Can you tell me if inner join and equi-join are the same or not ?
An 'inner join' is not the same as an 'equi-join' in general terms.
'equi-join' means joining tables using the equality operator or equivalent. I would still call an outer join an 'equi-join' if it only uses equality (others may disagree).
'inner join' is opposed to 'outer join' and determines how to join two sets when there is no matching value.
Simply put: an equi-join is a possible type of inner-joins
For a more in-depth explanation:
An inner-join is a join that returns only rows from joined tables where a certain condition is met. This condition may be of equality, which means we would have an equi-join; if the condition is not that of equality - which may be a non-equality, greater than, lesser than, between, etc. - we have a nonequi-join, called more precisely theta-join.
If we do not want such conditions to be necessarily met, we can have
outer joins (all rows from all tables returned), left join (all rows
from left table returned, only matching for right table), right join
(all rows from right table returned, only matching for left table).
The answer is NO.
An equi-join is used to match two columns from two tables using explicit operator =:
Example:
select *
from table T1, table2 T2
where T1.column_name1 = T2.column_name2
An inner join is used to get the cross product between two tables, combining all records from both tables. To get the right result you can use a equi-join or one natural join (column names between tables must be the same)
Using equi-join (explicit and implicit)
select *
from table T1 INNER JOIN table2 T2
on T1.column_name = T2.column_name
select *
from table T1, table2 T2
where T1.column_name = T2.column_name
Or Using natural join
select *
from table T1 NATURAL JOIN table2 T2
The answer is No,here is the short and simple for readers.
Inner join can have equality (=) and other operators (like <,>,<>) in the join condition.
Equi join only have equality (=) operator in the join condition.
Equi join can be an Inner join,Left Outer join, Right Outer join
If there has to made out a difference then ,I think here it is .I tested it with DB2.
In 'equi join'.you have to select the comparing column of the table being joined , in inner join it is not compulsory you do that . Example :-
Select k.id,k.name FROM customer k
inner join dealer on(
k.id =dealer.id
)
here the resulted rows are only two columns rows
id name
But I think in equi join you have to select the columns of other table too
Select k.id,k.name,d.id FROM customer k,dealer d
where
k.id =d.id
and this will result in rows with three columns , there is no way you cannot have the unwanted compared column of dealer here(even if you don't want it) , the rows will look like
id(from customer) name(from Customer) id(from dealer)
May be this is not true for your question.But it might be one of the major difference.
The answer is YES, But as a resultset. So here is an example.
Consider three tables:
orders(ord_no, purch_amt, ord_date, customer_id, salesman_id)
customer(customer_id,cust_name, city, grade, salesman_id)
salesman(salesman_id, name, city, commission)
Now if I have a query like this:
Find the details of an order.
Using INNER JOIN:
SELECT * FROM orders a INNER JOIN customer b ON a.customer_id=b.customer_id
INNER JOIN salesman c ON a.salesman_id=c.salesman_id;
Using EQUI JOIN:
SELECT * FROM orders a, customer b,salesman c where
a.customer_id=b.customer_id and a.salesman_id=c.salesman_id;
Execute both queries. You will get the same output.
Coming to your question There is no difference in output of equijoin and inner join. But there might be a difference in inner executions of both the types.
Related
As far as I understand in a left outer join between two tables (say a & b) all the rows of the table on the left side of the join are retrieved regardless of the values in the rows on the right table. Then why do we need an 'ON' clause specifying a condition, something like this:
select * from a LEFT OUTER JOIN b on a.some_column1 = b.some_column2;
Why is there a need for the statement "a.some_column1 = b.some_column2".
A left join would return all the rows from table a, and for each row the matching row in table b, if it exists - if it doesn't, nulls would be returned instead of b's columns. The on clause defines how this matching is done.
An on clause is required since you are "joining", and you need to tell which columns you want to join by. Otherwise you would use traditional from without any where condition to all possible row combinations. But you wanted a join, right?
Yeah, that's pretty much it is.
As far as I understand in a left outer join between two tables (say a & b) all the rows of the table on the left side of the join are retrieved regardless of the values in the rows on the right table.
That is correct in the sense that it says something about what left join on returns, but it isn't a definition of what it returns. left join on returns inner join on rows plus (union all) unmatched left table rows extended by nulls.
inner join on returns the rows of cross join that satisfy the on condition--which could be any condition on the columns. cross join returns every combination of a row from the left table & a row from the right table.
What do you expect outer join without on to mean? In standard SQL outer & inner join have to have an on. inner join on a true condition is the same as cross join. Which has no unmatched left table rows. So if you want outer join with no on to mean outer join on a true condition then, since there are no unmatched rows in the inner join on that condition, the result is also just cross join. (MySQL allows inner join to be used without an on, but it just means cross join.)
I need to select all data from 2 tables in an sql database.
I searched the site and dried numerous ways but no sucess.
One table has no data but the other is full of it.
If i select each one individually i get good results, but if i use for instance:
select * from relatorio cross join temp
or
select * from relatorio r,temp t
or even:
select t.*, r.* from temp t inner join relatorio r on 1=1
The join works, but none of them shows data.
Can anyone help?
Thanks in advance.
All three select statements in the questions are cross joins.
A cross joins returns data only if both tables have at least one row.
It returns a cartesian product of both tables, meaning that every row in one table will be joined to every row in the other table.
One table has no data but the other is full of it.
Since one of your tables is empty, it will return no results at all. You can think about it as multipling by 0.
Now you have two options: one is to use a full join and the other one is to use left join, in this case both will return the same results, since one table is empty:
select *
from relatorio
left join temp on <join condition> -- assuming temp is the empty table
or
select *
from relatorio
full join temp on <join condition> -- in this case, it doesn't matter what table is empty
If you want to return all matched and umatched rows, use Full Outer Join.The FULL OUTER JOIN keyword returns all rows from the left table (table1) and from the right table (table2).
The FULL OUTER JOIN keyword combines the result of both LEFT and RIGHT joins.
In SQL the FULL OUTER JOIN combines the results of both left and right outer joins and returns all (matched or unmatched) rows from the tables on both sides of the join clause.
SQL FULL OUTER JOIN Syntax:
SELECT column_name(s)
FROM table1
FULL OUTER JOIN table2
ON table1.column_name=table2.column_name;
The SQL CROSS JOIN produces a result set which is the number of rows in the first table multiplied by the number of rows in the second table if no WHERE clause is used along with CROSS JOIN. This kind of result is called as Cartesian Product.
If WHERE clause is used with CROSS JOIN, it functions like an INNER JOIN.
An alternative way of achieving the same result is to use column names separated by commas after SELECT and mentioning the table names involved, after a FROM clause.
CROSS JOIN SYNTAX
SELECT *
FROM table1
CROSS JOIN table2;
This LEFT OUTER JOIN with several conditionals is not working, it's probably something obvious. It is returning the result of all distinct sid and not performing conditionals at all.
SELECT
count(distinct student_status.sid)
FROM studentcoursedb.student_status
LEFT OUTER JOIN studentcoursedb.student_status AS t0
ON t0.sid = student_status.sid
AND t0.term < student_status.term
AND student_status.major LIKE 'ABC%';
The result, 32684 is the count of total distinct sids, the same value returned by this query:
select count(distinct sid)
from studentcoursedb.student_status;
The two query
SELECT
count(distinct student_status.sid)
FROM studentcoursedb.student_status
LEFT OUTER JOIN studentcoursedb.student_status AS t0
ON t0.sid = student_status.sid
AND t0.term < student_status.term
AND student_status.major LIKE 'ABC%';
select count(distinct sid)
from studentcoursedb.student_status;
return the same number of rows correctly because
You are left joining (left join or left outer join is the same) the same table this mean that the resulting number of rows is ever the same number of the main table
If you want a subset matching you should use inner join (or other join relation)
You are counting a column from the left table that might have duplicate rows as a result of the LEFT JOIN, but certainly no filtered rows.
A LEFT OUTER JOIN keeps all rows in the first table along with matching rows in the second. Hence, it does not filter the first table. You are counting a column from the first table. So, the LEFT OUTER JOIN does not affect the distinct count.
If you want to filter rows, then use INNER JOIN instead. I would also move the conditions to the WHERE clause:
SELECT count(distinct ss.sid)
FROM studentcoursedb.student_status ss INNER JOIN
studentcoursedb.student_status ss2
ON ss2.sid = ss.sid
WHERE ss2.term < ss.term AND ss.major LIKE 'ABC%';
I should note that I don't think you need a self join. Have you considered:
select dense_rank(ss.term) over (order by term)
from studentcoursedb.student_status ss
where ss.major like 'ABC%';
Much simpler and should have better performance.
I know conditions are used in table joining. But I met a specific situation and the SQL codes writes like "Table A join table B ON TRUE"
What will happen based on the "ON TRUE" condition? Is that just a total cross join without any condition selection?
Actually, the original expression is like:
Table A LEFT outer join table B on TRUE
Let's say A has m rows and B has n rows. Is there any conflict between "left outer join" and "on true"? Because it seems "on true" results a cross join.
From what I guess, the result will be m*n rows. So, it has no need to write "left outer join", just a "join" will give the same output, right?
Yes. That's the same thing as a CROSS JOIN.
In MySQL, we can omit the [optional] CROSS keyword. We can also omit the ON clause.
The condition in the ON clause is evaluated as a boolean, so we could also jave written something like ON 1=1.
UPDATE:
(The question was edited, to add another question about a LEFT [OUTER] JOIN b which is different than the original construct: a JOIN b)
The "LEFT [OUTER] JOIN" is slightly different, in that rows from the table on the left side will be returned even when there are no matching rows found in the table on the right side.
As noted, a CROSS JOIN between tables a (containing m rows) and table b containing n rows, absent any other predicates, will produce a resultset of m x n rows.
The LEFT [OUTER] JOIN will produce a different resultset in the special case where table b contains 0 rows.
CREATE TABLE a (i INT);
CREATE TABLE b (i INT);
INSERT INTO a VALUES (1),(2),(3);
SELECT a.i, b.i FROM a LEFT JOIN b ON TRUE ;
Note that the LEFT JOIN will returns rows from table a (a total of m rows) even when table b contains 0 rows.
A cross join produces a cartesian product between the two tables, returning all possible combinations of all rows. It has no on clause because you're just joining everything to everything.
Cross join does not combine the rows, if you have 100 rows in each table with 1 to 1 match, you get 10.000 results, Innerjoin will only return 100 rows in the same situation.
These 2 examples will return the same result:
Cross join
select * from table1 cross join table2 where table1.id = table2.fk_id
Inner join
select * from table1 join table2 on table1.id = table2.fk_id
Use the last method
The join syntax's general form:
SELECT *
FROM table_a
JOIN table_b ON condition
The condition is used to tell the database how to match rows from table_a to table_b, and would usually look like table_a.some_id = table_b.some_id.
If you just specify true, you will match every row from table_a with every row of table_b, so if table_a contains n rows and table_b contains m rows the result would have m*n rows.
Most(?) modern databases have a cleaner syntax for this, though:
SELECT *
FROM table_a
CROSS JOIN table_b
The difference between the pure cross join and left join (where the condition is forced to be always true, as when using ON TRUE) is that the result set for the left join will also have rows where the left table's rows appear next to a bunch of NULLs where the right table's columns would have been.
The most common type of join is: SQL INNER JOIN (simple join). An SQL INNER JOIN return all rows from multiple tables where the join condition is met.
This what W3Schools says about Inner Join. I was reading database management by Korth and one chapter in it was on relational algebra. In that, there was a Natural Join which, in my limited understanding, is the same as Inner Join.
Can someone please tell me if there is a difference between the two or they are different names of referring to the same thing.
A Natural Join is a form of Inner Join where the join is implicitly across all columns of matching names on both sides of the join.
E.g.
Table A
abc int
def int
ghi varchar(20)
Table B
abc int
def int
jkl int
A natural join between tables A and B would be the same as an inner join on columns abc and def.
Inner joins that could not be replaced with a Natural Join:
TableA
inner join
TableB
on
TableA.Column1 = TableB.Column2 --Column names don't match
or
TableA
inner join
TableB
on
TableA.Column1 >= TableB.Column1 --Not equality
Natural Join and Inner Join are not same commands.
Natural Join joins the tables on the basis of equality of values of common columns without typing the condition in query......while Inner join joins tables on the basis of condition specified in query which can be "=" or ">=" or "<="....
Natural Join :
tab1 NATURAL JOIN tab2;
this will automatically check for equality of values of common columns
Iner Join:
tab1 INNER JOIN tab2 ON (condition);
Moreover, NATURAL JOIN gives common column once in the output of query while INNER JOIN gives common columns of both tables