I want to write a comparation procedure (t-sql) for site seo.
I have a table with field 'url' (nvarchar()) that contain a part of site url's.
Ex: 'mysyte.com/?id=2'. Also this table for each url contains metadata, that i need to extract.
The main problem is that full url on site looks like 'mysyte.com/?id=2®ion=0&page=1', and i just need to ignore everething, except url in table:
I mean: 'mysyte.com/?id=2' => is a part of 'mysyte.com/?id=2®ion=0&page=1'
You can use the LIKE operator to compare the content of a T-SQL string, e.g.
SELECT * FROM [table] WHERE [field] LIKE '%stringtosearchfor%'
The percent character '%' is a wild card- in this case it says return any records where [field] at least contains the value "stringtosearchfor".
SELECT *
FROM myTable
WHERE URL = LEFT('mysyte.com/?id=2®ion=0&page=1', LEN(URL))
Or use CHARINDEX
http://msdn.microsoft.com/en-us/library/aa258228(v=SQL.80).aspx
you can use CHARINDEX in t-sql.
select * from table where CHARINDEX(url, 'http://url.com/url?url...') > 0
Related
I'm just taking a look at the following query
select * from tablename
where id like '%%';
So that it can handle parameters to include all of the data or filtered data like bellow
select * from tablename
where id like '%1%';
Which is fine for most parameters I use but this seems wrong for an ID because it will return all data that has IDs containing 1 which I don't want
To get around this I can only append the where clause if the ID is given but that seems like a pain in the butt
Is it possible to use a different type of where clause so that a wildcard can be used in a where equals clause instead of a where like clause, example
select * from tablename
where id = '*';
So that the same query can be used to return all or filtered data? Pass parameter '*' for all or parameter '1' for ID 1 specifically
(I'm not sure if it matters for this case but I'm using PostgreSQL 9.6.12 in this example)
This would often be expressed as:
where (id = :id or :id is null)
null is the "magic" value that represents all rows.
I'm trying to compare two columns from a table. In which i have to check the email is containing his mobile number or not.
TableName:- Table1
TableColumns:- id,email,MOB
Ex.
SQL:
'SELECT * FROM Tabel1 WHERE email LIKE %MOB%'
Laravel :
Tabel1::whereColumn('email', 'LIKE','%MOB%')->get();
I have Tried this above query but it is showing syntax error.
Lets start by answering you question SQL-wise, anything in quotes is a literal to SQL, so you need to use column reference and add the wildcard symbols. You can do that like this:
SELECT * FROM Table1 WHERE email LIKE CONCAT('%', MOB, '%');
Now lets look at Laravel now, the 3rd argument to where expects a literal value not another column. You can overcome this via either whereRaw or DB::raw:
Table1::whereRaw("email LIKE CONCAT('%', MOB, '%')");
or
Table1::where('email', 'LIKE', DB::raw("CONCAT('%', MOB, '%')"));
You should try this
SELECT * FROM Tabel1 WHERE email LIKE '%' +MOB+'%'
SELECT * FROM `table` WHERE `email` LIKE '%MOB%';
I have a table Product which looks like this:
Name (nvarchar(100), not null)
It has data that looks like this:
4503-U**F19
When I query like this:
select * from Product where Name = '4503-U**F19'
I get nothing back... what gives?
Is there some special way to escape a where clause that contains an asterisk?
I'm probably staring at the answer and can't see it.
Have you tried the N in the prefix?
select * from Product where Name = N'4503-U**F19'
I'm trying to make a search feature that will search multiple columns to find a keyword based match. This query:
SELECT title FROM pages LIKE %$query%;
works only for searching one column, I noticed separating column names with commas results in an error. So is it possible to search multiple columns in mysql?
If it is just for searching then you may be able to use CONCATENATE_WS.
This would allow wild card searching.
There may be performance issues depending on the size of the table.
SELECT *
FROM pages
WHERE CONCAT_WS('', column1, column2, column3) LIKE '%keyword%'
You can use the AND or OR operators, depending on what you want the search to return.
SELECT title FROM pages WHERE my_col LIKE %$param1% AND another_col LIKE %$param2%;
Both clauses have to match for a record to be returned. Alternatively:
SELECT title FROM pages WHERE my_col LIKE %$param1% OR another_col LIKE %$param2%;
If either clause matches then the record will be returned.
For more about what you can do with MySQL SELECT queries, try the documentation.
If your table is MyISAM:
SELECT *
FROM pages
WHERE MATCH(title, content) AGAINST ('keyword' IN BOOLEAN MODE)
This will be much faster if you create a FULLTEXT index on your columns:
CREATE FULLTEXT INDEX fx_pages_title_content ON pages (title, content)
, but will work even without the index.
1)
select *
from employee em
where CONCAT(em.firstname, ' ', em.lastname) like '%parth pa%';
2)
select *
from employee em
where CONCAT_ws('-', em.firstname, em.lastname) like '%parth-pa%';
First is usefull when we have data like : 'firstname lastname'.
e.g
parth patel
parth p
patel parth
Second is usefull when we have data like : 'firstname-lastname'. In it you can also use special characters.
e.g
parth-patel
parth_p
patel#parth
Here is a query which you can use to search for anything in from your database as a search result ,
SELECT * FROM tbl_customer
WHERE CustomerName LIKE '%".$search."%'
OR Address LIKE '%".$search."%'
OR City LIKE '%".$search."%'
OR PostalCode LIKE '%".$search."%'
OR Country LIKE '%".$search."%'
Using this code will help you search in for multiple columns easily
SELECT * FROM persons WHERE (`LastName` LIKE 'r%') OR (`FirstName` LIKE 'a%');
Please try with above query.
I'm looking for a character that I can use in an Oracle contains to get ALL results.
If I search for the string "test" in a title column I use this statement:
select *
from my_table
where contains (title,
'<query><textquery grammar="CTXCAT">test</textquery></query>') > 0
With this statement I get the rows which have the "test"-string included in title-column.
BUT: Is there any way to use contains and select ALL rows?
Would this work for you?
select * from my_table
where title like
'<query><textquery grammar="CTXCAT">%</textquery></query>'
This uses the LIKE syntax and the % wildcard to achieve what I think you want.
The documentation says wildcards with the Oracle Text CONTAINS() predicate are % and _ just like the LIKE predicate.
Does the following work? I don't have an instance of Oracle handy to test.
select *
from my_table
where contains (title,
'<query><textquery grammar="CTXCAT">%</textquery></query>') > 0