I have a table like this:
+-----+-----+-------+
| id | fk | value |
+-----+-----+-------+
| 0 | 1 | peter |
| 1 | 1 | josh |
| 3 | 2 | marc |
| ... | ... | ... |
I'd like now to get all entries which have more than one value.
The expected result would be:
+-----+-------+
| fk | count |
+-----+-------+
| 1 | 2 |
| ... | ... |
I tried to achieve that like this:
select fk, count(value) from table where count(value) > 1;
But Oracle didn't like it.
So I tried this...
select * from (
select fk, count(value) as cnt from table
) where cnt > 1;
...with no success.
Any ideas?
Use the having clause for comparing aggregates.
Also, you need to group by what you're aggregating against for the query to work correctly. The following is a start, but since you're missing a group by clause still it won't quite work. What exactly are you trying to count?
select fk, count(value)
from table
group by fk
having count(value) > 1;
Related
The query works fine with any operator for multiple values for any comparison.
SELECT Name, ID
from tblABC
where ID = ANY (1,2,3,4,5 )
But when a subquery is used for any comparison a right parenthesis missing error occurs
SELECT Name, ID
from tblABC
where ID = ANY (select ID from tblXYZ where ROWNUM <= 10 order by ID desc )
The subquery just gives the top 10 recent id entries from the selected table. Should there be a conversion to number or missing condition in this query?
The reason is order by, which is not necessary as it is evaluated after count stopkey (which is rownum < <constant>).
select *
from table(dbms_xplan.display_cursor(format => 'BASIC +PREDICATE'));
| PLAN_TABLE_OUTPUT |
| :----------------------------------------------------------------------- |
| EXPLAINED SQL STATEMENT: |
| ------------------------ |
| select /*+ gather_plan_statistics */ * from t where rownum < 5 order by |
| 1 asc |
| |
| Plan hash value: 846588679 |
| |
| ------------------------------------ |
| | Id | Operation | Name | |
| ------------------------------------ |
| | 0 | SELECT STATEMENT | | |
| | 1 | SORT ORDER BY | | |
| |* 2 | COUNT STOPKEY | | |
| | 3 | TABLE ACCESS FULL| T | |
| ------------------------------------ |
| |
| Predicate Information (identified by operation id): |
| --------------------------------------------------- |
| |
| 2 - filter(ROWNUM<5) |
| |
If you are on Oracle 12C+, then you may use fetch first:
select *
from dual
where 1 = any(select l from t order by 1 asc fetch first 4 rows only)
| DUMMY |
| :---- |
| X |
Or row_number() for older versions:
select *
from dual
where 1 = any (
select l
from (
select l, row_number() over(order by l asc) as rn
from t
)
where rn < 5
)
| DUMMY |
| :---- |
| X |
db<>fiddle here
It is order by part. It is not supported within sub-queries like this.
Just remove it. You don't need it for comparison anyway.
SELECT Name, ID
from tblABC
where ID = ANY (select ID from tblXYZ where ROWNUM <= 10 )
You can use FETCH FIRST <n> ROWS ONLY instead of using the old ROWNUM in the subquery.
For example:
SELECT Name, ID
from tblABC
where ID = ANY (select ID
from tblXYZ
order by ID desc
fetch first 10 rows only)
See running example at db<>fiddle.
I have a table that has a number column and an attribute column like this:
1.
+-----+-----+
| num | att |
-------------
| 1 | a |
| 1 | b |
| 1 | a |
| 2 | a |
| 2 | b |
| 2 | b |
+------------
I want to make the number unique, and the attribute to be whichever attribute occured most often for that number, like this (This is the end-product im interrested in) :
2.
+-----+-----+
| num | att |
-------------
| 1 | a |
| 2 | b |
+------------
I have been working on this for a while and managed to write myself a query that looks up how many times an attribute occurs for a given number like this:
3.
+-----+-----+-----+
| num | att |count|
------------------+
| 1 | a | 1 |
| 1 | b | 2 |
| 2 | a | 1 |
| 2 | b | 2 |
+-----------------+
But I can't think of a way to only select those rows from the above table where the count is the highest (for each number of course).
So basically what I am asking is given table 3, how do I select only the rows with the highest count for each number (Of course an answer describing providing a way to get from table 1 to table 2 directly also works as an answer :) )
You can use aggregation and window functions:
select num, att
from (
select num, att, row_number() over(partition by num order by count(*) desc, att) rn
from mytable
group by num, att
) t
where rn = 1
For each num, this brings the most frequent att; if there are ties, the smaller att is retained.
Oracle has an aggregation function that does this, stats_mode().:
select num, stats_mode(att)
from t
group by num;
In statistics, the most common value is called the mode -- hence the name of the function.
Here is a db<>fiddle.
You can use group by and count as below
select id, col, count(col) as count
from
df_b_sql
group by id, col
I've seen similar questions about but not quite hitting the nail on the head for what I need. Lets say I have a table.
+-----+-------+
| ID | Value |
+-----+-------+
| 123 | 1 |
| 123 | 2 |
| 123 | 3 |
| 456 | 1 |
| 456 | 2 |
| 456 | 4 |
| 789 | 1 |
| 789 | 2 |
+-----+-------+
I want to return DISTINCT IDs but exclude those that have a certain value. For example lets say I don't want any IDs that have a 3 as a value. My results should look like.
+-----+
| ID |
+-----+
| 456 |
| 789 |
+-----+
I hope this makes sense. If more information is needed please ask and if this has been answered before please point me in the right direction. Thanks.
You can use group by and having:
select id
from t
group by id
having sum(case when value = 3 then 1 else 0 end) = 0;
The having clause counts the number of "3"s for each id. The = 0 returns only returns groups where the count is 0 (i.e. there are no "3"s).
You can use not exists :
select distinct t.id
from table t
where not exists (select 1 from table t1 where t1.id = t.id and t1.value = 3);
Try this:
select id from tablename
group by id
having (case when value=3 then 1 else 0 end)=0
You can also use EXCEPT for comparing following two data sets that will give the desired result set
select distinct Id from ValuesTbl
except
select Id from ValuesTbl where Value = 3
I am working on Terradata SQL. I would like to get the duplicate fields with their count and other variables as well. I can only find ways to get the count, but not exactly the variables as well.
Available input
+---------+----------+----------------------+
| id | name | Date |
+---------+----------+----------------------+
| 1 | abc | 21.03.2015 |
| 1 | def | 22.04.2015 |
| 2 | ajk | 22.03.2015 |
| 3 | ghi | 23.03.2015 |
| 3 | ghi | 23.03.2015 |
Expected output :
+---------+----------+----------------------+
| id | name | count | // Other fields
+---------+----------+----------------------+
| 1 | abc | 2 |
| 1 | def | 2 |
| 2 | ajk | 1 |
| 3 | ghi | 2 |
| 3 | ghi | 2 |
What am I looking for :
I am looking for all duplicate rows, where duplication is decided by ID and to retrieve the duplicate rows as well.
All I have till now is :
SELECT
id, name, other-variables, COUNT(*)
FROM
Table_NAME
GROUP BY
id, name
HAVING
COUNT(*) > 1
This is not showing correct data. Thank you.
You could use a window aggregate function, like this:
SELECT *
FROM (
SELECT id, name, other-variables,
COUNT(*) OVER (PARTITION BY id) AS duplicates
FROM users
) AS sub
WHERE duplicates > 1
Using a teradata extension to ISO SQL syntax, you can simplify the above to:
SELECT id, name, other-variables,
COUNT(*) OVER (PARTITION BY id) AS duplicates
FROM users
QUALIFY duplicates > 1
As an alternative to the accepted and perfectly correct answer, you can use:
SELECT {all your required 'variables' (they are not variables, but attributes)}
, cnt.Count_Dups
FROM Table_NAME TN
INNER JOIN (
SELECT id
, COUNT(1) Count_Dups
GROUP BY id
HAVING COUNT(1) > 1 -- If you want only duplicates
) cnt
ON cnt.id = TN.id
edit: According to your edit, duplicates are on id only. Edited my query accordingly.
try this,
SELECT
id, COUNT(id)
FROM
Table_NAME
GROUP BY
id
HAVING
COUNT(id) > 1
I need to apologize for the title. I put a lot of thought into it but didn't get too far.
I have a table that looks like this:
+--------------------------------------+--------------------------------------+--------------------------------------+--------------------------------------+--------+
| accountid | pricexxxxxid | accountid | pricelevelid | counts |
+--------------------------------------+--------------------------------------+--------------------------------------+--------------------------------------+--------+
| 36B077D4-E765-4C70-BE18-2ECA871420D3 | 00000000-0000-0000-0000-000000000000 | 36B077D4-E765-4C70-BE18-2ECA871420D3 | F43C47CE-28C6-42E2-8399-92C58ED4BA9D | 1 |
| EBC18CBC-2D2E-44CB-B36A-0ADE9E2BDE9F | 00000000-0000-0000-0000-000000000000 | EBC18CBC-2D2E-44CB-B36A-0ADE9E2BDE9F | 3BEEA9D3-F26B-47E4-88FA-A2AA366980ED | 1 |
| 8DC8D0FC-3138-425A-A922-2F0CAC57E887 | 00000000-0000-0000-0000-000000000000 | 8DC8D0FC-3138-425A-A922-2F0CAC57E887 | F1B8AD5D-B008-4C3F-94A0-AD3F90C777D7 | 1 |
| 8F908A92-1327-4655-BAE4-C890D971A554 | 00000000-0000-0000-0000-000000000000 | 8F908A92-1327-4655-BAE4-C890D971A554 | 2E0EC67E-5F8F-4305-932E-BBF8DF83DBEC | 1 |
| 37221AAC-B885-4002-B7D9-591F8C14D019 | 00000000-0000-0000-0000-000000000000 | 37221AAC-B885-4002-B7D9-591F8C14D019 | F4A2A0CA-FDFF-4C21-AE92-D4583DC18DED | 1 |
| 66F406B4-0D9B-40B8-9A23-119EE74B00B7 | 00000000-0000-0000-0000-000000000000 | 66F406B4-0D9B-40B8-9A23-119EE74B00B7 | 204B8570-CEBA-4C72-9B72-8B9B14AF625E | 2 |
| D0168CE3-479E-439E-967C-4FF0D701291A | 00000000-0000-0000-0000-000000000000 | D0168CE3-479E-439E-967C-4FF0D701291A | 204B8570-CEBA-4C72-9B72-8B9B14AF625E | 2 |
| 57E5F6E5-0A8A-4E54-B793-2F6493DC1EA3 | 00000000-0000-0000-0000-000000000000 | 57E5F6E5-0A8A-4E54-B793-2F6493DC1EA3 | 893F9FD2-43C9-4355-AEFC-08A62BF2B066 | 3 |
+--------------------------------------+--------------------------------------+--------------------------------------+--------------------------------------+--------+
It is sorted by ascending counts.
I would like to update the pricexxxxids that are all 00000000-0000-0000-0000-000000000000 with their corresponding pricelevelid.
For example for accountid = 36B077D4-E765-4C70-BE18-2ECA871420D3 I would like the pricexxxxid to be F43C47CE-28C6-42E2-8399-92C58ED4BA9D.
After that is done, I would like all the records FOLLOWING this one where accountid = 36B077D4-E765-4C70-BE18-2ECA871420D3 to be deleted.
Another words in result I will end up with a distinct list of accountids with pricexxxxid to be assigned with the corresponding value from pricelevelid.
Thank you so much for your guidance.
for your first case do !
update table
set pricexxxxids=pricelevelid.
if i understand your second case correctly :(delete duplicates/select distinct)?
delete from
(
select *,rn=row_number()over(partition by accountid order by accountid) from table
)x
where rn>1
--select distinct * from table
edited
select * from
(
select *,rn=row_number()over(partition by accountid order by accountid) from table
)x
where x.rn=1
updated
SELECT accountid,pricelevelid FROM
(
(SELECT *,
Row_number() OVER ( partition BY accountid ORDER BY counts, pricelevelid ) AS Recency
FROM table
)x
WHERE x.Recency = 1