What's the best way to select only those rows from the table that have been created in last 7 days?
There are dozens of time and date functions in MySQL and I'm a little bit confused about what's the easiest way to do this.
For the sake of this question, assume that you have a table called "my_table" and it contains a row "created_at" which is a DATETIME.
SELECT * FROM my_table WHERE ...
What would you fill in the WHERE clause?
WHERE DATEDIFF(NOW(), created_at) <= 7;
I like it because it reads: "Where the Difference in Date between Now and when it was created is at most 7 (days)." in my own head
...WHERE created_at >= Date_Add(now(), INTERVAL -7 DAY)
This is my preferred way because it's so...clear. But ADDDATE is fine too (and you can use the INTERVAL form with that for clarity as well; its default is days so you see people leaving it off). You don't want to do a calculation on created_at and compare it to now() because that requires the computation on created_at on each row (assuming MySQL doesn't optimise it out), whereas modifying now() and comparing to an unmodified created_at means MySQL does that bit once and uses the result when comparing against rows, not to mention indexes.
...... WHERE created_at >= DATE_SUB(CURRENT_DATE, INTERVAL 7 DAY)
hopefully that will help
WHERE ADDDATE(datefield, 7) > NOW();
SELECT * FROM my_table
WHERE DATE(created_at) >= SUBDATE(DATE(NOW()), 7)
SELECT * FROM my_table WHERE my_table.datefield > sysdate - 7
Related
Hello I have table "os_txn.pay_link" and inside there are many columns.
What I want to do is that I want to count the row numbers by looking at "merchant_id" column for the current day.
So for example what I am looking for an output is that today one of "merchant_id" has
"8" rows. So I want to know the number of rows of the "merchant_id" column for current day.
I think I should use count(*) in view with select statement but couldnt succeed about syntax. So I am open your suggestions thank you.
If I understood you correctly, a simple option would be
select merchant_id, count(*)
from os_txn.pay_link
where date_column = trunc(sysdate)
group by merchant_id;
presuming that date_column contains date only (i.e. for today, 8th of October 2022, that's its value - no hours, minutes or seconds).
If date column contains time component, again - a simple option - would be
select merchant_id, count(*)
from os_txn.pay_link
where trunc(date_column) = trunc(sysdate)
group by merchant_id;
If there's an index on date_column, then such a code wouldn't use it (unless it is a function-based index) so you'd rather modify it to
where date_column >= trunc(sysdate)
and date_column < trunc(sysdate + 1)
If that's not it, do post sample data and desired result.
i have this table:
COD (Integer) (PK)
ID (Varchar)
DATE (Date)
I just want to get the new ID's from today, compared with yesterday (the ID's from today that are not present yesterday)
This needs to be done with just one query, maximum efficiency because the table will have 4-5 millions records
As a java developer i am able to do this with 2 queries, but with just one is beyond my knowledge so any help would be so much appreciated
EDIT: date format is dd/mm/yyyy and every day each ID may come 0 or 1 times
Here is a solution that will go over the base data one time only. It selects the id and the date where the date is either yesterday or today (or both). Then it GROUPS BY id - each group will have either one or two rows. Then it filters by the condition that the MIN date in the group is "today". Those are the id's that exist today but did not exist yesterday.
DATE is an Oracle keyword, best not used as a column name. I changed that to DT. I also assume that your "dt" field is a pure date (as pure as it can be in Oracle, meaning: time of day, which is always present, is 00:00:00).
select id
from your_table
where dt in (trunc(sysdate), trunc(sysdate) - 1)
group by id
having min(dt) = trunc(sysdate)
;
Edit: Gordon makes a good point: perhaps you may have more than one such row per ID, in the same day? In that case the time-of-day may also be different from 00:00:00.
If so, the solution can be adapted:
select id
from your_table
where dt >= trunc(sysdate) - 1 and dt < trunc(sysdate) + 1
group by id
having min(dt) >= trunc(sysdate)
;
Either way: (1) the base table is read just once; (2) the column DT is not wrapped within any function, so if there is an index on that column, it can be used to access just the needed rows.
The typical method would use not exists:
select t.*
from t
where t.date >= trunc(sysdate) and t.date < trunc(sysdate + 1) and
not exists (select 1
from t t2
where t2.id = t.id and
t2.date >= trunc(sysdate - 1) and t2.date < trunc(sysdate)
);
This is a general solution. If you know that there is at most one record per day, there are better solutions, such as using lag().
Use MINUS. I suppose your date column has a time part, so you need to truncate it.
select id from mytable where trunc(date) = trunc(sysdate)
minus
select id from mytable where trunc(date) = trunc(sysdate) - 1;
I suggest the following function index. Without it, the query would have to full scan the table, which would probably be quite slow.
create idx on mytable( trunc(sysdate) , id );
So I have a question (running oracle sql developer), I can't seem to get the syntax of it right.
Let's say T1 has a stat_code column and a last_updated column; I want to query all records which have been in t1.stat_code < 90 for one hour or more.
From research I have come with the following query;
select * from t1
where t1.stat_code <90
and t1.last_updated > (SYSDATE-1/24);
This is right, but also pulls back records which are less than an hour old.
Any help is very much appreciated!
You could also use an INTERVAL literal to explicitly state the duration:
SELECT *
FROM t1
WHERE stat_code < 90
AND last_updated <= SYSTIMESTAMP - INTERVAL '1' HOUR;
I need to list number of column1 that have been added to the database over the selected time period (since the day the list is requested)-daily, weekly (last 7 days), monthly (last 30 days) and quarterly (last 3 months). for example below is the table I created to perform this task.
Column | Type | Modifiers
------------------+-----------------------------+-----------------------------------------------------
column1 character varying (256) not null default nextval
date timestamp without time zone not null default now()
coloumn2 charater varying(256) ..........
Now, I need the total count of entries in column1 with respect the selected time period.
Like,
Column 1 | Date | Coloumn2
------------------+-----------------------------+-----------------------------------------------------
abcdef 2013-05-12 23:03:22.995562 122345rehr566
njhkepr 2013-04-10 21:03:22.337654 45hgjtron
ffb3a36dce315a7 2013-06-14 07:34:59.477735 jkkionmlopp
abcdefgggg 2013-05-12 23:03:22.788888 22345rehr566
From above data, for daily selected time period it should be count= 2
I have tried doing this query
select count(column1) from table1 where date='2012-05-12 23:03:22';
and have got the exact one record matching the time stamp. But I really needed to do it in proper way I believe this is not an efficient way of retrieving the count. Anyone who could help me know the right and efficient way of writing such query would be great. I am new to the database world, and I am trying to be efficient in writing any query.
Thanks!
[EDIT]
Each query currently is taking 175854ms to get process. What could be the efficient way to lessen the time to have it processed accordingly. Any help would be really great. I am using Postgresql to do the same.
To be efficient, conditions should compare values of the sane type as the columns being compared. In this case, the column being compared - Date - has type timestamp, so we need to use a range of tinestamp values.
In keeping with this, you should use current_timestamp for the "now" value, and as confirmed by the documentation, subtracting an interval from a timestamp yields a timestamp, so...
For the last 1 day:
select count(*) from table1
where "Date" > current_timestamp - interval '1 day'
For the last 7 days:
select count(*) from table1
where "Date" > current_timestamp - interval '7 days'
For the last 30 days:
select count(*) from table1
where "Date" > current_timestamp - interval '30 days'
For the last 3 months:
select count(*) from table1
where "Date" > current_timestamp - interval '3 months'
Make sure you have an index on the Date column.
If you find that the index is not being used, try converting the condition to a between, eg:
where "Date" between current_timestamp - interval '3 months' and current_timestamp
Logically the same, but may help the optimizer to choose the index.
Note that column1 is irrelevant to the question; being unique there is no possibility of the row count being different from the number of different values of column1 found by any given criteria.
Also, the choice of "Date" for the column name is poor, because a) it is a reserved word, and b) it is not in fact a date.
If you want to count number of records between two dates:
select count(*)
from Table1
where "Date" >= '2013-05-12' and "Date" < '2013-05-13'
-- count for one day, upper bound not included
select count(*)
from Table1
where "Date" >= '2013-05-12' and "Date" < '2013-06-13'
-- count for one month, upper bound not included
select count(*)
from Table1
where
"Date" >= current_date and
"Date" < current_date + interval '1 day'
-- current date
What I understand from your wording is
select date_trunc('day', "date"), count(*)
from t
where "date" >= '2013-01-01'
group by 1
order by 1
Replace 'day' for 'week', 'month', 'quarter' as needed.
http://www.postgresql.org/docs/current/static/functions-datetime.html#FUNCTIONS-DATETIME-TRUNC
Create an index on the "date" column.
select count(distinct column1) from table1 where date > '2012-05-12 23:03:22';
I assume "number of column1" means "number of distinct values in column1.
Edit:
Regarding your second question (speed of the query): I would assume that an index on the date column should speed up the runtime. Depending on the data content, this could even be declared unique.
To throw another option into the mix...
Add a column of type "date" and index that -- named "datecol" for this example:
create index on tbl_datecol_idx on tbl (datecol);
analyze tbl;
Then your query can use an equality operator:
select count(*) from tbl where datecol = current_date - 1; --yesterday
Or if you can't add the date datatype column, you could create a functional index on the existing column:
create index tbl_date_fbi on tbl ( ("date"::DATE) );
analyze tbl;
select count(*) from tbl where "date"::DATE = current_date - 1;
Note1: you do not need to query "column1" directly as every row has that attribute filled due to the NOT NULL.
Note2: Creating a column named "date" is poor form, and even worse that it is of type TIMESTAMP.
I have a table containing events which happen in my application like people logging in and people changing settings.
They have a date/time against the event in the following format:
2010-01-29 10:27:29
Is it possible to use SQL to select the events that have only happened in the last 5 mins?
So if the date/time was 2010-01-29 10:27:29 it would only select the events that happened between 10:27:29 and 10:22:29?
Cheers
Eef
SELECT foo FROM bar WHERE event_time > DATE_SUB(NOW(), INTERVAL 5 MINUTES)
(Not sure if it's minutes or minute)
WHERE my_timestamp < DATE_SUB(now(), INTERVAL 5 MINUTE)
You should provide table and column names to make it easy for us to answer your question.
You can write SQL as
SELECT *
FROM Table
WHERE DateTimeColumnName <= '2010/01/29 10:27:29'
AND DateTimeColumnName >= '2010/01/29 10:22:29'
or you can use BETWEEN
SELECT *
FROM Table
WHERE DateTimeColumnName BETWEEN '2010/01/29 10:22:29' AND '2010/01/29 10:27:29'
Now see if there are datetime functions in MySQL to do a Date Math so just pass a single date stamp, and do the math to subtract 5 min from it and use it as the second parameter in the between clause.