I need to write a SQL query that helps return the highest count in a given hourly range. The problem is that in my table, it just logs orders as they come and doesn’t have a unique identifier that separates hours from hours.
So basically, I need to find the highest number of orders (on any given hour), from 7/08/2022, - 7/15/2022, have a table that does not distinguish distinct hour sets, and logs orders as they come.
I have tried to use a query that combines MAX(), COUNT(), and DATETIME(), but to no avail.
Can I please receive some help?
I've had to tackle this kind of measurement in the past..
Here's what I did for 15 minute intervals:
My datetime column is named datreg in my database log area.
cast(round(floor(cast(datreg as float(53))*24*4)/(24*4),5) as smalldatetime
I times by 4 in this formula, to get 4 intervals inside my 24 hour period.. For you it would look like this to get just hourly intervals:
cast(round(floor(cast(datreg as float(53))*24)/(24),5) as smalldatetime
This is a little piece of magic when it comes to dashboards and reports.
I have the following table in SQL:
Start - End - Amount **per day**
06.07.2020 10.07.2020 10
08.07.2020 08.07.2020 5
08.07.2020 15.07.2020 20
02.07.2020 06.07.2020 3
Now I want to filter this table by the calendar week. Let's say "where [calendar week] = cw28". cw28 is from the 06th of july to the 12th of july.
With that I'd like to have the sum of the amount of the days that lie between those two dates. One single number.
I'm using MS SQL Server (SQL Express).
I can't figure out how to distinguish (and break down) if one day lays between the two date values or not. And if yes how much I need to sum up.
I tried to make a picture in excel to create a logic from this:
"Logic" in Excel
Can anyone help me with this? :)
Thx and Best!,
Max
Not sure about your exact requirement. But below is the query to get the sum of values between two dates.
select sum(amount_of_days) from table where date_column between '06-JUL-2020' and '07-JUL-2010';
Change the column name and table name according to your requirement
Im trying to calculate the average time a tool stays on loan. The time a tool stays on loan is the number of days between loan_status_change_date and tool_out_date (table columns). the date type of these 2 columns is ex: 01-SEP-17
whats the best way to approach this?
We can do arithmetic with Oracle dates. It's not clear from the column names which one is the start of the loan and which the end; in the following example I've assumed loan_status_change is when the tool is returned.
select tool
, avg(loan_status_change - tool_out_date) as avg_loan_days
from your_table
group by tool
/
The AVG() function is an aggregate function, so it handles the /ns for us. The substraction is to calculate the length of a particular loan, which is the value you want to average. The result of that substraction already is a number of days, so no further transformation is necessary. If your columns have a time element then the result might not be an integer.
I have a table of data with the following:
User,Platform,Dt,Activity_Flag,Total_Purchases
1,iOS,05/05/2016,1,1
1,Android,05/05/2016,1,2
2,iOS,05/05/2016,1,0
2,Android,05/05/2016,1,2
3,iOS,05/05/2016,1,1
3,Android,06/05/2016,1,3
1,iOS,06/05/2016,1,2
4,Android,06/05/2016,1,2
1,Android,06/05/2016,1,0
3,iOS,07/05/2016,1,2
2,iOS,08/05/2016,1,0
I want to do a GROUPING SETS (Platform,Dt,(Platform,Dt),()) aggregation to be able to find for each combination of Platform and Dt the following:
Total Purchases
Total Unique Users
Average Purchases per User per Day
The first two are simple as these can be achieved via a sum(Total_Purchases) and count(distinct user) respectively.
The problem I have is with the last metric. The result set should look like this but I don't know how to get the last column to be calculated correctly:
Platform,Dt,Total_Purchases,Total_Unique_Users,Average_Purchases_Per_User_Per_Day
Android,05/05/2016,4,2,2.0
iOS,05/05/2016,2,3,0.7
Android,06/05/2016,5,3,1.7
iOS,06/05/2016,2,1,2.0
iOS,07/05/2016,2,1,2.0
iOS,08/05/2016,0,1,0.0
,05/05/2016,6,3,2.0
,06/05/2016,7,3,2.3
,07/05/2016,1,1,1.0
,08/05/2016,1,1,1.0
Android,,9,4,1.8
iOS,,6,3,1.2
,,15,4,1.6
For the first ten rows we see that getting the Average purchase per user per day is a simple division of the first two columns as the dimension in these rows represent a single date only. But when we look at the final 3 rows we see that the division is not the way to achieve the desired result. This is because it needs to take an average for each day in turn to get the overall per day amount.
If this isn't clear please let me know and I'll be happy to explain better. This is my first post on this site!
I'm trying to create a query that will show the properties that were sold and were on the market for less than 6 weeks. In the listings table, there is BeginListDate and EndList Date.
So far my WHERE statement looks like
WHERE SaleStatus.Salestatus = 'Sold' AND DATEDIFF(YEAR,BeginListDate, EndListDate) >42
but that query is incorrect. I'm just confused on how to write a where statement where it only considers those that were on the market for less than 6 weeks.
Just to elaborate on #JamieD77's very correct comment...
Your condition:
DATEDIFF(YEAR,BeginListDate, EndListDate) >42
Says "The number of Years between the BeginListDate and the EndListDate is greater than 42". That's a hell of a long list period. You say you are looking for the the list period to be less than 42 days, so #JamieD77's suggestion to:
Datediff(day,BeginListDate, EndListDate) < 42
Is the right way to go. This says "The number of Days between beginlistdate and endlistdate is less than 42."
The difference here is the DatePart as #squillman suggested changing from Year to Day as well as the inequality itself. You wanted Less Than, <.
Hint but depended on how would you preferred in report or project.
this example and if both startdate and endate are in the same calendar week, the return value for week would be 0.
select DATEDIFF(week,getdate(),getdate()+7)
it has been consider week start for sunday based on system.