I have a temporary table with three columns
pay_id,
id_client_grp,
id_user
Basically i want to ensure that this table should have all the rows having same client group and same id_user if not i want to know which pay_id is the culprit and throw error to user.
Can somebody help me with a query.
Thanks,
Rishi
When you say 'culprit,' I assume you mean the pay_id(s) that are not like the others, assuming there is a majority.
The problem is all of the pay_id's could potentially become culprits once your SELECT COUNT(DISTINCT id_client_grp, id_user) returns > 1 record, if there is a relatively even distribution. It is difficult to program for this scenario, since you will need to determine what exactly a majority is.
Your best bet will be to return all distinct combinations of those 3 fields, then decide where to go from there based on your business logic.
So could this question be asked like this:
If I wanted to add a unique index on my table across the three columns: client group, id user, pay id, identify those that break the unique condition where we have non unique pay id for a client group and id user??
select a.id_client_grp, a.id_user, a.pay_id , a.count from (
/* this should return 1 row per client group and user, */
/* if the pay id is the same for all */
select id_client_grp, id_user, pay_id, count(1) as count
from table t
group by id_client_grp, id_user ) a
group by a.id_client_grp, a.id_user
/* if we have more than one row per client group and user, then we have a dupe, so report them all */
having count (1) > 1
If you want all the rows to have the same values for some set of columns (your question is not entirely clear to me as t9o what you want to be the same)
Do you know going in WHICH pay_id, id_client_grp all the rows should be? Or do you not care, as long as they are all the same?
If you know the values you are looking for, simply test for rows that are not set to those desired values
Select distinct id_user
From tempTable
Where pay_id <> #PayIdValue
Or id_client_grp <> #ClientGroupIDValue
If you don't care, and just want them all to be the same, and they're not, then you need to specify which of the more than one set of values IS the "culprit" as you said...
If you want some other question answered. please explain more clearly...
Based on yr comment, then, to determine if there is more than one id_client_grp, pay_id
Select Count(Distinct id_client_grp, pay_id)
From tempTable
If this = 1 then every record has the same values for these 2 fields.... Any other value indicates that three is more than one set of distinct values in the table.
SELECT DISTINCT p.pay_id,
t.[count]
FROM rishi_table p
INNER JOIN ( SELECT id_client_grp, id_user, COUNT(*) As 'count'
FROM rishi_table
GROUP BY id_client_grp, id_user
HAVING COUNT(*) > 1 ) t
ON p.id_client_grp = t.id_client_grp AND p.id_user = t.id_user
basically create a set with the dupes, and bounce that against the main table to get your offending list.
SELECT DISTINCT id_client_grp, id_user
should let you do something like
IF ##ROWCOUNT > 1 THEN
...
Or possibly SELECT COUNT(DISTINCT id_client_grp, id_user) ...
but that's more vendor-dependent as to its availability and proper syntax.
Related
I have an SQL database that shows the amount of times a person submits an entry. I want to count how many time each person who owns a unique id makes a claim. Each unique i.d can make mulpile entries into the table and I want to find out how many everyone has made.
I also want to filter the people based on the amount of entries they have made. For example 10.
select id, entry, COUNT(ID) from Table where COUNT(entry) <=10 GROUP BY ID
This is my thinking so far but I havent had much success. If anyone could help I would greatly appreciate it.
This is all you need
select id, COUNT(*) cnt
from Table
GROUP BY ID
having COUNT(*) <= 10
order by 2 desc -- optional descending count
Optionally, add Order by 2. desc or asc
I have a list of activities where one field is AccountName indicating the name of the person. There is another field called ActivityType.
Basically I want to return the number of accounts that have at least one ActivityType that is equal to RET (indicating a returned item). Since a person may have multiple returns in a given year I don't want to count the number of returns total, just the number of accounts that have at least one RET.
I've tried various combinations of select statements, count statements, having statements, it's just not working right.
Here is what I tried:
Select DISTINCT Count(Activities.AccountName) AS CountOfAccountName
FROM Activities
GROUP BY Activities.ActivityType
HAVING (Activities.ActivityType = "RET")
But this seems to return a much larger number than if I just do the select statement:
SELECT DISTINCT Activities.AccountName
FROM Activities
WHERE (Activities.ActivityType = "RET")
I think you need a simple COUNT and GROUP BY function. Since Access doesn't allow Count Distinct, You need to first select distinct records and then count them -
SELECT Count(T.AccountName) AS CountOfAccountName
FROM (SELECT AccountName
FROM Activities
WHERE Activities.ActivityType = 'RET'
GROUP BY AccountName) T;
This will filter only those records having ActivityType = 'RET' and then will count the distinct AccountName.
Use a subquery:
SELECT Count(*) AS ActiveAccounts
FROM
(SELECT DISTINCT AccountName
FROM Activities
WHERE ActivityType = "RET")
If activity/types cannot be duplicated, then you can simply use:
select count(*) AS CountOfAccountName
from Activities
where Activities.ActivityType = "RET";
If they can be, then you need a subquery as shown in other answers.
I have 2 data sets. One of all patients who got ill (endo-2) and one of a special group of patients that also exists in endo-2 called "xp-56"
I've been trying to run this query and I'm not sure why it isn't working. I want to do counts of 3 columns in endo-2 of those patients that belong in the xp-56 table.
this is the code I've been using with the following error
SELECT list expression references column user_id which is neither grouped nor aggregated at [8:5]
how do I fix this so I never make the same mistake again!
SELECT
Virus_Exposure,
Medical_Delivery,
Number_of_Site
FROM
(
SELECT
medical_id,
COUNT(DISTINCT Virus_id) AS Virus_Exposure,
COUNT(EndoCrin_id) AS Medical_Delivery,
COUNT (site_id_clinic) AS Number_of_Site
FROM
`endo-2`
WHERE
_PARTITIONTIME BETWEEN TIMESTAMP("2017-12-15")
AND TIMESTAMP("2018-01-10")) AS a
RIGHT JOIN
(
SELECT
medical_id
FROM
`xp-56`
ORDER BY
medical_id DESC) AS b
ON
a.medical_id=b.medical_id
GROUP BY
medical_id
Why doesnt the medical_id in table a work?
Why not just do this?
SELECT e.medical_id,
COUNT(DISTINCT e.Virus_id) AS Virus_Exposure,
COUNT(e.EndoCrin_id) AS Medical_Delivery,
COUNT(e.site_id_clinic) AS Number_of_Site
FROM `endo-2` e JOIN
`xp-56` x
ON x.medical_id = e.medical_id
WHERE e._PARTITIONTIME BETWEEN TIMESTAMP("2017-12-15") AND TIMESTAMP("2018-01-10")
GROUP BY e.medical_id;
I have code that identifies potential duplicate records based on the fact that several rows (with different IDs) have the same value in various other columns. This info gets manually reviewed, so I am not worried about the fact that a husband and wife could legitimately share an email address, for example. An example of the query I am using is this:
SELECT DISTINCT ID, Email
FROM Customers
WHERE Email IS NOT NULL AND Email != '' AND Email IN
(SELECT Email FROM Customers GROUP BY Email HAVING COUNT(DISTINCT ID) > 1)
ORDER BY Email;
Which gives me results like this:
ID Email
108 bob#hotmail.com
381 bob#hotmail.com
205 mary#gmail.com
772 mary#gmail.com
908 mary#gmail.com
This works great for my purposes, except when I try matching by phone number, which has multiple columns (HomePhone, BusinessPhone, CellPhone). This creates two problems - the first, which has been pretty well documented on this forum, is how to identify rows in which any of three columns contain a matching value (If a value in [row 1 column A, B, or C] matches a column in [row 2 column A, B, or C] then I want to select both rows). The second problem, which I haven't figured out yet and haven't found an answer to, is how to select [ID], [Value that Matched] as my output.
I suppose that I could select all three columns and do some further code magic in my program to make sense of it, but that prevents me from reusing existing code and also seems like the type of hack that a developer would use to keep from admitting that he needs help from a DBA. (Help!) In all seriousness, though, I am stuck trying to find an elegant solution, and any help would be appreciated.
Based on my understanding of the question,
You can initially use union all and get the different phone numbers into one column and group by that column to see if there are duplicates. Thereafter, join on the original table to get the customer id.
with cnts as (
select phone
from (select id,homephone phone from customers
union all
select id,businessphone from customers
union all
select id,cellphone from customers) x
group by phone
having count(distinct id) > 1
)
select c.id,cn.phone value_matched
from customers c
join cnts cn on cn.phone in (c.homephone,c.businessphone,c.cellphone)
order by 1,2
I would do this with apply:
select c.*, phone
from (select c.*, count(*) over (partition by phone) as cnt
from customers c cross apply
(select distinct v.phone
from (values (homephone), (businessphone), (cellphone)
) v(phone)
where v.phone is not null
) v(phone)
) c
where cnt > 1
order by phone;
The innermost subquery selects the distinct phones for each customer. The count(*) over . . . then counts the number of times that the phone appears (which because of the distinct is for different customers). The final where chooses phones that appear for multiple customers.
I have two tables. Table 1 has about 750,000 rows and table 2 has 4 million rows. Table two has an extra ID field in which I am interested, so I want to write a query that will check if the 750,000 table 1 records exist in table 2. For all those rows in table 1 that exist in table 2, I want the respective ID based on same SSN. I tried the following query:
SELECT distinct b.UID, a.*
FROM [Analysis].[dbo].[Table1] A, [Proteus_8_2].dbo.Table2 B
where a.ssn = b.ssn
Instead of getting 750,000 rows in the output, I am getting 5.4 million records. Where am i going wrong?
Please help?
You're requesting all the rows in your select if b.UID is a unique field in column two.
Also if SSN is not unique in table one you can get the higher row count than the total row count for table 2.
You need to consider what you want from table 2 again.
EDIT
You can try this to return distinct combinations of ssn and uid when ssn is found in table 2 provided that ssn and uid have a cardinality of 1:1, i.e., every unique ssn has a single unique uid.
select distinct
a.ssn,b.[UID]
from [Analysis].[dbo].[Table1] a
cross apply
( select top 1 [uid] from [Proteus_8_2].[dbo].[Table2] where ssn = a.ssn ) b
where b.[UID] is not null
Try with LEFT JOIN
SELECT distinct b.UID, a.*
FROM [Analysis].[dbo].[Table1] A LEFT JOIN [Proteus_8_2].dbo.Table2 B
on a.ssn = b.ssn
Since the order detail table is in a one-many relationship to the order table, that is the expected result of any join. If you want something different, you need to define for us the business rule that will tell us how to select only one record from the Order detail table. You cannot effectively write SQL code without understanding the business rules that of what you are trying to achieve. You should never just willy nilly select one record out of the many, you need to understand which one you want.