How to find a matching range based on a given value x
For example, in column A, we have the value: {15-17,18-20,21-23}
The output expected for the x=16 should be 15-17
or x=21 should be 21-23
Any idea of the best way to achieve that ?
Try
select rangetext
from unnest('{15-17,18-20,21-23}'::text[]) as t(rangetext)
where 16 between split_part(rangetext , '-', 1)::integer
and split_part(rangetext , '-', 2)::integer;
Related
I'm trying to create a new column (y) from another column (x) - my aim is to extract the numeric value after the 1st space of the string from the right-hand side, and if there is no numeric value after the space, then NULL.
I used the following SQL query below; however, the query extracted both numeric and non-numeric after the space into the new column (y) - please see the first image below. I have also attempted to use case statement but have yet to achieve the required output.
SELECT x, SUBSTR(x, INSTR(x,' ', -1) + 1) AS y
FROM <table_name>;
I would like the table to return:-
Thanks for your help in advance!
You could try regular expression function REGEXP_SUBSTR
SELECT x, REGEXP_SUBSTR (x, '(\s)(\d+)$') AS y
FROM <table_name>
Please check demo here: http://sqlfiddle.com/#!4/7bc0ee/4866
If you want to keep your SUBSTRING idea, you can use VALIDATE_CONVERSION to check whether your substring is numeric or not.
Then a CASE will select this substring or NULL if not numeric:
SELECT x,
CASE WHEN VALIDATE_CONVERSION(SUBSTR(x, INSTR(x,' ', -1) + 1) AS NUMBER) = 1
THEN SUBSTR(x, INSTR(x,' ', -1) + 1)
ELSE NULL END AS y
FROM yourtable;
Try out db<>fiddle
Here the documentation of VALIDATE_CONVERSION
I have a column with the given values
MRN
1946
456
27
557
The column values length is fixed.
If at all any value is less than 6characters,then it should concate 0's to the left and make it 6characters length.
The desired output is
MRN
001946
000456
000027
000557
This is called left paddings. In SQL Server, this is typically done with more basic string operations:
select right(replicate('0', 6) + mrn, 6)
If mrn is a number, then use the concat() function:
select right(concat(replicate('0', 6), mrn), 6)
You can also use the FORMAT function for this. (Demo)
SELECT FORMAT(MRN ,'D6')
FROM YourTable
Change the number 6 to whatever your total length needs to be:
SELECT REPLICATE('0',6-LEN(EmployeeId)) + EmployeeId
If the column is an INT, you can use RTRIM to implicitly convert it to a VARCHAR
SELECT REPLICATE('0',6-LEN(RTRIM(EmployeeId))) + RTRIM(EmployeeId)
And the code to remove these 0s and get back the 'real' number:
SELECT RIGHT(EmployeeId,(LEN(EmployeeId) - PATINDEX('%[^0]%',EmployeeId)) + 1)
We can achieve this by adding leading zero's
select RIGHT('0000'+CAST(MRN AS VARCHAR(10)),6)
I have a column called Supervisor from a table JobData in a SQL Server database. In this Supervisor column the records are of the format below.
DANNYL
ADITYAG
SAMMYS
BOBBYJ
I want to convert these records to lower case and bring the last letter to first letter. For example, DANNYL should be changed to the format ldanny and this format should be applied to all the remaining records.
Can anyone help me out with a SQL query for this?
You can use the following solution using LEFT and RIGHT to get the parts of the name. By using LOWER you can convert the upper case characters to lower case:
SELECT LOWER(RIGHT(Supervisor, 1) + LEFT(Supervisor, LEN(Supervisor) - 1))
FROM JobData
WHERE LTRIM(RTRIM(Supervisor)) <> ''
-- or using ABS on the length - 1 so the WHERE isn't needed.
SELECT LOWER(RIGHT(Supervisor, 1) + LEFT(Supervisor, ABS(LEN(Supervisor) - 1)))
FROM JobData
Since it looks like the column Supervisor contains empty values you can also use the following solution without calculation and not failing on the empty values:
SELECT LOWER(RIGHT(Supervisor, 1) + REVERSE(SUBSTRING(REVERSE(Supervisor), 2, LEN(Supervisor))))
FROM JobData
... and another possibility using STUFF:
SELECT LOWER(LEFT(STUFF(Supervisor, 1, 0, RIGHT(Supervisor, 1)), LEN(Supervisor)))
FROM JobData
demo on dbfiddle.uk
there is probably a better way do to that , but here is my proposition.
SELECT lower(left(right('DANYL',1)+'DANYL',len('DANYL')))
Using SUBSTRING you can get the expected result:
SELECT LOWER(CONCAT(SUBSTRING(Supervisor, LEN(Supervisor), 1), SUBSTRING(Supervisor, 0, LEN(Supervisor))))
FROM JobData
Demo with the given sample data:
DECLARE #JobData TABLE (Supervisor VARCHAR(100));
INSERT INTO #JobData (Supervisor) VALUES
('DANNYL'), ('ADITYAG'), ('SAMMYS'), ('BOBBYJ');
SELECT LOWER(CONCAT(SUBSTRING(Supervisor, LEN(Supervisor), 1), SUBSTRING(Supervisor, 0, LEN(Supervisor)))) AS Supervisor
FROM #JobData
Output:
ldanny
gaditya
ssammy
jbobby
Like this? :
SELECT
LOWER(CONCAT(SUBSTRING([Supervisor], LEN([Supervisor]), 1),SUBSTRING([Supervisor], 1, ABS(LEN([Supervisor])-1))))
FROM TABLE
I have a column that has entries such as 86D12345, 86A12345, etc. I need to be able to do 2 things:
Select MAX value of this column
Add 1 to get the next number
This column is nvarchar, so I assume I will have to utilize the substring function plus the select MAX, but cannot seem to get the results. Example is when I run this query:
select substring(convert(numeric(5,0), certno),4,len(certno))+1 from maxcertno
I get:
Argument data type numeric is invalid for argument 1 of substring function.
Same error with cast
Any ideas?
Assuming the format if fixed like nn N nnnnn (without the blanks).
This gives the next value (12346):
cast(substring(certno, 4, len(certno)) as int) + 1
And this gives the whole string incremented by 1 (86D12346):
left(certno, 3) + cast(cast(substring(certno, 4, len(certno)) as int) + 1 as nvarchar(50))
With the max function:
select
cast(substring(max(certno), 4, len(max(certno))) as int) + 1,
left(max(certno), 3) + cast(cast(substring(max(certno), 4, len(max(certno))) as int) + 1 as nvarchar(50))
from YourTable
The last is probably not a good solution in that it's repeating max all over the query. Better to get the max value first and then apply the logic. Or maybe make it a function or stored proc.
I have, in my DB oracle 10g, a field that contains references.
It's stored as : name/yyyy/mm/number
The new number, is the max number found in the part mm/number.
So, for now, I have a split of my string that gives me a list of str_array like this :
str_array(name, yyyy, mm, number)
I'd like, with this, found max number, for the couple mm/number.
Is this possible to do this?
Can I have something like :
SELECT MAX(split(reference, '/').lastPartOfArray) into nb
FROM table
where lastPartOfArray-1 = sysdate.month;
Data samples :
Smith/2013/12/1
Smith/2013/11/1
Smith/2013/12/3
Jones/2013/12/6
Smith/2013/12/3
Jones/2013/11/7
Since we are in the month 12, a max on those data must give me 6 into nb.
The number part, has no limit, it can be 1000, 10000...
The part Jones/2013 doesn't really matter for the number. But I can't have the same number, for a month.
My apologies, I don't know if this is possible, so I tried to write what I want in the query.
Is this possible, or should I create more than one field in my table(name/yyyy, mm, number)?
edit : valex answer and some custom
select MAX(CAST(SUBSTR(num,INSTR(num,'/')+9,1000) as Int))
from T
where num like TO_CHAR(sysdate,'%/YYYY/MM/%')
So this, count searching first occurence.
select MAX(CAST(SUBSTR(num,INSTR(num,'/',1 ,n)+1,1000) as Int))
from T
where num like TO_CHAR(sysdate,'%/YYYY/MM/%')
This found the n occurence of the char.
This is a helpful solution in other cases.
To get a maximum you should convert this last part into INT values otherwise you can get not right results because of STRING comparing rules will be used.
As soon as /YYYY/MM/ has got a fixed length = 9 so we can find first \ position and add 9 to this position to find a last part number substring start.
Here is an example:
select MAX(CAST(SUBSTR(num,INSTR(num,'/')+9,1000) as Int))
from T
where num like TO_CHAR(sysdate,'%/YYYY/MM/%')
SQLFiddle demo
Also you can exclude wrong formatted values from this query to avoid conversion errors using the following way:
select MAX(CAST(SUBSTR(num,INSTR(num,'/')+9,1000) as Int))
from T
where num like TO_CHAR(sysdate,'%/YYYY/MM/%')
AND
LENGTH(TRIM(TRANSLATE(SUBSTR(num,INSTR(num,'/')+9,1000),
' 0123456789', ' '))) is null
SQLfiddle demo
Try this:
SELECT
MAX(SUBSTR(num, INSTR(num, '/', 1, 3) + 1))
FROM ref
WHERE
SUBSTR(num, INSTR(num, '/', 1, 2) + 1, INSTR(num, '/', 1, 3) - INSTR(num, '/', 1, 2) - 1) = TO_CHAR(sysdate, 'MM')
Sample: http://sqlfiddle.com/#!4/1b03a/1