I need to calculate age in years, months and days format between two dates (DateFrom and DateTo) in a way that:
If day of month in DateFrom is 1st then take it as a whole month
If day of month in DateFrom is not 1st then count days till the end of the month.
Example:
DateFrom='2010-02-01', DateTo='2011-03-11', Age= 1 Years, 1 Months 11 Days
DateFrom='2010-02-02', DateTo='2011-03-11', Age= 1 Years, 1 Months 8 Days
After calculating the age I'd need to sum the ages assuming that month is 30 days - in the above example I'd expect result: 2 Years, 2 Months, 19 Days.
My assumption would be that you have have a table containing "DateFrom" and "DateTo" columns so the query would be something like this:
DECLARE #TotalDiffInDays int = (SELECT AVG(DATEDIFF(DAY, DateFrom, DateTo)) AS [TotalDays] FROM #t)
SELECT #TotalDiffInDays
DECLARE #DaysInMonth int = 30;
DECLARE #DaysInYear int = 365;
SELECT
#TotalDiffInDays / 365 AS AvgYearsDiff,
(#TotalDiffInDays / #DaysInMonth - #TotalDiffInDays / #DaysInYear * 12) AS AvgMonthsDiff,
#TotalDiffInDays - ((#TotalDiffInDays / 365) * #DaysInYear + (#TotalDiffInDays / #DaysInMonth - #TotalDiffInDays / #DaysInYear * 12) * #DaysInMonth) AS AvgDaysDiff
Note that in this case I am using INT division to get correct numbers.
In addition, if you just want to get dates difference in the format you desribed above you can use this query:
SELECT
DATEDIFF(YEAR, DateFrom, DateTo) AS [Years],
-- Add year diff to get corret months diff
DATEDIFF(MONTH, DATEADD(YEAR, DATEDIFF(YEAR, DateFrom, DateTo), DateFrom), DateTo) AS [Months],
-- Add months diff to get correct days diff
DATEDIFF(DAY, DATEADD(MONTH, DATEDIFF(MONTH, DateFrom, DateTo), DateFrom), DateTo) AS [Days]
FROM #t
I hope this will helps.
Yeah, just forgot about your rule of the 1st and not 1st day of the month, you can easily modify those queries with adding the DATEPART(DAY , your_date) function to check if it's a 1st date of the month and perform DETEADD() to apply this logic or just add a value of 1 before AVG.
So basically since this custom date maths, you'd need to implement your own functions to get desired results.
See the TSQL below
CREATE FUNCTION dbo.getDateSum(#d1 varchar(100), #d2 varchar(100))
RETURNS varchar(100)
WITH EXECUTE AS CALLER
AS
BEGIN
DECLARE #y int, #m int, #d int
Select
#d1= REPLACE(REPLACE(REPLACE(#d1,' years, ', '-'),' months, ','-'),' days',''),
#d2= REPLACE(REPLACE(REPLACE(#d2,' years, ', '-'),' months, ','-'),' days','')
Select
#y= CAST(LEFT(#d1,CHARINDEX('-',#d1)-1) AS INT)+CAST(LEFT(#d2,CHARINDEX('-',#d2)-1) AS INT),
#m= CAST(SUBSTRING(#d1,CHARINDEX('-',#d1)+1,LEN(#d1)-CHARINDEX('-',REVERSE(#d1))-CHARINDEX('-',#d1))AS INT)+CAST(SUBSTRING(#d2,CHARINDEX('-',#d2)+1,LEN(#d2)-CHARINDEX('-',REVERSE(#d2))-CHARINDEX('-',#d2)) AS INT),
#d= CAST(LEFT(REVERSE(#d1),CHARINDEX('-',REVERSE(#d1))-1)AS INT)+CAST(LEFT(REVERSE(#d2),CHARINDEX('-',REVERSE(#d2))-1) AS INT)
IF(#d>30)
BEGIN
SET #d=#d%30
SET #m=#m+CAST(#d/30 as INT)
END
IF(#m>30)
BEGIN
SET #m=#m%12
SET #y=#y+CAST(#m/12 as INT)
END
RETURN (cast(#y as varchar)+ ' years, ' + cast(#m as varchar) +' months, '+ cast(#d as varchar) + ' days' );
END
go
CREATE FUNCTION dbo.getDateDiff(#df date, #dt date)
RETURNS varchar(100)
WITH EXECUTE AS CALLER
AS
BEGIN
declare #y int, #m int, #d int
Select #y= YEAR(#dt)- YEAR(#df),#m= MONTH(#dt)- MONTH(#df),#d=CASE WHEN DAY(#df)=1 THEN DAY(#dt)- DAY(#df)+1 ELSE DAY(#dt)- DAY(#df) -1 END
If (#d<0)
BEGIN
Set #m=#m-1
set #d=#d + DATEDIFF(d, #dt, EOMONTH(#dt))
END
IF(#m<0)
BEGIN
Set #y=#y-1
Set #m=#m+ 12
END
RETURN (cast(#y as varchar)+ ' years, ' + cast(#m as varchar) +' months, '+ cast(#d as varchar) + ' days' )
END
go
SELECT dbo.getDateSum(dbo.getDateDiff('2010-02-01','2011-03-11'),dbo.getDateDiff('2010-02-02', '2011-03-11'))
go
Is there a way to calculate how old someone is based on today's date and their birthday then display it in following manners:
If a user is less than (<) 1 year old THEN show their age in MM & days.
Example: 10 months & 2 days old
If a user is more than 1 year old AND less than 6 years old THEN show their age in YY & MM & days.
Example: 5 years & 3 months & 10 days old
If a user is more than 6 years old THEN display their age in YY.
Example: 12 years
This is basically what you are looking for:
DECLARE #date1 DATETIME
, #date2 DATETIME;
SELECT #date1 = '1/1/2008'
, #date2 = GETDATE();
SELECT CASE
WHEN DATEDIFF(YEAR, #date1, #date2) < 1 THEN CAST(DATEDIFF(mm, #date1, #date2) AS VARCHAR)+' Months & '+CAST(DATEDIFF(dd, DATEADD(mm, DATEDIFF(mm, #date1, #date2), #date1), #date2) AS VARCHAR)+' Days'
WHEN DATEDIFF(YEAR, #date1, #date2) BETWEEN 1 AND 5 THEN CAST(DATEDIFF(mm, #date1, #date2) / 12 AS VARCHAR)+' Years & '+CAST(DATEDIFF(mm, #date1, #date2) % 12 AS VARCHAR)+' Months'
WHEN DATEDIFF(YEAR, #date1, #date2) >= 6 THEN CAST(DATEDIFF(YEAR, #date1, #date2) AS VARCHAR)+' Years'
END;
Result for when a user is less than (<) 1 year old THEN show their age in MM & days:
Result for when a user is more than 1 year old AND less than 6 years old THEN show their age in YY & MM & days:
Result for when a user is more than 6 years old THEN display their age in YY:
from this previous question
How to calculate age in T-SQL with years, months, and days
you can do procedure like this
CREATE procedure [dbo].[proc_datediff]
(
#date datetime
)
as
begin
DECLARE #diff varchar(70)
DECLARE #tmpdate datetime, #years int, #months int, #days int
SELECT #tmpdate = #date
SELECT #years = DATEDIFF(yy, #tmpdate, GETDATE()) - CASE WHEN
(MONTH(#date) > MONTH(GETDATE())) OR (MONTH(#date) =
MONTH(GETDATE()) AND DAY(#date) > DAY(GETDATE())) THEN 1 ELSE 0 END
SELECT #tmpdate = DATEADD(yy, #years, #tmpdate)
SELECT #months = DATEDIFF(m, #tmpdate, GETDATE()) - CASE WHEN
DAY(#date) > DAY(GETDATE()) THEN 1 ELSE 0 END
SELECT #tmpdate = DATEADD(m, #months, #tmpdate)
SELECT #days = DATEDIFF(d, #tmpdate, GETDATE())
select #diff=
case
when #years < 1 then
concat( #months,' Months ',#days,' days ' )
when #years >=1 and #years < 6
then
concat(#years,' year ', #months,' Months ',#days,' days ' )
when #years >= 6 then
concat( #years,' years ' )
end;
select #diff
end
execute proc_datediff '1/1/2016'
go
CREATE FUNCTION [dbo].[FindDateDiff](#Date1 date,#Date2 date, #IncludeTheEnDate bit)
RETURNS TABLE
AS
RETURN
(
SELECT
CALC.Years,CALC.Months,D.Days,
Duration = RTRIM(Case When CALC.Years > 0 Then CONCAT(CALC.Years, ' year(s) ') Else '' End
+ Case When CALC.Months > 0 Then CONCAT(CALC.Months, ' month(s) ') Else '' End
+ Case When D.Days > 0 OR (CALC.Years=0 AND CALC.Months=0) Then CONCAT(D.Days, ' day(s)') Else '' End)
FROM (VALUES(IIF(#Date1<#Date2,#Date1,#Date2),DATEADD(DAY, IIF(#IncludeTheEnDate=0,0,1), IIF(#Date1<#Date2,#Date2,#Date1)))) T(StartDate, EndDate)
CROSS APPLY(Select
TempEndYear = Case When ISDATE(CONCAT(YEAR(T.EndDate), FORMAT(T.StartDate,'-MM-dd')))=1 Then CONCAT(YEAR(T.EndDate), FORMAT(T.StartDate,'-MM-dd'))
Else CONCAT(YEAR(T.EndDate),'-02-28') End
) TEY
CROSS APPLY(Select EndYear = Case When TEY.TempEndYear > T.EndDate Then DATEADD(YEAR, -1, TEY.TempEndYear) Else TEY.TempEndYear End) EY
CROSS APPLY(Select
Years = DATEDIFF(YEAR,T.StartDate,EY.EndYear),
Months = DATEDIFF(MONTH,EY.EndYear,T.EndDate)-IIF(DAY(EY.EndYear)>DAY(T.EndDate),1,0)
) CALC
CROSS APPLY(Select Days = DATEDIFF(DAY,DATEADD(MONTH,CALC.Months,DATEADD(YEAR,CALC.Years,T.StartDate)),T.EndDate)) D
)
Sample:
Select [From] = '2021-01-01',[To] = '2021-12-31',IncludeEndDate='Yes',* From dbo.FindDateDiff('2021-01-01','2021-12-31',1)
Select [From] = '2021-01-01',[To] = '2021-12-31',IncludeEndDate='No',* From dbo.FindDateDiff('2021-01-01','2021-12-31',0)
Select [From] = '2015-12-15',[To] = '2018-12-14',IncludeEndDate='Yes',* From dbo.FindDateDiff('2015-12-15','2018-12-14',1)
Select [From] = '2015-12-15',[To] = '2018-12-14',IncludeEndDate='No',* From dbo.FindDateDiff('2015-12-15','2018-12-14',0)
Probably not the most efficient way to go about it, but here's how I did it:
I had to first get the date difference between today's date and person's birthdate. I used it to get years, months, days, etc by combining it with ABS(), and Remainder (%) function.
declare #year int = 365
declare #month int = 30
declare #sixYears int = 2190
select
--CAST(DATEDIFF(mm, a.BirthDateTime, getdate()) AS VARCHAR) as GetMonth,
--CAST(DATEDIFF(dd, DATEADD(mm, DATEDIFF(mm, a.BirthDateTime, getdate()), a.BirthDateTime), getdate()) AS VARCHAR) as GetDays,
CASE
WHEN
DATEDIFF(dd,a.BirthDateTime,getdate()) < #year
THEN
cast((DATEDIFF(dd,a.BirthDateTime,getdate()) / (#month)) as varchar) +' Months & ' +
CAST(ABS(DATEDIFF(dd, DATEADD(mm, DATEDIFF(mm, a.BirthDateTime, getdate()), a.BirthDateTime), getdate())) AS VARCHAR)
+ ' Days'
WHEN
DATEDIFF(dd,a.BirthDateTime,getdate()) between #year and #sixYears
THEN
cast((DATEDIFF(dd,a.BirthDateTime,getdate()) / (#year)) as varchar) +' Years & ' +
CAST((DATEDIFF(mm, a.BirthDateTime, getdate()) % (12)) AS VARCHAR) + ' Months'
WHEN DATEDIFF(dd,a.BirthDateTime,getdate()) > #sixYears
THEN cast(a.Age as varchar) + ' Years'
end as FinalAGE,
dc.DayMarker = cast(getdate() as date)
DAYmarker is your date field.
Is there any way to take the difference between two datetime in sql server?
For example, my dates are
2010-01-22 15:29:55.090
2010-01-22 15:30:09.153
So, the result should be 14.063 seconds.
Just a caveat to add about DateDiff, it counts the number of times you pass the boundary you specify as your units, so is subject to problems if you are looking for a precise timespan.
e.g.
select datediff (m, '20100131', '20100201')
gives an answer of 1, because it crossed the boundary from January to February, so even though the span is 2 days, datediff would return a value of 1 - it crossed 1 date boundary.
select datediff(mi, '2010-01-22 15:29:55.090' , '2010-01-22 15:30:09.153')
Gives a value of 1, again, it passed the minute boundary once, so even though it is approx 14 seconds, it would be returned as a single minute when using Minutes as the units.
SELECT DATEDIFF (MyUnits, '2010-01-22 15:29:55.090', '2010-01-22 15:30:09.153')
Substitute "MyUnits" based on DATEDIFF on MSDN
SELECT DATEDIFF(day, '2010-01-22 15:29:55.090', '2010-01-22 15:30:09.153')
Replace day with other units you want to get the difference in, like second, minute etc.
I can mention four important functions of MS SQL Server that can be very useful:
1) The function DATEDIFF() is responsible to calculate differences between two dates, the result could be "year quarter month dayofyear day week hour minute second millisecond microsecond nanosecond", specified on the first parameter (datepart):
select datediff(day,'1997-10-07','2011-09-11')
2) You can use the function GETDATE() to get the actual time and calculate differences of some date and actual date:
select datediff(day,'1997-10-07', getdate() )
3) Another important function is DATEADD(), used to convert some value in datetime using the same datepart of the datediff, that you can add (with positive values) or substract (with negative values) to one base date:
select DATEADD(day, 45, getdate()) -- actual datetime adding 45 days
select DATEADD( s,-638, getdate()) -- actual datetime subtracting 10 minutes and 38 seconds
4) The function CONVERT() was made to format the date like you need, it is not parametric function, but you can use part of the result to format the result like you need:
select convert( char(8), getdate() , 8) -- part hh:mm:ss of actual datetime
select convert( varchar, getdate() , 112) -- yyyymmdd
select convert( char(10), getdate() , 20) -- yyyy-mm-dd limited by 10 characters
DATETIME cold be calculated in seconds and one interesting result mixing these four function is to show a formated difference um hours, minutes and seconds (hh:mm:ss) between two dates:
declare #date1 datetime, #date2 datetime
set #date1=DATEADD(s,-638,getdate())
set #date2=GETDATE()
select convert(char(8),dateadd(s,datediff(s,#date1,#date2),'1900-1-1'),8)
... the result is 00:10:38 (638s = 600s + 38s = 10 minutes and 38 seconds)
Another example:
select distinct convert(char(8),dateadd(s,datediff(s, CRDATE , GETDATE() ),'1900-1-1'),8) from sysobjects order by 1
I tried this way and it worked. I used SQL Server version 2016
SELECT DATEDIFF(MILLISECOND,'2010-01-22 15:29:55.090', '2010-01-22 15:30:09.153')/1000.00;
Different DATEDIFF Functions are:
SELECT DATEDIFF(year, '2005-12-31 23:59:59.9999999', '2006-01-01 00:00:00.0000000');
SELECT DATEDIFF(quarter, '2005-12-31 23:59:59.9999999', '2006-01-01 00:00:00.0000000');
SELECT DATEDIFF(month, '2005-12-31 23:59:59.9999999', '2006-01-01 00:00:00.0000000');
SELECT DATEDIFF(dayofyear, '2005-12-31 23:59:59.9999999', '2006-01-01 00:00:00.0000000');
SELECT DATEDIFF(day, '2005-12-31 23:59:59.9999999', '2006-01-01 00:00:00.0000000');
SELECT DATEDIFF(week, '2005-12-31 23:59:59.9999999', '2006-01-01 00:00:00.0000000');
SELECT DATEDIFF(hour, '2005-12-31 23:59:59.9999999', '2006-01-01 00:00:00.0000000');
SELECT DATEDIFF(minute, '2005-12-31 23:59:59.9999999', '2006-01-01 00:00:00.0000000');
SELECT DATEDIFF(second, '2005-12-31 23:59:59.9999999', '2006-01-01 00:00:00.0000000');
SELECT DATEDIFF(millisecond, '2005-12-31 23:59:59.9999999', '2006-01-01 00:00:00.0000000');
Ref: https://learn.microsoft.com/en-us/sql/t-sql/functions/datediff-transact-sql?view=sql-server-2017
Ok we all know the answer involves DATEDIFF(). But that gives you only half the result you may be after. What if you want to get the results in human-readable format, in terms of Minutes and Seconds between two DATETIME values?
The CONVERT(), DATEADD() and of course DATEDIFF() functions are perfect for a more easily readable result that your clients can use, instead of a number.
i.e.
CONVERT(varchar(5), DATEADD(minute, DATEDIFF(MINUTE, date1, date2), 0), 114)
This will give you something like:
HH:MM
If you want more precision, just increase the VARCHAR().
CONVERT(varchar(12), DATEADD(minute, DATEDIFF(MINUTE, date1, date2), 0), 114)
HH:MM.SS.MS
There are a number of ways to look at a date difference, and more when comparing date/times. Here's what I use to get the difference between two dates formatted as "HH:MM:SS":
ElapsedTime AS
RIGHT('0' + CAST(DATEDIFF(S, StartDate, EndDate) / 3600 AS VARCHAR(2)), 2) + ':'
+ RIGHT('0' + CAST(DATEDIFF(S, StartDate, EndDate) % 3600 / 60 AS VARCHAR(2)), 2) + ':'
+ RIGHT('0' + CAST(DATEDIFF(S, StartDate, EndDate) % 60 AS VARCHAR(2)), 2)
I used this for a calculated column, but you could trivially rewrite it as a UDF or query calculation. Note that this logic rounds down fractional seconds; 00:00.00 to 00:00.999 is considered zero seconds, and displayed as "00:00:00".
If you anticipate that periods may be more than a few days long, this code switches to D:HH:MM:SS format when needed:
ElapsedTime AS
CASE WHEN DATEDIFF(S, StartDate, EndDate) >= 359999
THEN
CAST(DATEDIFF(S, StartDate, EndDate) / 86400 AS VARCHAR(7)) + ':'
+ RIGHT('0' + CAST(DATEDIFF(S, StartDate, EndDate) % 86400 / 3600 AS VARCHAR(2)), 2) + ':'
+ RIGHT('0' + CAST(DATEDIFF(S, StartDate, EndDate) % 3600 / 60 AS VARCHAR(2)), 2) + ':'
+ RIGHT('0' + CAST(DATEDIFF(S, StartDate, EndDate) % 60 AS VARCHAR(2)), 2)
ELSE
RIGHT('0' + CAST(DATEDIFF(S, StartDate, EndDate) / 3600 AS VARCHAR(2)), 2) + ':'
+ RIGHT('0' + CAST(DATEDIFF(S, StartDate, EndDate) % 3600 / 60 AS VARCHAR(2)), 2) + ':'
+ RIGHT('0' + CAST(DATEDIFF(S, StartDate, EndDate) % 60 AS VARCHAR(2)), 2)
END
The following query should give the exact stuff you are looking out for.
select datediff(second, '2010-01-22 15:29:55.090' , '2010-01-22 15:30:09.153')
Here is the link from MSDN for what all you can do with datediff function .
https://msdn.microsoft.com/en-us/library/ms189794.aspx
Internally in SQL Server dates are stored as 2 integers. The first integer is the number of days before or after the base date (1900/01/01). The second integer stores the number of clock ticks after midnight, each tick is 1/300 of a second.
More info here
Because of this, I often find the simplest way to compare dates is to simply substract them. This handles 90% of my use cases. E.g.,
select date1, date2, date2 - date1 as DifferenceInDays
from MyTable
...
When I need an answer in units other than days, I will use DateDiff.
SELECT DATEDIFF(yyyy, '2011/08/25', '2017/08/25') AS DateDiff
It's gives you difference between two dates in Year
Here (2017-2011)=6 as a result
Syntax:
DATEDIFF(interval, date1, date2)
Use This for DD:MM:SS:
SELECT CONVERT(VARCHAR(max), Datediff(dd, '2019-08-14 03:16:51.360',
'2019-08-15 05:45:37.610'))
+ ':'
+ CONVERT(CHAR(8), Dateadd(s, Datediff(s, '2019-08-14 03:16:51.360',
'2019-08-15 05:45:37.610'), '1900-1-1'), 8)
So this isn't my answer but I just found this while searching around online for a question like this as well. This guy set up a procedure to calculate hours, minutes and seconds. The link and the code:
--Creating Function
If OBJECT_ID('UFN_HourMinuteSecond') Is Not Null
Drop Function dbo.UFN_HourMinuteSecond
Go
Exec(
'Create Function dbo.UFN_HourMinuteSecond
(
#StartDateTime DateTime,
#EndDateTime DateTime
) Returns Varchar(10)
As
Begin
Declare #Seconds Int,
#Minute Int,
#Hour Int,
#Elapsed Varchar(10)
Select #Seconds = ABS(DateDiff(SECOND ,#StartDateTime,#EndDateTime))
If #Seconds >= 60
Begin
select #Minute = #Seconds/60
select #Seconds = #Seconds%60
If #Minute >= 60
begin
select #hour = #Minute/60
select #Minute = #Minute%60
end
Else
Goto Final
End
Final:
Select #Hour = Isnull(#Hour,0), #Minute = IsNull(#Minute,0), #Seconds = IsNull(#Seconds,0)
select #Elapsed = Cast(#Hour as Varchar) + '':'' + Cast(#Minute as Varchar) + '':'' + Cast(#Seconds as Varchar)
Return (#Elapsed)
End'
)
declare #dt1 datetime='2012/06/13 08:11:12', #dt2 datetime='2012/06/12 02:11:12'
select CAST((#dt2-#dt1) as time(0))
PRINT DATEDIFF(second,'2010-01-22 15:29:55.090','2010-01-22 15:30:09.153')
select
datediff(millisecond,'2010-01-22 15:29:55.090','2010-01-22 15:30:09.153') / 1000.0 as Secs
result:
Secs
14.063
Just thought I'd mention it.
Sol-1:
select
StartTime
, EndTime
, CONVERT(NVARCHAR,(EndTime-StartTime), 108) as TimeDiff
from
[YourTable]
Sol-2:
select
StartTime
, EndTime
, DATEDIFF(hh, StartTime, EndTime)
, DATEDIFF(mi, StartTime, EndTime) % 60
from
[YourTable]
Sol-3:
select
DATEPART(hour,[EndTime]-[StartTime])
, DATEPART(minute,[EndTime]-[StartTime])
from
[YourTable]
Datepart works the best
Please check below trick to find the date difference between two dates
DATEDIFF(DAY,ordr.DocDate,RDR1.U_ProgDate) datedifff
where you can change according your requirement as you want difference of days or month or year or time.
CREATE FUNCTION getDateDiffHours(#fdate AS datetime,#tdate as datetime)
RETURNS varchar (50)
AS
BEGIN
DECLARE #cnt int
DECLARE #cntDate datetime
DECLARE #dayDiff int
DECLARE #dayDiffWk int
DECLARE #hrsDiff decimal(18)
DECLARE #markerFDate datetime
DECLARE #markerTDate datetime
DECLARE #fTime int
DECLARE #tTime int
DECLARE #nfTime varchar(8)
DECLARE #ntTime varchar(8)
DECLARE #nfdate datetime
DECLARE #ntdate datetime
-------------------------------------
--DECLARE #fdate datetime
--DECLARE #tdate datetime
--SET #fdate = '2005-04-18 00:00:00.000'
--SET #tdate = '2005-08-26 15:06:07.030'
-------------------------------------
DECLARE #tempdate datetime
--setting weekends
SET #fdate = dbo.getVDate(#fdate)
SET #tdate = dbo.getVDate(#tdate)
--RETURN #fdate
SET #fTime = datepart(hh,#fdate)
SET #tTime = datepart(hh,#tdate)
--RETURN #fTime
if datediff(hour,#fdate, #tdate) <= 9
RETURN(convert(varchar(50),0) + ' Days ' + convert(varchar(50),datediff(hour,#fdate, #tdate))) + ' Hours'
else
--setting working hours
SET #nfTime = dbo.getV00(convert(varchar(2),datepart(hh,#fdate))) + ':' +dbo.getV00(convert(varchar(2),datepart(mi,#fdate))) + ':'+ dbo.getV00(convert(varchar(2),datepart(ss,#fdate)))
SET #ntTime = dbo.getV00(convert(varchar(2),datepart(hh,#tdate))) + ':' +dbo.getV00(convert(varchar(2),datepart(mi,#tdate))) + ':'+ dbo.getV00(convert(varchar(2),datepart(ss,#tdate)))
IF #fTime > 17
begin
set #nfTime = '17:00:00'
end
else
begin
IF #fTime < 8
set #nfTime = '08:00:00'
end
IF #tTime > 17
begin
set #ntTime = '17:00:00'
end
else
begin
IF #tTime < 8
set #ntTime = '08:00:00'
end
-- used for working out whole days
SET #nfdate = dateadd(day,1,#fdate)
SET #ntdate = #tdate
SET #nfdate = convert(varchar,datepart(yyyy,#nfdate)) + '-' + convert(varchar,datepart(mm,#nfdate)) + '-' + convert(varchar,datepart(dd,#nfdate))
SET #ntdate = convert(varchar,datepart(yyyy,#ntdate)) + '-' + convert(varchar,datepart(mm,#ntdate)) + '-' + convert(varchar,datepart(dd,#ntdate))
SET #cnt = 0
SET #dayDiff = 0
SET #cntDate = #nfdate
SET #dayDiffWk = convert(decimal(18,2),#ntdate-#nfdate)
--select #nfdate,#ntdate
WHILE #cnt < #dayDiffWk
BEGIN
IF (NOT DATENAME(dw, #cntDate) = 'Saturday') AND (NOT DATENAME(dw, #cntDate) = 'Sunday')
BEGIN
SET #dayDiff = #dayDiff + 1
END
SET #cntDate = dateadd(day,1,#cntDate)
SET #cnt = #cnt + 1
END
--SET #dayDiff = convert(decimal(18,2),#ntdate-#nfdate) --datediff(day,#nfdate,#ntdate)
--SELECT #dayDiff
set #fdate = convert(varchar,datepart(yyyy,#fdate)) + '-' + convert(varchar,datepart(mm,#fdate)) + '-' + convert(varchar,datepart(dd,#fdate)) + ' ' + #nfTime
set #tdate = convert(varchar,datepart(yyyy,#tdate)) + '-' + convert(varchar,datepart(mm,#tdate)) + '-' + convert(varchar,datepart(dd,#tdate)) + ' ' + #ntTime
set #markerFDate = convert(varchar,datepart(yyyy,#fdate)) + '-' + convert(varchar,datepart(mm,#fdate)) + '-' + convert(varchar,datepart(dd,#fdate)) + ' ' + '17:00:00'
set #markerTDate = convert(varchar,datepart(yyyy,#tdate)) + '-' + convert(varchar,datepart(mm,#tdate)) + '-' + convert(varchar,datepart(dd,#tdate)) + ' ' + '08:00:00'
--select #fdate,#tdate
--select #markerFDate,#markerTDate
set #hrsDiff = convert(decimal(18,2),datediff(hh,#fdate,#markerFDate))
--select #hrsDiff
set #hrsDiff = #hrsDiff + convert(int,datediff(hh,#markerTDate,#tdate))
--select #fdate,#tdate
IF convert(varchar,datepart(yyyy,#fdate)) + '-' + convert(varchar,datepart(mm,#fdate)) + '-' + convert(varchar,datepart(dd,#fdate)) = convert(varchar,datepart(yyyy,#tdate)) + '-' + convert(varchar,datepart(mm,#tdate)) + '-' + convert(varchar,datepart(dd,#tdate))
BEGIN
--SET #hrsDiff = #hrsDiff - 9
Set #hrsdiff = datediff(hour,#fdate,#tdate)
END
--select FLOOR((#hrsDiff / 9))
IF (#hrsDiff / 9) > 0
BEGIN
SET #dayDiff = #dayDiff + FLOOR(#hrsDiff / 9)
SET #hrsDiff = #hrsDiff - FLOOR(#hrsDiff / 9)*9
END
--select convert(varchar(50),#dayDiff) + ' Days ' + convert(varchar(50),#hrsDiff) + ' Hours'
RETURN(convert(varchar(50),#dayDiff) + ' Days ' + convert(varchar(50),#hrsDiff)) + ' Hours'
END
For Me This worked Perfectly
Convert(varchar(8),DATEADD(SECOND,DATEDIFF(SECOND,LogInTime,LogOutTime),0),114)
and the Output is
HH:MM:SS which is shown accurately in my case.
Please try
DECLARE #articleDT DATETIME;
DECLARE #nowDate DATETIME;
-- Time of the ARTICLE created
SET #articleDT = '2012-04-01 08:10:16';
-- Simulation of NOW datetime
-- (in real world you would probably use GETDATE())
SET #nowDate = '2012-04-10 11:35:36';
-- Created 9 days ago.
SELECT 'Created ' + CAST(DATEDIFF(day, #articleDT, #nowDate) AS NVARCHAR(50)) + ' days ago.';
-- Created 1 weeks, 2 days, 3 hours, 25 minutes and 20 seconds ago.
SELECT 'Created '
+ CAST(DATEDIFF(second, #articleDT, #nowDate) / 60 / 60 / 24 / 7 AS NVARCHAR(50)) + ' weeks, '
+ CAST(DATEDIFF(second, #articleDT, #nowDate) / 60 / 60 / 24 % 7 AS NVARCHAR(50)) + ' days, '
+ CAST(DATEDIFF(second, #articleDT, #nowDate) / 60 / 60 % 24 AS NVARCHAR(50)) + ' hours, '
+ CAST(DATEDIFF(second, #articleDT, #nowDate) / 60 % 60 AS NVARCHAR(50)) + ' minutes and '
+ CAST(DATEDIFF(second, #articleDT, #nowDate) % 60 AS NVARCHAR(50)) + ' seconds ago.';
For MS SQL, you can convert the datetime value to a double value.
The integer part contains the number of days since 1900-01-01, the fractional part contains the time in hours.
So you can calculate date difference as:
cast(date1-date2 as FLOAT)
Given two date/times:
#start_date = '2009-04-15 10:24:00.000'
#end_date = '2009-04-16 19:43:01.000'
Is it possible to calculate the time elapsed between the two dates in the following format
1d 9h 19m
You can get the difference between the two dates to whatever resolution you want (in your example, minutes):
DATEDIFF(minute, #start_date, #end_date)
From there it's a simple matter of dividing minutes into hours and hours into days and modding the remainder.
I know this thread is older and the original participants are likely no longer watching, but I stumbled upon it, and had already written some code fairly recently to do something very close to what jdiaz is requesting. The result is rendered as a string in D:H:M:S format.
Step one would be to get the time span in seconds:
DECLARE #ElapsedS INT
SET #ElapsedS = DATEDIFF(second, #start_date, #end_date)
Now create the following scalar function:
CREATE FUNCTION [dbo].[udfTimeSpanFromSeconds]
(
#Seconds int
)
RETURNS varchar(15)
AS
BEGIN
DECLARE
--Variable to hold our result
#DHMS varchar(15)
--Integers for doing the math
, #Days int --Integer days
, #Hours int --Integer hours
, #Minutes int --Integer minutes
--Strings for providing the display
, #sDays varchar(5) --String days
, #sHours varchar(2) --String hours
, #sMinutes varchar(2) --String minutes
, #sSeconds varchar(2) --String seconds
--Get the values using modulos where appropriate
SET #Hours = #Seconds/3600
SET #Minutes = (#Seconds % 3600) /60
SET #Seconds = (#Seconds % 3600) % 60
--If we have 24 or more hours, split the #Hours value into days and hours
IF #Hours > 23
BEGIN
SET #Days = #Hours/24
SET #Hours = (#Hours % 24)
END
ELSE
BEGIN
SET #Days = 0
END
--Now render the whole thing as string values for display
SET #sDays = convert(varchar, #Days)
SET #sHours = RIGHT('0' + convert(varchar, #Hours), 2)
SET #sMinutes = RIGHT('0' + convert(varchar, #Minutes), 2)
SET #sSeconds = RIGHT('0' + convert(varchar, #Seconds), 2)
--Concatenate, concatenate, concatenate
SET #DHMS = #sDays + ':' + #sHours + ':' + #sMinutes + ':' + #sSeconds
RETURN #DHMS
END
Now feed your timespan into the newly created function:
SELECT TimeSpan = dbo.udfTimeSpanFromSeconds(#ElapsedS)
Should produce '1:09:19:01'
CONVERT(
varchar(8),
(
CAST(#end_date AS DATETIME)
-
CAST(#start_date AS DATETIME)
)
,108
)
This'll give it to you as HH:MM:SS
Cheers
DATEDIFF can return unintuitive values. For example, the two dates below differ by one second yet DATEDIFF with the parameters below and interpreted as others have interpreted it above returns 1 year:
SELECT DATEDIFF(year, '2005-12-31 23:59:59', '2006-01-01 00:00:00')
Look at the MSDN documentation for DATEDIFF to understand how it works.
datediff(datepart, date1, date2);
Rex's answer is more complete.
Here's how you format the datediff (50d 8h 35m) in a query:
Declare #Date1 as Datetime, #Date2 as Datetime
Set #Date1 = '2005-01-01 08:00:00'
Set #Date2 = '2005-02-20 16:35:30'
Select
CAST(DATEDIFF(Minute,#Date1, #Date2)/60/24 as Varchar(50)) ++ 'd ' ++
CAST((DATEDIFF(Minute,#Date1, #Date2)/60)-((DATEDIFF(Minute,#Date1, #Date2)/60/24)*24) as Varchar(50)) ++ 'h ' ++
CAST((DATEDIFF(Minute,#Date1, #Date2)) - (DATEDIFF(HOUR,#Date1, #Date2)*60) as Varchar(50)) ++ 'm' as FormattedDateDiff
DECLARE #FirstDate DATETIME, #SecondDate DATETIME, #result VARCHAR(MAX)
SELECT #FirstDate = '2017-03-01 09:54:00.637', #SecondDate = GETDATE()
DECLARE #Day INT,#Month INT,#Hour INT, #Minute INT,#TotalSeconds INT,#Year INT
SELECT #TotalSeconds = ABS(DATEDIFF(SECOND,#FirstDate,#SecondDate))
-- Standard values in seconds
DECLARE #YearSeconds INT, #MonthSeconds INT, #DaySeconds INT, #HourSeconds INT, #MinuteSeconds INT
SELECT #MinuteSeconds = 60
SELECT #HourSeconds = 60 * #MinuteSeconds
SELECT #DaySeconds = 24 * #HourSeconds
SELECT #MonthSeconds = 30 * #DaySeconds
SELECT #YearSeconds = 12 * #MonthSeconds
--SELECT #MinuteSeconds AS [Minutes], #HourSeconds AS [Hours], #DaySeconds AS [Day],#MonthSeconds AS [Month],#YearSeconds AS [Year]
IF #TotalSeconds < #MinuteSeconds
BEGIN
SELECT #result = CAST(#TotalSeconds AS NVARCHAR(20)) + ' seconds ago'
END
ELSE IF #TotalSeconds < #HourSeconds
BEGIN
SELECT #result = CAST(ABS(DATEDIFF(MINUTE,#FirstDate,#SecondDate)) AS NVARCHAR(20)) + ' minutes ago'
END
ELSE IF #TotalSeconds < #DaySeconds
BEGIN
SELECT #result = CAST(ABS(DATEDIFF(HOUR,#FirstDate,#SecondDate)) AS NVARCHAR(20)) + ' hours ago'
END
ELSE IF #TotalSeconds < #MonthSeconds
BEGIN
SELECT #result = CAST(ABS(DATEDIFF(DAY,#FirstDate,#SecondDate)) AS NVARCHAR(20)) + ' days ago'
END
ELSE IF #TotalSeconds < #YearSeconds
BEGIN
SELECT #result = CAST(ABS(DATEDIFF(MONTH,#FirstDate,#SecondDate)) AS NVARCHAR(20)) + ' months ago'
END
ELSE IF #TotalSeconds > #YearSeconds
BEGIN
SELECT #result = CAST(ABS(DATEDIFF(YEAR,#FirstDate,#SecondDate)) AS NVARCHAR(20)) + ' year ago'
END
SELECT #result