I am calculating the time difference between 2 times, I want to print the hour min and sec. Can anyone please tell me how to do it.
My query
SELECT
CONVERT(VARCHAR(8), DATEADD(ms, DATEDIFF(ms, CONVERT(VARCHAR(8), GETDATE(), 114), CONVERT(VARCHAR(8), VCTime, 114)), 0), 114) AS TImeDifference
FROM
Test
Output:
TimeDifference
---------------
10:51:37
20:51:37
21:51:37
22:21:37
08:51:37
00:51:37
Expected Output
TimeDifference
---------------
10h:51m:37s
20h:51m:37s
21h:51m:37s
22h:21m:37s
08h:51m:37s
00h:51m:37s
One way is to use sub query and concatenation operator + for 2008 with DATEPART function as below:
SELECT (
CAST(DATEPART(HOUR,(TImeDifference)) AS VARCHAR) + 'h:' +
CAST(DATEPART(MINUTE,(TImeDifference)) AS VARCHAR) + 'm:' +
CAST(DATEPART(SECOND,(TImeDifference)) AS VARCHAR) + 's')
FROM(
SELECT
CONVERT(varchar(8), DATEADD(ms, DATEDIFF(ms, convert(varchar(8),getdate(),114),
convert(varchar(8),VCTime,114)), 0), 114) as TImeDifference
FROM test
) t
Yes I realized concat is introduced in 2012 so we can use + instead
you can follow below way
DECLARE #x int,
#dt1 smalldatetime = '2018-08-17 03:24:16',
#dt2 smalldatetime = getdate()
SET #x = datediff (s, #dt1, #dt2)
SELECT convert(varchar, #x / (60 * 60 * 24)) + ':'
+ convert(varchar, dateadd(s, #x, convert(datetime2, '0001-01-01')), 108)
this will return 1:05:57:00
Try this:
select cast(date_diff / 3600 as varchar(4)) + 'h:' +
cast((date_diff % 3600) / 60 as varchar(4)) + 'm:' +
cast(date_diff % 60 as varchar(4)) + 's'
from (
select datediff(second, getdate(), VCTime) date_diff from my_table
) a
First, you should not be converting to strings to get the difference. I think this should be fine:
SELECT CONVERT(VARCHAR(8),
DATEDIFF(ms, CAST(GETDATE() as TIME), CAST(VCTime as TIME)),
114
) as TImeDifference
FROM Test;
Then you want to add "h", "m", and "s". You can use the STUFF() function. But let me do this using APPLY so the code doesn't look quite so messy:
SELECT ( STUFF(STUFF(TimeDifference_str, 6, 0, 'm'), 3, 0, 'h') + 's' ) as TimeDifference_hms
FROM test t CROSS APPLY
(VALUES (CONVERT(VARCHAR(8),
DATEDIFF(ms, CAST(GETDATE() as TIME), CAST(VCTime as TIME)),
114
)
)
) v(TimeDifference_str)
How to Find Time difference with all conditions like
if difference only minutes
49 mintus
if a difference in Hour
1 hour 20 minutes
i am trying
SELECT DATEDIFF(MINUTE,'2018-08-09 10:16:49.000','2018-08-09 11:14:40.000') AS Diff
but this is only show in minutes
I have also tried this one
DECLARE #StartTime datetime = '2018-08-09 10:16:49.000',
#EndTime datetime = '2018-08-09 12:44:05.000'
SELECT CAST(#EndTime - #StartTime as Time) As TimeDiffere
output : 02:27:16.0000000
but I want to 2hr 27mins 16Sec
If your SQL-server version higher than 2012, you can try to sue format function.
CREATE TABLE T(
StartTime datetime,
EndTime datetime
);
insert into t values ('2018-08-09 10:16:49.000','2018-08-09 12:44:05.000')
Query 1:
SELECT format(EndTime - StartTime ,'hh\hr mm\min\s ss\Sec') As TimeDiffere
FROM T
Results:
| TimeDiffere |
|-------------------|
| 02hr 27mins 16Sec |
NOTE
Backslash \ can escape keyword from the format like hr,min,s..., then display it as the original word.
DECLARE #StartTime datetime = '2018-08-09 10:01:15.000',
#EndTime datetime = '2018-08-09 12:50:00.000'
SELECT CONCAT((DATEDIFF(second,#StartTime,#EndTime )/60)/60,'hr ',(DATEDIFF(second,#StartTime,#EndTime)/60)%60,'mins ',DATEDIFF(second,#StartTime,#EndTime)%60,'Sec')
As TimeDiffere
DECLARE #StartTime datetime = '2018-08-09 12:16:49.000',
#EndTime datetime = '2018-08-09 12:44:05.000'
select [hour] + [minute] + [second] as TimeDiffere
from (
select diff_sec = datediff(second, #StartTime, #EndTime)
) t
cross apply
(
select [hour] = isnull(convert(varchar(10), nullif(diff_sec / 60 / 60, 0))
+ ' hours ', '')
) hr
cross apply
(
select [minute] = isnull(convert(varchar(10), nullif(diff_sec / 60 % 60, 0))
+ ' mintues ', '')
) mn
cross apply
(
select [second] = isnull(convert(varchar(10), nullif(diff_sec % 60, 0))
+ ' seconds', '')
) sc
/* RESULT
27 mintues 16 seconds
*/
If you have a poor datetime functionality to get hh.mm.ss, then you can use apply :
select t.*, concat( (dtdiff / 3600), 'hr ', (dtdiff / 60) % 60, 'mins ', dtdiff % 60, 'sec')
from table t cross apply
( values (datediff(second, startdate, enddate))
) tt(dtdiff);
hi i wrote this query in SqlServer 2008
but some thing goes wrong
select * from News_Table
where (DATEDIFF( DAY ,convert(datetime, NewsDate) , convert(datetime,#Todaydate )) <= #Count)
that #NewsDate and #Todaydate are two nvarchar parameters that are saved like this 2014/11/16
running this query give me an error:
Conversion failed when converting date and/or time from character string
Try adding the correct style parameter to your convert function (see MSDN: link )
ie CONVERT(DATETIME, NewsDate, 111) (111 is the style for YYYY/MM/DD)
Then you get:
SELECT *
FROM News_Table
WHERE (DATEDIFF( DAY ,
CONVERT(DATETIME, NewsDate, 111) ,
CONVERT(DATETIME,#Todaydate, 111)
) <= #Count)
use Convert(datetime, #yourvalue, 111)
select * from News_Table
where (DATEDIFF( DAY ,convert(datetime, #NewsDate, 111) , convert(datetime,#Todaydate, 111 )) <= #Count)
http://www.sqlusa.com/bestpractices/datetimeconversion/
To know more click here
SELECT convert(datetime, '2014/11/16', 111) as datetime
OP
So your query would be like this
Select * from News_Table
where (DATEDIFF( DAY ,convert(datetime, '2014/11/16', 111) , convert(datetime,#Todaydate,111 )) <= #Count)
Try like this
SELECT *
FROM News_Table
WHERE (DATEDIFF(DAY,CAST(NewsDate AS Datetime),CAST(#Todaydate AS Datetime)) <= #Count)
You will need to do something like this to convert that string into DATETIME datatype
DECLARE #Date NVARCHAR(20) = '2013/11/16'
SELECT CAST((LEFT(#Date, 4) + SUBSTRING(#Date, 6 ,2) + RIGHT(#Date, 2)) AS DATETIME)
for your query
select * from News_Table
where (DATEDIFF( DAY , CAST((LEFT(NewsDate, 4) + SUBSTRING(NewsDate, 6 ,2) + RIGHT(NewsDate, 2)) AS DATETIME)
, CAST((LEFT(#Todaydate, 4) + SUBSTRING(#Todaydate, 6 ,2) + RIGHT(#Todaydate, 2)) AS DATETIME)
) <= #Count)
Note
If variable #Todaydate is actually storing today's date then why not use simply GETDATE() function.
I have looked into Cast and Convert, but I cannot find a way to do this. I need to convert four digits into an hour format. For instance, 0800 would become 8:00 or 1530 would become 15:30. I cannot use functions, I'm using a InterSystem's CacheSQL. Any suggestions? Thanks in advance!
EDIT:
If it is any more convenient, I can just divide the four digits by one hundred to get values like 15 from original 1500, or 8.30 from 0830. Does this make converting to hour:minute format easier?
For CacheSQL, you can do this:
SELECT {fn TRIM(LEADING '0' FROM LEFT(col_name, 2) || ':' || RIGHT(col_name, 2)) }
FROM table_name
In SQL Server 2008, given data that looks like
create table #data
(
HHMM int not null ,
)
insert #data values ( 0800 )
insert #data values ( 0815 )
insert #data values ( 1037 )
insert #data values ( 2359 )
You can say:
select * ,
strTime = right( '0' + convert(varchar, HHMM / 100 ) , 2 )
+ ':'
+ right( '0' + convert(varchar, HHMM % 100 ) , 2 ) ,
myTime = convert(time ,
right( '0' + convert(varchar, HHMM / 100 ) , 2 )
+ ':'
+ right( '0' + convert(varchar, HHMM % 100 ) , 2 ) ,
120
)
from #data
Other SQL implementations likely have similar functionality.
In earlier versions of SQL Server that lack the time datatype, just use datetime, thus:
select * ,
strTime = right( '0' + convert(varchar, HHMM / 100 ) , 2 )
+ ':'
+ right( '0' + convert(varchar, HHMM % 100 ) , 2 ) ,
myTime = convert(datetime,
right( '0' + convert(varchar, HHMM / 100 ) , 2 )
+ ':'
+ right( '0' + convert(varchar, HHMM % 100 ) , 2 ) ,
120
)
from #data
You'll get a datetime value that is 1 Jan 1900 with the desired time-of-day.
Well, if it is something like Oracle you might have a try with the to_date() function.
Read more here.
Example:
SELECT to_date(yourColumn, 'HH24MI') FROM ...
EDIT (why? see comments): If necessary (I'm actually not familiar with Oracle) you can wrap another function like TIME() around it.
SELECT TIME(to_date(yourColumn, 'HH24MI')) FROM ...
Read more about TIME() here.
</EDIT>
In MySQL the equivalent would be the STR_TO_DATE() function:
SELECT STR_TO_DATE(yourColumn, '%H%i') FROM ...
Read about STR_TO_DATE() and its parameters under the DATE_FORMAT() function.
left( case when (EndTime / 100) < 10 then ('0'+ convert(varchar, EndTime / 100 )) else convert(varchar, EndTime / 100 ) end, 2 )
+ ':'
+ right( '0' + convert(varchar, EndTime % 100 ) , 2 )
Is there any way to take the difference between two datetime in sql server?
For example, my dates are
2010-01-22 15:29:55.090
2010-01-22 15:30:09.153
So, the result should be 14.063 seconds.
Just a caveat to add about DateDiff, it counts the number of times you pass the boundary you specify as your units, so is subject to problems if you are looking for a precise timespan.
e.g.
select datediff (m, '20100131', '20100201')
gives an answer of 1, because it crossed the boundary from January to February, so even though the span is 2 days, datediff would return a value of 1 - it crossed 1 date boundary.
select datediff(mi, '2010-01-22 15:29:55.090' , '2010-01-22 15:30:09.153')
Gives a value of 1, again, it passed the minute boundary once, so even though it is approx 14 seconds, it would be returned as a single minute when using Minutes as the units.
SELECT DATEDIFF (MyUnits, '2010-01-22 15:29:55.090', '2010-01-22 15:30:09.153')
Substitute "MyUnits" based on DATEDIFF on MSDN
SELECT DATEDIFF(day, '2010-01-22 15:29:55.090', '2010-01-22 15:30:09.153')
Replace day with other units you want to get the difference in, like second, minute etc.
I can mention four important functions of MS SQL Server that can be very useful:
1) The function DATEDIFF() is responsible to calculate differences between two dates, the result could be "year quarter month dayofyear day week hour minute second millisecond microsecond nanosecond", specified on the first parameter (datepart):
select datediff(day,'1997-10-07','2011-09-11')
2) You can use the function GETDATE() to get the actual time and calculate differences of some date and actual date:
select datediff(day,'1997-10-07', getdate() )
3) Another important function is DATEADD(), used to convert some value in datetime using the same datepart of the datediff, that you can add (with positive values) or substract (with negative values) to one base date:
select DATEADD(day, 45, getdate()) -- actual datetime adding 45 days
select DATEADD( s,-638, getdate()) -- actual datetime subtracting 10 minutes and 38 seconds
4) The function CONVERT() was made to format the date like you need, it is not parametric function, but you can use part of the result to format the result like you need:
select convert( char(8), getdate() , 8) -- part hh:mm:ss of actual datetime
select convert( varchar, getdate() , 112) -- yyyymmdd
select convert( char(10), getdate() , 20) -- yyyy-mm-dd limited by 10 characters
DATETIME cold be calculated in seconds and one interesting result mixing these four function is to show a formated difference um hours, minutes and seconds (hh:mm:ss) between two dates:
declare #date1 datetime, #date2 datetime
set #date1=DATEADD(s,-638,getdate())
set #date2=GETDATE()
select convert(char(8),dateadd(s,datediff(s,#date1,#date2),'1900-1-1'),8)
... the result is 00:10:38 (638s = 600s + 38s = 10 minutes and 38 seconds)
Another example:
select distinct convert(char(8),dateadd(s,datediff(s, CRDATE , GETDATE() ),'1900-1-1'),8) from sysobjects order by 1
I tried this way and it worked. I used SQL Server version 2016
SELECT DATEDIFF(MILLISECOND,'2010-01-22 15:29:55.090', '2010-01-22 15:30:09.153')/1000.00;
Different DATEDIFF Functions are:
SELECT DATEDIFF(year, '2005-12-31 23:59:59.9999999', '2006-01-01 00:00:00.0000000');
SELECT DATEDIFF(quarter, '2005-12-31 23:59:59.9999999', '2006-01-01 00:00:00.0000000');
SELECT DATEDIFF(month, '2005-12-31 23:59:59.9999999', '2006-01-01 00:00:00.0000000');
SELECT DATEDIFF(dayofyear, '2005-12-31 23:59:59.9999999', '2006-01-01 00:00:00.0000000');
SELECT DATEDIFF(day, '2005-12-31 23:59:59.9999999', '2006-01-01 00:00:00.0000000');
SELECT DATEDIFF(week, '2005-12-31 23:59:59.9999999', '2006-01-01 00:00:00.0000000');
SELECT DATEDIFF(hour, '2005-12-31 23:59:59.9999999', '2006-01-01 00:00:00.0000000');
SELECT DATEDIFF(minute, '2005-12-31 23:59:59.9999999', '2006-01-01 00:00:00.0000000');
SELECT DATEDIFF(second, '2005-12-31 23:59:59.9999999', '2006-01-01 00:00:00.0000000');
SELECT DATEDIFF(millisecond, '2005-12-31 23:59:59.9999999', '2006-01-01 00:00:00.0000000');
Ref: https://learn.microsoft.com/en-us/sql/t-sql/functions/datediff-transact-sql?view=sql-server-2017
Ok we all know the answer involves DATEDIFF(). But that gives you only half the result you may be after. What if you want to get the results in human-readable format, in terms of Minutes and Seconds between two DATETIME values?
The CONVERT(), DATEADD() and of course DATEDIFF() functions are perfect for a more easily readable result that your clients can use, instead of a number.
i.e.
CONVERT(varchar(5), DATEADD(minute, DATEDIFF(MINUTE, date1, date2), 0), 114)
This will give you something like:
HH:MM
If you want more precision, just increase the VARCHAR().
CONVERT(varchar(12), DATEADD(minute, DATEDIFF(MINUTE, date1, date2), 0), 114)
HH:MM.SS.MS
There are a number of ways to look at a date difference, and more when comparing date/times. Here's what I use to get the difference between two dates formatted as "HH:MM:SS":
ElapsedTime AS
RIGHT('0' + CAST(DATEDIFF(S, StartDate, EndDate) / 3600 AS VARCHAR(2)), 2) + ':'
+ RIGHT('0' + CAST(DATEDIFF(S, StartDate, EndDate) % 3600 / 60 AS VARCHAR(2)), 2) + ':'
+ RIGHT('0' + CAST(DATEDIFF(S, StartDate, EndDate) % 60 AS VARCHAR(2)), 2)
I used this for a calculated column, but you could trivially rewrite it as a UDF or query calculation. Note that this logic rounds down fractional seconds; 00:00.00 to 00:00.999 is considered zero seconds, and displayed as "00:00:00".
If you anticipate that periods may be more than a few days long, this code switches to D:HH:MM:SS format when needed:
ElapsedTime AS
CASE WHEN DATEDIFF(S, StartDate, EndDate) >= 359999
THEN
CAST(DATEDIFF(S, StartDate, EndDate) / 86400 AS VARCHAR(7)) + ':'
+ RIGHT('0' + CAST(DATEDIFF(S, StartDate, EndDate) % 86400 / 3600 AS VARCHAR(2)), 2) + ':'
+ RIGHT('0' + CAST(DATEDIFF(S, StartDate, EndDate) % 3600 / 60 AS VARCHAR(2)), 2) + ':'
+ RIGHT('0' + CAST(DATEDIFF(S, StartDate, EndDate) % 60 AS VARCHAR(2)), 2)
ELSE
RIGHT('0' + CAST(DATEDIFF(S, StartDate, EndDate) / 3600 AS VARCHAR(2)), 2) + ':'
+ RIGHT('0' + CAST(DATEDIFF(S, StartDate, EndDate) % 3600 / 60 AS VARCHAR(2)), 2) + ':'
+ RIGHT('0' + CAST(DATEDIFF(S, StartDate, EndDate) % 60 AS VARCHAR(2)), 2)
END
The following query should give the exact stuff you are looking out for.
select datediff(second, '2010-01-22 15:29:55.090' , '2010-01-22 15:30:09.153')
Here is the link from MSDN for what all you can do with datediff function .
https://msdn.microsoft.com/en-us/library/ms189794.aspx
Internally in SQL Server dates are stored as 2 integers. The first integer is the number of days before or after the base date (1900/01/01). The second integer stores the number of clock ticks after midnight, each tick is 1/300 of a second.
More info here
Because of this, I often find the simplest way to compare dates is to simply substract them. This handles 90% of my use cases. E.g.,
select date1, date2, date2 - date1 as DifferenceInDays
from MyTable
...
When I need an answer in units other than days, I will use DateDiff.
SELECT DATEDIFF(yyyy, '2011/08/25', '2017/08/25') AS DateDiff
It's gives you difference between two dates in Year
Here (2017-2011)=6 as a result
Syntax:
DATEDIFF(interval, date1, date2)
Use This for DD:MM:SS:
SELECT CONVERT(VARCHAR(max), Datediff(dd, '2019-08-14 03:16:51.360',
'2019-08-15 05:45:37.610'))
+ ':'
+ CONVERT(CHAR(8), Dateadd(s, Datediff(s, '2019-08-14 03:16:51.360',
'2019-08-15 05:45:37.610'), '1900-1-1'), 8)
So this isn't my answer but I just found this while searching around online for a question like this as well. This guy set up a procedure to calculate hours, minutes and seconds. The link and the code:
--Creating Function
If OBJECT_ID('UFN_HourMinuteSecond') Is Not Null
Drop Function dbo.UFN_HourMinuteSecond
Go
Exec(
'Create Function dbo.UFN_HourMinuteSecond
(
#StartDateTime DateTime,
#EndDateTime DateTime
) Returns Varchar(10)
As
Begin
Declare #Seconds Int,
#Minute Int,
#Hour Int,
#Elapsed Varchar(10)
Select #Seconds = ABS(DateDiff(SECOND ,#StartDateTime,#EndDateTime))
If #Seconds >= 60
Begin
select #Minute = #Seconds/60
select #Seconds = #Seconds%60
If #Minute >= 60
begin
select #hour = #Minute/60
select #Minute = #Minute%60
end
Else
Goto Final
End
Final:
Select #Hour = Isnull(#Hour,0), #Minute = IsNull(#Minute,0), #Seconds = IsNull(#Seconds,0)
select #Elapsed = Cast(#Hour as Varchar) + '':'' + Cast(#Minute as Varchar) + '':'' + Cast(#Seconds as Varchar)
Return (#Elapsed)
End'
)
declare #dt1 datetime='2012/06/13 08:11:12', #dt2 datetime='2012/06/12 02:11:12'
select CAST((#dt2-#dt1) as time(0))
PRINT DATEDIFF(second,'2010-01-22 15:29:55.090','2010-01-22 15:30:09.153')
select
datediff(millisecond,'2010-01-22 15:29:55.090','2010-01-22 15:30:09.153') / 1000.0 as Secs
result:
Secs
14.063
Just thought I'd mention it.
Sol-1:
select
StartTime
, EndTime
, CONVERT(NVARCHAR,(EndTime-StartTime), 108) as TimeDiff
from
[YourTable]
Sol-2:
select
StartTime
, EndTime
, DATEDIFF(hh, StartTime, EndTime)
, DATEDIFF(mi, StartTime, EndTime) % 60
from
[YourTable]
Sol-3:
select
DATEPART(hour,[EndTime]-[StartTime])
, DATEPART(minute,[EndTime]-[StartTime])
from
[YourTable]
Datepart works the best
Please check below trick to find the date difference between two dates
DATEDIFF(DAY,ordr.DocDate,RDR1.U_ProgDate) datedifff
where you can change according your requirement as you want difference of days or month or year or time.
CREATE FUNCTION getDateDiffHours(#fdate AS datetime,#tdate as datetime)
RETURNS varchar (50)
AS
BEGIN
DECLARE #cnt int
DECLARE #cntDate datetime
DECLARE #dayDiff int
DECLARE #dayDiffWk int
DECLARE #hrsDiff decimal(18)
DECLARE #markerFDate datetime
DECLARE #markerTDate datetime
DECLARE #fTime int
DECLARE #tTime int
DECLARE #nfTime varchar(8)
DECLARE #ntTime varchar(8)
DECLARE #nfdate datetime
DECLARE #ntdate datetime
-------------------------------------
--DECLARE #fdate datetime
--DECLARE #tdate datetime
--SET #fdate = '2005-04-18 00:00:00.000'
--SET #tdate = '2005-08-26 15:06:07.030'
-------------------------------------
DECLARE #tempdate datetime
--setting weekends
SET #fdate = dbo.getVDate(#fdate)
SET #tdate = dbo.getVDate(#tdate)
--RETURN #fdate
SET #fTime = datepart(hh,#fdate)
SET #tTime = datepart(hh,#tdate)
--RETURN #fTime
if datediff(hour,#fdate, #tdate) <= 9
RETURN(convert(varchar(50),0) + ' Days ' + convert(varchar(50),datediff(hour,#fdate, #tdate))) + ' Hours'
else
--setting working hours
SET #nfTime = dbo.getV00(convert(varchar(2),datepart(hh,#fdate))) + ':' +dbo.getV00(convert(varchar(2),datepart(mi,#fdate))) + ':'+ dbo.getV00(convert(varchar(2),datepart(ss,#fdate)))
SET #ntTime = dbo.getV00(convert(varchar(2),datepart(hh,#tdate))) + ':' +dbo.getV00(convert(varchar(2),datepart(mi,#tdate))) + ':'+ dbo.getV00(convert(varchar(2),datepart(ss,#tdate)))
IF #fTime > 17
begin
set #nfTime = '17:00:00'
end
else
begin
IF #fTime < 8
set #nfTime = '08:00:00'
end
IF #tTime > 17
begin
set #ntTime = '17:00:00'
end
else
begin
IF #tTime < 8
set #ntTime = '08:00:00'
end
-- used for working out whole days
SET #nfdate = dateadd(day,1,#fdate)
SET #ntdate = #tdate
SET #nfdate = convert(varchar,datepart(yyyy,#nfdate)) + '-' + convert(varchar,datepart(mm,#nfdate)) + '-' + convert(varchar,datepart(dd,#nfdate))
SET #ntdate = convert(varchar,datepart(yyyy,#ntdate)) + '-' + convert(varchar,datepart(mm,#ntdate)) + '-' + convert(varchar,datepart(dd,#ntdate))
SET #cnt = 0
SET #dayDiff = 0
SET #cntDate = #nfdate
SET #dayDiffWk = convert(decimal(18,2),#ntdate-#nfdate)
--select #nfdate,#ntdate
WHILE #cnt < #dayDiffWk
BEGIN
IF (NOT DATENAME(dw, #cntDate) = 'Saturday') AND (NOT DATENAME(dw, #cntDate) = 'Sunday')
BEGIN
SET #dayDiff = #dayDiff + 1
END
SET #cntDate = dateadd(day,1,#cntDate)
SET #cnt = #cnt + 1
END
--SET #dayDiff = convert(decimal(18,2),#ntdate-#nfdate) --datediff(day,#nfdate,#ntdate)
--SELECT #dayDiff
set #fdate = convert(varchar,datepart(yyyy,#fdate)) + '-' + convert(varchar,datepart(mm,#fdate)) + '-' + convert(varchar,datepart(dd,#fdate)) + ' ' + #nfTime
set #tdate = convert(varchar,datepart(yyyy,#tdate)) + '-' + convert(varchar,datepart(mm,#tdate)) + '-' + convert(varchar,datepart(dd,#tdate)) + ' ' + #ntTime
set #markerFDate = convert(varchar,datepart(yyyy,#fdate)) + '-' + convert(varchar,datepart(mm,#fdate)) + '-' + convert(varchar,datepart(dd,#fdate)) + ' ' + '17:00:00'
set #markerTDate = convert(varchar,datepart(yyyy,#tdate)) + '-' + convert(varchar,datepart(mm,#tdate)) + '-' + convert(varchar,datepart(dd,#tdate)) + ' ' + '08:00:00'
--select #fdate,#tdate
--select #markerFDate,#markerTDate
set #hrsDiff = convert(decimal(18,2),datediff(hh,#fdate,#markerFDate))
--select #hrsDiff
set #hrsDiff = #hrsDiff + convert(int,datediff(hh,#markerTDate,#tdate))
--select #fdate,#tdate
IF convert(varchar,datepart(yyyy,#fdate)) + '-' + convert(varchar,datepart(mm,#fdate)) + '-' + convert(varchar,datepart(dd,#fdate)) = convert(varchar,datepart(yyyy,#tdate)) + '-' + convert(varchar,datepart(mm,#tdate)) + '-' + convert(varchar,datepart(dd,#tdate))
BEGIN
--SET #hrsDiff = #hrsDiff - 9
Set #hrsdiff = datediff(hour,#fdate,#tdate)
END
--select FLOOR((#hrsDiff / 9))
IF (#hrsDiff / 9) > 0
BEGIN
SET #dayDiff = #dayDiff + FLOOR(#hrsDiff / 9)
SET #hrsDiff = #hrsDiff - FLOOR(#hrsDiff / 9)*9
END
--select convert(varchar(50),#dayDiff) + ' Days ' + convert(varchar(50),#hrsDiff) + ' Hours'
RETURN(convert(varchar(50),#dayDiff) + ' Days ' + convert(varchar(50),#hrsDiff)) + ' Hours'
END
For Me This worked Perfectly
Convert(varchar(8),DATEADD(SECOND,DATEDIFF(SECOND,LogInTime,LogOutTime),0),114)
and the Output is
HH:MM:SS which is shown accurately in my case.
Please try
DECLARE #articleDT DATETIME;
DECLARE #nowDate DATETIME;
-- Time of the ARTICLE created
SET #articleDT = '2012-04-01 08:10:16';
-- Simulation of NOW datetime
-- (in real world you would probably use GETDATE())
SET #nowDate = '2012-04-10 11:35:36';
-- Created 9 days ago.
SELECT 'Created ' + CAST(DATEDIFF(day, #articleDT, #nowDate) AS NVARCHAR(50)) + ' days ago.';
-- Created 1 weeks, 2 days, 3 hours, 25 minutes and 20 seconds ago.
SELECT 'Created '
+ CAST(DATEDIFF(second, #articleDT, #nowDate) / 60 / 60 / 24 / 7 AS NVARCHAR(50)) + ' weeks, '
+ CAST(DATEDIFF(second, #articleDT, #nowDate) / 60 / 60 / 24 % 7 AS NVARCHAR(50)) + ' days, '
+ CAST(DATEDIFF(second, #articleDT, #nowDate) / 60 / 60 % 24 AS NVARCHAR(50)) + ' hours, '
+ CAST(DATEDIFF(second, #articleDT, #nowDate) / 60 % 60 AS NVARCHAR(50)) + ' minutes and '
+ CAST(DATEDIFF(second, #articleDT, #nowDate) % 60 AS NVARCHAR(50)) + ' seconds ago.';
For MS SQL, you can convert the datetime value to a double value.
The integer part contains the number of days since 1900-01-01, the fractional part contains the time in hours.
So you can calculate date difference as:
cast(date1-date2 as FLOAT)