I'm using a SQL SELECT query to bring back all rows from a specific date.
The column I'm using is called TimeStamp (datetime)
(An example of data from this column = 01/02/2018 07:55:55)
What I would like is to return all rows from a specific date eg 24/06/2019
I have tried
SELECT top 20 TimeStamp
from Report
where TimeStamp = '02/01/2018 07:55:55'
which returns one row (which is correct as there is only one row containing this data)
If I then try
SELECT top 20 TimeStamp
from Report
where TimeStamp LIKE '02/01/2018%'
I get no results, I have also tried escaping the forward slashes
SELECT top 20 TimeStamp
from Report
where TimeStamp = '02\/01\/2018%'
Most databases support a string function called left(). If I assume that your "timestamp" is a string, then:
where left(timestamp, 10) = '01/02/2018'
However, it should be stored as a date or date/time. If so, then you can do:
where timestamp >= '2018-02-01' and
timestamp < '2018-02-02'
Note the use of standard formatted dates (YYYY-MM-DD). That is the way most databases implement date literals.
In SQL Server, you can also use:
where convert(date, timestamp) = '2018-02-01'
Both this and the previous version will use an index on timestamp, so both are reasonable solutions.
this should work
SELECT TimeStamp FROM report where convert(Date, TimeStamp) = '2019-06-24'
or select timestamp from report where timestamp between '2019-06-24' and '2019-06-25'. This will get you everything between 2019-06-24 00:00:00 and 2019-06-25 00:00:00 thus all records with date 2019-06-24
Convert timestamp value to date.
SELECT TimeStamp
FROM report
WHERE CAST(TimeStamp AS DATE) = '2019-06-24'
Related
sql table
here in the table above named carpooling contains a column name start_on which has date time as timestamp i have to write a query to select all the rows having date as 25-11-20 using to_char and to_date.
You write a timestamp literal like this:
timestamp '2020-11-25 00:00:00'
so the full filtering condition will be
where start_on >= timestamp '2020-11-25 00:00:00'
and start_on < timestamp '2020-11-26 00:00:00'
Note that dates and timestamps are different in Oracle, and dates include times down to the second (this is for historical reasons - originally there was only the date type, and timestamp was added much later).
Use the TRUNC function, along with date and interval literals:
SELECT *
FROM CARPOOLING
WHERE START_ON BETWEEN DATE '2020-11-25'
AND (DATE '2020-11-26' - INTERVAL '0.000001' SECOND)
You can simply use to_date, but it's recommended to remove the time when comparing the dates. Otherwise, rows having the same date, but a different time will not be selected. Removing the time can be done using TRUNC.
So you can do something like this:
SELECT * FROM carpooling
WHERE TRUNC(start_on) = TO_DATE('2020-11-25','yyyy.mm.dd');
If you don't want to check the 25th of November 2020, but another data, change the date to match your goal.
I'm querying a table to get some date, like so:
SELECT date - INTERVAL '10 day' AS date
FROM example_table
WHERE username = 'Bob'
LIMIT 1;
The date column in the example_table does not have a timestamp. All dates in the column are stored in the following manner:
YYYY-MM-DD
The query above will return a result like so:
2016-11-20 00:00:00.000000
It takes the date found, goes back 10 days, and returns that date. But I want it to return the date without adding the timestamp, like so:
2016-11-20
If I use INTERVAL it always seems to add a timestamp. Is there a way to only get the date?
Your query is fine (but can be simplified, as demonstrated by a_horse_with_no_name). What you are seeing is a display issue. You can format your date to a string in the relevant format using to_char():
SELECT to_char("date" - INTERVAL '10 day', 'yyyy-mm-dd') AS "date"
FROM example_table
WHERE username = 'Bob'
LIMIT 1;
Note: LIMIT without an ORDER BY does not make sense: if there is more than one record in the resultset, you actually get a random record out of them.
You can use the interval notation and convert back to a date:
SELECT (date - INTERVAL '10 day')::date AS date
You can subtract (or add) an integer from a date. That integer represents the number of days:
SELECT "date" - 10 AS "date"
FROM example_table
WHERE username = 'Bob'
LIMIT 1;
In my dataset, one column called timestamp was created with datatype as String.
It contains values like:
2018-05-30T12:56:27:487+0200
I want to construct a query where I can fetch all column from the dataset table based on the date in 'YYYY-MM-DD' format.
I want to use it in where clause with DATE Range between.
Can you guide?
Thank you.
convert String to Date
Below example for BigQuery Standard SQL
#standardSQL
WITH `project.dataset.table` AS (
SELECT '2018-05-30T12:56:27.487+0200' ts UNION ALL
SELECT '2018-05-30T01:56:27.487+0200'
)
SELECT ts AS ts_as_string,
PARSE_TIMESTAMP('%FT%H:%M:%E3S%z', ts) ts_as_timestamp,
DATE(PARSE_TIMESTAMP('%FT%H:%M:%E3S%z', ts)) ts_as_date
FROM `project.dataset.table`
with result
ts_as_string ts_as_timestamp ts_as_date
2018-05-30T12:56:27.487+0200 2018-05-30 10:56:27.487 UTC 2018-05-30
2018-05-30T01:56:27.487+0200 2018-05-29 23:56:27.487 UTC 2018-05-29
As you can see - first i am parsing timestamp out of the string - this is important part - this is where you can take timezone into account (see difference in dates in the result 2018-05-29 vs. 2018-05-29). Then you can get Date out of TIMESTAMP
I want to use it in where clause with DATE Range between.
So, now you can use below in your WHERE clause
WHERE DATE(PARSE_TIMESTAMP('%FT%H:%M:%E3S%z', ts)) BETWEEN date1 AND date2
Update
You can use below to avoid dealing with "wrong" format
PARSE_DATE('%F', SUBSTR(ts, 1, 10))
In case if you need to account for timezone - you can use below (which fix : to . before applying PARSE_TIMESTAMP)
DATE(PARSE_TIMESTAMP('%FT%H:%M:%E3S%z', FORMAT('%s.%s', SUBSTR(ts, 1, 19), SUBSTR(ts, 21, 8))))
If you want the date in the same timezone represented, then the simplest method is to use string operations and convert to a date:
select PARSE_DATE('%Y-%m-%d', SUBSTR('2018-05-30T12:56:27:487+0200', 1, 10))
I have a column in my table that stores a date in format (DD-MM-YY HH:MM:SS). For e.g.:
05-06-15 01:02:03
I need to output for instance all the records that have a date between the 4th and the 5th of June, so i tried:
SELECT * from table where date BETWEEN '04-06-15 00:00:00' AND '05-06-15 23:59:59'
But it also output results with a different month, as:
05-07-15 14:52:34
Is there a way to use a single query for solving this issue or I have to change all my database date format?
SELECT *
from table
where
STR_TO_DATE(date,'%d-%m-%Y %T') between
'2015-06-05 00:00:00' and '2015-06-5 23:59:59';
I have this table
CREATE TABLE Table1 (
MY_ID INTEGER NOT NULL,
SCAN_TIME TIMESTAMP NOT NULL,
WORKCELL_ID SMALLINT
);
My problem when I use select SQL to get records between two dates I get empty result if the user select the same date for the two dates
For ex:
Select * from Table1
where SCAN_TIME between '20.9.2014' and '20.9.2014'
Although there are records in that date '20.9.2014' but I get empty result and I get results only if I increase the second date by one day to be '21.9.2014' !! why is that and how I should fix ?
The problem is that you used timestamp as the type, and things messed up due to the time portion. Try to use Date.
When you said between 2014-09-20 and 2014-09-20, you are actually saying between 2014-09-20 midnight and 2014-09-20 midnight, apparently nothing falls in between other than the exact moment of midnight.
If you cannot control the table structure, do what PM 77-1 suggested in his comment below - use cast to cast timestamp into date:
select 1 from table1
where cast(scan_time as date) between 'someday1' and 'someday2';
A TIMESTAMP contains both a date and a time. Since you're not specifying the time in your WHERE clause, it's using the beginning of the day for both times. So you're actually writing the equivalent of:
WHERE SCAN_TIME between '20.9.2014 00:00:00' and '20.9.2014 00:00:00'
Unless the time part of the timestamp is actually 00:00:00, it won't satisfy this criterion. You should convert the timestamp to a date, or specify the times in your range, e.g.
WHERE SCAN_TIME between '20.9.2014 00:00:00' and '20.9.2014 23:59:59'