I know that I can validate an input field by adding a inputmaskvalidator tag. I read the documentum doc :
The mask character string:
: numeric characters
& : all characters
A : alphanumeric characters only
? : alphabetic characters only
U : uppercase alphabetic characters only
L : lowercase alphabetic characters only
Example: date mask ##/##/## permits
the input date 12/24/95 To use one of
the mask characters as a literal
member of the mask string, place a
double slash (\) preceding the
character.
Let's guess I want to accept double only to store it as a double in the content server. What must be the inputmask value?
Something like that?
<dmf:inputmaskvalidator inputmask="#.#" controltovalidate="my_double" name="my_double_validator"/>
or
<dmf:inputmaskvalidator inputmask="##.##" controltovalidate="my_double" name="my_double_validator"/>
You must use other type of validator. Inputmaskvalidator is bad for your purpose. Use for example regexpvalidator. Example you can find on this page:
Related
Hi I tried using Regex_replace and it is still not working.
select CASE WHEN sbbb <> ' ' THEN regexp_replace(sbbb,'[a-zA-Z _-#]','']
ELSE sbbb
AS ABCDF
from Table where sccc=1;
This is the query which I am using to remove alphabets and specials characters from string and have only numbers. but it doesnot work. Query returns me the complete string with numbers,characters and special characters .What is wrong in the above query
I am working on a sql query. There is a column in database which contains characters,special characters and numbers. I want to only keep the numbers and remove all the special characters and alphabets. How can I do it in query of DB2. If a use PATINDEX it is not working. please help here.
The allowed regular expression patterns are listed on this page
Regular expression control characters
Outside of a set, the following must be preceded with a backslash to be treated as a literal
* ? + [ ( ) { } ^ $ | \ . /
Inside a set, the follow must be preceded with a backslash to be treated as a literal
Characters that must be quoted to be treated as literals are [ ] \
Characters that might need to be quoted, depending on the context are - &
So for you, this should work
regexp_replace(sbbb,'[a-zA-Z _\-#]','')
I am defining my own Item in and ItemGroup where I have custom values that I don't want to be evaluated to paths
When I try to do transforms, the ./ is being treated as a path and so I only get a single item for transforms and batching.
How can I force the . at the end to be treated as a literal?
For using special characters in the Include attribute you can use the hexadecimal representations of the ASCII characters. For example the symbol . will be represents as 2e. The percent symbol always precedes the hexadecimal representation: %2e.
You can get the full list of special characters to escape from the
official documentation.
Special characters to escape | ASCII to Hex text converter
I would like to have a regular expression to make an Oracle SQL REGEXP_LIKE query that checks
if a string starts with one alphanumeric character
if the string ends with one alphanumeric character
if the "body" of the string contains only alphanumeric character OR these authorized characters (written) : hyphen (dash), dot, apostrophe, space
if the authorised characters are NOT adjacent (to avoid something like "he--'''l..'-lo")
I started with this :
^[a-zA-Z0-9]+(a-zA-Z0-9\-\.'|([^\-\.'])\1)*[a-zA-Z0-9]$
I used backslash to escape assuming that dot and hyphen are metacharacters
I think this is what you want:
^[a-zA-Z0-9]+([-.' ][a-zA-Z0-9]|[a-zA-Z0-9])*\w?$
It looks for
at least 1 alphanumeric (alnum),
followed by
either an authorized character followed by an alphanumeric or just an alphanumeric, repeated any number of times (including 0).
optionally followed by
an alnum
This meets your specification. I'm not sure if starts with one alnum and ends with one alnum means that there must be at least 2 alnums, or if they can be the same. If there must be at least 2 of them, remove the last ? (which make the last alnum optional).
Regards
assuming you meant "authorised characters are NOT adjacent to each other"
try something along these lines
^[a-zA-Z0-9]+([a-zA-Z0-9]+[\-\.' ]?)*[a-zA-Z0-9]$
so that the repeating middle part always has one alphanumeric character followed by zero to one special characters.
When I search one ldap server using the following filter
(cn=%*)
It return all results under the base dn? LDAP treat '%' specially? But I haven't found any description about it.
What is your directory server ?
Are you sure tha '%' is not replace by your command line interpreter or your compiler ?
According to RFC2254 % is not a special character
If a value should contain any of the following characters
Character ASCII value
---------------------------
* 0x2a
( 0x28
) 0x29
\ 0x5c
NUL 0x00
the character must be encoded as the backslash '\' character (ASCII
0x5c) followed by the two hexadecimal digits representing the ASCII
value of the encoded character. The case of the two hexadecimal
digits is not significant.
This simple escaping mechanism eliminates filter-parsing ambiguities
and allows any filter that can be represented in LDAP to be
represented as a NUL-terminated string. Other characters besides the
ones listed above may be escaped using this mechanism, for example,
non-printing characters.
For example, the filter checking whether the "cn" attribute contained
a value with the character "" anywhere in it would be represented as
"(cn=\2a*)".
Note that although both the substring and present productions in the
grammar above can produce the "attr=*" construct, this construct is
used only to denote a presence filter.
I have a Sql statament using special character (ex: ('), (/), (&)) and I don't know how to write them in my VB.NET code. Please help me. Thanks.
Find out the Unicode code point for the character (from http://www.unicode.org) and then use ChrW to convert from the code point to the character. (To put this in another string, use concatenation. I'm somewhat surprised that VB doesn't have an escape sequence, but there we go.)
For example, for the Euro sign (U+20AC) you'd write:
Dim euro as Char = ChrW(&H20AC)
The advantage of this over putting the character directly into source code is that your source code stays "just pure ASCII" - which means you won't have any strange issues with any other program trying to read it, diff it, etc. The disadvantage is that it's harder to see the symbol in the code, of course.
The most common way seems to be to append a character of the form Chr(34)... 34 represents a double quote character. The character codes can be found from the windows program "charmap"... just windows/Run... and type charmap
If you are passing strings to be processed as SQL statement try doubling the characters for example.
"SELECT * FROM MyRecords WHERE MyRecords.MyKeyField = ""With a "" Quote"" "
The '' double works with the other special characters as well.
The ' character can be doubled up to allow it into a string e.g
lSQLSTatement = "Select * from temp where name = 'fred''s'"
Will search for all records where name = fred's
Three points:
1) The example characters you've given are not special characters. They're directly available on your keyboard. Just press the corresponding key.
2) To type characters that don't have a corresponding key on the keyboard, use this:
Alt + (the ASCII code number of the special character)
For example, to type ¿, press Alt and key in 168, which is the ASCII code for that special character.
You can use this method to type a special character in practically any program not just a VB.Net text editor.
3) What you probably looking for is what is called 'escaping' characters in a string. In your SQL query string, just place a \ before each of those characters. That should do.
Chr() is probably the most popular.
ChrW() can be used if you want to generate unicode characters
The ControlChars class contains some special and 'invisible' characters, plus the quote - for example, ControlChars.Quote