I have a table where i have ID,matchid,point1,point2. I need to get the ID which has the maximum points but the problem i am facing is i need find max record depending on sum of both (point1+point), I have no idea how I can get the max with the combination of 2 columns i have tried query such as,
SELECT MAX(column1+column2) FROM table
MAX(SUM(column1,column2)) FROM table
but nothing works I am using Ms:Access
This will return more than one answer if more than one sum=max:
SELECT ID FROM Table1
WHERE ([Field1]+[Field2])=(
SELECT Max([Field1]+[Field2]) AS Expr1
FROM Table1)
You can use a subquery e.g.
select id from table where point1+point2 = (select max(point1+point2) from table)
Note that this will return multiple rows if more than one record has the same maximum points.
Related
i have this query
SELECT PersonalInfo.id, PersonalInfo.[k-commission], Abs(Not IsNull([PersonalInfo]![k-commission].[Value])) AS CommissionAbsent
FROM PersonalInfo;
and the PersonalInfo.k-commission is a multi value field. the CommissionAbsent shows duplicate values for each k-commission value. when i use DISTINCT i get an error saying that the keyword cannot be used with a multi value field.
now i want to remove the duplicates and show only one result for each. i tried using a WHERE but i dont know how.
edit: i have a lot more columnes and in the example i only showed the few i need.
You can use GROUP BY and COUNT to solve your problem, here is an example for it
SELECT clmn1, clmn2, COUNT(*) as count
FROM table
GROUP BY clmn1, clmn2
HAVING COUNT(*) > 1;
the query groups the rows in the table by the clmn1 and clmn2 columns, and counts the number of occurrences of each group. The HAVING clause is then used to filter the groups and only return the groups that have a count greater than 1, which indicates duplicates.
If you want to select all, then you can do like this
SELECT *
FROM table
WHERE (clmn1, clmn2) IN (SELECT clmn1, clmn2
FROM table
GROUP BY clmn1, clmn2
HAVING COUNT(*) > 1)
SELECT PersonalInfo.id, PersonalInfo.[k-commission], Abs(Not IsNull([PersonalInfo]![k-commission].[Value])) AS CommissionAbsent
FROM PersonalInfo
GROUP BY PersonalInfo.id, PersonalInfo.[k-commission], Abs(Not IsNull([PersonalInfo]![k-commission].[Value]))
HAVING COUNT(*) > 1
I have a scenario for a type2 table where I have to remove duplicates on total row level.
Lets consider below example as the data in table.
A|B|C|D|E
100|12-01-2016|2|3|4
100|13-01-2016|3|4|5
100|14-01-2016|2|3|4
100|15-01-2016|5|6|7
100|16-01-2016|5|6|7
If you consider A as key column, you know that last 2 rows are duplicates.
Generally to find duplicates, we use group by function.
select A,C,D,E,count(1)
from table
group by A,C,D,E
having count(*)>1
for this output would be 100|2|3|4 as duplicate and also 100|5|6|7.
However, only 100|5|6|7 is only duplicate as per type 2 and not 100|2|3|4 because this value has come back in 3rd run and not soon after 1st load.
If I add date field into group by 100|5|6|7 will not be considered as duplicate, but in reality it is.
Trying to figure out duplicates as explained above.
Duplicates should only be 100|5|6|7 and not 100|2|3|4.
can someone please help out with SQL for the same.
Regards
Raghav
Use row_number analytical function to get rid of duplicates.
delete from
(
select a,b,c,d,e,row_number() over (partition by a,b,c,d,e) as rownumb
from table
) as a
where rownumb > 1
if you want to see all duplicated rows, you need join table with your group by query or filter table using group query as subquery.
wITH CTE AS (select a, B, C,D,E, count(*)
from TABLE
group by 1,2,3,4,5
having count(*)>1)
sELECT * FROM cte
WHERE B <> B + 1
Try this query and see if it works. In case you are getting any errors then let me know.
I am assuming that your column B is in the Date format if not then cast it to date
If you can see the duplicate then just replace select * to delete
I need help on creating a select statement in sql to get the unique rows.
I need the unique Reference ID but since Call Time is also unique, I only need to get the first row out of the similar rows.
I have this table[Calls]:
The result should be:
When I used:
Select Distinct * FROM Calls
It will return the same table and not the result I want.
It may helps you...
min(date) is the first datetime for each individual
Select referenceid,min(date),number from calls
group by referenceid,number
Perhaps a simple GROUP BY:
SELECT ReferenceID,
MIN(CallTime) AS CallTime,
MIN(Number) AS Number
FROM dbo.TableName t
GROUP BY ReferenceID
We are in the process of optimizing our database.We have most of store procedure that uses CTE because it gives us high performance according to our table strucure.We have almost dynamic query that have different result according to different condition.We hold all data in CTE, and check condition, that was the not problem but we need total number of rows that return by each query ,in calculating this it takes lots of time.Temporary table or table variable not suitable in our case as it takes lots of time to insert data in it.We have structure as following
With t(fields) as
(select field1,field2.......
ROW_NUMBER() OVER (order by some column) as row...
from some table and lots of
inner n left joins
where some condition ),
rowTotal(RowTotal) as
(select max(row) from t)
select * from t,RowTotal
where condition for paging
But max(row) took lots of times if i remove this it return data within 100ms. I tried Coun(*),Count(SomeField) and many other it works but took lots of time.How can i achieve total number of rows from cte within some ms any aggregate function will not work for me.Is there any other way to calculate rowtotal like ##rowcount.Thanks in advance for any help.
If you are after the total number of rows from the inner query you can add this as a column to your select using COUNT() and PARTITION BY().
With t(fields) as
(select COUNT(*) OVER (PARTITION BY 1) AS TotalRows,
field1,field2.......
ROW_NUMBER() OVER (order by some column) as row...
from some table ...
This should give you a count of the total rows in 't' as the first column of t
I don't know that this is the fastest way to get the result you want but it works for me on 000's of returned records and prevents extra select queries to find the count separately.
What is the most efficient way to select the first and last element only, from a column in SQLite?
The first and last element from a row?
SELECT column1, columnN
FROM mytable;
I think you must mean the first and last element from a column:
SELECT MIN(column1) AS First,
MAX(column1) AS Last
FROM mytable;
See http://www.sqlite.org/lang_aggfunc.html for MIN() and MAX().
I'm using First and Last as column aliases.
if it's just one column:
SELECT min(column) as first, max(column) as last FROM table
if you want to select whole row:
SELECT 'first',* FROM table ORDER BY column DESC LIMIT 1
UNION
SELECT 'last',* FROM table ORDER BY column ASC LIMIT 1
The most efficient way would be to know what those fields were called and simply select them.
SELECT `first_field`, `last_field` FROM `table`;
Probably like this:
SELECT dbo.Table.FirstCol, dbo.Table.LastCol FROM Table
You get minor efficiency enhancements from specifying the table name and schema.
First: MIN() and MAX() on a text column gives AAAA and TTTT results which are not the first and last entries in my test table. They are the minimum and maximum values as mentioned.
I tried this (with .stats on) on my table which has over 94 million records:
select * from
(select col1 from mitable limit 1)
union
select * from
(select col1 from mitable limit 1 offset
(select count(0) from mitable) -1);
But it uses up a lot of virtual machine steps (281,624,718).
Then this which is much more straightforward (which works if the table was created without WITHOUT ROWID) [sql keywords are in capitals]:
SELECT col1 FROM mitable
WHERE ROWID = (SELECT MIN(ROWID) FROM mitable)
OR ROWID = (SELECT MAX(ROWID) FROM mitable);
That ran with 55 virtual machine steps on the same table and produced the same answer.
min()/max() approach is wrong. It is only correct, if the values are ascending only. I needed something liket this for currency rates, which are random raising and falling.
This is my solution:
select st.*
from stats_ticker st,
(
select min(rowid) as first, max(rowid) as last --here is magic part 1
from stats_ticker
-- next line is just a filter I need in my case.
-- if you want first/last of the whole table leave it out.
where timeutc between datetime('now', '-1 days') and datetime('now')
) firstlast
WHERE
st.rowid = firstlast.first --and these two rows do magic part 2
OR st.rowid = firstlast.last
ORDER BY st.rowid;
magic part 1: the subselect results in a single row with the columns first,last containing rowid's.
magic part 2 easy to filter on those two rowid's.
This is the best solution I've come up so far. Hope you like it.
We can do that by the help of Sql Aggregate function, like Max and Min. These are the two aggregate function which help you to get last and first element from data table .
Select max (column_name ), min(column name) from table name
Max will give you the max value means last value and min will give you the min value means it will give you the First value, from the specific table.