vb express 2010 populating array - vb.net

it doesnt like my code:
Dim n As Integer
Dim flag As Boolean
Dim i
Dim x() As Integer
n = InputBox("How many numbers do you want to be sorted?")
For i = 1 To n - 1 Step 1
x(i) = InputBox("Please enter a record")
Next i
I want to put values into x()

You need to use a ReDim to specify the size of x as soon as you know it (ie after your first InputBox):
n = InputBox("How many numbers do you want to be sorted?")
ReDim x(n - 1)
Also, your For loop will be simpler to handle if it's zero based as in:
For i = 0 To n - 1 Step 1

Related

Trying to ask for an integer input based on user

Vb.net how to ask a user for an integer? That’s how many times they have to input a number and then find the largest number
Can’t think of the logic
Print("Please enter count")
Dim input As String = ReadFromUser()
Dim count As Integer = ConvertToInteger(input)
Dim numbers(count - 1) As Integer
For i = 0 To count - 1
input = ReadFromUser()
Dim n As Integer = ConvertToInteger(input)
numbers(i) = n
Next
Sort(numbers)

How to rename a variable (Loops to fill multiple matrices)

Im trying to fill multiple matrices according to inputs from a userform.
Right now i have to create 5 matrices but i want this to be able to change in the future, so i want to create the variables "on the fly" in my loop. I basically want to Create Matrix1, Matrix2, Matrix3 ... Matrixn, but i can't figure how to do it. Any Ideas ?
Following you can see the script --> The two last lines are totally wrong (i know it) but i just added them in hope that you understand what i want to do :)
PS: And most important i should be able to then look to Matrix1(i,j),..., Matrixn(i,j) values easily
Looking Forward your help <3
'FicheCalcul ----------------------------------------------------------------------------------------------------
Dim Temp4 As String
Dim Temp5 As String
Dim MatrixTemp(3 - 1, 5 - 1) As Double 'm-1,x-1
For i = 1 To 5 'n
For j = 0 To 3 - 1 'm-1
For k = 0 To 5 - 1 'X-1
Temp4 = j & "C" & i
Temp5 = Temp4 & k
If UserForm1.Controls(Temp5) = False Then
MatrixTemp(j, k) = ""
Else
If UserForm1.Controls(Temp5) = True Then
MatrixTemp(j, k) = k - 2 ' -2 -1 0 1 2
End If
End If
Next k
Next j
Dim ("Matrix"&i)(3-1,5-1) As Double
("Matrix"&i) = MatrixTemp
Next i
You cannot have variable variable names. Therefore you need to use arrays.
Option Explicit
Sub example()
Dim MatrixTemp(4, 5) As Double
'do your matrix stuff here
MatrixTemp(0, 0) = 1
MatrixTemp(0, 1) = 2
MatrixTemp(0, 2) = 3
Dim Matrix(4) As Variant 'create an array of 5 matices
Matrix(0) = MatrixTemp 'fill your temp matrix into the first matrix
Debug.Print Matrix(0)(0, 2) 'outputs 3
End Sub

Randomly select an item from a list based on a class, repeat number of times based on different numbers

I am not familiar with using macro's, but I think that what I would like excel to perform is best handled with a macro. So I can use all the input you may have!
I have these headers;
ID Tag Pen Sex Weight Class Inside range
With 450 rows of data. Based on the distribution of the weight data, I have in two other columns (class and number) the number of rows I want to select within each class. The selected rows must have the value "Yes" in the column "Inside range".
I want to randomly select the rows, based on the number needed for each class, and copy these rows to a new sheet. It sums up to 30 rows in the new sheet.
I hope you have a suggestion how to complete this action!
can you try the following, you will need to add a reference to Microsoft Scripting Runtime library:
Const rowCount = 450
Public Sub copyRows()
Dim i As Integer
Dim j As Integer
Dim classes As Scripting.Dictionary
Dim source As Worksheet
Dim colNumber As Integer
Dim colClassName as Integer
Dim colInsideRange As Integer
Dim allSelected As Boolean
Dim randomRow as Integer
Dim sumRemaining as Integer
allSelected = False
Set source = Worksheets("YourWorksheetName")
colClassName = 6 'this is the column number where class names are entered. I am assuming 6
colNumber = 7 'this is the column number where number of rows to be selected are entered. I am assuming 7
colInsideRange = 8 'this is the column number where "Inside Range" values are entered. I am assuming 9
For i = 2 to rowCount + 1 'assuming you have a header row
classes(CStr(source.Cells(i, colClassName))) = CInt(source.cells(i, colNumber)
Next i
Do until allSelected
Randomize
randomRow = Int ((Rnd * 450) + 2) 'assuming you have a header row, + 1 if you don't
If classes(CStr(source.Cells(randomRow, colClassName))) = 0 Then
With classes
sumRemaining = 0
For j = 1 to .Count - 1
sumRemaining = sumRemaining + .Items(j)
If sumRemaining > 0 Then Exit For
Next j
allSelected = (sumRemaining = 0)
End With
Else
source.Cells(randomRow, colInsideRange) = "Yes"
classes(CStr(source.Cells(randomRow, colClassName))) = classes(CStr(source.Cells(randomRow, colClassName))) - 1
End If
Loop
'Enter your code to copy rows with "Inside Range" = "Yes"
End Sub
Sorry if there are some errors or typos, I wrote from my mobile phone.

Debugging VBA code - appending values to array

I am trying to use code of the following form to populate an array of x rows:
Dim myarray() As Variant
Dim string1 As String
Dim myarray_ubound As Integer
myarray_ubound = 0
For i = 1 to x
myarray_ubound = myarray_ubound + 1
ReDim Preserve myarray(1 To myarray_ubound, 1 To 2)
myarray(myarray_ubound,1) = i
myarray(myarray_ubound,2) = string1
Next i
However, when I run it it gets stuck after the first loop, telling me that a subscript is out of range. Debugging takes me to the ReDim command.
I used myarray_ubound as an alternative to calling the UBound function many times, but I have tried using this as well and I get the same error.
Can anyone spot what's gone wrong?
See: http://msdn.microsoft.com/en-us/library/aa266231.aspx
"If you use the Preserve keyword, you can resize only the last array dimension and you can't change the number of dimensions at all."
Try
ReDim Preserve myarray(1 To 2, 1 To myarray_ubound)
instead.
you can only redim the last element of the array (not the first), see below. As you know x I would suggest to redim your array with this value from the beginning.
Dim myarray() As Variant
Dim string1 As String
Dim myarray_ubound As Integer
myarray_ubound = 0
For i = 1 To 10
myarray_ubound = myarray_ubound + 1
ReDim Preserve myarray(1 To 2, 1 To myarray_ubound)
myarray(1, myarray_ubound) = i
myarray(2, myarray_ubound) = string1
Next i
Since you are declaring the variable as a Variant i don't see why you need to re-dim. (maybe related to memory issues, feel free to fill in).
I would suggest:
For i = 1 to 10
myArray(1, i-1) = i
myArray(2, i-1) = string1
next i

Populating 2 dimensional array using a For loop

Currently I'm trying to fill a 3x3 square with random x's and o's to make a tic tac toe
game. Unfortunately the game doesn't seem to output all the x's and o's. Logically, from what I can see, it should be able to but it's not. Any help would be appreciated.
Shared Sub twodimension()
Dim tic(2, 2) As String
Dim min As Integer
Dim x As String
Dim random As New Random()
Dim i As Integer
Dim x1 As Integer
Dim bound0 As Integer = tic.GetUpperBound(0)
Dim bound1 As Integer = tic.GetLowerBound(1)
For i = 0 To bound0
For x1 = 0 To bound1
min = random.Next(2)
If min = 0 Then
x = "x"
Console.WriteLine("{0}", x)
Else
x = "o"
Console.WriteLine("{0}", x)
End If
Console.Write(" "c)
Next
Console.WriteLine()
Next
End Sub
So presumably you've got this declaration somewhere, right?
Public Shared Tic(2, 2) As String
In your code you've got GetLowerBound which will (almost) always returns zero and instead you should have GetUpperBound().
Dim bound0 As Integer = tic.GetUpperBound(0)
Dim bound1 As Integer = Tic.GetUpperBound(1)
EDIT (in response to comment)
GetUpperBound(int) returns the highest number that you can use for the dimension that you specify.
So for the following array:
Dim MyArray(4, 6, 8) As Integer
Trace.WriteLine(MyArray.GetUpperBound(0)) ''//Returns 4
Trace.WriteLine(MyArray.GetUpperBound(1)) ''//Returns 6
Trace.WriteLine(MyArray.GetUpperBound(2)) ''//Returns 8
GetLowerBound(int) returns the lowest number that you can use for the dimension that you specify. In almost every case this is zero but in older versions of VB (and using some COM interop) you can create arrays that don't "start" at zero and instead start at whatever you wanted. So in old VB you could actually say Dim Bob(1 To 4) As Integer and GetLowerBound(0) would return 1 instead of 0. For the most part there is no reason to even be aware that GetLowerBound exists even.