I have a smalldatetime field I am converting to varchar (which works fine) now I wanna cut it in the select query to only return the time and not the date.
convert(varchar, [DTMON_F]) as mondayFrom
This returns "Feb 28 2011 10:30AM" I want to just return "10:30AM"
You could use one of the predefined format styles that only contain time parts, such as:
convert(varchar, [DTMON_F], 108)
convert(varchar, [DTMON_F], 114)
if they give you a suitable output.
Otherwise you can create your own output by concatenating results of various DATEPART function calls.
Try RIGHT(CONVERT(VARCHAR, [DTMON_F]), 7)
http://msdn.microsoft.com/en-us/library/ms187928%28v=SQL.105%29.aspx
Two ways spring to mind
select convert(varchar,[DTMON_F],8) as mondayFrom
will return 10:30:00 (in 24hr format)
select ltrim(right(convert(varchar,[DTMON_F]),7)) as mondayFrom
will return 10:30PM
Related
I have the following datetime format ( as varchar ) in my database 13-04-2018 1:05:00.
I need to convert it to the following format: 2018-04-13 01:05:00. As datetime.
Normal convert functions can't do this because they try to take the 13th month, and that month doesn't exist. This error:
The conversion of a varchar data type to a datetime data type resulted
in an out-of-range value.
Does someone know how to convert this date issue?
Using datetimes is always a pain regardless of the language because of all the different formats across the world.
To sort your issue out currently, you need to use a format style which is a third parameter to CONVERT. Personally what I would suggest here is to store as a datetime, because storing datetimes as strings is never a good idea. It just gets too messy later on, but if saved in the format you would like, it would be saved as yyyy-MM-dd hh:mm:ss
SELECT CONVERT(DATETIME, '13-04-2018 1:05:00',103)
You can create your own function to format it in your desired output string.
CREATE FUNCTION FormatMyDate
(#Date DATETIME) RETURNS VARCHAR(20)
AS
BEGIN
RETURN FORMAT(#Date,'yyyy-dd-MM hh:mm:ss')
END
And then you can call it in SELECT statements like this:
SELECT dbo.FormatMyDate(yourDateCol)
FROM yourTable
this takes the date from the format where month comes before day and reverses the 2 values (month and day)
SELECT CONVERT(DATETIME, '2018-13-04 01:05:00', 103);
Results:
2018-04-13 01:05:00.000
This should work for you requirement...
SELECT FORMAT(yourdate, 'yyyy-dd-MM')
Your Solution Bro...
DECLARE #d DATETIME = GETDATE()
SELECT FORMAT ( #d, 'MM-dd-yyyy hh:mm:ss', 'de-de' ) AS 'Hoping your result'
I am working on a project in which dates and times ar stored as a varchar e.g. "30-11-2017,7:30" first date in dd-mm-yyy format and then time separated with a comma. I am trying to filter on it but it is not working correctly kindly guide me how to filter data on date.
select *
from timetrack
where startDateAndTime >= '30-11-2017,7:30'
In attached image records have been shown. When I apply above query it shows no records
You can easily convert your date to SQL datatype datetime uisng parse function, for example select parse('30-11-2017,7:30' as datetime using 'it-IT').
So, in your case, you can apply this function in where clause, so you can easily apply comparison between dates:
select *
from timetrack
where parse(startDateAndTime as datetime using 'it-IT') >= '2017-11-30 07:30:00.000'
Your format is apparently italian :) But you have to specify your own date in the format convertable to datetime, as I have done in above example.
NOTE: parse is available starting with SQL Management Studio 2012.
Unless you are using ISO date format (yyyy-MM-dd HH:mm:ss or close) applying ordering (which inequalities like greater than or equal use) will not work: the date order is disconnected from the string ordering.
You'll need to parse the date and times into a real date time type and then compare to that (details of this depend on which RDBMS you are using).
If, you want to just filter out the date then you could use convert() function for SQL Server
select *
from timetrack
where startDateAndTime >= convert(date, left(#date, 10), 103)
Else convert it to datetime as follow
select *
from timetrack
where startDateAndTime >= convert(datetime, left(#date, 10)+' ' +
reverse(left(reverse(#date), charindex(',', reverse(#date))-1)), 103)
You need the date in a datetime column, Otherwise you can't filter with your current varchar format of your date.
Without changing the existing columns, this can be achieved by making a computed column and making it persisted to optimize performance.
ALTER TABLE test add CstartDateTime
as convert(datetime, substring(startDateAndTime, 7,4)+ substring(startDateAndTime, 4,2)
+ left(startDateAndTime, 2) +' '+ right(startDateAndTime, 5), 112) persisted
Note: this require all rows in the column contains a valid date with the current format
Firstly, you need to check what is the data that is entered in the 'startDateAndTime' column,then you can convert that varchar into date format
If the data in 'startDateAndTime' column has data like '30-11-2017,07:30', you would then have to convert it into date:
SELECT to_date('30-11-2017,07:30','dd-mm-yyyy,hh:mm') from dual; --check this
--Your query:
SELECT to_date(startDateAndTime ,'dd-mm-yyyy,hh:mm') from timetrack;
I have a rather strange issue here. I have a date string, which I've created partly by myself to incorporate a variable. The problem is, that I'm setting another language settings. In this case, I have to also convert the string to fit the language settings format. I'm using this code:
cast(convert(varchar, cast(cast(getdate() as date) as varchar) + ' ' + RIGHT('0' + CAST(#HR as varchar), 2) + ':00:00.000', 120) as datetime)
I get the error "The conversion of a varchar data type to a datetime data type resulted in an out-of-range value.", which is normal if you assign wrong date format before casting.
The problem is, that when I try to convert the personally created date string, it doesn't change its format no matter what format code I set it in. That doesn't change even when I hardcode a number instead of my variable:
convert(varchar, cast(cast(getdate() as date) as varchar) + ' 0' + CAST(2 as varchar) + ':00:00.000', 101)
results in 2016-09-14 02:00:00.000
For example,
convert(varchar, dateadd(Hour, 2, getdate()), 101) as datetime
Results in 09/14/2016.
Even though I have a different language setting, isn't SQL server supposed to always recognize the date format in the standard format?
Please give me an advice so I can overcome this issue.
Thanks in advance!
PS: I managed to solve my issue by inserting converted datetime column in a variable before setting bulgarian language. I'm still very interested to know what causes the problem though.
Ok I may have a soution for the question: Why is the format differently handled in SQL-SERVER when converting.
CONVERT(data_type(length),expression,style)
The STYLEvalue only applies for date/time.
So it's because of the datatype that the output is different.
See following example:
SELECT convert(varchar, dateadd(Hour, 2, getdate()), 101) as datetime
You get the result:
09/14/2016
Here your are converting a datetime datatype into a varchar and the STYLE-value with 101 applies for CONVERT and the output is converted in that format.
Example 2 is the same but the inner most part is casted into a varchar before converting it:
SELECT convert(varchar, CAST(dateadd(Hour, 2, getdate()) AS varchar), 101) as datetime
The result you get is:
Sep 14 2016 4:09PM
So because we are trying to convert a varchar into a varchar the STYLE-value doesn't apply for the conversion.
That is also why the first query is handled diffrent then the other:
SELECT convert(varchar, cast(cast(getdate() as date) as varchar) + ' 0' + CAST(2 as varchar) + ':00:00.000', 101)
Here you cast into varchar cast(cast(getdate() as date) as varchar) before converting. So the STYLE-value is not applying because it's not from datatype date/time.
I hope it made it a bit clear. Let me know if this helped.
When you use convert to format the datetime, you can pass a style number to it.
Looky here or here for those numbers.
The query below converts custom created datetimes to the 126 (ISO8601) format.
declare #d int = 2;
SELECT
CONVERT(varchar,
CONVERT(datetime,
CONCAT(FORMAT(GETDATE(),'yyyy-MM-dd'),' ',#d,':0')
)
,126) AS MyDateStamp1,
CONVERT(varchar,
CONVERT(datetime,
CONVERT(varchar,GETDATE(),102)+' '+convert(varchar,#d)+':0'
)
,126) AS MyDateStamp2;
The FORMAT & CONCAT functions can be used in SQL Server 2012 and beyond.
But if you have an earlier version then CONVERT should work instead.
Additional tip:
If you're using the CONVERT solution above, note that
"convert(varchar, CAST(dateadd(Hour, 2, getdate()) AS varchar), 101)" calls for you to set datatype to varchar.
I just came across code
"Convert(date,ML.StartDate,101)"
and since style 101 is mm/dd/yyyy, and the output was yyyy-mm-dd, I knew something was wrong. By changing the code to
"Convert(varchar,ML.StartDate,101)"
the proper date style was displayed in the result set.
I want to retrive data from table according to a particular time so I use this query below.
select * from a
where convert(smalldatetime,date,datepart(hh,date)) ='09:12:00'
but I get no row as result. So what should I do for my expected result?
You can convert directly to varchar as below
SELECT * FROM a
WHERE CONVERT(VARCHAR(8), [date], 108) = '09:12:00'
Try this:
SELECT *
FROM a
WHERE CONVERT(VARCHAR(8), [DATE],108) = '09:12:00'
Your datatype is already smalldatetime so you have to convert to varchar and compare with string.
EDIT:
Answer explanation:
You have smalldatetime inside [DATE] column. For example 2015-10-01 09:12:00. To compare only time you need to convert to string which contains only time. For this reason you will use command CONVERT from TSQL.
It will convert smalldatetime to 8 characters string. As a result you will have 09:12:00 and then you compare it with your string.
In Sql server 2008 you can convert to TIME. By specifying TIME(0) you have the desired format:
SELECT *
FROM a
WHERE CAST(date as time(0)) ='09:12:00'
//CONVERT(data_type(length),expression,style)
SELECT * FROM a
WHERE CONVERT(varchar(8),[columnName],108) = '09:12:00'
I am running a select against a datetime column in SQL Server 2005. I can select only the date from this datetime column?
Best way is:
SELECT DATEADD(day, DATEDIFF(Day, 0, #ADate), 0)
This is because internally, SQL Server stores all dates as two integers, of which the first one is the ****number of days*** since 1 Jan 1900. (the second one is the time portion, stored as the number of seconds since Midnight. (seconds for SmallDateTimes, or milleseconds for DateTimes)
Using the above expression is better because it avoids all conversions, directly reading and accessing that first integer in a dates internal representation without having to perform any processing... the two zeroes in the above expression (which represent 1 Jan 1900), are also directly utilized w/o processing or conversion, because they match the SQL server internal representation of the date 1 jan 1900 exactly as presented (as an integer)..
*NOTE. Actually, the number of date boundaries (midnights) you have to cross to get from the one date to the other.
Yes, by using the convert function. For example:
select getdate(), convert(varchar(10),getdate(),120)
RESULTS:
----------------------- ----------
2010-05-21 13:43:23.117 2010-05-21
You can use the functions:
day(date)
month(date)
year(date)
Also the Datepart() function might be of some use:
http://msdn.microsoft.com/en-us/library/ms174420(SQL.90).aspx
DECLARE #dToday DATETIME
SET #dToday = CONVERT(nvarchar(20), GETDATE(), 101)
SELECT #dToday AS Today
This returns today's date at 12:00am : '2010-05-21 00:00:00.000'
Then you can use the #dToday variable in a query as needed
CONVERT (date, GETUTCDATE())
CONVERT (date, GETDATE())
CONVERT (date, '2022-18-01')
I don't know why the others recommend it with varchar(x) tbh.
https://learn.microsoft.com/de-de/sql/t-sql/functions/getdate-transact-sql