I don't understand what this order_by clause is doing and whether I need it or not:
select c.customerid, c.firstname, c.lastname, i.order_date, i.item, i.price from
items_ordered i, customers c
where i.customerid = c.customerid
group by c.customerid, i.item, i.order_date
order by i.order_date desc;
This produces this data:
10330 Shawn Dalton 30-Jun-1999 Pogo stick 28.00
10101 John Gray 30-Jun-1999 Raft 58.00
10410 Mary Ann Howell 30-Jan-2000 Unicycle 192.50
10101 John Gray 30-Dec-1999 Hoola Hoop 14.75
10449 Isabela Moore 29-Feb-2000 Flashlight 4.50
10410 Mary Ann Howell 28-Oct-1999 Sleeping Bag 89.22
10339 Anthony Sanchez 27-Jul-1999 Umbrella 4.50
10449 Isabela Moore 22-Dec-1999 Canoe 280.00
10298 Leroy Brown 19-Sep-1999 Lantern 29.00
10449 Isabela Moore 19-Mar-2000 Canoe paddle 40.00
10413 Donald Davids 19-Jan-2000 Lawnchair 32.00
10330 Shawn Dalton 19-Apr-2000 Shovel 16.75
10439 Conrad Giles 18-Sep-1999 Tent 88.00
10298 Leroy Brown 18-Mar-2000 Pocket Knife 22.38
10299 Elroy Keller 18-Jan-2000 Inflatable Mattress 38.00
10438 Kevin Smith 18-Jan-2000 Tent 79.99
10101 John Gray 18-Aug-1999 Rain Coat 18.30
10449 Isabela Moore 15-Dec-1999 Bicycle 380.50
10439 Conrad Giles 14-Aug-1999 Ski Poles 25.50
10449 Isabela Moore 13-Aug-1999 Unicycle 180.79
10101 John Gray 08-Mar-2000 Sleeping Bag 88.70
10299 Elroy Keller 06-Jul-1999 Parachute 1250.00
10438 Kevin Smith 02-Nov-1999 Pillow 8.50
10101 John Gray 02-Jan-2000 Lantern 16.00
10315 Lisa Jones 02-Feb-2000 Compass 8.00
10449 Isabela Moore 01-Sep-1999 Snow Shoes 45.00
10438 Kevin Smith 01-Nov-1999 Umbrella 6.75
10298 Leroy Brown 01-Jul-1999 Skateboard 33.00
10101 John Gray 01-Jul-1999 Life Vest 125.00
10330 Shawn Dalton 01-Jan-2000 Flashlight 28.00
10298 Leroy Brown 01-Dec-1999 Helmet 22.00
10298 Leroy Brown 01-Apr-2000 Ear Muffs 12.50
While if I remove the order_by clause completely, as in this query:
select c.customerid, c.firstname, c.lastname, i.order_date, i.item, i.price from
items_ordered i, customers c
where i.customerid = c.customerid
group by c.customerid, i.item, i.order_date;
I get these results:
10101 John Gray 30-Dec-1999 Hoola Hoop 14.75
10101 John Gray 02-Jan-2000 Lantern 16.00
10101 John Gray 01-Jul-1999 Life Vest 125.00
10101 John Gray 30-Jun-1999 Raft 58.00
10101 John Gray 18-Aug-1999 Rain Coat 18.30
10101 John Gray 08-Mar-2000 Sleeping Bag 88.70
10298 Leroy Brown 01-Apr-2000 Ear Muffs 12.50
10298 Leroy Brown 01-Dec-1999 Helmet 22.00
10298 Leroy Brown 19-Sep-1999 Lantern 29.00
10298 Leroy Brown 18-Mar-2000 Pocket Knife 22.38
10298 Leroy Brown 01-Jul-1999 Skateboard 33.00
10299 Elroy Keller 18-Jan-2000 Inflatable Mattress 38.00
10299 Elroy Keller 06-Jul-1999 Parachute 1250.00
10315 Lisa Jones 02-Feb-2000 Compass 8.00
10330 Shawn Dalton 01-Jan-2000 Flashlight 28.00
10330 Shawn Dalton 30-Jun-1999 Pogo stick 28.00
10330 Shawn Dalton 19-Apr-2000 Shovel 16.75
10339 Anthony Sanchez 27-Jul-1999 Umbrella 4.50
10410 Mary Ann Howell 28-Oct-1999 Sleeping Bag 89.22
10410 Mary Ann Howell 30-Jan-2000 Unicycle 192.50
10413 Donald Davids 19-Jan-2000 Lawnchair 32.00
10438 Kevin Smith 02-Nov-1999 Pillow 8.50
10438 Kevin Smith 18-Jan-2000 Tent 79.99
10438 Kevin Smith 01-Nov-1999 Umbrella 6.75
10439 Conrad Giles 14-Aug-1999 Ski Poles 25.50
10439 Conrad Giles 18-Sep-1999 Tent 88.00
10449 Isabela Moore 15-Dec-1999 Bicycle 380.50
10449 Isabela Moore 22-Dec-1999 Canoe 280.00
10449 Isabela Moore 19-Mar-2000 Canoe paddle 40.00
10449 Isabela Moore 29-Feb-2000 Flashlight 4.50
10449 Isabela Moore 01-Sep-1999 Snow Shoes 45.00
10449 Isabela Moore 13-Aug-1999 Unicycle 180.79
I'm not sure what the order_by is doing here and if it's having the intended effects.
It looks like it is ordering on i.ordered_date, but using string comparison rather than date comparison, which is why 30-Jun-1999 is placed before 29-Feb-2000. As a string "30-Jun-1999" > "28-Feb-2000", but as dates, the reverse is true.
Check the type of i.ordered_date in the items_ordered table - it should be datetime or similar - if it's varchar, then you will need to either change it to a date type, or cast the value to a date in the order-by clause. E.g.
order by CAST(i.order_date AS DATE) desc
You should always use proper DATETIME datatype to store dates
Related
Hello Everyone I have a problem…
Table 1 (sorted) is laid out like this:
User ID Producer ID Company Number
JWROSE 23401 234
KXPEAR 23903 239
LMWEEM 27902 279
KJMORS 18301 183
Table 2 (unsorted) looks like this:
Client Name City Company Number
Rajat Smith London JWROSE
Robert Singh Cleveland KXPEAR
Alberto Johnson New York City LMWEEM
Betty Lee Dallas KJMORS
Chase Galvez Houston 23401
Hassan Jackson Seattle 23903
Tooti Fruity Boise 27902
Joe Trump Tokyo 18301
Donald Biden Cairo 234
Mike Harris Rome 239
Kamala Pence Moscow 279
Adolf Washington Bangkok 183
Now… Table 1 has all of the User IDs and Producer IDs properly rowed with the Company Number.
I want to pull all the data and correctly sorted….
Client Name City User ID Producer ID Company Number
Rajat Smith London JWROSE 23401 234
Robert Singh Cleveland KXPEAR 23903 239
Alberto Johnson New York City LMWEEM 27902 279
Betty Lee Dallas KJMORS 18301 183
Chase Galvez Houston JWROSE 23401 234
Hassan Jackson Seattle KXPEAR 23903 239
Tooti Fruity Boise LMWEEM 27902 279
Joe Trump Tokyo KJMORS 18301 183
Donald Biden Cairo JWROSE 23401 234
Mike Harris Rome KXPEAR 23903 239
Kamala Pence Moscow LMWEEM 27902 279
Adolf Washington Bangkok KJMORS 18301 183
Query:
Select
b.client_name,
b.city.,
a.user_id,
a.producer_id,
a.company_number
From Table 1 A
Left Join Table 2 B On a.company….
And this is where I don’t know what do to….because both tables have all the same variables, but Company Number in Table 2 is mixed with User IDs and Producer IDs... however we know what company Number those ID's are associated to.
As I mention in the comments, and others do, the real problem is your design. "The fact that UserID is clearly a varchar, while the other 2 columns are an int really does not make this any better", and makes this not simple (and certainly not SARGable).
To get the data in the correct order, as well, you need a column to order it on which the data lacks. I have therefore added a pseudo column, MissingIDColumn, to represent this missing column you need to add to your data; which you can do when you fix the design:
SELECT T2.ClientName,
T2.City,
T1.UserID,
T1.ProducerID,
T1.CompanyNumber
FROM (VALUES('JWROSE',23401,234),
('KXPEAR',23903,239),
('LMWEEM',27902,279),
('KJMORS',18301,183))T1(UserID,ProducerID,CompanyNumber)
JOIN (VALUES(1,'Rajat Smith ','London ','JWROSE'),
(2,'Robert Singh ','Cleveland ','KXPEAR'),
(3,'Alberto Johnson ','New York City','LMWEEM'),
(4,'Betty Lee ','Dallas ','KJMORS'),
(5,'Chase Galvez ','Houston ','23401'),
(6,'Hassan Jackson ','Seattle ','23903'),
(7,'Tooti Fruity ','Boise ','27902'),
(8,'Joe Trump ','Tokyo ','18301'),
(9,'Donald Biden ','Cairo ','234'),
(10,'Mike Harris ','Rome ','239'),
(11,'Kamala Pence ','Moscow ','279'),
(12,'Adolf Washington','Bangkok ','183'))T2(MissingIDColumn,ClientName,City,CompanyNumber) ON T2.CompanyNumber IN (T1.UserID,CONVERT(varchar(6),T1.ProducerID),CONVERT(varchar(6),T1.CompanyNumber))
ORDER BY MissingIDColumn;
I need to generate 10 business reports based on the following tables and I'm having some troubles. I know I do not have enough for 10 reports yet, but I am having troubles starting.
CARE_CENTER
Care Center ID|Care Center Name |Care Center Address |Nurse In Charge
------------------+--------------------------+-----------------------------------+--------------------
11111 |Centers Health Care |4770 White Plains Rd, Bronx, NY |Nurse Johnson
22222 |Bronx Urgent Care |1733 E 174th Street, Bronx, NY |Nurse Robinson
33333 |BronxCare Special Care Center|1265 Fulton Avenue, Bronx, NY |Nurse Jones
44444 |Gold Crest Care Center |2316 Bruner Avenue, Bronx, NY |Nurse Gonzalez
55555 |Regeis Care Center |3200 Baychester Avenue, Bronx, NY |Nurse Waterman
66666 |MedCarePlus |1643 Westchester Avenue, Bronx, NY |Nurse Connor
77777 |ArchCare Senior Center |900 Intervale, Avenue, Bronx, NY |Nurse Rodriguez
88888 |Bronx Center for Rehab |1010 Underhill Avenu, Bronx, NY |Nurse Morales
VISIT_CARE_CENTER
Patient ID|Visit Number|Care Center ID
-------------+-----------------+-----------------
1122 |78945 |11111
2233 |89123 |22222
3344 |91456 |33333
4455 |64981 |44444
5566 |12065 |55555
6677 |98106 |66666
7788 |40169 |77777
8899 |26013 |88888
Volunteer_Assigned_Care_Center
Volunteer ID|Care Center ID
----------------+------------------
12333 |11111
23444 |22222
34555 |33333
45666 |44444
56777 |55555
67888 |66666
78999 |77777
89000 |88888
VOLUNTEER
Volunteer ID|Interest ID
---------------+-------------
12333 |00001
23444 |00002
34555 |00003
45666 |00004
56777 |00005
67888 |00006
78999 |00007
89000 |00008
INTEREST
Interest ID|Interest Description
--------------+--------------------
00001 |Organzing
00002 |Coordinating
00003 |Daily Activites
00004 |Assisting with fundraising
00005 |Planning Special Events
00006 |Feeding Patients
00007 |Cleaning Social Rooms
00008 |Caring for Visitors
I need to generate a report that shows the Care centers and the volunteer relationships.
How would I write the SQL query to generate this report based on the above table structure?
You basically need a join first
Select c.CareCenterID,
c.CareCenterName,
c.CareCenterAddress,
c.NurseInCharge, v.VolunteerID,
i.InterestID, i.InterestDescription
From
CARE_CENTER c
Join
Volunteer_Assigned_Care_Center va
On
c.CareCenterID =va.CareCenterID
Join
VOLUNTEER v
On va.VOLUNTEERId=
v.VOLUNTEERId
Join
Interest i
v.InterestId=i.InterestId
How do I write a query to identify names(possibly including non-English names) that have similar sounds? Soundex does not seem to handle non-English names well.
The code should be able to identify that for example the following(or most of them) are names with similar sounds?
Helena - Elena
Violet - Viola
Beatrix - Beatrice
Madeline - Madeleine (ma-duh-LINE vs ma-duh-LEN)
Alice - Elise
Madeline - Adeline
Kristen - Kirsten
Lily - Millie
Charlotte - Scarlett
Zara / Lara / Sara / Mara
Elena - Alana
Emily - Emmeline
Amelia - Amalia
Stella - Bella - Ella
Isabel - Isabeau
Holly - Hallie
Laura - Lara
Fiona - Finola
Louise - Eloise
Cara - Clara
Susanna vs Susannah
Nora vs Norah
Talia vs Tahlia vs Thalia
Catherine vs Katherine
Cecilia vs Cecelia
Lucy vs Lucie
Vivian vs Vivien
Lillian vs Lilian
Gwendolen vs Gwendolyn
Sofia vs Sophia
Isabel vs Isobel vs Isabelle
Seraphina vs Serafina
Juliet vs Juliette
Annabel vs Annabelle
Emily vs Emilie
Elisabeth vs Elizabeth
...and non-English names too.
Would it help by using algorithm like Levenshtein Distance to compare the similarity between two sequences?
https://en.wikipedia.org/wiki/Levenshtein_distance
Particularly in Oracle, you can use utl_match.
For example:
--Find closest names based on UTL_MATCH.EDIT_DISTANCE.
with names as
(
--Names data.
select column_value name
from table(sys.odcivarchar2list('Adeline','Alana','Alice','Amalia','Amelia','Annabel',
'Annabelle','Beatrice','Beatrix','Bella','Cara','Catherine','Cecelia','Cecilia',
'Charlotte','Clara','Elena','Elisabeth','Elise','Elizabeth','Ella','Eloise','Emilie',
'Emily','Emmeline','Finola','Fiona','Gwendolen','Gwendolyn','Hallie','Helena','Holly',
'Isabeau','Isabel','Isabelle','Isobel','Juliet','Juliette','Katherine','Kirsten',
'Kristen','Lara','Laura','Lilian','Lillian','Lily','Louise','Lucie','Lucy',
'Madeleine','Madeline','Mara','Millie','Nora','Norah','Sara','Scarlett','Serafina',
'Seraphina','Sofia','Sophia','Stella','Susanna','Susannah','Tahlia','Talia','Thalia',
'Viola','Violet','Vivian','Vivien','Zara'))
)
--Name with the closest matches.
select name1, edit_distance, listagg(name2, ',') within group (order by name2) names
from
(
--Compare strings.
select names1.name name1, names2.name name2
,utl_match.edit_distance(names1.name, names2.name) edit_distance
,min(utl_match.edit_distance(names1.name, names2.name))
over (partition by names1.name) min_edit_distance
from names names1
cross join names names2
--This cross join could get expensive. It may help to add conditions here to
--filter out obvious non-matches. For example, maybe throw out rows where the
--string length is vastly different?
where names1.name <> names2.name
order by 1, 3, 2
)
where edit_distance = min_edit_distance
group by name1, edit_distance
order by 1;
Results:
NAME1 EDIT_DISTANCE NAMES
----- ------------- -----
Adeline 2 Madeline
Alana 2 Clara,Elena
Alice 2 Elise
Amalia 1 Amelia
Amelia 1 Amalia
Annabel 2 Annabelle
Annabelle 2 Annabel
Beatrice 2 Beatrix
Beatrix 2 Beatrice
Bella 2 Ella,Stella
Cara 1 Clara,Lara,Mara,Sara,Zara
Catherine 1 Katherine
Cecelia 1 Cecilia
Cecilia 1 Cecelia
Charlotte 4 Scarlett
Clara 1 Cara
Elena 2 Alana,Ella,Helena
Elisabeth 1 Elizabeth
Elise 1 Eloise
Elizabeth 1 Elisabeth
Ella 2 Bella,Elena
Eloise 1 Elise
Emilie 2 Emily
Emily 2 Emilie,Lily
Emmeline 3 Adeline,Emilie,Madeline
Finola 2 Fiona,Viola
Fiona 2 Finola,Viola
Gwendolen 1 Gwendolyn
Gwendolyn 1 Gwendolen
Hallie 2 Millie
Helena 2 Elena
Holly 3 Bella,Ella,Emily,Hallie,Lily
Isabeau 2 Isabel
Isabel 1 Isobel
Isabelle 2 Isabel
Isobel 1 Isabel
Juliet 2 Juliette
Juliette 2 Juliet
Katherine 1 Catherine
Kirsten 2 Kristen
Kristen 2 Kirsten
Lara 1 Cara,Laura,Mara,Sara,Zara
Laura 1 Lara
Lilian 1 Lillian
Lillian 1 Lilian
Lily 2 Emily,Lucy
Louise 3 Elise,Eloise,Lucie
Lucie 2 Lucy
Lucy 2 Lily,Lucie
Madeleine 1 Madeline
Madeline 1 Madeleine
Mara 1 Cara,Lara,Sara,Zara
Millie 2 Hallie
Nora 1 Norah
Norah 1 Nora
Sara 1 Cara,Lara,Mara,Zara
Scarlett 4 Charlotte
Serafina 2 Seraphina
Seraphina 2 Serafina
Sofia 2 Sophia
Sophia 2 Sofia
Stella 2 Bella
Susanna 1 Susannah
Susannah 1 Susanna
Tahlia 1 Talia
Talia 1 Tahlia,Thalia
Thalia 1 Talia
Viola 2 Finola,Fiona,Violet
Violet 2 Viola
Vivian 1 Vivien
Vivien 1 Vivian
Zara 1 Cara,Lara,Mara,Sara
I am having some minor trouble with creating a query in Access using SQL. Any help would be greatly appreciated.
I am trying to create a query that looks like this
The database looks like this (I had to recreate it with generic names)
LOG
dispatcher tech zone serviceorder casesummary resolution date_
John Doe Trump MZ 13458215 MZ/ description Replaced Printer 8/1/2015
John Doe Clinton Core 45821654 Core/ description Added Paper 8/1/2015
John Doe Smith WA 12458254 WA/ description WOA 8/1/2015
John Doe Smith WA 15465224 WA/ description Replaced Printer 8/2/2015
John Doe Williams WB 15468521 WB/ description Replaced Scangun 8/2/2015
John Doe Jones WFF 48593258 WFF/ description Replaced Scangun 8/3/2015
John Doe Jones WFF 15487528 WFF/ description Replaced printer 8/4/2015
Bob Dole Jones WA 65328451 WA/ description WOA 8/4/2015
Bob Dole Williams WB 48521596 WB/ description WOA 8/5/2015
Bob Dole Trump WC 34852369 WC/ description WOA 8/5/2015
Bob Dole Trump WC 63214789 WC/ description Replaced Printer 8/5/2015
Bob Dole Williams WB 52369852 WB/ description Added Paper 8/6/2015
Bob Dole Johnson WE 25896325 WE/ description WOA 8/6/2015
Jack Hill Jones WC 78521478 WC/ description Replaced Printer 8/6/2015
Jack Hill Jones WC 52585258 WC/ description Replaced Scangun 8/7/2015
Jack Hill Johnson WD 12457898 WD/ description Replaced Scangun 8/8/2015
Jack Hill Clinton Core 45698523 Core/ description Replaced printer 8/8/2015
Jack Hill Smith WA 32589654 WA/ description WOA 8/8/2015
The current code I have is this
SELECT DISTINCT Format(Log.Date_,"ddd") AS [Day], LOG.Date_,
(select COUNT(*) FROM LOG
Where Zone_of_call = "WFF") AS WA
FROM LOG
WHERE (((LOG.Date_) >= [Start Date] And (LOG.Date_) <= [End Date]))
ORDER BY LOG.Date_;
Where the database is LOG. I skipped techs and dispatches and jumped to the Columns for the daily count of each case by zone.
In Oracle SQL, I wish to find all user names,whose Last name contains some specific Characters like ('Z','X','D','F') Or contains Some Range of Characters from 'A-F'.
I tried this:
SELECT user_last_name
FROM userbase
WHERE user_last_name LIKE '%A%' OR user_last_name LIKE '%F%' .
So How can I go about it.
And I written facebook in question although its not directly related to it,because,its the example given by my sir.
UPDATE: I tried the above code,it works with so many OR's, but How can we define some range to search for like IN('Z','X','D','F') or IN ('A-F')
If you are using a recent version of Oracle, you should be able to use regular expressions
SQL> ed
Wrote file afiedt.buf
1 select first_name, last_name
2 from employees
3* where regexp_like( last_name, 'Z|X|D|[A-F]' )
SQL> /
FIRST_NAME LAST_NAME
-------------------- -------------------------
Ellen Abel
Sundar Ande
Mozhe Atkinson
David Austin
Hermann Baer
Shelli Baida
Amit Banda
Elizabeth Bates
Sarah Bell
David Bernstein
Laura Bissot
Harrison Bloom
Alexis Bull
Anthony Cabrio
Gerald Cambrault
Nanette Cambrault
John Chen
Kelly Chung
Karen Colmenares
Curtis Davies
Lex De Haan
Julia Dellinger
Jennifer Dilly
Louise Doran
Bruce Ernst
Alberto Errazuriz
Britney Everett
Daniel Faviet
Pat Fay
Kevin Feeney
Jean Fleaur
Tayler Fox
Adam Fripp
Samuel McCain
Allan McEwen
Donald OConnell
Eleni Zlotkey
37 rows selected.
If you want the search to be case-insensitive
SQL> ed
Wrote file afiedt.buf
1 select first_name, last_name
2 from employees
3* where regexp_like( last_name, 'Z|X|D|[A-F]', 'i' )
SQL> /
FIRST_NAME LAST_NAME
-------------------- -------------------------
Ellen Abel
Sundar Ande
Mozhe Atkinson
David Austin
Hermann Baer
Shelli Baida
Amit Banda
Elizabeth Bates
Sarah Bell
David Bernstein
Laura Bissot
Harrison Bloom
Alexis Bull
Anthony Cabrio
Gerald Cambrault
Nanette Cambrault
John Chen
Kelly Chung
Karen Colmenares
Curtis Davies
Lex De Haan
<<snip>>
Matthew Weiss
Jennifer Whalen
Eleni Zlotkey
93 rows selected.
You can use INSTR to test whether characters exist in your field, like so:
SELECT
user_last_name
FROM
userbase
WHERE 0 < INSTR(user_last_name,'A')
or 0 < INSTR(user_last_name,'B')
...repeat for each character you want to test for...