I've been trying to figure out how to query a shopping cart database to find all Orders that contain tangible items (items can be downloadable, therefore, not shipped) that have not been assigned a UPS tracking label. I haven't been able to do it.
The involved tables are as follows:
// dbo.Inventory - details about the individual product being sold
- ProductID int primary - Name nvarchar - IsDownloadable bit -
| 5 | Awesome Shirt | 0 |
| 7 | An Audio Track | 1 |
// dbo.ShoppingCart --("ShopID" groups the items in the cart)
- CartID int primary - ProductID int - ShopID char (guid) - Quantity int -
| 2 | 5 | e854a982c9264a72 | 4 |
| 3 | 7 | e854a982c9264a72 | 1 |
// dbo.Orders - Order information (shipping address, etc)
- OrderID int primary - ShopID char(x) - BillingInfoColumns -
| 13 | e854a982c9264a72 | Name,Address,etc |
// dbo.Tracking - Shipments' (note: a shipment can contain several items) tracking numbers
- TrackingID int primary - OrderID int - TrackingNumber char(x) -
| 5 | 13 | Ze5Whatever... |
// dbo.ShippedItems - Maps a ShoppingCart's shipped items to tracking numbers
- ShippingID int primary - TrackingID int - CartID int - QuantityInShipment int
| 6 | 5 | 2 | 3 |
Hopefully the above provides an reasonable approximation of how the DB is designed.
So, to clarify what I think I need:
SELECT all OrderIDs that have NOT had ALL their tangible items Shipped.
Non-tangible items are IsDownloadable = 1
Must take into account the ShoppingCart.Quantity column. If we order 4 t-shirts we may put them in one box (with one UPS tracking label). Then again, we may put 2 per box. Or we may put one pair of jeans with one shirt in one same box (again, with one tracking label)...etc.
I have been concocting crap with endless JOINs and nested WHERE NOT IN (SELECT * FROM)s to no avail. Sadly, I can't seem to wrap my head around it...I'm still waiting for my eureka moment.
I'm relatively new to SQL and database design so any information or (constructive) criticism will be greatly appreciated. Feel free to poke holes in the design of the database itself if you think that will help. :-)
// I wish I could run this on my brain right now...
// (Neurons, apparently, are "excitable")
UPDATE Brain SET Neuron = 'Excited' WHERE Cortex = 'SQL'
UPDATE
Here is what I came up with thanks to Benoit Vidis. This is the actual query I'm using on my real tables/data:
SELECT
d.OrderID
FROM
Person.ShoppingCart c
JOIN
Inventory.Item i
ON
i.ItemID = c.ItemID
JOIN
Orders.Details d
ON
d.ShopID = c.ShopID
LEFT JOIN
Orders.Shipping s
ON
d.OrderID = s.OrderID
LEFT JOIN
Orders.ShippedItems si
ON
s.ShippingID = si.ShippingID
WHERE
i.DownloadableMedia = 0 AND
d.Billed = 1 AND
d.Ordered = 1
GROUP BY
d.OrderID
HAVING
SUM(c.Quantity) > CASE WHEN SUM(si.Quantity) IS NULL THEN 0 ELSE SUM(si.Quantity) END
You might be able to do it using the HAVING clause. In MySQL, it would give something like:
SELECT
c.OrderID,
SUM(c.Quantity) AS tangible_products_number,
SUM(s.QuantityInShipment) as shipped_items_number
FROM
(
Inventory i,
ShoppingCart c
)
LEFT JOIN
ShippedItems s
ON
c.OrderID = s.OrderID
WHERE
i.ProductID = c.ItemID AND
i.IsDOwnloadable = 0 AND
c.OrderID = t.OrderID AND
s.CartID = c.ID
GROUP BY
c.OrderID
HAVING
SUM(c.Quantity) > SUM(s.QuantityInShipment)
The group by syntax will probably need to be adapted for SQL-Server
Can you query dbo.Tracking where TrackingNumber is Null? Would that give you the required information?
Related
I take a Database course in which we have listings of AirBnBs and need to be able to do some SQL queries in the Relationship-Model we made from the data, but I struggle with one in particular :
I have two tables that we are interested in, Billing and Amenities. The first one have the id and price of listings, the second have id and wifi (let's say, to simplify, that it equals 1 if there is Wifi, 0 otherwise). Both have other attributes that we don't really care about here.
So the query is, "What is the difference in the average price of listings with and without Wifi ?"
My idea was to build to JOIN-tables, one with listings that have wifi, the other without, and compare them easily :
SELECT avg(B.price - A.price) as averagePrice
FROM (
SELECT Billing.price, Billing.id
FROM Billing
INNER JOIN Amenities
ON Billing.id = Amenities.id
WHERE Amenities.wifi = 0
) A, (
SELECT Billing.price, Billing.id
FROM Billing
INNER JOIN Amenities
ON Billing.id = Amenities.id
WHERE Amenities.wifi = 1) B
WHERE A.id = B.id;
Obviously this doesn't work... I am pretty sure that there is a far easier solution to it tho, what do I miss ?
(And by the way, is there a way to compute the absolute between the difference of price ?)
I hope that I was clear enough, thank you for your time !
Edit : As mentionned in the comments, forgot to say that, but both tables have idas their primary key, so that there is one row per listing.
Just use conditional aggregation:
SELECT AVG(CASE WHEN a.wifi = 0 THEN b.price END) as avg_no_wifi,
AVG(CASE WHEN a.wifi = 1 THEN b.price END) as avg_wifi
FROM Billing b JOIN
Amenities a
ON b.id = a.id
WHERE a.wifi IN (0, 1);
You can use a - if you want the difference instead of the specific values.
Let's assume we're working with data like the following (problems with your data model are noted below):
Billing
+------------+---------+
| listing_id | price |
+------------+---------+
| 1 | 1500.00 |
| 2 | 1700.00 |
| 3 | 1800.00 |
| 4 | 1900.00 |
+------------+---------+
Amenities
+------------+------+
| listing_id | wifi |
+------------+------+
| 1 | 1 |
| 2 | 1 |
| 3 | 0 |
+------------+------+
Notice that I changed "id" to "listing_id" to make it clear what it was (using "id" as an attribute name is problematic anyways). Also, note that one listing doesn't have an entry in the Amenities table. Depending on your data, that may or may not be a concern (again, refer to the bottom for a discussion of your data model).
Based on this data, your averages should be as follows:
Listings with wifi average $1600 (Listings 1 and 2)
Listings without wifi (just 3) average 1800).
So the difference would be $200.
To achieve this result in SQL, it may be helpful to first get the average cost per amenity (whether wifi is offered). This would be obtained with the following query:
SELECT
Amenities.wifi AS has_wifi,
AVG(Billing.price) AS avg_cost
FROM Billing
INNER JOIN Amenities ON
Amenities.listing_id = Billing.listing_id
GROUP BY Amenities.wifi
which gives you the following results:
+----------+-----------------------+
| has_wifi | avg_cost |
+----------+-----------------------+
| 0 | 1800.0000000000000000 |
| 1 | 1600.0000000000000000 |
+----------+-----------------------+
So far so good. So now we need to calculate the difference between these 2 rows. There are a number of different ways to do this, but one is to use a CASE expression to make one of the values negative, and then simply take the SUM of the result (note that I'm using a CTE, but you can also use a sub-query):
WITH
avg_by_wifi(has_wifi, avg_cost) AS
(
SELECT Amenities.wifi, AVG(Billing.price)
FROM Billing
INNER JOIN Amenities ON
Amenities.listing_id = Billing.listing_id
GROUP BY Amenities.wifi
)
SELECT
ABS(SUM
(
CASE
WHEN has_wifi = 1 THEN avg_cost
ELSE -1 * avg_cost
END
))
FROM avg_by_wifi
which gives us the expected value of 200.
Now regarding your data model:
If both your Billing and Amenities table only have 1 row for each listing, it makes sense to combine them into 1 table. For example: Listings(listing_id, price, wifi)
However, this is still problematic, because you probably have a bunch of other amenities you want to model (pool, sauna, etc.) So you might want to model a many-to-many relationship between listings and amenities using an intermediate table:
Listings(listing_id, price)
Amenities(amenity_id, amenity_name)
ListingsAmenities(listing_id, amenity_id)
This way, you could list multiple amenities for a given listing without having to add additional columns. It also becomes easy to store additional information about an amenity: What's the wifi password? How deep is the pool? etc.
Of course, using this model makes your original query (difference in average cost of listings by wifi) a bit tricker, but definitely still doable.
Greetings Benevolent Gods of Stackoverflow,
I am presently struggling to get a spatially enabled query to work for a SQL assignment I am working on. The wording is as follows:
SELECT PURCHASES.TotalPrice, STORES.GeoLocation, STORES.StoreName
FROM MuffinShop
join (SELECT SUM(PURCHASES.TotalPrice) AS StoreProfit, STORES.StoreName
FROM PURCHASES INNER JOIN STORES ON PURCHASES.StoreID = STORES.StoreID
GROUP BY STORES.StoreName
HAVING (SUM(PURCHASES.TotalPrice) > 600))
What I am trying to do with this query is perform a function query (like avg, sum etc) and get the spatial information back as well. Another example of this would be:
SELECT STORES.StoreName, AVG(REVIEWS.Rating),Stores.Shape
FROM REVIEWS CROSS JOIN
STORES
GROUP BY STORES.StoreName;
This returns a Column 'STORES.Shape' is invalid in the select list because it is not contained in either an aggregate function or the GROUP BY clause. error message.
I know I require a sub query to perform this task, I am just having endless trouble getting it to work. Any help at all would be wildly appreciated.
There are two parts to this question, I would tackle the first problem with the following logic:
List all the store names and their respective geolocations
Get the profit for each store
With that in mind, you need to use the STORES table as your base, then bolt the profit onto it through a sub query or an apply:
SELECT s.StoreName
,s.GeoLocation
,p.StoreProfit
FROM STORES s
INNER JOIN (
SELECT pu.StoreId
,StoreProfit = SUM(pu.TotalPrice)
FROM PURCHASES pu
GROUP BY pu.StoreID
) p
ON p.StoreID = s.StoreID;
This one is a little more efficient:
SELECT s.StoreName
,s.GeoLocation
,profit.StoreProfit
FROM STORES s
CROSS APPLY (
SELECT StoreProfit = SUM(p.TotalPrice)
FROM PURCHASES p
WHERE p.StoreID = s.StoreID
GROUP BY p.StoreID
) profit;
Now for the second part, the error that you are receiving tells you that you need to GROUP BY all columns in your select statement with the exception of your aggregate function(s).
In your second example, you are asking SQL to take an average rating for each store based on an ID, but you are also trying to return another column without including that inside the grouping. I will try to show you what you are asking SQL to do and where the issue lies with the following examples:
-- Data
Id | Rating | Shape
1 | 1 | Triangle
1 | 4 | Triangle
1 | 1 | Square
2 | 1 | Triangle
2 | 5 | Triangle
2 | 3 | Square
SQL Server, please give me the average rating for each store:
SELECT Id, AVG(Rating)
FROM Store
GROUP BY StoreId;
-- Result
Id | Avg(Rating)
1 | 2
2 | 3
SQL Server, please give me the average rating for each store and show its shape in the result (but don't group by it):
SELECT Id, AVG(Rating), Shape
FROM Store
GROUP BY StoreId;
-- Result
Id | Avg(Rating) | Shape
1 | 2 | Do I show Triangle or Square ...... ERROR!!!!
2 | 3 |
It needs to be told to get the average for each store and shape:
SELECT Id, AVG(Rating), Shape
FROM Store
GROUP BY StoreId, Shape;
-- Result
Id | Avg(Rating) | Shape
1 | 2.5 | Triangle
1 | 1 | Square
2 | 3 | Triangle
2 | 3 | Square
As in any spatial query you need an idea of what your final geometry will be. It looks like you are attempting to group by individual stores but delivering an average rating from the subquery. So if I'm reading it right you are just looking to get the stores shape info associated with the average ratings?
Query the stores table for the shape field and join the query you use to get the average rating
select a.shape
b.*
from stores a inner join (your Average rating query with group by here) b
on a.StoreID = b.Storeid
I'm a little stuck here. I'm trying to modify a returned View based on a condition. I'm fairly green on SQL and am having a bit of difficultly with the returned result. Heres a partial component of the view I wrote:
WITH A AS (
SELECT
ROW_NUMBER() OVER (PARTITION BY fkidContract,fkidTemplateItem ORDER BY bStdActive DESC, dtdateplanned ASC) AS RANK,
tblWorkItems.fkidContract AS ContractNo,
....
FROM tblWorkItems
WHERE fkidTemplateItem IN
(2895,2905,2915,2907,2908,
2909,3047,2930,2923,2969,
2968,2919,2935,2936,2927,
2970,2979)
AND ...
)
SELECT * FROM A WHERE RANK = 1
The return result is similar to the following:
ContractNo| ItemNumber | Planned | Complete
001 | 100 | 01/01/1900 | 02/01/1900
001 | 101 | 03/04/1900 | 02/01/1901
001 | 102 | 03/06/1901 | 02/08/1900
002 | 100 | 01/03/1911 | 02/08/1913
This gives me the results I expect, but due a nightmare crystal report I need to alter this view slightly. I want to take this returned result set and modify an existing column with a value pulled from the same table and the same Contract relationship, something like the following:
UPDATE A
SET A.Completed = ( SELECT R.Completed
FROM myTable R
INNER JOIN A
ON A.ContractNo = R.ContractNo
WHERE A.ItemNumber = 100 AND R.ItemNumber = 101
)
What I'm trying to do is modify the "Completed Date" of one task and make it the complete date of another task if they both share the same ContractNo field value.
I'm not sure about the ItemNumber relationships between A and R (perhaps it was just for testing...), but it seems like you don't really want to UPDATE anything, but you want to use a different value under some circumstances. So, maybe you just want to change the non-cte part of your query to something like:
SELECT A.ContractNo, A.ItemNumber, A.Planned,
COALESCE(R.Completed,A.Completed) as Completed
FROM A
LEFT OUTER JOIN myTable R
ON A.ContractNo = R.ContractNo
AND A.ItemNumber = 100 AND R.ItemNumber = 101 -- I'm not sure about this part
WHERE A.Rank = 1
So it turns out that actually reading the vendor documentation helps :)
SELECT
column1,
column2 =
case
when date > 1999 then 'some value'
when date < 1999 then 'other value'
else 'back to the future'
end
FROM ....
For reference, the total query did a triple inner join over ~5 million records and this case statement was surprisingly performant.
I suggest that this gets closed as a duplicate.
I have a query I need to perform to show search results for a project. What needs to happen, I need to sort the results by the "horsesActiveDate" and this applies to all of them except for any ad with the adtypesID=7. Those results are sorted by date but they must always result after all other ads.
So I will have all my ads in the result set be ordered by the Active Date AND adtypesID != 7. After that, I need all adtypesID=7 to be sorted by Active Date and appended at the bottom of all the results.
I'm hoping to put this in one query instead of two and appending them together in PHP. The way the code is written, I have to find a way to get it all in one query.
So here is my original query which has worked great until I had to ad the adtypesID=7 which has different sorting requirements.
This is the query that exists now that doesn't take into account the adtypesID for sorting.
SELECT
horses.horsesID,
horsesDescription,
horsesActiveDate,
adtypesID,
states.statesName,
horses_images.himagesPath
FROM horses
LEFT JOIN states ON horses.statesID = states.statesID
LEFT JOIN horses_images ON horses_images.himagesDefault = 1 AND horses_images.horsesID = horses.horsesID AND horses_images.himagesPath != ''
WHERE
horses.horsesStud = 0
AND horses.horsesSold = 0
AND horses.horsesID IN
(
SELECT DISTINCT horses.horsesID
FROM horses
LEFT JOIN horses_featured ON horses_featured.horsesID = horses.horsesID
WHERE horses.horsesActive = 1
)
ORDER BY adtypesID, horses.horsesActiveDate DESC
My first thought was to do two queries where one looked for all the ads that did not contain adtypesID=7 and sort those as the query does, then run a second query to find only those ads with adtypesID=7 and sort those by date. Then take those two results and append them to each other. Since I need to get this all into one query, I can't use a php function to do that.
Is there a way to merge the two query results one after the other in mysql? Is there a better way to run this query that will accomplish this sorting?
The Ideal Results would be as below (I modified the column names so they would be shorter):
ID | Description | ActiveDate | adtypesID | statesName | himagesPath
___________________________________________________________________________
3 | Ad Text | 06-01-2010 | 3 | OK | image.jpg
2 | Ad Text | 05-31-2010 | 2 | LA | image1.jpg
9 | Ad Text | 03-01-2010 | 4 | OK | image3.jpg
6 | Ad Text | 06-01-2010 | 7 | OK | image5.jpg
6 | Ad Text | 05-01-2010 | 7 | OK | image5.jpg
6 | Ad Text | 04-01-2010 | 7 | OK | image5.jpg
Any help that can be provided will be greatly appreciated!
I am not sure about the exact syntax in MySQL, but something like
ORDER BY case when adtypesID = 7 then 2 else 1 end ASC, horses.horsesActiveDate DESC
would work in many other SQL dielects.
Note that most SQL dialects allow the order by to not only be a column, but an expression.
This should work:
ORDER BY (adtypesID = 7) ASC, horses.horsesActiveDate DESC
Use a Union to append two queries together, like this:
SELECT whatever FROM wherever ORDER BY something AND adtypesID!=7
UNION
SELECT another FROM somewhere ORDER BY whocares AND adtypesID=7
http://dev.mysql.com/doc/refman/5.0/en/union.html
I re-wrote your query as:
SELECT h.horsesID,
h.horsesDescription,
h.horsesActiveDate,
adtypesID,
s.statesName,
hi.himagesPath
FROM HORSES h
LEFT JOIN STATES s ON s.stateid = h.statesID
LEFT JOIN HORSES_IMAGES hi ON hi.horsesID = h.horsesID
AND hi.himagesDefault = 1
AND hi.himagesPath != ''
LEFT JOIN HORSES_FEATURED hf ON hf.horsesID = h.horsesID
WHERE h.horsesStud = 0
AND h.horsesSold = 0
AND h.horsesActive = 1
ORDER BY (adtypesID = 7) ASC, h.horsesActiveDate DESC
The IN subquery, using a LEFT JOIN and such, will mean that any horse record whose horsesActive value is 1 will be returned - regardless if they have an associated HORSES_FEATURED record. I leave it to you for checking your data to decide if it should really be an INNER JOIN. Likewise for the STATES table relationship...
This is sort of what I want to do, but MySQL doesn't seem to accept it.
SELECT Name, Content, Lft, Rht FROM Articles WHERE
(Lft > (SELECT Lft FROM Articles WHERE idArticle = 1))
AND WHERE
(Rht < (SELECT Rht FROM Articles WHERE idArticle = 1));
I'm implementing the modified preorder tree transversal algorithm, and I want to get all the children of an Article using a single database query.
The Articles table looks like this:
Articles
+=============+===========+
| Type | Name |
+=============+===========+
| VARCHAR(45) | Name |
+-------------+-----------+
| LONGTEXT | Content |
+-------------+-----------+
| INT | Lft |
+-------------+-----------+
| INT | Rht |
+-------------+-----------+
| INT | idArticle |
+-------------+-----------+
idArticle is a primary key, and there are UNIQUE indexes on the Lft and Rht columns.
How might something like this be accomplished?
*Note: I'm currently using MySQL but I'd like to avoid any MySQL extensions where possible, because there are possible plans to move to another DB like Postgres or Oracle sometime in the future...
It's not being accepted because the WHERE keyword can only appear once in a query (outside of a subquery):
SELECT x.name,
x.content,
x.lft,
x.rht
FROM ARTICLES x
WHERE EXISTS(SELECT NULL
FROM ARTICLES y
WHERE y.idarticle = 1
AND y.lft < x.lft)
AND EXISTS(SELECT NULL
FROM ARTICLES z
WHERE z.idarticle = 1
AND z.rht > x.rht)
Apparently it was just a simple syntax error (too many WHERE), but if you want to avoid the scalar subselect, you could also do a join (with the potential advantage that the row with idArticle 1 only needs to be loaded once, an optimization that your query planner may or may not be able to figure out by itself):
SELECT a.Name, a.Content, a.Lft, a.Rht FROM Articles a
join Articles b on (b.idArticle =1 )
where a.lft > b.lft and a.rht < b.rht;
Alternate equivalent
SELECT a.Name, a.Content, a.Lft, a.Rht
FROM Articles a
join Articles b on a.lft > b.lft
and a.rht < b.rht
AND b.idArticle = 1 ;