I have a MySql database that holds datetime in one field, in this format:
'2011-01-04 16:32:49'
How can I filter out results based on this datetime such that it shows results only from Today. basically, I only want to compare against the date part of the field.
Can I do something like this?
Select * from table where timestamp.date() = now().date
Use DATE:
SELECT * FROM table
WHERE DATE(timestamp) = DATE(now())
Another alternative that will be able to use the index on timestamp if you have one:
SELECT * FROM table
WHERE timestamp >= DATE(now())
AND timestamp < DATE(now()) + interval 1 day
Yes you can but the column that stores the dateTime field in your database simply needs to be referenced, you should not be calling a .date() function on it.
For mySQL, this would be:
Select * from table where DATEDIFF(NOW(),timestamp) = 0
This would give you only records in which the Date is today.
Select * from table where DATE_FORMAT(timestamp, '%Y-%m-%d') = DATE_FORMAT(NOW(), '%Y-%m-%d')
Related
The table has a created_date column which has big integer as time stamp values. One of the time stamp looks like this 1596007131121. How can I query this?
select count(*) from user where created_date: date >='2020-08-30';
I need to query this.
You can convert that to a proper timestamp using the to_timestamp() function:
select *
from the_table
where to_timestamp(created_date/1000::bigint) >= date '2020-08-30';
But I would highly recommend to convert that column to a proper timestamp column.
I think you want:
select '1970-01-01'::timestamp + (created_date / 1000) * interval '1 second'
If you want this in a where clause, then use:
where created_date >= extract(epoch from '2020-08-30') * 1000
This has the nice feature that you can use an index.
I'm using a SQL SELECT query to bring back all rows from a specific date.
The column I'm using is called TimeStamp (datetime)
(An example of data from this column = 01/02/2018 07:55:55)
What I would like is to return all rows from a specific date eg 24/06/2019
I have tried
SELECT top 20 TimeStamp
from Report
where TimeStamp = '02/01/2018 07:55:55'
which returns one row (which is correct as there is only one row containing this data)
If I then try
SELECT top 20 TimeStamp
from Report
where TimeStamp LIKE '02/01/2018%'
I get no results, I have also tried escaping the forward slashes
SELECT top 20 TimeStamp
from Report
where TimeStamp = '02\/01\/2018%'
Most databases support a string function called left(). If I assume that your "timestamp" is a string, then:
where left(timestamp, 10) = '01/02/2018'
However, it should be stored as a date or date/time. If so, then you can do:
where timestamp >= '2018-02-01' and
timestamp < '2018-02-02'
Note the use of standard formatted dates (YYYY-MM-DD). That is the way most databases implement date literals.
In SQL Server, you can also use:
where convert(date, timestamp) = '2018-02-01'
Both this and the previous version will use an index on timestamp, so both are reasonable solutions.
this should work
SELECT TimeStamp FROM report where convert(Date, TimeStamp) = '2019-06-24'
or select timestamp from report where timestamp between '2019-06-24' and '2019-06-25'. This will get you everything between 2019-06-24 00:00:00 and 2019-06-25 00:00:00 thus all records with date 2019-06-24
Convert timestamp value to date.
SELECT TimeStamp
FROM report
WHERE CAST(TimeStamp AS DATE) = '2019-06-24'
Is there a way in SQL to filter a query based on the date a specific record was added if I don't have a field that has the date it was created on.
Something like this:
Select * from Table where Table.recorddate = '2013-01-01'
I think that what you are trying to achieve is not possible. If it's really necessary, just add the field. It'd be easier for you that way.
Use UTC format:
SELECT * FROM Table WHERE recorddate = '2014-01-01'
Note that UTC is YYYY-MM-DD. So Today's date would be:
SELECT * FROM Table WHERE recorddate = '2014-05-19'
If your date field also includes a time stamp you can use a between:
SELECT * FROM Table
WHERE recorddate BETWEEN '2014-05-19 00:00:00' AND '2014-05-19 23:59:59'
Im trying to do a query where a TIMESTAMP field is = to a specific date but my query is not working:
The field is type TIMESTAMP(6) which I have only ever worked with DATE / DATETIME fields before. Here is example of a value stored here: 04-OCT-13 12.29.53.000000000 PM
Here is my SELECT statement:
SELECT * FROM SomeTable WHERE timestampField = TO_DATE('2013-10-04','yyyy-mm-dd')
I am retrieving no results and I am assuming it has to do with the fact that its not matching the TIME portion of the timestamp
If you want every record that occurs on a given day then this should work:
SELECT * FROM SomeTable
WHERE timestampField >= TO_TIMESTAMP( '2013-03-04', 'yyyy-mm-dd' )
AND timestampField < TO_TIMESTAMP( '2013-03-05', 'yyyy-mm-dd')
That will be likely to take advantage of an index on timestampField if it exists. Another way would be:
SELECT * FROM SomeTable
WHERE TRUNC(timestampField) = TO_DATE( '2013-03-04', 'yyyy-mm-dd' )
in which case you may want a function-based index on TRUNC(timestampField).
(Note that TRUNC applied to a TIMESTAMP returns a DATE.)
I'm trying to retrieve records from table by knowing the date in column contains date and time.
Suppose I have table called t1 which contains only two column name and date respectively.
The data stored in column date like this 8/3/2010 12:34:20 PM.
I want to retrieve this record by this query for example (note I don't put the time):
Select * From t1 Where date="8/3/2010"
This query give me nothing !
How can I retrieve date by knowing only date without the time?
DATE is a reserved keyword in Oracle, so I'm using column-name your_date instead.
If you have an index on your_date, I would use
WHERE your_date >= TO_DATE('2010-08-03', 'YYYY-MM-DD')
AND your_date < TO_DATE('2010-08-04', 'YYYY-MM-DD')
or BETWEEN:
WHERE your_date BETWEEN TO_DATE('2010-08-03', 'YYYY-MM-DD')
AND TO_DATE('2010-08-03 23:59:59', 'YYYY-MM-DD HH24:MI:SS')
If there is no index or if there are not too many records
WHERE TRUNC(your_date) = TO_DATE('2010-08-03', 'YYYY-MM-DD')
should be sufficient. TRUNC without parameter removes hours, minutes and seconds from a DATE.
If performance really matters, consider putting a Function Based Index on that column:
CREATE INDEX trunc_date_idx ON t1(TRUNC(your_date));
Personally, I usually go with:
select *
from t1
where date between trunc( :somedate ) -- 00:00:00
and trunc( :somedate ) + .99999 -- 23:59:59
Convert your date column to the correct format and compare:
SELECT * From my_table WHERE to_char(my_table.my_date_col,'MM/dd/yyyy') = '8/3/2010'
This part
to_char(my_table.my_date_col,'MM/dd/yyyy')
Will result in string '8/3/2010'
You could use the between function to get all records between 2010-08-03 00:00:00:000 AND 2010-08-03 23:59:59:000
trunc(my_date,'DD') will give you just the date and not the time in Oracle.
Simply use this one:
select * from t1 where to_date(date_column)='8/3/2010'
Try the following way.
Select * from t1 where date(col_name)="8/3/2010"