASE
WHEN (Select 1 from DUAL) = 1 THEN 'TEST'
ELSE 'TEST2'
END) AS TEST
FROM...
) v
WHERE v.test = 'TEST2';
As a common table expression, it would be:
WITH cte AS ( SELECT........
(CASE
WHEN (Select 1 from DUAL) = 1 THEN 'TEST'
ELSE 'TEST2'
END) AS TEST
FROM ... )
SELECT ...
FROM cte
WHERE test = 'TEST2';
You can use a case statement in the where clause, for eg.:
select * from table
where table.field = (CASE
WHEN (Select 1 from DUAL) = 1 THEN 'TEST'
ELSE 'TEST2'
END)
This will compare the value returned from the case statement with the table field.
I'll cut right to the chase: I have a select I'm currently writing with a rather lengthy where clause, what I want to do is calculate percentages.
So what I need is the count of all results and then my each distinct counts.
SELECT distinct count(*)
FROM mytable
WHERE mywhereclause
ORDER BY columnIuseInWhereClause
works fine for getting each individual values, but I want to avoid doing something like
Select (Select count(*) from mytable WHERE mywhereclause),
distinct count(*)
FROM mytable
WHERE mywhereclause
because I'd be using the same where-clause twice which just seems unnecessary.
This is for OracleDB but I'm only using standard SQL syntax, nothing database specific if I can help it.
Thanks for any ideas.
Edit:
Sample Data
__ID__,__someValue__
1 | A
2 | A
3 | B
4 | C
I want the occurances of A, B, C as numbers as well as the overall count.
__CountAll__,__ACounts__,__BCounts__,__CCounts__
4 | 2 | 1 | 1
So I can get to
100% | 50% | 25% | 25%
That last part I can probably figure out on my own. Excuse my lack of experience or even logic thinking, it's early in the morning. ;)
Edit2:
I do have written a query that works but is clumsy and long as all holy heck, this one is for trying with group by.
Try:
select count(*) as CountAll,
count(distinct SomeColumn) as CoundDistinct -- The DISTINCT goes inside the brackets
from myTable
where SomeOtherColumn = 'Something'
Use case expressions to do conditional counting:
select count(*) as CountAll,
count(case when someValue = 'A' then 1 end) as ACounts,
count(case when someValue = 'B' then 1 end) as BCounts,
count(case when someValue = 'C' then 1 end) as CCounts
FROM mytable
WHERE mywhereclause
Wrap it up in a derived table to do the % part easy:
select 100,
ACounts * 100 / CountAll,
BCounts * 100 / CountAll,
CCounts * 100 / CountAll
from
(
select count(*) as CountAll,
count(case when someValue = 'A' then 1 end) as ACounts,
count(case when someValue = 'B' then 1 end) as BCounts,
count(case when someValue = 'C' then 1 end) as CCounts
FROM mytable
WHERE mywhereclause
) dt
Here's an alternative using window function:
with data_table(ID, some_value)
AS
(SELECT 1,'A' UNION ALL
SELECT 2,'A' UNION ALL
SELECT 3,'B' UNION ALL
SELECT 4,'C'
)
SELECT DISTINCT [some_value],
COUNT([some_value]) OVER () AS Count_All,
COUNT([some_value]) OVER (PARTITION BY [some_value]) AS 'Counts' FROM [data_table]
ORDER BY [some_value]
The advantage is that you don't have to hard-code your [some_value]
Having touble getting only values that appear once. I currently have some sql code that gets out the all the entries that have 0 percent. The problem is that two rows can contain the same person With different percentages. If one of these is above 0 then i dont want it to come out in the Query
abridged table:
Name - Percent
steve 0
dan 0
mike 100
harold 50
steve 80
carl 0
carl 0
Result:
dan - 0
Carl - 0
Here is how far ive gotten, but not managed to make any variation of Count() or having or Group by working.
select person, Value2, Value3, Value4, percent
from
Table1
INNER JOIN Table1 ON Table2.valueNum = Table1.valueNum
INNER JOINTable1 ON Table3.valueNum = Table1.valueNum
INNER JOIN Table1 ON Table4.valueNum = Table1.valueNum
WHERE
(#date BETWEEN table1.FROMDATE AND table1.todate)
AND table1.percent = 0
AND table1.varchar IN ('T', 'X')
This is one method
select name,0 as percent from abridged
group by name
having min(percent)=0 and max(percent)=0
Your example SQL and abridged table don't match. However, this looks like the basic idea you are after:
select
*
from
dbo.table a
where
a.percent = 0 and
not exists (
select
'x'
from
dbo.table b
where
a.Name = b.Name and
b.percent > 0
);
I would just use window functions:
with t as (
<your query here>
)
select t.*
from (select t.*, count(*) over (partition by name) as cnt
from t
) t
where cnt = 1;
To resolve your problem you can use this query:
select [name], 0 as [percent] from [abridged]
group by [name]
having sum([percent])=0
This should solve your problem right?
select name,sum([percent]) from abridged
group by name
having SUM([percent]) = 0
Query
SELECT distinct name, min(percentage) from a
group by name
having min(percentage) = 0
and count(*) > 1;
I have two queries:
Select count(*) as countOne where field = '1'
Select count(*) as countTwo where field = '2'
What I want to see after executing these queries in my results viewer:
countOne | countTwo
23 | 123
How can I get the results from both queries by only running one query?
SELECT COUNT(CASE WHEN field = '1' THEN 1 END) AS countOne,
COUNT(CASE WHEN field = '2' THEN 1 END) AS countTwo
FROM YourTable
WHERE field IN ( '1', '2' )
The simplest way is to run each as a subselect eg.
SELECT
(
Select count(*) where field = '1' as countOne,
Select count(*) where field = '2' as countTwo
)
BUt this is not necesarily the best way
Another wayto do it would be to Group by field and then do PIVOT to select out each group as a separate column.