i have this table in my DB
categoriesSupports-> id, category_id, support_id, date
the thing is that i need to extract all support_id where date is the closest date from now...
something like this... if there is in the DB table
id, category_id, support_id, date
1 1 1 2010-11-23
2 1 2 2010-11-25
3 1 1 2010-11-26
4 1 3 2010-11-24
i need to get just
id, category_id, support_id, date
2 1 2 2010-11-25
3 1 1 2010-11-26
4 1 3 2010-11-24
So for better undestanding... i need the closest date for each support and i only have date from the past...
Ive being trying a lot and I dont know how...
The following should give you:
all the categoriesSupports for current date(one or multiple)
One previous categoriesSupport(if exists)
One future categoriesSupport(if exists)
(
SELECT *
FROM `categoriesSupports`
WHERE `date` < CURDATE()
ORDER BY `date` DESC
LIMIT 1
)
UNION
(
SELECT *
FROM `categoriesSupports`
WHERE `date` = CURDATE()
)
UNION
(
SELECT *
FROM `categoriesSupports`
WHERE `date` > CURDATE()
ORDER BY `date` ASC
LIMIT 1
)
A. This answers 'where date is the closest date from now...':
SELECT *
FROM `categoriesSupports`
WHERE `date` IN (
SELECT `date`
FROM `categoriesSupports`
ORDER BY `date` DESC
LIMIT 1
)
Notes:
You can set LIMIT n to select entries for more dates.
If you only want for the last date you can replace IN with = because the sub-select will return only one value.
If your table includes future dates replace ORDER BY date DESC with ORDER BY ABS(NOW() - date) ASC.
A solution with JOINS. Will work only if you have past dates.
SELECT a.*
FROM `categoriesSupports` AS a
LEFT JOIN `categoriesSupports` AS b
ON b.date > a.date
WHERE b.id IS NULL
Added just for reference.
B. This answers 'where date is in the last 3 days (including today)':
SELECT *
FROM `categoriesSupports`
WHERE DATEDIFF(NOW(), `date`) < 3
Replace 3 with any number if you want more or less days.
C. Same as A., but per support id
SELECT a.*
FROM `categoriesSupports` AS a
LEFT JOIN `categoriesSupports` AS b
ON b.support_id = a.support_id AND b.date > a.date
WHERE b.id IS NULL
This answers the latest version of the question.
SELECT *
FROM CurrentDeals
WHERE (julianday(Date('now')) - julianday(date))<=3
ORDER BY date ASC
Here, you have to decide what would be your meaning of "closest". I have used 3 as the sample. This will list out the records, which has a date value lesser that or equal to 3.
Hope this is what you wanted.
Related
How to get only the first row from the result of the below query. I need the latest record for each date so I did the partition by created_date. But in some places, I am getting the same row number and not able to get the expected output. Please find the below query, current output, and expected output.
What changes do in need to make in order to get the expected output? Thank you.
WITH ctetable
AS (
SELECT created_date BPMDate
,tenor
,row_number() OVER (
PARTITION BY created_date ORDER BY created_date DESC
) rw
FROM table1 a
INNER JOIN table2 b ON a.case_id = b.case_id
AND a.eligible_transaction = 'true'
AND to_date(a.created_date) >= '2020-10-01'
AND to_date(a.created_date) <= '2020-10-05'
AND case_status = 'Completed'
)
SELECT BPMDate
,Tenor
,rw
FROM ctetable
Current output:
date tenor rw
2020-10-05 13:24:15.0 1W 1
2020-10-05 12:15:43.0 1Y 1
2020-10-05 12:15:43.0 1Y 2
2020-10-01 13:30:59.0 1W 1
2020-10-01 13:30:59.0 1W 2
Expected output:
date tenor rw
2020-10-05 13:24:15.0 1W 1
2020-10-01 13:30:59.0 1W 1
Regards,
Viresh
That would be:
with ctetable as (
select created_date, bpmdate, tenor,
row_number() over (partition by date(created_date) order by created_date desc ) rn
from table1 a
inner join table2 b
on a.case_id = b.case_id
and a.eligible_transaction = 'true'
and to_date(a.created_date) >= '2020-10-01'
and to_date(a.created_date) <= '2020-10-05'
and case_status='completed'
)
select bpmdate,tenor,rw
from ctetable
where rn = 1
Changes to your original code:
you need to remove the time portion of the date in the partition by clause of the window function; you didn't tell which database you are using: I used date(), but the function might be different in your database (trunc() in Oracle, date_trunc() in Postgres, and so on)
the outer query needs to filter on the row number that is equal to 1
You seem to want the first row per day:
select BPMDate, Tenor, rw
from (select t.*,
row_number() over (partition by trunc(bpmdate) order by bpmdate) as seqnum
from ctetable
) t
where seqnum = 1;
Note: I don't know if your database supports trunc(), but that is simply some method for extracting the date from the column.
I have two table with different appointment dates.
Table 1
id start date
1 5/1/14
2 3/2/14
3 4/5/14
4 9/6/14
5 10/7/14
Table 2
id start date
1 4/7/14
1 4/10/14
1 7/11/13
2 2/6/14
2 2/7/14
3 1/1/14
3 1/2/14
3 1/3/14
If i had set date ranges i can count each appointment date just fine but i need to change the date ranges.
For each id in table 1 I need to add the distinct appointment dates from table 2 BUT only
6 months prior to the start date from table 1.
Example: count all distinct appointment dates for id 1 (in table 2) with appointment dates between 12/1/13 and 5/1/14 (6 months prior). So the result is 2...4/7/14 and 4/10/14 are within and 7/1/13 is outside of 6 months.
So my issue is that the range changes for each record and i can not seem to figure out how to code this.For id 2 the date range will be 9/1/14-3/2/14 and so on.
Thanks everyone in advance!
Try this out:
SELECT id,
(
SELECT COUNT(*)
FROM table2
WHERE id = table1.id
AND table2.start_date >= DATEADD(MM,-6,table1.start_date)
) AS table2records
FROM table1
The DATEADD subtracts 6 months from the date in table1 and the subquery returns the count of related records.
I think what you want is a type of join.
select t1.id, count(t2.id) as numt2dates
from table1 t1 left outer join
table2 t2
on t1.id = t2.id and
t2.startdate between dateadd(month, -6, t1.startdate) and t1.startdate
group by t1.id;
The exact syntax for the date arithmetic depends on the database.
Thank you this solved my issue. Although this may not help you since you are not attempting to group by date. But the answer gave me the insights to resolve the issue I was facing.
I was attempting to gather the total users a date criteria that had to be evaluated by multiple fields.
WITH data AS (
SELECT generate_series(
(date '2020-01-01')::timestamp,
NOW(),
INTERVAL '1 week'
) AS date
)
SELECT d.date, (SELECT COUNT(DISTINCT h.id) AS user_count
FROM history h WHERE h.startDate < d.date AND h.endDate > d.date
ORDER BY 1 DESC) AS total_records
FROM data d ORDER BY d.date DESC
2022-05-16, 15
2022-05-09, 13
2022-05-02, 13
...
I'm trying the find a value at a certain date.
My data looks like
Date Value
2013-11-02 5
2013-10-10 8
2013-09-14 6
2013-08-15 4
How can I determine what the value was on 2013-09-30?
Obviously the answer is 6 but I can't figure out the SQL code.
Thanks
You can do it with order by and limiting the number of rows. In SQL Server syntax (and Sybase and Access):
select top 1 t.*
from table t
where date <= '2013-09-30'
order by date desc;
In MySQL (and Postgres):
select t.*
from table t
where date <= '2013-09-30'
order by date desc
limit 1;
In Oracle:
select t.*
from (select t.*
from table t
where date <= '2013-09-30'
order by date desc
) t
where rownum = 1
EDIT:
And, a SQL standard way to it (should work in any database):
select t.*
from table t
where date = (select max(date)
from table t2
where date <= '2013-09-30'
);
Sorry for confusing title. Please, tell, if it's possible to do via db request. Assume we have following table
ind_id name value date
----------- -------------------- ----------- ----------
1 a 10 2010-01-01
1 a 20 2010-01-02
1 a 30 2010-01-03
2 b 10 2010-01-01
2 b 20 2010-01-02
2 b 30 2010-01-03
2 b 40 2010-01-04
3 c 10 2010-01-01
3 c 20 2010-01-02
3 c 30 2010-01-03
3 c 40 2010-01-04
3 c 50 2010-01-05
4 d 10 2010-01-05
I need to query all rows to include each ind_id once for the given date, and if there's no ind_id for given date, then take the nearest lower date, if there's no any lower dates, then return ind_id + name (name/ind_id pairs are equal) with nulls.
For example, date is 2010-01-04, I expect following result:
ind_id name value date
----------- -------------------- ----------- ----------
1 a 30 2010-01-03
2 b 40 2010-01-04
3 c 40 2010-01-04
4 d NULL NULL
If it's possible, I'll be very grateful if someone help me with building query. I'm using SQL server 2008.
Check this SQL FIDDLE DEMO
with CTE_test
as
(
select int_id,
max(date) MaxDate
from test
where date<='2010-01-04 00:00:00:000'
group by int_id
)
select A.int_id, A.[Value], A.[Date]
from test A
inner join CTE_test B
on a.int_id=b.int_id
and a.date = b.Maxdate
union all
select int_id, null, null
from test
where int_id not in (select int_id from CTE_test)
(Updated) Try:
with cte as
(select m.*,
max(date) over (partition by ind_id) max_date,
max(case when date <= #date then date end) over
(partition by ind_id) max_acc_date
from myTable m)
select ind_id,
name,
case when max_acc_date is null then null else value end value,
max_acc_date date
from cte c
where date = coalesce(max_acc_date, max_date)
(SQLFiddle here)
Here is a query that returns the result that you are looking for:
SELECT
t1.ind_id
, CASE WHEN t1.date <= '2010-01-04' THEN t1.value ELSE null END
FROM test t1
WHERE t1.date=COALESCE(
(SELECT MAX(DATE)
FROM test t2
WHERE t2.ind_id=t1.ind_id AND t2.date <= '2010-01-04')
, t1.date)
The idea is to pick a row in a correlated query such that its ID matches that of the current row, and the date is the highest one prior to your target date of '2010-01-04'.
When such row does not exist, the date for the current row is returned. This date needs to be replaced with a null; this is what the CASE statement at the top is doing.
Here is a demo on sqlfiddle.
You can use something like:
declare #date date = '2010-01-04'
;with ids as
(
select distinct ind_id
from myTable
)
,ranks as
(
select *
, ranking = row_number() over (partition by ind_id order by date desc)
from myTable
where date <= #date
)
select ids.ind_id
, ranks.value
, ranks.date
from ids
left join ranks on ids.ind_id = ranks.ind_id and ranks.ranking = 1
SQL Fiddle with demo.
Ideally you wouldn't be using the DISTINCT statement to get the ind_id values to include, but I've used it in this case to get the results you needed.
Also, standard disclaimer for these sorts of queries; if you have duplicate data you should consider a tie-breaker column in the ORDER BY or using RANK instead of ROW_NUMBER.
Edited after OPs update
Just add the new column into the existing query:
with ids as
(
select distinct ind_id, name
from myTable
)
,ranks as
(
select *
, ranking = row_number() over (partition by ind_id order by date desc)
from myTable
where date <= #date
)
select ids.ind_id
, ids.name
, ranks.value
, ranks.date
from ids
left join ranks on ids.ind_id = ranks.ind_id and ranks.ranking = 1
SQL Fiddle with demo.
As with the previous one it would be best to get the ind_id/name information through joining to a standing data table if available.
Try
DECLARE #date DATETIME;
SET #date = '2010-01-04';
WITH temp1 AS
(
SELECT t.ind_id
, t.name
, CASE WHEN t.date <= #date THEN t.value ELSE NULL END AS value
, CASE WHEN t.date <= #date THEN t.date ELSE NULL END AS date
FROM test1 AS t
),
temp AS
(
SELECT *, ROW_NUMBER() OVER (PARTITION BY ind_id ORDER BY t.date DESC) AS rn
FROM temp1 AS t
WHERE t.date <= #date OR t.date IS NULL
)
SELECT *
FROM temp AS t
WHERE rn = 1
Use option with EXISTS operator
DECLARE #date date = '20100104'
SELECT ind_id,
CASE WHEN date <= #date THEN value END AS value,
CASE WHEN date <= #date THEN date END AS date
FROM dbo.test57 t
WHERE EXISTS (
SELECT 1
FROM dbo.test57 t2
WHERE t.ind_id = t2.ind_id AND t2.date <= #date
HAVING ISNULL(MAX(t2.date), t.date) = t.date
)
Demo on SQLFiddle
This is not the exact answer but will give you the concept as i just write it down quickly without any testing.
use
go
if
(Select value from table where col=#col1) is not null
--you code to get the match value
else if
(Select LOWER(Date) from table ) is not null
-- your query to get the nerst dtae record
else
--you query withh null value
end
price date time
1.0 20100815 1
1.2 20100815 2
1.3 20100815 3
2 20100814 1
3.1 20100813 1
3.2 20100813 2
:
:
:
Now I want to select the latest 3 days price with all the time, I use like this
select price, date from allquotes where date in
(select date from allquotes group by date order by date desc limit 3)
Is this right? Is this efficient?
Any suggestion to improve this?
If I would like to show only one price with the latest time, how to do that?
Thanks so much!
This should do the trick on SQL Server:
select top 3 q.pricee, q.date, q.time
from (
select date, max(time) as MaxTime
from allquotes
group by date
) qm
inner join quotes q on qm.date = q.date and qm.MaxTime = time
order by date desc
For MySQL, try:
select q.pricee, q.date, q.time
from (
select date, max(time) as MaxTime
from allquotes
group by date
) qm
inner join quotes q on qm.date = q.date and qm.MaxTime = time
order by date desc
limit 3
Select Top 3 Sum(price),
date,
Sum(time)
From allquotes
Group By date
Order By date Desc