I have a SQLite DB that has people LastName, FirstName, Department and I need to make a query that shows me any people with the same First & Last Names. I've found the following statement that supposedly does what I want for a single field, however it doesn't seem to work for me when I try to use it to pull all records with just the last name being the same. How can I do this?
Select myField From myTable Group by myField Where count(myField)>1
try:
Select
firstname,LastName,Count(*)
From myTable
Group by firstname,LastName
HAVING Count(*)>1
GROUP BY combines rows where the named values are the same.
HAVING removes groups that do not meet the condition.
The above query will list the first and last names, along with a count of duplicates for all first/last names that actually have duplicates.
Firstly, you need to use HAVING, not WHERE to qualify the GROUPed BY result:
SELECT myField FROM myTable GROUP BY myField HAVING COUNT(myField) > 1
Secondly, you can extend this to multiple columns like this:
SELECT MyCol1, MyCol2 FROM MyTable
GROUP BY MyCol1, MyCol2
HAVING COUNT(*) > 1
Related
i have this query
SELECT PersonalInfo.id, PersonalInfo.[k-commission], Abs(Not IsNull([PersonalInfo]![k-commission].[Value])) AS CommissionAbsent
FROM PersonalInfo;
and the PersonalInfo.k-commission is a multi value field. the CommissionAbsent shows duplicate values for each k-commission value. when i use DISTINCT i get an error saying that the keyword cannot be used with a multi value field.
now i want to remove the duplicates and show only one result for each. i tried using a WHERE but i dont know how.
edit: i have a lot more columnes and in the example i only showed the few i need.
You can use GROUP BY and COUNT to solve your problem, here is an example for it
SELECT clmn1, clmn2, COUNT(*) as count
FROM table
GROUP BY clmn1, clmn2
HAVING COUNT(*) > 1;
the query groups the rows in the table by the clmn1 and clmn2 columns, and counts the number of occurrences of each group. The HAVING clause is then used to filter the groups and only return the groups that have a count greater than 1, which indicates duplicates.
If you want to select all, then you can do like this
SELECT *
FROM table
WHERE (clmn1, clmn2) IN (SELECT clmn1, clmn2
FROM table
GROUP BY clmn1, clmn2
HAVING COUNT(*) > 1)
SELECT PersonalInfo.id, PersonalInfo.[k-commission], Abs(Not IsNull([PersonalInfo]![k-commission].[Value])) AS CommissionAbsent
FROM PersonalInfo
GROUP BY PersonalInfo.id, PersonalInfo.[k-commission], Abs(Not IsNull([PersonalInfo]![k-commission].[Value]))
HAVING COUNT(*) > 1
I need to know where the mistake is in this oracle query?
SELECT(KEY1),COUNT(*) FROM TABLE1 GROUP BY AGE
SELECT KEY1,COUNT(*) FROM TABLE1 GROUP BY KEY1
There are two problems. First one: You cannot close the parenthesis after the first keyword. Second: You have to group by all keys that are in the query that are not all row dependend. In that case "KEY1". If you want to order by age you have to query age as parameter.
SELECT AGE,COUNT(*) FROM TABLE1 GROUP BY AGE
Your table naming is not very good. I assume you should have a look at group by tutorials like https://www.w3schools.com/sql/sql_groupby.asp or the sql tutorial https://www.w3schools.com/sql/
Your query had an issue. You have to modify your query as below
SELECT KEY1,COUNT(*) FROM TABLE1 GROUP BY KEY1.
Observation:
All the columns that are added in the select statement alongside the aggregate functions, should be included the group by columns.
Your first column does have the bracket in it which should be removed.
Following Example Table Structure:
NR1 | NR2 | PRENAME | LASTNAME
If i query all 4 fields of this table and grouping it´s first 2 fields (NR1,NR2) in mysql,
i can do something like this:
SELECT NR1,NR2,PRENAME,LASTNAME FROM tbl GROUP BY NR1,NR1
But this won´t work in informix.
INFORMIX ERROR: the column (PRENAME) must be in the group by list
After reading some Topics at google, it is an "Informix feature" that all Selected Columns has to be in the Grouping List.
But if i will do that, the result is not that result, that i wish to have.
If i use
DISTINCT
instead GROUP BY the result is similar false, because i can not put the DISTINCTfunction only to column 1 and 2.
So: How can i make a "MYSQL GROUP BY" function ?
Your original syntax is suitable in one database -- MySQL. And, that database says that the results of the non-aggregated columns come from indeterminate rows. So, an equivalent query is just to use MIN() or MAX():
SELECT NR1, NR2, MIN(PRENAME), MIN(LASTNAME)
FROM tbl
GROUP BY NR1, NR1;
My guess is that you want an arbitrary value from just one row. I'd be inclined to concatenate them:
SELECT NR1, NR2, MIN(PRENAME || ' ' || LASTNAME)
FROM tbl
GROUP BY NR1, NR1;
My sample sql query
SELECT EID,p,p1,p2,p3 FROM table 1 GROUP BY EID;
Giving error not part of aggregate function.I wanted to group by only EID not all other p,p1,p2,p3. How do i specify that in sql query.
In most dialects of SQL, you have to specify which column you want, if the column is not in the group by clause. For instance, maybe you want the minimum value:
SELECT EID, min(p), min(p1), min(p2), min(p3)
FROM table 1
GROUP BY EID;
Or, if you wanted all the values from a particular record, use first or last:
SELECT EID, first(p), first(p1), first(p2), first(p3)
FROM table 1
GROUP BY EID;
According to tips from MySQL performance wiki:
Don't use DISTINCT when you have or could use GROUP BY.
Can somebody post example of queries where GROUP BY can be used instead of DISTINCT?
If you know that two columns from your result are always directly related then it's slower to do this:
SELECT DISTINCT CustomerId, CustomerName FROM (...)
than this:
SELECT CustomerId, CustomerName FROM (...) GROUP BY CustomerId
because in the second case it only has to compare the id, but in the first case it has to compare both fields. This is a MySQL specific trick. It won't work with other databases.
SELECT Code
FROM YourTable
GROUP BY Code
vs
SELECT DISTINCT Code
FROM YourTable
The basic rule : Put all the columns from the SELECT clause into the GROUP BY clause
so
SELECT DISTINCT a,b,c FROM D
becomes
SELECT a,b,c FROM D GROUP BY a,b,c
Example.
Relation customer(ssnum,name, zipcode, address) PK(ssnum). ssnum is social security number.
SQL:
Select DISTINCT ssnum from customer where zipcode=1234 group by name
This SQL statement returns unique records for those customer's that have zipcode 1234. At the end results are grouped by name.
Here DISTINCT is no not necessary. because you are selecting ssnum which is already unique because ssnun is primary key. two person can not have same ssnum.
In this case Select ssnum from customer where zipcode=1234 group by name will give better performance than "... DISTINCT.......".
DISTINCT is an expensive operation in a DBMS.