Can you please help me to form a sql query (MySQL) that allows me to sort the results by order ascending / descending (A- Z / Z - A) and putting in the last lines that have no value.
Less error prone than altering the column of order is:
SELECT
columnOfInterest
FROM
theTable
ORDER BY
CASE WHEN columnOfInterest IS NULL THEN 1 ELSE 0 END CASE
, columnOfInterest
select stateName
from stateTable
order by coalesce(stateName, 'ZZZZZZZZZZZZZZZZZZZZZZZZZ')
You're looking for the 'order by' statement tacked on to your select query.
http://dev.mysql.com/doc/refman/5.0/en/sorting-rows.html
SELECT HEADER FROM TABLE ORDER BY ELEMENTTOORDER
Related
This is the original table:
I have 2 different query and I want to make 1 query for these:
SELECT *
FROM SAMPLE
WHERE ORDER_PRIORITY<40
ORDER BY FS_GENERATE_DATE IS NOT NULL, FS_GENERATE_DATE,ORDER_PRIORITY,CREATE_ID,CR_DATE,ORDER_QTY;
second:
SELECT *
FROM SAMPLE
WHERE ORDER_PRIORITY>=40
ORDER BY FS_GENERATE_DATE IS NOT NULL, FS_GENERATE_DATE,ORDER_PRIORITY,CREATE_ID,CR_DATE,ORDER_QTY;
I need the next result in only 1 query:
if the order_priority<40 than the order will be the first according to the order by
but if order_priority>=40 than these data will be after the lower priority (first conditional /op<40/).
Result:
You can add this to your order by clause:
case when ORDER_PRIORITY<40 then 0 else 1 end
The final query will be:
SELECT
*
FROM SAMPLE
WHERE ORDER_PRIORITY>=40
ORDER BY
case when ORDER_PRIORITY<40 then 0 else 1 end,
FS_GENERATE_DATE IS NOT NULL, FS_GENERATE_DATE,ORDER_PRIORITY,CREATE_ID,CR_DATE,ORDER_QTY;
You are clearly using a database where booleans are allowed in the ORDER BY. So, you can just use:
SELECT S.*
FROM SAMPLE S
ORDER BY (ORDER_PRIORITY < 40) DESC,
FS_GENERATE_DATE IS NOT NULL,
FS_GENERATE_DATE,
ORDER_PRIORITY,
CREATE_ID, CR_DATE, ORDER_QTY;
I have a query like this:
Select ShipViaCode
from tbl_VW_Epicor_ShipVia_Master
and I am getting this output:
AIR
CHRT
COMP
CO20
Co40
CSPU
FEDX
NFRT
ser
TRCK
I want to get my first row as 'TRCK', so how can I re-write the query?
Select ShipViaCode from tbl_VW_Epicor_ShipVia_Master order by ShipViaCode desc;
Cheers :)
Select ShipViaCode from tbl_VW_Epicor_ShipVia_Master
order by (case when ShipViaCode = 'TRCK' then 0 else 1 end)
You can sort you result by that column but in descending order,
Select ShipViaCode from tbl_VW_Epicor_ShipVia_Master order by ShipViaCode desc
I was using a simple sql query and getting an ordered list, but when I changed some of the values in the column I'm sorting by, those rows were no longer being sorted correctly.
select distinct u.Email,
case
when l.region_id is null then 'EU'
else l.region_id
end
as Location
from TB_User u
left join cat..location l on l.location=u.Location
where u.Username in (....)
order by l.region_id
I have about 5 rows that returned null for their region_id so they would be at the top of the result set. When I added the case and replaced their value, they still remain at the top. Is there anyway to make these rows sort according to their given value?
You can use CASE also in the ORDER BY. But in this case it seems that you instead want to order by the column which uses the CASE.
ORDER BY Location
If you instead want the null-regions at the bottom:
ORDER BY CASE WHEN l.region_id is null THEN 0 ELSE 1 END DESC,
Location ASC
If your rdbms doesn't support this (like SQL-Server does) you have to repeat it:
ORDER BY CASE WHEN l.region_id IS NULL THEN 'EU' ELSE l.region_id END ASC
You just order by the column value, which is null.
If you want to order by the case statement, just copy it in the order by clause:
order by
case
when l.region_id is null then 'EU'
else l.region_id end
If you are using SQL, try within the SELECT statement, use:
ISNULL(l.region_id, 'EU') AS Location
and then
ORDER BY 2
This will make your query:
SELECT DISTINCT u.Email, ISNULL(l.region_id, 'EU') AS Location
FROM TB_User u
LEFT JOIN cat..location l ON l.location=u.Location
WHERE u.Username in (....)
ORDER BY 2
How can the below query be adjusted to return always the member with MemberID = 'xxx' as the first row
SELECT * FROM Members
select * from Members
order by case when MemberID = XXX then 0 else 1 end
This should work and it will also allow you to order the remaining items by MemberID (Assuming xxx=12 in this example)
SELECT *
FROM Members
ORDER BY CASE WHEN MemberID=12 THEN NULL ELSE isnull(MemberID,0) END
If the memberID column can't contain nulls, you can get away with this which might perform slightly better.
SELECT *
FROM Members
ORDER BY CASE WHEN MemberID=12 THEN NULL ELSE MemberID END
SELECT
CASE WHEN MemberID = 'xxx' AS 1 ELSE 0 END CASE AS magic,
*
FROM Members
ORDER BY magic DESC
The syntax might vary depending on yr db, but I hope you get the idea.
SELECT * FROM `Members` WHERE `MemberID` = '[ID]' LIMIT 1 UNION SELECT * FROM `Members`
This should work. Tested on my database instance. Chosen ID is always first.
A more robust solution, if you have more than one record that has to be floated to the top, or if you have a specific order for multiple records, is to add a ResultsOrder column to your table, or even another table MemberOrder(memberid, resultorder). Fill resultorder with big numbers and ...
Select m.*
From Members m
Left Join MemberOrder mo on m.MemberID=mo.MemberID
Order by coalesce(mo.resultorder, 0) DESC
try this:
SELECT * FROM Members
ORDER BY IF(x.MemberId = XXX, -1, ABS(x.MemberId))
Let's say I have this MySQL query:
SELECT * FROM A WHERE x='abc' OR y=0;
How can I prioritize the rows so that cases where x='abc' are ordered FIRST? If y=0 but x!='abc', I want those rows to come after cases where x='abc'.
Can this be accomplished with a simple ORDER BY clause?
Thanks!
SELECT *
FROM A
WHERE x='abc'
OR y=0
order by case when x='abc' then 0 else 1 end;
I would do it with a case statement:
SELECT *,
CASE WHEN column_one = 0 THEN 0
WHEN column_two = 'ADMIN' THEN 1
END AS multi_column
FROM sometable
ORDER BY multi_column;
ORDER BY FIELD(x,'abc',x)