Using two tables in MSSQL:
One table, [CUSTOMER], containing information on donors.
- Relevent columns: [CustID], [Name]
One table, [DONATION], containing records for each donation given.
- Relevent columns: [CustID], [Amount], [Date]
The tables share a key, [CustID].
I want to aggregate the [Amounts] according to each [CustID]
SELECT DONATION.CUSTID
,PEOPLE.NAME
,SUM (DONATION.AMOUNT) as TOTAL_DONATION
FROM [dbo].[DONATION] INNER JOIN [dbo].[PEOPLE] ON DONATION.CUSTID = PEOPLE.CUSTID
GROUP BY
DONATION.CUSTID
,PEOPLE.NAME
HAVING SUM (DONATION.AMOUNT) > 100
This query works fine, even with adding the HAVING clause.
When I want to restrict the dates of donations to aggregate (adding to the SELECT,GROUP BY, and HAVING clauses) however...
SELECT DONATION.CUSTID
,PEOPLE.NAME,DONATION.DATE
,SUM (DONATION.AMOUNT) as TOTAL_DONATION
FROM [dbo].[DONATION] INNER JOIN [dbo].[PEOPLE] ON DONATION.CUSTID = PEOPLE.CUSTID
GROUP BY
DONATION.CUSTID
,PEOPLE.NAME
,DONATION.DATE
HAVING SUM (DONATION.AMOUNT) > 100
and DONATION.DATE > '1-1-2010'
The query no longer returns aggregate sums of each person's donations, but returns individual donations for each person, which meet the HAVING criteria.
How can I implement this date restriction? Is it how I'm joining or summing or....? Thanks.
Move it to the WHERE clause
SELECT DONATION.CUSTID
,PEOPLE.NAME
,SUM (DONATION.AMOUNT) as TOTAL_DONATION
FROM [dbo].[DONATION]
INNER JOIN [dbo].[PEOPLE] ON DONATION.CUSTID = PEOPLE.CUSTID
WHERE DONATION.DATE > '1-1-2010'
GROUP BY
DONATION.CUSTID
,PEOPLE.NAME
HAVING SUM (DONATION.AMOUNT) > 100
What this means:
- given the people who donated
- look only at data where donation date is in 2010 or later
- and within that data, show the people who donated a total of more than 100
Modify your first query like:
,SUM (CASE WHEN DONATION.DATE > '1-1-2010' THEN DONATION.AMOUNT END)
as TOTAL_DONATION
You can't group by date unless you want one row per customer per date.
How about doing it from the donation table and just looking up customer names?
select Donator=(select name from [people] where [people].custid=[donation].custid),
custid,SUM(amount)
from [donation]
where [donation].date between '1/1/2011' and '1/15/2011'
group by custid
having SUM(amount)>100
Related
I am trying to run a query to gather the total items on hand in our database. However it seems i'm getting incorrect data. I am selecting selecting just the amount field and summing it using joins from separate tables based on certain parameters, however if I display additional fields such as order number, and date all of a sudden im getting different data, even though those fields are being used as filters in the query. Is it because its not in the select statement? If it needs to be in the select statement is it possible to not display them?
Here are the two queries.
-- Items On Hand
select CONVERT(decimal(25, 2), SUM(tw.amount)) as 'Amt'
from [Sales Header] sh
join
(
select *
from TWAllOrders
where [Status] like 'Released'
) tw
on tw.[Order Nb] = sh.No_
join
(
select *
from OnHand
) oh
on tw.No_ = oh.[Item No_]
where sh.[Requested Delivery Date] < getdate()
HAVING SUM(tw.Quantity) <= SUM(oh.Qty)
providing a sum of 21667457.20
and with the added columns
-- Items On Hand
select CONVERT(decimal(25, 2), SUM(tw.amount)) as 'Amt', [Requested Delivery Date], sh.No_, tw.[Status]
from [Sales Header] sh
join
(
select *
from TWAllOrders
where [Status] like 'Released'
) tw
on tw.[Order Nb] = sh.No_
join
(
select *
from OnHand
) oh
on tw.No_ = oh.[Item No_]
where sh.[Requested Delivery Date] < getdate()
group by sh.[Requested Delivery Date], sh.No_, tw.[Status]
HAVING SUM(tw.Quantity) <= SUM(oh.Qty)
order by sh.[Requested Delivery Date] ASC
Providing a sum of 12319998
I'm self taught in SQL so I may be misunderstanding something obvious, thanks for the help.
With no sample data, I am going to have to demonstrate this in principle. In the latter query you have a GROUP BY meaning the scope of the values in the HAVING will differ, and thus the filtering from said HAVING will be different.
Let's take the following sample data:
CREATE TABLE dbo.MyTable (Grp char(1),
Quantity int,
Required int);
INSERT INTO dbo.MyTable (Grp, Quantity, [Required])
VALUES('a',2,7),
('a',14,2),
('b',4, 7),
('b',3,4),
('c',17,5);
Now we'll perform an overly simplified version of your query:
SELECT SUM(Quantity)
FROM dbo.MyTable
HAVING SUM(Quantity) > SUM(Required);
This brings back the value 40; which is the SUM of all the values in Quantity. A value is returned because the total SUM of Required is 25.
Now let's add a GROUP BY like your second query:
SELECT SUM(Quantity)
FROM dbo.MyTable
GROUP BY Grp
HAVING SUM(Quantity) > SUM(Required);
Now we have 2 rows, with the values 16 and 17 giving a total value of 33. That's because the rows where Grp have a value of 'B' are filtered out, as the SUM of Quantity is lower that Required for 'B'.
The same is happening in your data; in the grouped data you have groups where the HAVING condition isn't met, so those rows aren't returned.
I am trying to write a query that will give me transaction amount sum happened in one date. The problem is , when I added column date in my query, I get individual values not their sum. The requirement for this query is to have one entry for each merchant but i am getting multiple rows for one merchant.
SELECT SUBSTR(m.MERCHANTLASTNAME, 1, 36) Name1,
m.MERCHANTBANKBSB MerchantAccbsb,
m.MERCHANTBANKACCNR Merchant_act,
m.MERCHANTID merchantid,
t.transactiondate date1,
sum(t.TRANSACTIONAMOUNT) as total
FROM fss_merchant m
JOIN fss_terminal term
ON m.MERCHANTID = term.MERCHANTID
JOIN FSS_DAILY_TRANSACTION t
ON term.TERMINALID = t.TERMINALID
group by t.transactiondate, SUBSTR(m.MERCHANTLASTNAME, 1, 36), m.MERCHANTID, m.MERCHANTBANKBSB, m.MERCHANTBANKACCNR,
m.MERCHANTLASTNAME
Output of my query:
I want to get one entry per each merchant with the sum of transaction amount in one day, not multiple rows of transaction in that day.
You can calculate the total amount in different inner query with the truncated date and join it with FSS_MERCHANT table so that issues described by #SatishSK and #mangusta is taken care.
You can use the following query:
SELECT
SUBSTR(M.MERCHANTLASTNAME, 1, 36) NAME1,
M.MERCHANTBANKBSB MERCHANTACCBSB,
M.MERCHANTBANKACCNR MERCHANT_ACT,
M.MERCHANTID MERCHANTID,
M_DATA.TRANSACTIONDATE DATE1,
M_DATA.TOTAL AS TOTAL
FROM
FSS_MERCHANT M
INNER JOIN (
SELECT
TERM.MERCHANTID MERCHANTID,
TRUNC(T.TRANSACTIONDATE) TRANSACTIONDATE,
SUM(T.TRANSACTIONAMOUNT) AS TOTAL
FROM
FSS_TERMINAL TERM
JOIN FSS_DAILY_TRANSACTION T ON TERM.TERMINALID = T.TERMINALID
GROUP BY
TERM.MERCHANTID,
TRUNC(T.TRANSACTIONDATE)
) M_DATA ON ( M.MERCHANTID = M_DATA.MERCHANTID );
Good luck!!
t.transactiondate column might contain date+time values. Use TRUNC(t.transactiondate) where you are using just t.transactiondate. You will get sum(transaction amount) "Date-wise" for each merchant.
OR
Filter out rows based on "Date" value in WHERE clause to retrieve data pertaining to a specific date.
Probably the reason is that you have included both m.MERCHANTLASTNAME and SUBSTR(m.MERCHANTLASTNAME,1,36) into the group by clause.
In case if there are entries with same SUBSTR(m.MERCHANTLASTNAME,1,36) but different m.MERCHANTLASTNAME, this is going to yield duplicates. You need to remove m.MERCHANTLASTNAME from group by clause
I have two tables one for receiving "PO_RECVR_HIST" and other table for sales "PS_TKT_HIST_LIN". I want to create a query showing the total for receiving and total for sales. The two dates are not related the results come wrong. The two tables has the same vendor. I am using the following query
SELECT P.VEND_NO,
sum(P.RECVR_TOT)AS RECV_TOT,
sum(S.CALC_EXT_PRC) AS SAL_TOT
FROM PO_RECVR_HIST P INNER JOIN
PS_TKT_HIST_LIN S
ON P.VEND_NO = S.ITEM_VEND_NO
WHERE P.RECVR_DAT > getdate()-7
GROUP BY P.VEND_NO, S.BUS_DAT
HAVING S.BUS_DAT > getdate()-7
ORDER BY P.VEND_NO
Any advise please?
I think I get it. You want the sums in different columns. One approach is to do a UNION ALL to get the data together, and then aggregate:
SELECT VEND_NO,
SUM(RECVR_TOT)AS RECV_TOT,
SUM(CALC_EXT_PRC) AS SAL_TOT
FROM ((SELECT P.VEND_NO, P.RECVR_DAT as dte, P.RECVR_TOT, 0 as CALC_EXT_PRC
FROM PO_RECVR_HIST P
) UNION ALL
(SELECT S.ITEM_VEND_NO, S.BUS_DAT, 0, CALC_EXT_PRC
FROM PS_TKT_HIST_LIN S
)
) PS
WHERE DTE > GETDATE() - 7
GROUP BY P.VEND_NO
ORDER BY P.VEND_NO;
A JOIN is just not a good approach because it will throw off the aggregation.
I am attempting to join a customer table with sales table where I show the list of all customers in database and any paid sale the customer might have in the sales tables. Now a customer can have multiple sales rows in the sales table.
This is an example sales record of one customer with multiple sales in the sale tables
while extracting this record I would like to get only the MAX (q_saledatetime) WHERE the q_paidamount is > 0.
as in show me the last time this customer made a payment to us. So in this case row 2 where they paid 8.90 is what I would like to get for that customer. If a customer has no record in the sales table, show their name/details on the list either way.
My failure at the moment is how to include the where clause of the paid amount + max date column.
ATTEMPT A
select DISTINCT ON (q_customer.q_code)
q_customer.q_code, q_customer.q_name, -- customer info
MAX(q_saleheader.q_saledatetime) AS latestDate, q_saleheader.q_paidamount -- saleheader info
FROM q_customer
LEFT JOIN q_saleheader ON (q_customer.q_code = q_saleheader.q_customercode)
group by q_customer.q_code, q_customer.q_name , q_saleheader.q_saledatetime, q_saleheader.q_paidamount
order by q_customer.q_code ASC
which results in
so for Fred Blogg is picking up details from row 4 instead of 2 (first image). As there's no rule for q_paidamount at this point
ATTEMPT B
SELECT
customer.q_code, customer.q_name, -- customer info
sale.q_saledatetime, sale.q_paidamount -- sale info
FROM q_customer customer
LEFT JOIN (SELECT * FROM q_saleheader WHERE q_saledatetime =
(SELECT MAX(q_saledatetime) FROM q_saleheader b1 where q_paidamount > 0 ))
sale ON sale.q_customercode = customer.q_code
which results in
This doesnt seem to be getting any information from the sale table at all.
Update:
After having a closer look at my first attempt I amended the statement and came up with this solution which achieves the same results as Michal's answer. I just curious to know is there any pitfalls or perfomance disadvantages with the following way.
select DISTINCT ON (q_customer.q_code)
q_customer.q_code, q_customer.q_name, -- customer info
q_saleheader.q_saledatetime, q_saleheader.q_paidamount -- saleheader info
FROM q_customer
LEFT JOIN q_saleheader ON (q_customer.q_code = q_saleheader.q_customercode AND
q_saleheader.q_paidamount > 0 )
group by q_customer.q_code, q_customer.q_name , q_saleheader.q_saledatetime,
q_saleheader.q_paidamount
order by q_customer.q_code ASC, q_saleheader.q_saledatetime DESC
main change was adding AND q_saleheader.q_paidamount > 0 on the join and q_saleheader.q_saledatetime DESC to make sure are getting the top row of that related data. As mentioned both Michal's answer and this solution achieve the same results. Just curious about pitfalls in either of the two ways.
Try this query:
SELECT c.q_code,
c.q_name,
CASE WHEN q_saledatetime <> '1900-01-01 00:00:00.000' THEN q_saledatetime END q_saledatetime,
q_paidamount
FROM (
SELECT c.q_code,
c.q_name,
coalesce(s.q_saledatetime, '1900-01-01 00:00:00.000') q_saledatetime, --it will indicate customer with no data
s.q_paidamount,
ROW_NUMBER() OVER (PARTITION BY c.q_code ORDER BY COALESCE(s.q_saledatetime, '1900-01-01') DESC) rn
FROM q_customer c
LEFT JOIN (SELECT q_saledatetime,
q_paidamount
FROM q_saleheader
WHERE q_paidamount > 0) s
ON c.q_code = s.q_customercode
) c WHERE rn = 1
I have at least 8 tables from where I need to match the customer name and fetch the quantities and get the sum of all the quantities fetched from these 8 tables. I am trying to write a code which will ignore the customer whose sum of quantities is zero.
For an example lets take two tables purchase_sugar and sales_sugar I have tried a lot of queries but only this one is returning some result which is wrong.
SELECT sum(purchase_sugar.qty + sales_sugar.qty) AS Total_Amount from purchase_sugar inner join sales_sugar on purchase_sugar.supplier = sales_sugar.customer WHERE purchase_sugar.supplier = "+str(x.id)+"
The Table structures are like:
purchase_sugar have two columns supplier and qty.
And sales_sugar have structure like customer and qty.
How can I get the SUM of QUANTITIES of these tables if I provide one name and search it through these tables and get the quantities. The other thing is that I dont want the customer to be found in all the tables. If it is found in one table we should just get the quantity from that one table and for that reason I don't think that JOIN is useful or may be i am wrong.
To take care of the situation where a supplier/customer is not in all the tables, you can use union all and group by:
select name, sum(p_qty) as sum_p, sum(s_qty) as sum_s,
sum(p_qty) + sum(s_qty)
from ((select ps.supplier as name, ps.qty as p_qty, 0 as s_qty
from purchase_sugar ps
) union all
(select ss.customer as name, 0, ss.qty
from sales_sugar ss
)
) s
group by name;
Notes:
This query gets results for all names. You can use a where clause to restrict the results to one name.
You don't have to split the quantities into two (or eight) different columns, if you just want the overall sum.
You can aggregate before the union all, but that is not necessary.
you should JOIN the sum and not sum the join
select t1.purchase_sum + sales_sum as Total_Amount
from (
select purchase_sugar.supplier, sum(purchase_sugar.qty) as purchase_sum
from purchase_sugar
group by purchase_sugar.supplier
) t1
inner join (
select sales_sugar.customer, sum(sales_sugar.qty) as sales_sum
from sales_sugar
group by sales_sugar.customer
) t2 on t1.supplier = t2.customer and t1.supplier = "+str(x.id)+"