antlr grammar for [Foo]-[Bar]-[Baz][X]-[Y][Z] - antlr

I am trying to define a grammar that allows for
[Foo]-[Bar]-[Baz][X]-[Y][Z]
I want to parse this as one set.
I currently have
grammar Sample;
items : (item association? item?)*;
item : LBRACK ID RBRACK;
association : ASSOCIATION;
RBRACK : ']';
LBRACK : '[';
ASSOCIATION : '-';
ID : ('a'..'z' | 'A'..'Z' | '_')*;
But this gives an error
warning(200): Sample.g:3:30: Decision can match input such as
"LBRACK ID RBRACK" using multiple alternatives: 1, 2
As a result, alternative(s) 2 were disabled for that input
And as a diagram I get
And I get this railroad diagram
How can I fix this?

Given the input [Foo]-[Bar]-[Baz][X]-[Y][Z], the following:
chunk : items+ EOF;
items : item (ASSOCIATION item)* ;
item : '[' ID ']' ;
RBRACK : ']';
LBRACK : '[';
ASSOCIATION : '-';
ID : ('a'..'z' | 'A'..'Z' | '_')*;
SPACE : (' ' | '\t' | '\r' | '\n'){skip();};
produces the following parse tree:

Try something like
items : ( '-'? item )* ;
item : '[' ID ']' ;
ID : ('a'..'z'|'A'..'Z'|'_') ;
which will allow a leading '-' or empty input
or
items : item? ( '-'? item )* ;
item : '[' ID ']' ;
ID : ('a'..'z'|'A'..'Z'|'_') ;
which won't allow a leading '-', but also allows empty input

You could try something like this:
ID : ('a'..'z'|'A'..'Z'|'_')* ;
item : '[' ID ']' ;
dependency : item ( '-' item )+ ;
list : ( item | dependency )+
;

Related

"The following sets of rules are mutually left-recursive"

I have tried to write a grammar to recognize expressions like:
(A + MAX(B) ) / ( C - AVERAGE(A) )
IF( A > AVERAGE(A), 0, 1 )
X / (MAX(X)
Unfortunately antlr3 fails with these errors:
error(210): The following sets of rules are mutually left-recursive [unaryExpression, additiveExpression, primaryExpression, formula, multiplicativeExpression]
error(211): DerivedKeywords.g:110:13: [fatal] rule booleanTerm has non-LL(*) decision due to recursive rule invocations reachable from alts 1,2. Resolve by left-factoring or using syntactic predicates or using backtrack=true option.
error(206): DerivedKeywords.g:110:13: Alternative 1: after matching input such as decision cannot predict what comes next due to recursion overflow to additiveExpression from formula
I have spent some hours trying to fix these, it would be great if anyone could at least help me fix the first problem. Thanks
Code:
grammar DerivedKeywords;
options {
output=AST;
//backtrack=true;
}
WS : ( ' ' | '\t' | '\n' | '\r' )
{ skip(); }
;
//for numbers
DIGIT
: '0'..'9'
;
//for both integer and real number
NUMBER
: (DIGIT)+ ( '.' (DIGIT)+ )?( ('E'|'e')('+'|'-')?(DIGIT)+ )?
;
// Boolean operatos
AND : 'AND';
OR : 'OR';
NOT : 'NOT';
EQ : '=';
NEQ : '!=';
GT : '>';
LT : '<';
GTE : '>=';
LTE : '<=';
COMMA : ',';
// Token for Functions
IF : 'IF';
MAX : 'MAX';
MIN : 'MIN';
AVERAGE : 'AVERAGE';
VARIABLE : 'A'..'Z' ('A'..'Z' | '0'..'9')*
;
// OPERATORS
LPAREN : '(' ;
RPAREN : ')' ;
DIV : '/' ;
PLUS : '+' ;
MINUS : '-' ;
STAR : '*' ;
expression : formula;
formula
: functionExpression
| additiveExpression
| LPAREN! a=formula RPAREN! // First Problem
;
additiveExpression
: a=multiplicativeExpression ( (MINUS^ | PLUS^ ) b=multiplicativeExpression )*
;
multiplicativeExpression
: a=unaryExpression ( (STAR^ | DIV^ ) b=unaryExpression )*
;
unaryExpression
: MINUS^ u=unaryExpression
| primaryExpression
;
functionExpression
: f=functionOperator LPAREN e=formula RPAREN
| IF LPAREN b=booleanExpression COMMA p=formula COMMA s=formula RPAREN
;
functionOperator :
MAX | MIN | AVERAGE;
primaryExpression
: NUMBER
// Used for scientific numbers
| DIGIT
| VARIABLE
| formula
;
// Boolean stuff
booleanExpression
: orExpression;
orExpression : a=andExpression (OR^ b=andExpression )*
;
andExpression
: a=notExpression (AND^ b=notExpression )*
;
notExpression
: NOT^ t=booleanTerm
| booleanTerm
;
booleanOperator :
GT | LT | EQ | GTE | LTE | NEQ;
booleanTerm : a=formula op=booleanOperator b=formula
| LPAREN! booleanTerm RPAREN! // Second problem
;
error(210): The following sets of rules are mutually left-recursive [unaryExpression, additiveExpression, primaryExpression, formula, multiplicativeExpression]
- this means that if the parser enters unaryExpression rule, it has the possibility to match additiveExpression, primaryExpression, formula, multiplicativeExpression and unaryExpression again without ever consuming a single token from input - so it cannot decide whether to use those rules or not, because even if it uses the rules, the input will be the same.
You're probably trying to allow subexpressions in expressions by this sequence of rules - you need to make sure that path will consume the left parenthesis of the subexpression. Probably the formula alternative in primaryExpression should be changed to LPAREN formula RPAREN, and the rest of grammar be adjusted accordingly.

ANTLR4 Token is not recognized when substituted

I try to modify the grammar of the sqlite syntax (I'm interested in a variant of the where clause only) and I'm keep having a weird error when substituting AND to it's own token.
grammar wtfql;
/*
SQLite understands the following binary operators, in order from highest to
lowest precedence:
||
* / %
+ -
<< >> & |
< <= > >=
= != <> IS IS NOT IN LIKE GLOB MATCH REGEXP
AND
OR
*/
start : expr EOF?;
expr
: literal_value
//BIND_PARAMETER
| ( table_name '.' )? column_name
| unary_operator expr
| expr '||' expr
| expr ( '*' | '/' | '%' ) expr
| expr ( '+' | '-' ) expr
| expr ( '<' | '<=' | '>' | '>=' ) expr
| expr ( '=' | '<>' | K_IN ) expr
| expr K_AND expr
| expr K_OR expr
| function_name '(' ( expr ( ',' expr )* )? ')'
| '(' expr ')'
| expr K_NOT expr
| expr ( K_NOT K_NULL )
| expr K_NOT? K_IN ( '(' ( expr ( ',' expr )* ) ')' )
;
unary_operator
: '-'
| '+'
| K_NOT
;
literal_value
: NUMERIC_LITERAL
| STRING_LITERAL
| K_NULL
;
function_name
: IDENTIFIER
;
table_name
: any_name
;
column_name
: any_name
;
any_name
: IDENTIFIER
| keyword
// | '(' any_name ')'
;
keyword
: K_AND
| K_NOT
| K_NULL
| K_IN
| K_OR
;
IDENTIFIER
: [a-zA-Z_] [a-zA-Z_0-9]* // TODO check: needs more chars in set
;
NUMERIC_LITERAL
: DIGIT+ ( '.' DIGIT* )? ( E [-+]? DIGIT+ )?
| '.' DIGIT+ ( E [-+]? DIGIT+ )?
;
STRING_LITERAL
: '\"' ( ~'\"' | '\"\"' )* '\"'
;
SPACES
: [ \u000B\t\r\n] -> channel(HIDDEN)
;
DOT : '.';
OPEN_PAR : '(';
CLOSE_PAR : ')';
COMMA : ',';
STAR : '*';
PLUS : '+';
MINUS : '-';
TILDE : '~';
DIV : '/';
MOD : '%';
AMP : '&';
PIPE : '|';
LT : '<';
LT_EQ : '<=';
GT : '>';
GT_EQ : '>=';
EQ : '=';
NOT_EQ2 : '<>';
K_AND : A N D;
K_NOT : N O T;
K_NULL : N U L L;
K_OR : O R;
K_IN : I N;
fragment DIGIT : [0-9];
fragment A : [aA];
fragment B : [bB];
fragment C : [cC];
fragment D : [dD];
fragment E : [eE];
fragment F : [fF];
fragment G : [gG];
fragment H : [hH];
fragment I : [iI];
fragment J : [jJ];
fragment K : [kK];
fragment L : [lL];
fragment M : [mM];
fragment N : [nN];
fragment O : [oO];
fragment P : [pP];
fragment Q : [qQ];
fragment R : [rR];
fragment S : [sS];
fragment T : [tT];
fragment U : [uU];
fragment V : [vV];
fragment W : [wW];
fragment X : [xX];
fragment Y : [yY];
fragment Z : [zZ];
writing
| expr K_AND expr
with the input
field1=1 and field2 = 2
results in
line 1:8 mismatched input 'and' expecting {<EOF>, '||', '*', '+', '-', '/', '%', '<', '<=', '>', '>=', '=', '<>', K_AND, K_NOT, K_OR, K_IN}
while
| expr 'and' expr
works like a charm:
$ antlr4 wtfql.g4 && javac -classpath /usr/local/Cellar/antlr/4.4/antlr-4.4-complete.jar wtfql*.java && cat test.txt | grun wtfql start -tree -gui
(start (expr (expr (expr (column_name (any_name feld1))) = (expr (literal_value 1))) and (expr (expr (column_name (any_name feld2))) = (expr (literal_value 2)))) <EOF>)
What am I missing?
I presume "and" is an IDENTIFIER since the rule for IDENTIFIER comes before the rule for AND and thus wins.
If you write 'and' in the parser rule this implicitly creates a token (not AND!) which comes before IDENTIFIER and thus wins.
Rule of thumb: More specific lexer rules first. Don't create new lexer tokens implicitly in parser rules.
If you check the token type, you'll get a clue what's going on.

Trying to resolve left-recursion trying to build Parser with ANTLR

I’m currently trying to build a parser for the language Oberon using Antlr and Ecplise.
This is what I have got so far:
grammar oberon;
options
{
language = Java;
//backtrack = true;
output = AST;
}
#parser::header {package dhbw.Oberon;}
#lexer::header {package dhbw.Oberon; }
T_ARRAY : 'ARRAY' ;
T_BEGIN : 'BEGIN';
T_CASE : 'CASE' ;
T_CONST : 'CONST' ;
T_DO : 'DO' ;
T_ELSE : 'ELSE' ;
T_ELSIF : 'ELSIF' ;
T_END : 'END' ;
T_EXIT : 'EXIT' ;
T_IF : 'IF' ;
T_IMPORT : 'IMPORT' ;
T_LOOP : 'LOOP' ;
T_MODULE : 'MODULE' ;
T_NIL : 'NIL' ;
T_OF : 'OF' ;
T_POINTER : 'POINTER' ;
T_PROCEDURE : 'PROCEDURE' ;
T_RECORD : 'RECORD' ;
T_REPEAT : 'REPEAT' ;
T_RETURN : 'RETURN';
T_THEN : 'THEN' ;
T_TO : 'TO' ;
T_TYPE : 'TYPE' ;
T_UNTIL : 'UNTIL' ;
T_VAR : 'VAR' ;
T_WHILE : 'WHILE' ;
T_WITH : 'WITH' ;
module : T_MODULE ID SEMI importlist? declarationsequence?
(T_BEGIN statementsequence)? T_END ID PERIOD ;
importlist : T_IMPORT importitem (COMMA importitem)* SEMI ;
importitem : ID (ASSIGN ID)? ;
declarationsequence :
( T_CONST (constantdeclaration SEMI)*
| T_TYPE (typedeclaration SEMI)*
| T_VAR (variabledeclaration SEMI)*)
(proceduredeclaration SEMI | forwarddeclaration SEMI)*
;
constantdeclaration: identifierdef EQUAL expression ;
identifierdef: ID MULT? ;
expression: simpleexpression (relation simpleexpression)? ;
simpleexpression : (PLUS|MINUS)? term (addoperator term)* ;
term: factor (muloperator factor)* ;
factor: number
| stringliteral
| T_NIL
| set
| designator '(' explist? ')'
;
number: INT | HEX ; // TODO add real
stringliteral : '"' ( ~('\\'|'"') )* '"' ;
set: '{' elementlist? '}' ;
elementlist: element (COMMA element)* ;
element: expression (RANGESEP expression)? ;
designator: qualidentifier
('.' ID
| '[' explist ']'
| '(' qualidentifier ')'
| UPCHAR )+
;
explist: expression (COMMA expression)* ;
actualparameters: '(' explist? ')' ;
muloperator: MULT | DIV | MOD | ET ;
addoperator: PLUS | MINUS | OR ;
relation: EQUAL ; // TODO
typedeclaration: ID EQUAL type ;
type: qualidentifier
| arraytype
| recordtype
| pointertype
| proceduretype
;
qualidentifier: (ID '.')* ID ;
arraytype: T_ARRAY expression (',' expression) T_OF type;
recordtype: T_RECORD ('(' qualidentifier ')')? fieldlistsequence T_END ;
fieldlistsequence: fieldlist (SEMI fieldlist) ;
fieldlist: (identifierlist COLON type)? ;
identifierlist: identifierdef (COMMA identifierdef)* ;
pointertype: T_POINTER T_TO type ;
proceduretype: T_PROCEDURE formalparameters? ;
variabledeclaration: identifierlist COLON type ;
proceduredeclaration: procedureheading SEMI procedurebody ID ;
procedureheading: T_PROCEDURE MULT? identifierdef formalparameters? ;
formalparameters: '(' params? ')' (COLON qualidentifier)? ;
params: fpsection (SEMI fpsection)* ;
fpsection: T_VAR? idlist COLON formaltype ;
idlist: ID (COMMA ID)* ;
formaltype: (T_ARRAY T_OF)* (qualidentifier | proceduretype);
procedurebody: declarationsequence (T_BEGIN statementsequence)? T_END ;
forwarddeclaration: T_PROCEDURE UPCHAR? ID MULT? formalparameters? ;
statementsequence: statement (SEMI statement)* ;
statement : assignment
| procedurecall
| ifstatement
| casestatement
| whilestatement
| repeatstatement
| loopstatement
| withstatement
| T_EXIT
| T_RETURN expression?
;
assignment: designator ASSIGN expression ;
procedurecall: designator actualparameters? ;
ifstatement: T_IF expression T_THEN statementsequence
(T_ELSIF expression T_THEN statementsequence)*
(T_ELSE statementsequence)? T_END ;
casestatement: T_CASE expression T_OF caseitem ('|' caseitem)*
(T_ELSE statementsequence)? T_END ;
caseitem: caselabellist COLON statementsequence ;
caselabellist: caselabels (COMMA caselabels)* ;
caselabels: expression (RANGESEP expression)? ;
whilestatement: T_WHILE expression T_DO statementsequence T_END ;
repeatstatement: T_REPEAT statementsequence T_UNTIL expression ;
loopstatement: T_LOOP statementsequence T_END ;
withstatement: T_WITH qualidentifier COLON qualidentifier T_DO statementsequence T_END ;
ID : ('a'..'z'|'A'..'Z')('a'..'z'|'A'..'Z'|'_'|'0'..'9')* ;
fragment DIGIT : '0'..'9' ;
INT : ('-')?DIGIT+ ;
fragment HEXDIGIT : '0'..'9'|'A'..'F' ;
HEX : HEXDIGIT+ 'H' ;
ASSIGN : ':=' ;
COLON : ':' ;
COMMA : ',' ;
DIV : '/' ;
EQUAL : '=' ;
ET : '&' ;
MINUS : '-' ;
MOD : '%' ;
MULT : '*' ;
OR : '|' ;
PERIOD : '.' ;
PLUS : '+' ;
RANGESEP : '..' ;
SEMI : ';' ;
UPCHAR : '^' ;
WS : ( ' ' | '\t' | '\r' | '\n'){skip();};
My problem is when I check the grammar I get the following error and just can’t find an appropriate way to fix this:
rule statement has non-LL(*) decision
due to recursive rule invocations reachable from alts 1,2.
Resolve by left-factoring or using syntactic predicates
or using backtrack=true option.
|---> statement : assignment
Also I have the problem with declarationsequence and simpleexpression.
When I use options { … backtrack = true; … } it at least compiles, but obviously doesn’t work right anymore when I run a test-file, but I can’t find a way to resolve the left-recursion on my own (or maybe I’m just too blind at the moment because I’ve looked at this for far too long now). Any ideas how I could change the lines where the errors occurs to make it work?
EDIT
I could fix one of the three mistakes. statement works now. The problem was that assignment and procedurecall both started with designator.
statement : procedureassignmentcall
| ifstatement
| casestatement
| whilestatement
| repeatstatement
| loopstatement
| withstatement
| T_EXIT
| T_RETURN expression?
;
procedureassignmentcall : (designator ASSIGN)=> assignment | procedurecall;
assignment: designator ASSIGN expression ;
procedurecall: designator actualparameters? ;

Small grammar that doesn't work; what am I missing (antlr4)

I have the following grammar. It's supposed to accept the string shown in the comments in the header. It does not. I must be missing something fundamental. Hints on how to debug this would also be appreciated.
/*
Should accept:
b
a:b
a:b^10
b^10
Should not accept:
:b
a:
a:^10
*/
grammar test;
filter:
boostedField EOF
;
boostedField
: qualifiedField (CARET NUMBER)?
;
qualifiedField
: (FIELDNAME COLON)? term
;
term
: TERM
;
FIELDNAME: (LETTER | UNDERSCORE) (ALPHANUM | UNDERSCORE)* ;
NUMBER : NUM_CHAR+ ('.' NUM_CHAR+)? ;
COLON : ':' ;
CARET : '^' ;
WS : (' ' | '\t' | '\n' | '\r' | '\u3000') -> skip ;
UNDERSCORE: '_' ;
// a term may not have a colon or a caret (unless escaped)
TERM : TERM_START_CHAR TERM_CHAR*;
fragment TERM_START_CHAR
: ~( ' ' | '\t' | '\n' | '\r' | '\u3000' | ':' | '^' ) ;
fragment TERM_CHAR : (TERM_START_CHAR | ESCAPED_CHAR) ;
fragment ESCAPED_CHAR : ( '\\' . ) ;
fragment NUM_CHAR: '0'..'9';
fragment LETTER: 'a'..'z' | 'A'..'Z' ;
fragment ALPHANUM: LETTER | NUM_CHAR;

ANTLR grammar error

I'm trying to built C-- compiler using ANTLR 3.4.
Full set of the grammar listed here,
program : (vardeclaration | fundeclaration)* ;
vardeclaration : INT ID (OPENSQ NUM CLOSESQ)? SEMICOL ;
fundeclaration : typespecifier ID OPENP params CLOSEP compoundstmt ;
typespecifier : INT | VOID ;
params : VOID | paramlist ;
paramlist : param (COMMA param)* ;
param : INT ID (OPENSQ CLOSESQ)? ;
compoundstmt : OPENCUR vardeclaration* statement* CLOSECUR ;
statementlist : statement* ;
statement : expressionstmt | compoundstmt | selectionstmt | iterationstmt | returnstmt;
expressionstmt : (expression)? SEMICOL;
selectionstmt : IF OPENP expression CLOSEP statement (options {greedy=true;}: ELSE statement)?;
iterationstmt : WHILE OPENP expression CLOSEP statement;
returnstmt : RETURN (expression)? SEMICOL;
expression : (var EQUAL expression) | sampleexpression;
var : ID ( OPENSQ expression CLOSESQ )? ;
sampleexpression: addexpr ( ( LOREQ | LESS | GRTR | GOREQ | EQUAL | NTEQL) addexpr)?;
addexpr : mulexpr ( ( PLUS | MINUS ) mulexpr)*;
mulexpr : factor ( ( MULTI | DIV ) factor )*;
factor : ( OPENP expression CLOSEP ) | var | call | NUM;
call : ID OPENP arglist? CLOSEP;
arglist : expression ( COMMA expression)*;
Used lexer rules as following,
ELSE : 'else' ;
IF : 'if' ;
INT : 'int' ;
RETURN : 'return' ;
VOID : 'void' ;
WHILE : 'while' ;
PLUS : '+' ;
MINUS : '-' ;
MULTI : '*' ;
DIV : '/' ;
LESS : '<' ;
LOREQ : '<=' ;
GRTR : '>' ;
GOREQ : '>=' ;
EQUAL : '==' ;
NTEQL : '!=' ;
ASSIGN : '=' ;
SEMICOL : ';' ;
COMMA : ',' ;
OPENP : '(' ;
CLOSEP : ')' ;
OPENSQ : '[' ;
CLOSESQ : ']' ;
OPENCUR : '{' ;
CLOSECUR: '}' ;
SCOMMENT: '/*' ;
ECOMMENT: '*/' ;
ID : ('a'..'z' | 'A'..'Z')+/*(' ')*/ ;
NUM : ('0'..'9')+ ;
WS : (' ' | '\t' | '\n' | '\r')+ {$channel = HIDDEN;};
COMMENT: '/*' .* '*/' {$channel = HIDDEN;};
But I try to save this it give me the error,
error(211): /CMinusMinus/src/CMinusMinus/CMinusMinus.g:33:13: [fatal] rule expression has non-LL(*) decision due to recursive rule invocations reachable from alts 1,2. Resolve by left-factoring or using syntactic predicates or using backtrack=true option.
|---> expression : (var EQUAL expression) | sampleexpression;
1 error
How can I resolve this problem?
As already mentioned: your grammar rule expression is ambiguous: both alternatives in that rule start, or can be, a var.
You need to "help" your parser a bit. If the parse can see a var followed by an EQUAL, it should choose alternative 1, else alternative 2. This can be done by using a syntactic predicate (the (var EQUAL)=> part in the rule below).
expression
: (var EQUAL)=> var EQUAL expression
| sampleexpression
;
More about predicates in this Q&A: What is a 'semantic predicate' in ANTLR?
The problem is this:
expression : (var EQUAL expression) | sampleexpression;
where you either start with var or sampleexpression. But sampleexpression can be reduced to var as well by doing sampleexpression->addExpr->MultExpr->Factor->var
So there is no way to find a k-length predicate for the compiler.
You can as suggested by the error message set backtrack=true to see whether this solves your problem, but it might lead not to the AST - parsetrees you would expect and might also be slow on special input conditions.
You could also try to refactor your grammar to avoid such recursions.