SQL INNER JOIN syntax - sql

the two bits of SQL below get the same result
SELECT c.name, o.product
FROM customer c, order o
WHERE c.id = o.cust_id
AND o.value = 150
SELECT c.name, o.product
FROM customer c
INNER JOIN order o on c.id = o.cust_id
WHERE o.value = 150
I've seen both styles used as standard at different companies. From what I've seen, the 2nd one is what most people recommend online. Is there any real reason for this other than style? Does using an Inner Join sometimes have better performance?
I've noticed Ingres and Oracle developers tend to use the first style, whereas Microsoft SQL Server users have tended to use the second, but that might just be a coincidence.
Thanks for any insight, I've wondered about this for a while.
Edit: I've changed the title from 'SQL Inner Join versus Cartesian Product' as I was using the incorrect terminlogy. Thanks for all the responses so far.

Both queries are an inner joins and equivalent. The first is the older method of doing things, whereas the use of the JOIN syntax only became common after the introduction of the SQL-92 standard (I believe it's in the older definitions, just wasn't particularly widely used before then).
The use of the JOIN syntax is strongly preferred as it separates the join logic from the filtering logic in the WHERE clause. Whilst the JOIN syntax is really syntactic sugar for inner joins it's strength lies with outer joins where the old * syntax can produce situations where it is impossible to unambiguously describe the join and the interpretation is implementation-dependent. The [LEFT | RIGHT] JOIN syntax avoids these pitfalls, and hence for consistency the use of the JOIN clause is preferable in all circumstances.
Note that neither of these two examples are Cartesian products. For that you'd use either
SELECT c.name, o.product
FROM customer c, order o
WHERE o.value = 150
or
SELECT c.name, o.product
FROM customer c CROSS JOIN order o
WHERE o.value = 150

To answer part of your question, I think early bugs in the JOIN ... ON syntax in Oracle discouraged Oracle users away from that syntax. I don't think there are any particular problems now.
They are equivalent and should be parsed into the same internal representation for optimization.

Actually these examples are equivalent and neither is a cartesian product. A cartesian product is returned when you join two tables without specifying a join condition, such as in
select *
from t1,t2
There is a good discussion of this on Wikipedia.

Oracle was late in supporting the JOIN ... ON (ANSI) syntax (not until Oracle 9), that's why Oracle developers often don't use it.
Personally, I prefer using ANSI syntax when it is logically clear that one table is driving the query and the others are lookup tables. When tables are "equal", I tend to use the cartesian syntax.
The performance should not differ at all.

The JOIN... ON... syntax is a more recent addition to ANSI and ISO specs for SQL. The JOIN... ON... syntax is generally preferred because it 1) moves the join criteria out of the WHERE clause making the WHERE clause just for filtering and 2) makes it more obvious if you are creating a dreaded Cartesian product since each JOIN must be accompanied by at least one ON clause. If all the join criteria are just ANDed in the WHERE clause, it's not as obvious when one or more is missing.

Both queries are performing an inner join, just different syntax.

TL;DR
An INNER JOIN statement can be rewritten as a CROSS JOIN with a WHERE clause matching the same condition you used in the ON clause of the INNER JOIN query.
Table relationship
Considering we have the following post and post_comment tables:
The post has the following records:
| id | title |
|----|-----------|
| 1 | Java |
| 2 | Hibernate |
| 3 | JPA |
and the post_comment has the following three rows:
| id | review | post_id |
|----|-----------|---------|
| 1 | Good | 1 |
| 2 | Excellent | 1 |
| 3 | Awesome | 2 |
SQL INNER JOIN
The SQL JOIN clause allows you to associate rows that belong to different tables. For instance, a CROSS JOIN will create a Cartesian Product containing all possible combinations of rows between the two joining tables.
While the CROSS JOIN is useful in certain scenarios, most of the time, you want to join tables based on a specific condition. And, that's where INNER JOIN comes into play.
The SQL INNER JOIN allows us to filter the Cartesian Product of joining two tables based on a condition that is specified via the ON clause.
SQL INNER JOIN - ON "always true" condition
If you provide an "always true" condition, the INNER JOIN will not filter the joined records, and the result set will contain the Cartesian Product of the two joining tables.
For instance, if we execute the following SQL INNER JOIN query:
SELECT
p.id AS "p.id",
pc.id AS "pc.id"
FROM post p
INNER JOIN post_comment pc ON 1 = 1
We will get all combinations of post and post_comment records:
| p.id | pc.id |
|---------|------------|
| 1 | 1 |
| 1 | 2 |
| 1 | 3 |
| 2 | 1 |
| 2 | 2 |
| 2 | 3 |
| 3 | 1 |
| 3 | 2 |
| 3 | 3 |
So, if the ON clause condition is "always true", the INNER JOIN is simply equivalent to a CROSS JOIN query:
SELECT
p.id AS "p.id",
pc.id AS "pc.id"
FROM post p
CROSS JOIN post_comment
WHERE 1 = 1
ORDER BY p.id, pc.id
SQL INNER JOIN - ON "always false" condition
On the other hand, if the ON clause condition is "always false", then all the joined records are going to be filtered out and the result set will be empty.
So, if we execute the following SQL INNER JOIN query:
SELECT
p.id AS "p.id",
pc.id AS "pc.id"
FROM post p
INNER JOIN post_comment pc ON 1 = 0
ORDER BY p.id, pc.id
We won't get any result back:
| p.id | pc.id |
|---------|------------|
That's because the query above is equivalent to the following CROSS JOIN query:
SELECT
p.id AS "p.id",
pc.id AS "pc.id"
FROM post p
CROSS JOIN post_comment
WHERE 1 = 0
ORDER BY p.id, pc.id
SQL INNER JOIN - ON clause using the Foreign Key and Primary Key columns
The most common ON clause condition is the one that matches the Foreign Key column in the child table with the Primary Key column in the parent table, as illustrated by the following query:
SELECT
p.id AS "p.id",
pc.post_id AS "pc.post_id",
pc.id AS "pc.id",
p.title AS "p.title",
pc.review AS "pc.review"
FROM post p
INNER JOIN post_comment pc ON pc.post_id = p.id
ORDER BY p.id, pc.id
When executing the above SQL INNER JOIN query, we get the following result set:
| p.id | pc.post_id | pc.id | p.title | pc.review |
|---------|------------|------------|------------|-----------|
| 1 | 1 | 1 | Java | Good |
| 1 | 1 | 2 | Java | Excellent |
| 2 | 2 | 3 | Hibernate | Awesome |
So, only the records that match the ON clause condition are included in the query result set. In our case, the result set contains all the post along with their post_comment records. The post rows that have no associated post_comment are excluded since they can not satisfy the ON Clause condition.
Again, the above SQL INNER JOIN query is equivalent to the following CROSS JOIN query:
SELECT
p.id AS "p.id",
pc.post_id AS "pc.post_id",
pc.id AS "pc.id",
p.title AS "p.title",
pc.review AS "pc.review"
FROM post p, post_comment pc
WHERE pc.post_id = p.id
The non-struck rows are the ones that satisfy the WHERE clause, and only these records are going to be included in the result set. That's the best way to visualize how the INNER JOIN clause works.
| p.id | pc.post_id | pc.id | p.title | pc.review |
|------|------------|-------|-----------|-----------|
| 1 | 1 | 1 | Java | Good |
| 1 | 1 | 2 | Java | Excellent |
| 1 | 2 | 3 | Java | Awesome |
| 2 | 1 | 1 | Hibernate | Good |
| 2 | 1 | 2 | Hibernate | Excellent |
| 2 | 2 | 3 | Hibernate | Awesome |
| 3 | 1 | 1 | JPA | Good |
| 3 | 1 | 2 | JPA | Excellent |
| 3 | 2 | 3 | JPA | Awesome |
Not that this only applies to INNER JOIN, not for OUTER JOIN.

Related

combine 2 sql's from different tables into one query

I have for example as first query: (ararnr = article number)
Select ararnr,ararir,aoarom from ar left join ao ON AR.ARARNR=AO.AOARNR WHERE AR.ARARKD=1389
the second query uses the result from the first column from the first query to search in another table
Select votgan, sum(ststan) as totalStock from vo INNER JOIN st on vo.voarnr=st.starnr where voarnr = ararnr
How could I combine both ?
Please note : Not all articlenumbers from the first query will be found in the second, but I need them in my result.
In the result I need the columns from both queries.
EDIT
for example :
first query returns article numbers and the description:
+---------+--------------+
| ararnr | aoarom |
+---------+--------------+
| a123456 | description1 |
| b123456 | description2 |
| 0123456 | description3 |
+---------+--------------+
second query returns the totalstock for those articles:
+---------+--------------+
| ararnr | totalstock |
+---------+--------------+
| a123456 | 12 |
| b123456 | |
| 0123456 | 6 |
+---------+--------------+
Note the second one doesn't return a value since the articlenumber doesn't exist in this table.
In my result I would like to get the articlenumber with corresponding description and stock.
+---------+--------------+-----------+---------+
| ararnr | aoarom | totalStock| vovoan |
+---------+--------------+-----------+---------+
| a123456 | description1 | 12 | 2 |
| b123456 | description2 | | 1 |
| 0123456 | description3 | 6 | |
+---------+--------------+-----------+---------+
I'm using sql on db2
SECOND EDIT
The first query will select some article numbers (ararnr) from table ar and find the corresponding description (aoarom) in another table ao.
The second query finds the stock (vovoan and sum ststan) from two differend tables vo and st for the article numbers found in the first query.
The result should have the article number with corresponding description with corresponding stock from vo and st
I can't fully understand what you're asking, but another join may assist you.
example:
SELECT ar.ararnr, ar.ararir, ar.ararom, vo.votgan, SUM(vo.ststan) as totalStock
FROM ar LEFT JOIN ao ON [id=id] LEFT JOIN vo ON [id=id]
Because I can't tell what your tables structure are, or what you're really asking for, this is the best response I can give you.
This also may be what you're looking for:
Combining 2 SQL queries and getting result set in one
You can use this query.
SELECT ar.ararnr, ar.ararir, ar.ararom, vo.votgan, SUM(vo.ststan) as totalStock
FROM ar
LEFT JOIN ao ON ao.ararnr = ar.ararnr
LEFT JOIN vo ON vo.voarnr = ao.ararnr
If you are using SQL Server as database then this can be done with help of OUTER APPLY
SELECT ararnr,aoarom ,temp.totalStock
FROM ar
LEFT JOIN ao ON AR.ARARNR=AO.AOARNR
OUTER APPLY(
SELECT sum(ststan) as totalStock
FROM vo
INNER JOIN st on vo.voarnr=st.starnr
where voarnr = ar.ararnr
)temp
WHERE AR.ARARKD=1389
You'd get a much more complete answer if you were to post the table structure and desired result, but..
You can use the first query as a resultset for your second query, and join to it. something like:
Select
votgan,
sum(ststan) as totalStock
from vo
inner join (Select
ararnr,
ararir,
ararom
from ar
left join ao .....) z on vo.voarnr = z.ararnr
EDIT:
Select
votgan,
sum(ststan) as totalStock,
z.ararnr,
z.aoarom
from vo
inner join (Select
ararnr,
ararir,
ararom
from ar
left join ao .....) z on vo.voarnr = z.ararnr

Shouldn't a full join get both sides even if one side has a null of both tables

This is not the full query(it is a subquery in a larger query). However, I know this is the part that is causing me a problem as I have taken it own and sourced it to it. I am trying to get both sides of two tables that don't always have matching composite keys. In particular, the GKey is not always the same.
I am currently using a full join, but I still get gaps on both sides. There is an example of how the data should essentially come out. You can see that there are nulls on both sides of the two different tables.
Input
| A | B |
| 2 | NULL |
| NULL | 5 |
| 3 | 3 |
|Null | 6 |
Outcome
| A | B |
| 3 | 3 |
SELECT DISTINCT BudgetUnit / (WorkDaysInMonth * 8) AS B
,Unit / (WorkDaysInMonth * 8) AS A
FROM BFact AS BMF
FULL JOIN GFact AS GF ON
BMF.GLKey = GF.GKey
AND
BMF.DKey = GF.DKey
AND GF.AKey = BMF.BKey
AND GF.PKey = BMF.PKey
INNER JOIN DimDate AS DA ON GF.AKey = DA.DateKey
Because you are selecting FROM BFact, and then using GFact in an INNER JOIN after the FULL JOIN, you are turning your FULL JOIN into an INNER JOIN because no results that don't satisfy the last INNER JOIN will be returned.
You could make that last INNER JOIN into a LEFT OUTER JOIN to get the desired results.

Access Query Combine Records from Many-to-Many into one row

This should be easy but I'm having a hard time.
I have a many-to-many relationship where, for example, many cars can have many components.
So I want a query to return all cars and the subsequent components used. If no component is used it should just return a NULL value.
Car | Engine | Tyre
----------------------
1 | Engine3 |
2 | Engine4 | Tyre3
3 | Engine1 | Tyre1
But with the following SQL:
SELECT Car.idCar, Engine.idEngine, Tyre.idTyre
FROM ((Component
RIGHT JOIN (Car
LEFT JOIN Car_Component ON Car.idCar = Car_Component.idCar) ON Component.idComponent = Car_Component.idComponent)
LEFT JOIN Engine ON Component.idComponent = Engine.idComponent)
LEFT JOIN Tyre ON Component.idComponent = Tyre.idComponent;
I get:
Car | Engine | Tyre
----------------------
1 | Engine3 |
2 | Engine4 |
2 | | Tyre3
3 | Engine1 |
3 | | Tyre1
I've been searching for a solution for quite some time now and I'm pretty sure I need to make subqueriesm but my knowledge of subqueries is limited and I don't know how to start.
Here is the problem in SQL Fiddle.
Does the following query work for you SQL Fiddle:
SELECT DISTINCT Car.idCar, Engine.idEngine, Tyre.idTyre
FROM (((Car
INNER JOIN Car_Component ON Car.idCar = Car_Component.idCar)
INNER JOIN Component ON Car_Component.idComponent = Component.idComponent)
LEFT JOIN Engine ON Component.idComponent = Engine.idComponent)
LEFT JOIN Tyre ON Component.idComponent = Tyre.idComponent;

SQL Order By Within A Count(Distinct)

I have the following tables:
filetype1
F1_ID | F1_ORDR | FILENAME
1 | 1 | file1.txt
2 | 2 | file2.txt
3 | 3 | file3.txt
4 | 2 | file4.txt
5 | 4 | file5.txt
filetype2
F2_ID | F2_ORDR | FILENAME
1 | 1 | file6.txt
2 | 2 | file7.txt
3 | 4 | file8.txt
ordr
OR_ID | OR_VENDOR
1 | 1
2 | 1
3 | 1
4 | 1
vendor
VE_ID | VE_NAME
1 | Company1
My goal is to have a list of vendors and a count of the number of orders where a file is connected for each type. For example, the end result of this data should be:
VENDOR | OR_CT | F1_CT | F2_CT
Company1 | 4 | 4 | 3
Because at least 1 type1 file was attached to 4 distinct orders and at least 1 type2 file was attached to 3 distinct orders. Currently my SQL code looks like this:
SELECT vendor.ve_id, vendor.ve_name,
(SELECT COUNT(or_id)
FROM ordr
WHERE ordr.or_vendor = vendor.ve_id) as OR_COUNT,
(SELECT COUNT(DISTINCT f1_order)
FROM filetype1 INNER JOIN ordr ON filetype1.f1_ordr = ordr.or_id
WHERE ordr.or_vendor = vendor.ve_id) as F1_CT,
(SELECT COUNT(DISTINCT f2_ordr)
FROM filetype2 INNER JOIN ordr ON filetype2.f2_ordr = ordr.or_id
WHERE ordr.or_vendor = vendor.ve_id) as F2_CT
FROM vendor
ORDER BY vendor.ve_name
Unfortunately this yields the following results:
VENDOR | OR_COUNT | F1_COUNT | F2_COUNT
Company1 | 4 | 5 | 3
My only guess is that because I'm using COUNT(DISTINCT) the COUNT is automatically assuming the DISTINCT is ordering by F1_ID instead of by F1_ORDR
If anyone can assist me on how to tell the COUNT(DISTINCT) to order by F1_ORDR that would be most helpful. I have searched the vast internet for a solution but its hard to explain what I want to a search engine, forums, etc. My database uses Microsoft SQL Server. My knowledge of database management is almost completely self taught, so I'm just glad I made it this far on my own. My expertise is in web design. Thank you for your time.
Your SQL yields the result you want for me.
Two pieces of advice
Order is a bad name for a table - it conflicts with a reserved word, and will cause you no end of hassle
You should join your tables like so
FROM filetype1
inner join [order]
on filetype1.f1_order = or_id
rather than using a where clause
Perhaps try this instead
select
vendor.VE_ID, vendor.VE_NAME,
count(distinct or_id),
count(distinct f1_order),
count(distinct f2_order)
from
vendor
left join [order]
on vendor.VE_ID = [order].OR_VENDOR
inner join filetype1
on [order].OR_ID = filetype1.F1_ORDER
left join filetype2
on [order].OR_ID = filetype2.F2_ORDER
group by
vendor.VE_ID, vendor.VE_NAME
Try this:
SELECT
vdr.VE_NAME
,COUNT(DISTINCT OR_ID) AS OR_ID
,COUNT(DISTINCT ft1.F1_ORDER) AS FT1_COUNT
,COUNT(DISTINCT ft2.F2_ORDER) AS FT2_COUNT
FROM
vendor vdr
LEFT OUTER JOIN [order] odr
ON vdr.VE_ID = odr.OR_VENDOR
INNER JOIN filetype1 ft1
ON odr.OR_ID = ft1.F1_ORDER
LEFT OUTER JOIN filetype2 ft2
ON odr.OR_ID = ft2.F2_ORDER
GROUP BY
vdr.VE_ID
,vdr.VE_NAME
I will propose you this:
Merge filetype1 and filetype2 tables in one table(filetype) and add another field named - f_type(for instance) of type INT or TINTYINT to store the filetype (1 or 2). This has the benefits of painlessly adding another filetype later
Now the query will look something like this:
SELECT
vendor.ve_name,
count(DISTINCT filetype.f_order),
filetype.f_type
FROM
filetype
INNER JOIN `order`
ON filetype.f_order = `order`.or_id
INNER JOIN vendor
ON `order`.or_vendor = vendor.ve_id
GROUP BY vendor.ve_id,filetype.f_type
This will give the count of orders for filetype.
For the total orders just add another query:
SELECT count(*) FROM `order`

Difference between natural join and inner join

What is the difference between a natural join and an inner join?
One significant difference between INNER JOIN and NATURAL JOIN is the number of columns returned.
Consider:
TableA TableB
+------------+----------+ +--------------------+
|Column1 | Column2 | |Column1 | Column3 |
+-----------------------+ +--------------------+
| 1 | 2 | | 1 | 3 |
+------------+----------+ +---------+----------+
The INNER JOIN of TableA and TableB on Column1 will return
SELECT * FROM TableA AS a INNER JOIN TableB AS b USING (Column1);
SELECT * FROM TableA AS a INNER JOIN TableB AS b ON a.Column1 = b.Column1;
+------------+-----------+---------------------+
| a.Column1 | a.Column2 | b.Column1| b.Column3|
+------------------------+---------------------+
| 1 | 2 | 1 | 3 |
+------------+-----------+----------+----------+
The NATURAL JOIN of TableA and TableB on Column1 will return:
SELECT * FROM TableA NATURAL JOIN TableB
+------------+----------+----------+
|Column1 | Column2 | Column3 |
+-----------------------+----------+
| 1 | 2 | 3 |
+------------+----------+----------+
The repeated column is avoided.
(AFAICT from the standard grammar, you can't specify the joining columns in a natural join; the join is strictly name-based. See also Wikipedia.)
(There's a cheat in the inner join output; the a. and b. parts would not be in the column names; you'd just have column1, column2, column1, column3 as the headings.)
An inner join is one where the matching row in the joined table is required for a row from the first table to be returned
An outer join is one where the matching row in the joined table is not required for a row from the first table to be returned
A natural join is a join (you can have either natural left or natural right) that assumes the join criteria to be where same-named columns in both table match
I would avoid using natural joins like the plague, because natural joins are:
not standard sql [SQL 92] and therefore not portable, not particularly readable (by most SQL coders) and possibly not supported by various tools/libraries
not informative; you can't tell what columns are being joined on without referring to the schema
your join conditions are invisibly vulnerable to schema changes - if there are multiple natural join columns and one such column is removed from a table, the query will still execute, but probably not correctly and this change in behaviour will be silent
hardly worth the effort; you're only saving about 10 seconds of typing
A natural join is just a shortcut to avoid typing, with a presumption that the join is simple and matches fields of the same name.
SELECT
*
FROM
table1
NATURAL JOIN
table2
-- implicitly uses `room_number` to join
Is the same as...
SELECT
*
FROM
table1
INNER JOIN
table2
ON table1.room_number = table2.room_number
What you can't do with the shortcut format, however, is more complex joins...
SELECT
*
FROM
table1
INNER JOIN
table2
ON (table1.room_number = table2.room_number)
OR (table1.room_number IS NULL AND table2.room_number IS NULL)
SQL is not faithful to the relational model in many ways. The result of a SQL query is not a relation because it may have columns with duplicate names, 'anonymous' (unnamed) columns, duplicate rows, nulls, etc. SQL doesn't treat tables as relations because it relies on column ordering etc.
The idea behind NATURAL JOIN in SQL is to make it easier to be more faithful to the relational model. The result of the NATURAL JOIN of two tables will have columns de-duplicated by name, hence no anonymous columns. Similarly, UNION CORRESPONDING and EXCEPT CORRESPONDING are provided to address SQL's dependence on column ordering in the legacy UNION syntax.
However, as with all programming techniques it requires discipline to be useful. One requirement for a successful NATURAL JOIN is consistently named columns, because joins are implied on columns with the same names (it is a shame that the syntax for renaming columns in SQL is verbose but the side effect is to encourage discipline when naming columns in base tables and VIEWs :)
Note a SQL NATURAL JOIN is an equi-join**, however this is no bar to usefulness. Consider that if NATURAL JOIN was the only join type supported in SQL it would still be relationally complete.
While it is indeed true that any NATURAL JOIN may be written using INNER JOIN and projection (SELECT), it is also true that any INNER JOIN may be written using product (CROSS JOIN) and restriction (WHERE); further note that a NATURAL JOIN between tables with no column names in common will give the same result as CROSS JOIN. So if you are only interested in results that are relations (and why ever not?!) then NATURAL JOIN is the only join type you need. Sure, it is true that from a language design perspective shorthands such as INNER JOIN and CROSS JOIN have their value, but also consider that almost any SQL query can be written in 10 syntactically different, but semantically equivalent, ways and this is what makes SQL optimizers so very hard to develop.
Here are some example queries (using the usual parts and suppliers database) that are semantically equivalent:
SELECT *
FROM S NATURAL JOIN SP;
-- Must disambiguate and 'project away' duplicate SNO attribute
SELECT S.SNO, SNAME, STATUS, CITY, PNO, QTY
FROM S INNER JOIN SP
USING (SNO);
-- Alternative projection
SELECT S.*, PNO, QTY
FROM S INNER JOIN SP
ON S.SNO = SP.SNO;
-- Same columns, different order == equivalent?!
SELECT SP.*, S.SNAME, S.STATUS, S.CITY
FROM S INNER JOIN SP
ON S.SNO = SP.SNO;
-- 'Old school'
SELECT S.*, PNO, QTY
FROM S, SP
WHERE S.SNO = SP.SNO;
** Relational natural join is not an equijoin, it is a projection of one. – philipxy
A NATURAL join is just short syntax for a specific INNER join -- or "equi-join" -- and, once the syntax is unwrapped, both represent the same Relational Algebra operation. It's not a "different kind" of join, as with the case of OUTER (LEFT/RIGHT) or CROSS joins.
See the equi-join section on Wikipedia:
A natural join offers a further specialization of equi-joins. The join predicate arises implicitly by comparing all columns in both tables that have the same column-names in the joined tables. The resulting joined table contains only one column for each pair of equally-named columns.
Most experts agree that NATURAL JOINs are dangerous and therefore strongly discourage their use. The danger comes from inadvertently adding a new column, named the same as another column ...
That is, all NATURAL joins may be written as INNER joins (but the converse is not true). To do so, just create the predicate explicitly -- e.g. USING or ON -- and, as Jonathan Leffler pointed out, select the desired result-set columns to avoid "duplicates" if desired.
Happy coding.
(The NATURAL keyword can also be applied to LEFT and RIGHT joins, and the same applies. A NATURAL LEFT/RIGHT join is just a short syntax for a specific LEFT/RIGHT join.)
Natural Join: It is combination or combined result of all the columns in the two tables.
It will return all rows of the first table with respect to the second table.
Inner Join: This join will work unless if any of the column name shall be sxame in two tables
A Natural Join is where 2 tables are joined on the basis of all common columns.
common column : is a column which has same name in both tables + has compatible datatypes in both the tables.
You can use only = operator
A Inner Join is where 2 tables are joined on the basis of common columns mentioned in the ON clause.
common column : is a column which has compatible datatypes in both the tables but need not have the same name.
You can use only any comparision operator like =, <=, >=, <, >, <>
Natural Join : A SQL Join clause combines fields from 2 or more tables in a relational database. A natural join is based on all columns in two tables that have the same name and selected rows from the two tables that have equal values in all matched columns.
--- The names and data types of both columns must be the same.
Using Clause : In a natural join,if the tables have columns with the same names but different data types, the join causes and error.To avoid this situation, the join clause can be modified with a USING clause. The USING clause specifies the columns that should be used for the join.
difference is that int the inner(equi/default)join and natural join that in the natuarl join common column win will be display in single time but inner/equi/default/simple join the common column will be display double time.
Inner join and natural join are almost same but there is a slight difference between them. The difference is in natural join no need to specify condition but in inner join condition is obligatory. If we do specify the condition in inner join , it resultant tables is like a cartesian product.
mysql> SELECT * FROM tb1 ;
+----+------+
| id | num |
+----+------+
| 6 | 60 |
| 7 | 70 |
| 8 | 80 |
| 1 | 1 |
| 2 | 2 |
| 3 | 3 |
+----+------+
6 rows in set (0.00 sec)
mysql> SELECT * FROM tb2 ;
+----+------+
| id | num |
+----+------+
| 4 | 40 |
| 5 | 50 |
| 9 | 90 |
| 1 | 1 |
| 2 | 2 |
| 3 | 3 |
+----+------+
6 rows in set (0.00 sec)
INNER JOIN :
mysql> SELECT * FROM tb1 JOIN tb2 ;
+----+------+----+------+
| id | num | id | num |
+----+------+----+------+
| 6 | 60 | 4 | 40 |
| 7 | 70 | 4 | 40 |
| 8 | 80 | 4 | 40 |
| 1 | 1 | 4 | 40 |
| 2 | 2 | 4 | 40 |
| 3 | 3 | 4 | 40 |
| 6 | 60 | 5 | 50 |
| 7 | 70 | 5 | 50 |
| 8 | 80 | 5 | 50 |
.......more......
return 36 rows in set (0.01 sec)
AND NATURAL JOIN :
mysql> SELECT * FROM tb1 NATURAL JOIN tb2 ;
+----+------+
| id | num |
+----+------+
| 1 | 1 |
| 2 | 2 |
| 3 | 3 |
+----+------+
3 rows in set (0.01 sec)
Inner join, join two table where column name is same.
Natural join, join two table where column name and data types are same.