For example, I have div tag that has two attributes.
class='hello#123' text='321#he#321llo#321'
<div> class='hello#123' text='321#he#321llo#321'></div>
Here, I want to write xpath for both class and text attributes but numbers may change dynamically. ie., "hello#123" may become "345" when we reload. "321#he#321llo#321" may become "567#he#456llo#321".
Note: Need to write xpath in single line not separately.
Assuming that you have the (corrected) two-attribute-HTML
<div class='hello#123' text='321#he#321llo#321'>...</div>
you can select it using the following, for example:
Using the contains() function
//div[contains(#class,'hello') and contains(#text,'#he#')]
This is quite specific and only applicable if the "hello" is always split in the same way
Using the translate() function to mask everything except the chars for "hello"
//div[translate(#class,'#0123456789','')='hello' and translate(#text,'#0123456789','')='hello']
This removes all # chars and digits and checks if the remaining string is "hello"
I guess combining these two approaches you will be able to create your own XPath expression fitting your needs. The patterns you provided were not fully clear, so this may only approach a good enough solution.
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Regular expression to remove HTML tags
Is there an expression which will get the value between two HTML tags?
Given this:
<td class="played">0</td>
I am looking for an expression which will return 0, stripping the <td> tags.
You should not attempt to parse HTML with regex. HTML is not a regular language, so any regex you come up with will likely fail on some esoteric edge case. Please refer to the seminal answer to this question for specifics. While mostly formatted as a joke, it makes a very good point.
The following examples are Java, but the regex will be similar -- if not identical -- for other languages.
String target = someString.replaceAll("<[^>]*>", "");
Assuming your non-html does not contain any < or > and that your input string is correctly structured.
If you know they're a specific tag -- for example you know the text contains only <td> tags, you could do something like this:
String target = someString.replaceAll("(?i)<td[^>]*>", "");
Edit:
Ωmega brought up a good point in a comment on another post that this would result in multiple results all being squished together if there were multiple tags.
For example, if the input string were <td>Something</td><td>Another Thing</td>, then the above would result in SomethingAnother Thing.
In a situation where multiple tags are expected, we could do something like:
String target = someString.replaceAll("(?i)<td[^>]*>", " ").replaceAll("\\s+", " ").trim();
This replaces the HTML with a single space, then collapses whitespace, and then trims any on the ends.
A trivial approach would be to replace
<[^>]*>
with nothing. But depending on how ill-structured your input is that may well fail.
You could do it with jsoup http://jsoup.org/
Whitelist whitelist = Whitelist.none();
String cleanStr = Jsoup.clean(yourText, whitelist);
I am writing as SQL query which might return HTML text also. HTML Tags are fine for me, because I want to show it formatted with the HTML tags in the front end. But I do not need links. I mean is there anyway I can strip off the hyper links only from the column. just the anchor tag. I am so bad in Regular Expressions, though i think that might be the solution for this. Any help!
This should work fine for links:
<a[^>]*>(.*?)<\/a>
Since you say you don't understand regular expressions, I might as well explain. The <a part is straightforward, the [^>]* will match anything up to the closing bracket, the bracket is just the bracket. (.*?) matches anything, regardless of length, empty links as well. The ? is required so that it becomes non-greedy, so it stops at the first closing tag. <\/a> matches the closing tag.
Edit: if you have spaces in between your tags, you can use <a[^>]*>((?:.|\s)*?)<\/a>. Notice I added the (?:.|\s)*? in place of .*?. The .|\s means match any character or space, the ?: indicate a non capturing group, since we don't care which particular character was matched.
In String Template one can easily get an element of a Java Map within the template.
Is it possible to get the n-th element of an array in a similar way?
According to the String Template Cheat Sheet you can easily get the first or second element:
You can combine operations to say things like first(rest(names)) to get second element.
but it doesn't seem possible to get the n-th element easily. I usually transform my list into a map with list indexes as keys and do something like
map.("25")
Is there some easier/more straightforward way?
Sorry, there is no mechanism to get a[i].
There is no easy way getting n-th element of the list.
In my opinion this indicates that your view and business logic are not separated enough: knowledge of what magic number 25 means is spread in both tiers.
One possible solution might be converting list of values to object which provides meaning to the elements. For example, lets say list of String represents address lines, in which case instead of map.("3") you would write address.street.
I have url, for example:
http://i.myhost.com/myimage.jpg
I want to change this url to
http://i.myhost.com/myimageD.jpg.
(Add D after image name and before point)
i.e I want add some words after image name and before point using regex.
What is the best way do it using regex?
Try using ^(.*)\.([a-zA-Z]{3,5}) and replacing with \1D\2. I'm assuming the extension is 3-5 alphanumeric numbers but you can modify it to suit. E.g. if it's just jpg images then you can put that instead of the [a-zA-Z]{3,5}.
Sounds like a homework question given the solution must use a regex, on that assumption here is an outline to get you going.
If all you have is a URL then #mathematical.coffee's solution will suit. However if you have a chunk of text within which is one or more URLs and you have to locate and change just those then you'll need something a little more involved.
Look at the structure of a URL: {protocol}{address}{item}; where
{protocol} is "http://", "ftp://" etc.;
{address} is a name, e.g. "www.google.com", or a number, e.g. "74.125.237.116" - there will always be at least one dot in the address; and
{item} is "/name" where name is quite flexible - there will be zero or more items, you can think of them as directories and a file but this isn't strictly true. Also the sequence of items can end in a "/" (including when there are zero of them).
To make a regex which matches a URL start by matching each part. In the case of the items you'll want to match the last in the sequence separately - you'll have zero or more "directories" and one "file", the latter must be of the form "name.extension".
Once you have regexes for each part you just concatenate them to produce a regex for the whole. To form the replacement pattern you can surround parts of your regex with parentheses and refer to those parts using \number in the replacement string - see #mathematical.coffee's solution for an example.
The best way to learn regexs is to use an editor which supports them and just experiment. The exact syntax may not be the same as NSRegularExpression but they are mostly pretty similar for the basic stuff and you can translate from one to another easily.
Can someone help me to bring this code working? I have several select fields and I only want the last one in my variable.
variable = browser.elements_by_xpath('//div[#class="nested-field"]//select[last()]
Thanks!
This is a FAQ: The [] operator in XPath has higher precedence (priority) than the // pseudo-operator. This is why brackets must be used to change the default operator priorities. There are at least several similar questions with good explanations -- search for them and read and understand.
Instead of:
//div[#class="nested-field"]//select[last()]
Use:
(//div[#class="nested-field"]//select)[last()]
is the class attribute an exact match?
if the mark up is like this
<div class="nested-field other">
...
then you'll have to either match by the exact class or use xpath contains.