SQL Server 2005 - Nested recursive query :( - sql

I have a query that I need to execute that I do not know how to structure.
I have a table called Employees. I have another table called Company. There is a third table called Files. As you can imagine, a Company has Employees, and Employees have Files.
I need to list out all of the Employees in my database. The challenge is, I need to list the total number of Files in the same company as the Employee. I have tried variations on the following without any luck:
SELECT
e.FirstName,
e.LastName,
e.Company,
(SELECT COUNT(*) FROM Files f WHERE f.EmployeeID IN (SELECT [ID] FROM Employees e2 WHERE e2.CompanyID=e.CompanyID)) as 'FileCount'
FROM
Employees e
What am I doing wrong? Thank you!

Try this:
SELECT
e.FirstName,
e.LastName,
e.Company,
(
SELECT COUNT(*)
FROM Files f
JOIN Employees e2 ON f.EmployeeID = e2.id
WHERE e2.CompanyID = e.CompanyID
) as 'FileCount'
FROM
Employees e

There are a lot of ways to get that. If the performance is a concern, this is more optimal according to estimated execution plan costs.
SELECT
e.FirstName,
e.LastName,
e.Company,
COUNT(f.FileId)
FROM
Employees e
INNER JOIN Files f ON e.EmployeeID = f.EmployeeID
GROUP BY
e.FirstName,
e.LastName,
e.Company

A solution with no correlation in SELECT clause. Probably quicker...
SELECT
e.FirstName,
e.LastName,
e.Company,
foo.FileCount
FROM
Employees e
JOIN
(
SELECT
COUNT(*) AS FileCount, --OR COUNT(DISTINCT something) ?
e2.Company, f.EmployeeID
FROM
Files f JOIN Employees e2 ON f.EmployeeID = e2.id
GROUP BY
e2.Company, f.EmployeeID
) foo ON e.Company = foo.Company AND e.id = foo.EmployeeID

How about:
SELECT
e.FirstName,
e.LastName,
e.Company,
select count(*) from Files f, Employees e where f.EmployeeID=e.EmployeeID and e.CompanyID=emp.CompanyID
FROM
Employees emp

WITH FilesPerCompany (CompanyID, NumberOfFiles)
AS (SELECT c.ID AS CompanyID,
COUNT(*) AS NumberOfFiles
FROM Companies c
INNER JOIN Employees e ON c.ID = e.CompanyID
INNER JOIN Files f ON e.ID = f.EmployeeID
GROUP BY c.ID
)
SELECT e.FirstName,
e.LastName,
e.Company,
COALESCE(s.NumberOfFiles, 0) AS NumberOfFilesPerCompany
FROM Employees e
LEFT JOIN FilesPerCompany s
ON s.CompanyID = e.CompanyID

The following statement uses recursive joins to iterate down employees who manage other employees who manage other employees .... etc. Our structure is a little convoluted as the management structure is role based which actually allows an employee to have more than 1 manager. You can add a reference to Files within this recursion.
WITH Manager as
(SELECT c.Forenames + ' ' + c.Surname as Employee,
c2.Forenames + ' ' + c2.Surname AS Manages,
c.accountid AS AccountID, c.[Status] AS [Status]
FROM [intranet].[dbo].[tblContact] c
LEFT JOIN tblContactPost cp ON cp.contactid = c.contactid
LEFT JOIN tblPost p ON p.ParentRoleId = cp.RoleID AND p.ParentPostArea = cp.PostArea AND p.ParentPostNo = cp.PostNo
INNER JOIN tblContactPost cp2 ON cp2.RoleId = p.RoleId AND cp2.PostArea = p.PostArea AND cp2.PostNo = p.PostNo
INNER JOIN tblContact c2 ON c2.ContactID = cp2.ContactId
)
,jn AS
(SELECT Employee, Manages
FROM Manager
Where AccountID = 'ad\lgardner' AND [Status] = 'A'
UNION ALL
SELECT c.Employee, c.Manages
FROM jn as p JOIN Manager AS c
ON c.Employee = p.Manages
)
SELECT jn.Employee, jn.Manages
From jn
Order BY 1

Related

Select value from 2 tables with condition

I want to select values Employee ID, employee first name, project name from tables employee and project of the employee assigned to more than one project.
Thanks everybody I can solve them and sorry about this question is not clear
You must use a JOIN
select EmplyoeeID, FirstName, ProjectName
from EmployeeDetail
join ProjectDetail on EmplyoeeDetailID = EmployeeID
where (select count(*) from ProjectDetail where EmplyoeeDetailID = EmployeeID) > 1
Please read more about joins here: https://www.w3schools.com/sql/sql_join.asp
Try this (a simple INNER JOIN)
SELECT e.EmployeeID, e.firstName, p.ProjectName
FROM Employee e
JOIN ProjectDetail p
ON e.EmployeeID = p.EmployeeDetailID
If you want only employees with more than 1 project
SELECT e.EmployeeID, e.firstName, p.ProjectName
FROM Employee e
JOIN ProjectDetail p
ON e.EmployeeID = p.EmployeeDetailID
WHERE
(SELECT COUNT(1) FROM ProjectDetail p2
WHERE p2.EmployeeDetailID = p.EmployeeDetailID) > 1
A window function is probably the most efficient
SELECT
e.EmployeeID,
e.firstName,
p.ProjectName
FROM Employee e
JOIN (
SELECT p.*,
count = COUNT(*) OVER (PARTITION BY p.EmployeeDetailID)
FROM ProjectDetail p
) p ON e.EmployeeID = p.EmployeeDetailID AND p.count > 1;

SQL to find table entries by consulting foreign keys

I have 4 tables as below:
Company: companyid, name
Employees: employeeid, name, companyid
Jobs: jobid, title, companyid
LinkEmpolyeeJob: employeeid, jobid
I want to identify invalid entries in the LinkEmpolyeeJob table where the employee and the job are from different company.
I want to avoid query like below because it was too slow:
select *
from LinkEmpolyeeJob
where (employeeid, jobid) not in (select a.employeeid, b.jobid
from Employees a, Jobs b
where a.companyid = b.companyid);
Anyone help? Thanks!
Try using joins:
select e.*, j.*
from LinkEmpolyeeJob lej join
Employees e
on lej.employeeid = e.employeeid join
Jobs j
on lej.jobid = j.jobid
where e.companyid <> j.companyid
Try using LEFT JOINs like below. (Did not test the query, but should give you idea)
select *
from LinkEmpolyeeJob lej
left join employees e on lej.employeeid = e.employeeid
left join jobs j on e.companyid = j.companyid and lef.jobid = j.jobid
where e.employeeid is null and j.jobid is null

How to get all the information in fewer rows when joining three tables?

Can someone help me in writing Oracle SQL Query for the following scenario:
Company can have multiple departments.
Each department can have multiple Employees.
Employee need not have department assigned but company Id is must.
This is the output I am trying for:
This is the query I have tried So far:
SELECT C.id Company_Id,
C.name Company_Name,
D.id Department_Id,
D.name Department_Name,
E.id Employee_Id,
E.name Employee_Name
FROM Company C
FULL OUTER JOIN Department D
ON D.CompanyId = C.Id
FULL OUTER JOIN Employee E
ON E.CompanyId = C.Id AND E.DepartmentId = D.Id
ORDER BY Company_Id,Department_Id,Employee_Id;
But it gives this output:
EDIT:
Sql fiddle : http://sqlfiddle.com/#!4/df238/3/0
The trick is to convert ON E.CompanyId = C.Id AND E.DepartmentId = D.Id join condition to
ON E.CompanyId = C.Id AND ( E.DepartmentId = D.Id OR E.DepartmentId is null )
SELECT C.id Company_Id,
C.name Company_Name,
D.id Department_Id,
D.name Department_Name,
E.id Employee_Id,
E.name Employee_Name
FROM Company C
FULL OUTER JOIN Department D
ON D.CompanyId = C.Id
FULL OUTER JOIN Employee E
ON E.CompanyId = C.Id AND ( E.DepartmentId = D.Id OR E.DepartmentId is null )
ORDER BY Company_Id,Department_Id,Employee_Id;
Demo

Rewrite SQL Code Using a Join Instead of Subquery

I'm having trouble visualizing how subqueries would look in the form of joins instead. In particular, the following SQL:
SELECT DISTINCT e.EmployeeID, e.LastName, e.FirstName
FROM Employees e
INNER JOIN Orders o ON e.EmployeeID = o.EmployeeID
WHERE EXISTS
(
SELECT c.Country
FROM Customers c
WHERE c.Country = e.Country
)
It would greatly be appreciated if I could receive some tips on what to do when I want to turn a statement with a subquery into a join instead.
You need to be careful about duplicates, but the transformation for EXISTS is quite direct:
SELECT DISTINCT e.EmployeeID, e.LastName, e.FirstName
FROM Employees e INNER JOIN
Orders o
ON e.EmployeeID = o.EmployeeID INNER JOIN
(SELECT DISTINCT c.Country
FROM Customers c
) c
ON c.Country = e.Country
This looks clean. In fact, it is not:
SELECT DISTINCT e.EmployeeID, e.LastName, e.FirstName
FROM Employees e
JOIN Orders o ON o.EmployeeID = e.EmployeeID
JOIN Customers c ON c.Country = e.Country
;
The point is that if there are more than one matching rows for orders and Customers, these will all cause a seperate copy of the Employee record to be merged. These will later have to be suppressed by theDISTINCT(the optimiser might catch this, or it might not)
The point is: you dont need a distinct, since you are only selecting columns from employee:
SELECT e.EmployeeID, e.LastName, e.FirstName
FROM Employees e
WHERE EXISTS(
SELECT * FROM Orders o
WHERE o.EmployeeID = e.EmployeeID
)
AND EXISTS(
SELECT * FROM Customers c
WHERE c.Country = e.Country
);
Or,in a more or less ugly style:
SELECT e.EmployeeID, e.LastName, e.FirstName
FROM Employees e
WHERE EXISTS(
SELECT c.Country
FROM Orders o
JOIN Customers c
ON o.EmployeeID = e.EmployeeID
AND c.Country = e.Country
);

I need sql query to merge info from 2 tables

i`m new in SQL and i need a tip. I got 2 tables ( employee and department ),
employee table as E:
id (int), name(nvarchar), gender(nvarchar), departmentID(int), dateofbirth(datetime)
department table as D :
dep_id(int), name(nvarchar), location(nvarchar), boss_id(int)
That`s what i need as output table:
E.id / E.name / D.name / D.location / (and last which i cant get with simple join is:) D.boss.name (not simple boss id but real employee name from E table)
Just simple question for advanced people :-)
Join the table a second time for the boss. (This is assuming that boss_id FK's to Employee)
SELECT
E.Id,
E.Name,
D.Name,
D.Location,
B.Name
FROM Employee E
INNER JOIN Department D on E.DepartmentID = D.Dep_id
INNER JOIN Employee B ON D.Boss_id = B.Id
You can write a query using cte as well:
WITH CTE AS(
Select
e.ID,
e.name,
d.boss_id,
d.Location as DepartmentLocation,
d.name as DepartmentName
From Employee e
INNER JOIN Department d on d.boss_id =E.id
)
Select c.id, c.name, e.name as BossName, c.DepartmentLocation, c.DepartmentName
from cte c
Inner Join Employee e1 on e1.id=c.boss_id
SELECT e.Id, e.Name, d.Name, d.Location,
(
SELECT e2.Name
FROM tblEmployee as e2
WHERE e2.id = d.boss_id
) AS [Boss name]
FROM tblEmployee as e
INNER JOIN tblDepartment as d
ON e.DepartmentID = d.dep_ID