Problem with MySQL Select query with "IN" condition - sql

I found a weird problem with MySQL select statement having "IN" in where clause:
I am trying this query:
SELECT ads.*
FROM advertisement_urls ads
WHERE ad_pool_id = 5
AND status = 1
AND ads.id = 23
AND 3 NOT IN (hide_from_publishers)
ORDER BY rank desc
In above SQL hide_from_publishers is a column of advertisement_urls table, with values as comma separated integers, e.g. 4,2 or 2,7,3 etc.
As a result, if hide_from_publishers contains same above two values, it should return only record for "4,2" but it returns both records
Now, if I change the value of hide_for_columns for second set to 3,2,7 and run the query again, it will return single record which is correct output.
Instead of hide_from_publishers if I use direct values there, i.e. (2,7,3) it does recognize and returns single record.
Any thoughts about this strange problem or am I doing something wrong?


There is a difference between the tuple (1, 2, 3) and the string "1, 2, 3". The former is three values, the latter is a single string value that just happens to look like three values to human eyes. As far as the DBMS is concerned, it's still a single value.
If you want more than one value associated with a record, you shouldn't be storing it as a comma-separated value within a single field, you should store it in another table and join it. That way the data remains structured and you can use it as part of a query.


You need to treat the comma-delimited hide_from_publishers column as a string. You can use the LOCATE function to determine if your value exists in the string.
Note that I've added leading and trailing commas to both strings so that a search for "3" doesn't accidentally match "13".
select ads.*
from advertisement_urls ads
where ad_pool_id = 5
and status = 1
and ads.id = 23
and locate(',3,', ','+hide_from_publishers+',') = 0
order by rank desc


You need to split the string of values into separate values. See this SO question...
Can Mysql Split a column?
As well as the supplied example...
http://blog.fedecarg.com/2009/02/22/mysql-split-string-function/


Here is another SO question:
MySQL query finding values in a comma separated string
And the suggested solution:
http://dev.mysql.com/doc/refman/5.0/en/string-functions.html#function_find-in-set

Related

How to get value string with regexp in bigquery

Hi i have string in BigQuery column like this
cancellation_amount: 602000
after_cancellation_transaction_amount: 144500
refund_time: '2022-07-31T06:05:55.215203Z'
cancellation_amount: 144500
after_cancellation_transaction_amount: 0
refund_time: '2022-08-01T01:22:45.94919Z'
i already using this logic to get cancellation_amount
regexp_extract(file,r'.*cancellation_amount:\s*([^\n\r]*)')
but the output only amount 602000, i need the output 602000 and 144500 become different column
Appreciate for helping

If your lines in the input (which will eventually become columns) are fixed you can use multiple regexp_extracts to get all the values.
SELECT
regexp_extract(file,r'cancellation_amount:\s*([^\n\r]*)') as cancellation_amount
regexp_extract(file,r'. after_cancellation_transaction_amount:\s*([^\n\r]*)') as after_cancellation_transaction_amount
FROM table_name
One issue I found with your regex expression is that .*cancellation_amount won't match after_cancellation_transaction_amount.
There is also a function called regexp_extract_all which returns all the matches as an array which you can later explode into columns, but if you have finite values separating them out in different columns would be a easier.

How to retrieve the required string in SQL having a variable length parameter

Here is my problem statement:
I have single column table having the data like as :
ROW-1>> 7302-2210177000-XXXX-XXXXXX-XXX-XXXXXXXXXX-XXXXXX-XXXXXX-U-XXXXXXXXX-XXXXXX
ROW-2>> 0311-1130101-XXXX-000000-XXX-XXXXXXXXXX-XXXXXX-XXXXXX-X-XXXXXXXXX-WIPXXX
Here i want to separate these values from '-' and load into a new table. There are 11 segments in this string separated by '-', therefore, 11 columns. The problem is:
A. The length of these values are changing, however, i have to keep it as the length of these values in the standard format or the length which it has
e.g 7302- (should have four values, if the value less then that then keep that value eg. 73 then it should populate 73.
Therefore, i have to separate as well as mentation the integrity. The code which i am writing is :
select
SUBSTR(PROFILE_ID,1,(case when length(instr(PROFILE_ID,'-')<>4) THEN (instr(PROFILE_ID,'-') else SUBSTR(PROFILE_ID,1,4) end)
)AS [RQUIRED_COLUMN_NAME]
from [TABLE_NAME];
getting right parenthesis error
Please help.

I used the regex_substr SQL function to solve the above issue. Here below is an example:
select regex_substr('7302-2210177000-XXXX-XXXXXX-XXX-XXXXXXXXXX-XXXXXX-XXXXXX-U-XXXXXXXXX-XXXXXX ROW-2>> 0311-1130101-XXXX-000000-XXX-XXXXXXXXXX-XXXXXX-XXXXXX-X-XXXXXXXXX-WIPXXX',[^-]+,1,1);
Output is: 7302 --which is the 1st segment of the string
Similarly, the send string segment which is separated by "-" in the string can be obtained by just replacing the 1 with 2 in the above query at the end.
Example : select regex_substr('7302-2210177000-XXXX-XXXXXX-XXX-XXXXXXXXXX-XXXXXX-XXXXXX-U-XXXXXXXXX-XXXXXX ROW-2>> 0311-1130101-XXXX-000000-XXX-XXXXXXXXXX-XXXXXX-XXXXXX-X-XXXXXXXXX-WIPXXX',[^-]+,1,2);
output: 2210177000 which is the 2nd segment of the string

SQL full text search behavior on numeric values

I have a table with about 200 million records. One of the columns is defined as varchar(100) and it's included in a full text index. Most of the values are numeric. Only few are not numeric.
The problem is that it's not working well. For example if a row contains the value '123456789' and i look for '567', it's not returning this row. It will only return rows where the value is exactly '567'.
What am I doing wrong?
sql server 2012.
Thanks.

Full text search doesn't support leading wildcards
In my setup, these return the same
SELECT *
FROM [dbo].[somelogtable]
where CONTAINS (logmessage, N'28400')
SELECT *
FROM [dbo].[somelogtable]
where CONTAINS (logmessage, N'"2840*"')
This gives zero rows
SELECT *
FROM [dbo].[somelogtable]
where CONTAINS (logmessage, N'"*840*"')
You'll have to use LIKE or some fancy trigram approach

The problem is probably that you are using a wrong tool since Full-text queries perform linguistic searches and it seems like you want to use simple "like" condition.
If you want to get a solution to your needs then you can post DDL+DML+'desired result'

You can do this:
....your_query.... LIKE '567%' ;
This will return all the rows that have a number 567 in the beginning, end or in between somewhere.

99% You're missing % after and before the string you search in the LIKE clause.
es:
SELECT * FROM t WHERE att LIKE '66'
is the same as as using WHERE att = '66'
if you write:
SELECT * FROM t WHERE att LIKE '%66%'
will return you all the lines containing 2 'sixes' one after other

MS Access Expression to Find Records Where the Value to the Left of a Comma is Greater than Zero

I have some records in a column that contain IDs and some of these records contain multiple IDs separated by commas. Additionally there are some records where I have ",3" and ",2" when they should simply be "3" and "2". I do not have write privileges in this DB so updating those records is not an option.
I am trying to write a query that returns records that have a comma where the value to the left of any comma in the record is greater than 0 e.g. "2,3", "2,3,12" etc but NOT ",3" or ",2".
What would this expression look like in MS Access?
Thanks in advance.

If you want to remove the starting comma from the records when you return them, you can do so using a simple query:
SELECT IIF(MyField LIKE ",*", Right(MyField, Len(MyField)-1), MyField)
FROM MyTable

To answer your original question, you could simply use Val:
SELECT * FROM YourTable WHERE Val([YourField]) > 0

I would simply use:
select t.*
from t
where val not like ",*";
This doesn't handle the 0 part, but you don't give any examples in your answer. Perhaps this answers that part:
select t.*
from t
where val not like ",*" and val not like "*0,*";

Natural or Human Sort order

I have been working on this on for months. I just cannot get the natural (True alpha-numeric) results. I am shocked that I cannot get them as I have been able to in RPG since 1992 with EBCDIC.
I am looking for any solution in SQL, VBS or simple excel or access. Here is the data I have:
299-8,
3410L-87,
3410L-88,
420-A20,
420-A21,
420A-40,
4357-3,
AN3H10A,
K117GM-8,
K129-1,
K129-15,
K271B-200L,
K271B-38L,
K271D-200EL,
KD1051,
KD1062,
KD1092,
KD1108,
KD1108,
M8000-3,
MS24665-1,
SK271B-200L,
SAYA4008
The order I am looking for is the true alpha-numeric order as below:
AN3H10A,
KD1051,
KD1062,
KD1092,
KD1108,
KD1108,
K117GM-8,
K129-1,
K129-15,
MS24665-1,
M8000-3,
SAYA4008,
SK271B-200L
The inventory is 7800 records so I have had some problems with processing power as well.
Any help would be appreciated.
Jeff

In native Excel, you can add multiple sorting columns to return the ASCII code for each character, but if the character is a number, then add a large number to the code (e.g 1000).
Then sort on each of the helper columns, including the first column in the table, but not in the sort.
The formula:
=IFERROR(CODE(MID($A1,COLUMNS($A:A),1))+AND(CODE(MID($A1,COLUMNS($A:A),1))>=48,CODE(MID($A1,COLUMNS($A:A),1))<=57)*1000,"")
The Sort dialog:
The results:
You can implement a similar algorithm using VBA, and probably SQL also. I dunno about VBS or Access.

You could try using format for left padding the string in order by
select column
from my_table
order by Format(column, "0000000000")

Add a sorting column:
, iif (left(fieldname, 1) between '0' and '9', 1, 0) sortField
etc
order by sortField, FieldName

Lets say you have your data in column "A". If you put this formula in column "B" =IFERROR(IF(LEFT(A1,1)+1>0,"ZZZZZZZ "&A1,A1),A1), it will automatically add Z in front of all numerical values, so that they will naturally appear after all alphabetical values when you sort A-Z. later you can find&replace that funny ZZZZZZ string...

There a number of approaches, but likely the least amount of work is to build two columns that split out the delimiter (-) in this case.
You then “pad” the results (spaces, or 0) right justified, and then sort on the two columns.
So in the query builder we have this:
SELECT Field1,
Format(
Mid(field1,1,IIf(InStr(field1,"-")=0,50,InStr(field1,"-")-1)),
">##########") AS Expr1,
Format(
Mid(field1,IIf(InStr(field1,"-")=0,99,InStr(field1,"-")+1)),
">##########") AS Expr2
FROM Data
When we run the above raw query we get this:
So now in the query builder, simply sort on the first derived column, and then sort on the 2nd derived column.
Eg this:
Run the query, and we get this result:
Edit:
Looking at you desired results, it looks like above sort is wrong. We have to RIGHT just and pad with 0’s.
So this 2nd try:
SELECT Field1,
Left(Mid(field1,1,IIf(InStr(field1,"-")=0,30,InStr(field1,"-")-1))
& String(30,"0"),30) AS Expr1,
Left(Mid(field1,IIf(InStr(field1,"-")=0,99,InStr(field1,"-")+1))
& String(30,"0"),30) AS Expr2
FROM Data
The results are thus this:
Given your small table size, then the above query should perform quite well.