SQL to query historical table that the count of the number of times in the column is 1 - sql

Question

I'm not even sure what to call this type of query and that's why the title might be misleading. Here's what I want to do. We have a history table that goes like this
id, mod_date, is_active
1, 2022-06-22:12:00:00, 1
1, 2022-06-22:13:00:00, 0
2, 2022-06-22:12:00:00, 0
3, 2022-07-07:00:00:00, 1
is_active means that the record was made active. For example, row 1 was made active at 2022-06-22:12:00:00 and then was made inactive at 13:00:00.
What I want is to get only the row that was made inactive on a specific day and not made active again on that day. I came up with this query
select distinct(id)
from history
where is_active = 0
and cast(ah.mod_date as date) = '2022-06-22'
It would return 1 and 2. But I only want 2 because 1 was toggled between states. So, I only want to find all of ids that was made inactive on a specific day and never made active again on that day or any of the toggling the same day.

Answer 1

You may phrase this using exists logic:
SELECT *
FROM history h1
WHERE is_active = 0 AND mod_date::date = '2022-06-22' AND
NOT EXISTS (SELECT 1
FROM history h2
WHERE h2.mod_date::date = '2022-06-22' AND
h2.id = h1.id AND h2.is_active = 1);

Answer 2

Count how many times an id has been activated and deactivated in a day. From the result select the ones that have been deactivated once and activated zero times.
with the_historical_table(id, mod_date, is_active) as
(
values
(1, '2022-06-22:12:00:00', 1),
(1, '2022-06-22:13:00:00', 0),
(2, '2022-06-22:12:00:00', 0),
(3, '2022-07-07:00:00:00', 1)
)
select id, mod_date from
(
select id, mod_date::date,
count(*) filter (where is_active = 1) activated,
count(*) filter (where is_active = 0) deactivated
from the_historical_table
group by id, mod_date::date
) t
where activated = 0 and deactivated = 1;
Result:
id
mod_date
2
2022-06-22

Answer 3

What I want is to get only the row that was made inactive on a
specific day and not made active again on that day
partition.: partition by id, mod_date::date order by id, mod_date
ordered set 1 0 1 row 0 the middle row, both lead and lag is 1. You don't want this situation in the partition.
Consider 3 case.
After partition only have one row, is_action = 0 that mean both lead and lag is NULL.
Partition have multi rows.
Partition have multi rows, ordered set multiple 1 followed by multiple 0
demo
The follow code is like compute base on these 3 logic and then union all.
WITH cte AS (
SELECT
*,
lag(is_active, 1) OVER w,
lead(is_active, 1) OVER w,
first_value(is_active) OVER (PARTITION BY id,
mod_date::date ORDER BY id,
mod_date DESC)
FROM test1
WINDOW w AS (PARTITION BY id,
mod_date::date ORDER BY id,
mod_date)) (
SELECT
id,
mod_date,
is_active
FROM
cte
WHERE (lead = 0
OR lead IS NULL)
AND (lag = 1)
AND is_active = 0
ORDER BY
id,
mod_date)
UNION ALL (
SELECT
id,
mod_date,
is_active
FROM
cte
WHERE
lead IS NULL
AND lag IS NULL
AND is_active = 0)
UNION ALL (
SELECT
id,
mod_date,
is_active
FROM
cte
WHERE
lead = 0
AND lag IS NULL
AND is_active = 0
AND first_value != 1)
ORDER BY
id,
mod_date;