I have a table called tbl_A with the following schema:
After insert, I have the following data in tbl_A:
Now the question is how to write a query for the following scenario:
Put (1) in front of any employee who was present three days consecutively
Put (0) in front of employee who was not present three days consecutively
The output screen shoot:
I think we should use case statement, but I am not able to check three consecutive days from date. I hope I am helped in this
Thank you
select name, case when max(cons_days) >= 3 then 1 else 0 end as presence
from (
select name, count(*) as cons_days
from tbl_A, (values (0),(1),(2)) as a(dd)
group by name, adate + dd
)x
group by name
With a self-join on name and available = 'Y', we create an inner table with different combinations of dates for a given name and take a count of those entries in which the dates of the two instances of the table are less than 2 units apart i.e. for each value of a date adate, it will check for entries with its own value adate as well as adate + 1 and adate + 2. If all 3 entries are present, the count will be 3 and you will have a flag with value 1 for such names(this is done in the outer query). Try the below query:
SELECT Z.NAME,
CASE WHEN Z.CONSEQ_AVAIL >= 3 THEN 1 ELSE 0 END AS YOUR_FLAG
FROM
(
SELECT A.NAME,
SUM(CASE WHEN B.ADATE >= A.ADATE AND B.ADATE <= A.ADATE + 2 THEN 1 ELSE 0 END) AS CONSEQ_AVAIL
FROM
TABL_A A INNER JOIN TABL_A B
ON A.NAME = B.NAME AND A.AVAILABLE = 'Y' AND B.AVAILABLE = 'Y'
GROUP BY A.NAME
) Z;
Due to the complexity of the problem, I have not been able to test it out. If something is really wrong, please let me know and I will be happy to take down my answer.
--Below is My Approch
select Name,
Case WHen Max_Count>=3 Then 1 else 0 end as Presence
from
(
Select Name,MAx(Coun) as Max_Count
from
(
select Name, (count(*) over (partition by Name,Ref_Date)) as Coun from
(
select Name,adate + row_number() over (partition by Name order by Adate desc) as Ref_Date
from temp
where available='Y'
)
) group by Name
);
select name as employee , case when sum(diff) > =3 then 1 else 0 end as presence
from
(select id, name, Available,Adate, lead(Adate,1) over(order by name) as lead,
case when datediff(day, Adate,lead(Adate,1) over(order by name)) = 1 then 1 else 0 end as diff
from table_A
where Available = 'Y') A
group by name;
Related
If I were to have a table such as the one below:
id_
last_updated_by
1
robot
1
human
1
robot
2
robot
3
robot
3
human
Using SQL, how could I group by the ID and create a new column to indicate whether a human has ever updated the record like this:
id_
last_updated_by
updated_by_human
1
robot
1
2
robot
0
3
robot
1
UPDATE
I'm currently doing the following, though I'm not sure how efficient this is. Selecting the latest record and then merging it with my calculated column via a sub-select.
SELECT MAIN.TRANSACTION_ID,
MAIN.CREATED_DATE
MAIN.CREATED_BY_USER_ID,
MAIN.OWNER_USER_ID,
STP.TOUCHED_BY_HUMAN
FROM (
SELECT TRANSACTION_ID,
CREATED_DATE
CREATED_BY_USER_ID_
OWNER_USER_ID_
FROM TABLE_NAME
WHERE CREATED_DATE >= CAST('{start_date} 00:00:00' AS TIMESTAMP)
AND CREATED_DATE <= CAST('{end_date} 23:59:59' AS TIMESTAMP)
QUALIFY row_number() OVER (partition by TRANSACTION_ID order by End_Dt desc) = 1
) MAIN
LEFT JOIN (
SELECT TRANSACTION_ID,
CASE
WHEN CREATED_BY_USER_ID IN ('ROBOT', 'MACHINE') OR
CREATED_BY_USER_ID LIKE 'N%' OR
CREATED_BY_USER_ID IS NULL
THEN 0
ELSE 1 END AS CREATED_BY_HUMAN,
CASE
WHEN OWNER_USER_ID IN ('ROBOT', 'MACHINE') OR
OWNER_USER_ID LIKE 'N%' OR
OWNER_USER_ID IS NULL
THEN 0
ELSE 1 END AS OWNED_BY_HUMAN,
CASE
WHEN CREATED_BY_HUMAN = 0 AND
OWNED_BY_HUMAN = 0
THEN 0
ELSE 1 END AS TOUCHED_BY_HUMAN_
FROM TABLE_NAME
WHERE CREATED_DATE >= CAST('{start_date} 00:00:00' AS TIMESTAMP)
AND CREATED_DATE <= CAST('{end_date} 23:59:59' AS TIMESTAMP)
QUALIFY row_number() OVER (partition by TRANSACTION_ID order by TOUCHED_BY_HUMAN_ desc) = 1
) STP
ON MAIN.TRANSACTION_ID = STP.TRANSACTION_ID
If I'm following your problem, then something like this should work.
SELECT
t.*
,CASE WHEN a.id IS NOT NULL THEN 1 ELSE 0 END AS updated_by_human
FROM table t
LEFT JOIN (SELECT DISTINCT id FROM table WHERE last_updated_by = 'human') a ON t.id = a.id
That takes care of the updated_by_human field, but if you also need to reduce the records in table (only keeping a subset) then you need more information to do that.
Exists clauses are usually not that performant but if your data isn't big this should work.
select id_,
IF (EXISTS (SELECT 1 FROM table_name t2 WHERE t2.last_updated_by = 'human' and t2.id_ = t1.id_), 1, 0) AS updated_by_human
from table_name t1;
here is another way
SELECT *
FROM table_name t1
GROUP BY ti.id_
HAVING COUNT(*) > 0
AND MAX(CASE t1.last_updated_by WHEN 'human' THEN 1 ELSE 0 END) = 1;
Since you didn't specified which column is used to determine this record is the newest record added by a given id, I assume that there will be a column to track the insert/modify timestamp (which is pretty standard table design), let's put it is last_updated_timestamp (if you don't have any, then I still insist you to have one as an auditing trail without timestamp does not make sense)
Given your table name is updating_trail
SELECT updating_trail.*, last_update_trail.modified_by_human
FROM updating_trail
INNER JOIN (
-- determine the id_, the lastest modified_timestamp, and a flag check to determine if there is any record with last_update_by is 'human' -> if yes then give 1
SELECT updating_trail.id_, MAX(last_update_timestamp) AS most_recent_update_ts, MAX(CASE WHEN updating_trail.last_updated_by = 'human' THEN 1 ELSE 0 END) AS modified_by_human
FROM updating_trail
GROUP BY updating_trail.id_
) last_update_trail
ON updating_trail.id_ = last_update_trail.id_ AND updating_trail.last_update_timestamp = last_update_trail.most_recent_update_ts;
Give
id_
last_updated_by
last_update_timestamp
modified_by_human
1
robot
2021-10-19T20:00:00.000Z
1
2
robot
2021-10-19T17:00:00.000Z
0
3
robot
2021-10-19T16:00:00.000Z
1
Check out this sample db fiddle I created for you
This is a 1:1 translation of your query to conditional aggregation:
SELECT TRANSACTION_ID,
CREATED_DATE,
CREATED_BY_USER_ID,
OWNER_USER_ID,
Max(CASE
WHEN CREATED_BY_USER_ID IN ('ROBOT', 'MACHINE') OR
CREATED_BY_USER_ID LIKE 'N%' OR
CREATED_BY_USER_ID IS NULL
THEN 0
ELSE 1
END) Over (PARTITION BY TRANSACTION_ID) AS CREATED_BY_HUMAN
FROM Table_Name
WHERE CREATED_DATE >= Cast('{start_date} 00:00:00' AS TIMESTAMP)
AND CREATED_DATE <= Cast('{end_date} 23:59:59' AS TIMESTAMP)
QUALIFY Row_Number() Over (PARTITION BY TRANSACTION_ID ORDER BY End_Dt DESC) = 1
I have below tables
Table1: "Demo"
Columns: SSN, sales, Create_DT,Update_Dt
Table2: "Agent"
Columns: SSN,sales, Agent_Name, Create_Dt, Update_DT
Scenario 1 and desired result set:
I want output as 0 if the count of SSN in Demo table is matched with the count of SSN in Agent table
if the count is not matched then I want result as 1
Scenario 2 and desired result set:
I want output as 0 if the sum of sales in Demo table is matched with the sum of sales in Agent table
if the sum is not matched then I want result as 1
Please help on this query part
Thanks
You can write two queries separately to take counts within the result query
SELECT (SELECT count(Demo.SSN) as SSN1 from Demo)!=(SELECT count(Agent.SSN) as SSN2 from Agent) AS Result;
Basically what the inner queries does is it checked whether the counts are equal or not and outputs 1 if it is true and 0 if it is false. Since you have asked to output 1 if it is false I used '!=' sign.
You can try the same procedure in scenario 2 also
For scenario 1
select (Case when (select count(ssn) from Demo)=(select count(ssn) from Agent) then 0 else 1 end) as desired_result
If you want to count unique ssn then:
select (Case when (select count(distinct ssn) from Demo)=(select count(distinct ssn) from Agent) then 0 else 1 end) as desired_result
For scenario 2:
select (Case when (select sum(sales) from Demo)=(select sum(sales) from Agent) then 0 else 1 end) as desired_result
I would suggest one query with both sets of information:
select (d.num_ssn <> a.num_ssn) as have_different_ssn_count,
(d.sales <> a.sales) as have_different_sales
from (select count(distinct ssn) as num_ssn,
coalesce(sum(sales), 0) as sales
from demo
) d cross join
(select count(distinct ssn) as num_ssn,
coalesce(sum(sales), 0) as sales
from agent
) a;
Note: This returns boolean values -- true/false rather than 1/0. If you really want 0/1, then use case:
select (case when d.num_ssn <> a.num_ssn then 1 else 0 end) as have_different_ssn_count,
(case when d.sales <> a.sales then 1 else 0 end) as have_different_sales
It would not surprise me if you were not only interested in the total counts but also that the agent/sales combinations are the same in both tables. If that is the case, please ask a new question with a clear explanation. Sample data and desired results help.
I have a table with 3 columns, id, name and vote. They're populated with many registers. I need that return the register with the best balance of votes. The votes types are 'yes' and 'no'.
Yes -> Plus 1
No -> Minus 1
This column vote is a string column. I am using SQL SERVER.
Example:
It must return Ann for me
Use conditional Aggregation to tally the votes as Kannan suggests in his answer
If you really only want 1 record then you can do it like so:
SELECT TOP 1
name
,SUM(CASE WHEN vote = 'yes' THEN 1 ELSE -1 END) AS VoteTotal
FROM
#Table
GROUP BY
name
ORDER BY
VoteTotal DESC
This will not allow for ties but you can use this method which will rank the responses and give you results use RowNum to get only 1 result or RankNum to get ties.
;WITH cteVoteTotals AS (
SELECT
name
,SUM(CASE WHEN vote = 'yes' THEN 1 ELSE -1 END) AS VoteTotal
,ROW_NUMBER() OVER (PARTITION BY 1 ORDER BY SUM(CASE WHEN vote = 'yes' THEN 1 ELSE -1 END) DESC) as RowNum
,DENSE_RANK() OVER (PARTITION BY 1 ORDER BY SUM(CASE WHEN vote = 'yes' THEN 1 ELSE -1 END) DESC) as RankNum
FROM
#Table
GROUP BY
name
)
SELECT name, VoteTotal
FROM
cteVoteTotals
WHERE
RowNum = 1
--RankNum = 1 --if you want with ties use this line instead
Here is the test data used and in the future do NOT just put an image of your test data spend the 2 minutes to make a temp table or a table variable so that people you are asking for help do not have to!
DECLARE #Table AS TABLE (id INT, name VARCHAR(25), vote VARCHAR(4))
INSERT INTO #Table (id, name, vote)
VALUES (1, 'John','no'),(2, 'John','no'),(3, 'John','yes')
,(4, 'Ann','no'),(5, 'Ann','yes'),(6, 'Ann','yes')
,(9, 'Marie','no'),(8, 'Marie','no'),(7, 'Marie','yes')
,(10, 'Matt','no'),(11, 'Matt','yes'),(12, 'Matt','yes')
Use this code,
;with cte as (
select id, name, case when vote = 'yes' then 1 else -1 end as votenum from register
) select name, sum(votenum) from cte group by name
You can get max or minimum based out of this..
This one gives the 'yes' rate for each person:
SELECT Name, SUM(CASE WHEN Vote = 'Yes' THEN 1 ELSE 0 END)/COUNT(*) AS Rate
FROM My_Table
GROUP BY Name
I have a table that has some duplicates. I can count the distinct records to get the Total Volume. When I try to Sum when the CompTia Code is B92 and run distinct is still counts the dupes.
Here is the query:
select
a.repair_week_period,
count(distinct a.notif_id) as Total_Volume,
sum(distinct case when a.header_comptia_cd = 'B92' then 1 else 0 end) as B92_Sum
FROM artemis_biz_app.aca_service_event a
where a.Sales_Org_Cd = '8210'
and a.notif_creation_dt >= current_date - 180
group by 1
order by 1
;
Is There a way to only SUM the distinct records for B92?
I also tried inner joining the table on itself by selecting the distinct notification id and joining on that notification id, but still getting wrong sum counts.
Thanks!
Your B92_Sum currently returns either NULL, 1 or 2, this is definitely no sum.
To sum distinct values you need something like
sum(distinct case when a.header_comptia_cd = 'B92' then column_to_sum else 0 end)
If this column_to_sum is actually the notif_id you get a conditional count but not a sum.
Otherwise the distinct might remove too many vales and then you probably need a Derived Table where you remove duplicates before aggregation:
select
repair_week_period,
--no more distinct needed
count(a.notif_id) as Total_Volume,
sum(case when a.header_comptia_cd = 'B92' then column_to_sum else 0 end) as B92_Sum
FROM
(
select repair_week_period,
notif_id
header_comptia_cd,
column_to_sum
from artemis_biz_app.aca_service_event
where a.Sales_Org_Cd = '8210'
and a.notif_creation_dt >= current_date - 180
-- only onw row per notif_id
qualify row_number() over (partition by notif_id order by ???) = 1
) a
group by 1
order by 1
;
#dnoeth It seems the solution to my problem was not to SUM the data, but to count distinct it.
This is how I resolved my problem:
count(distinct case when a.header_comptia_cd = 'B92' then a.notif_id else NULL end) as B92_Sum
I want a count but it repeats 1 with every record. Can you please suggest what to do?
SELECT Count(*),
innerTable.*
FROM (SELECT (SELECT NAME
FROM tours
WHERE tours.id = tourbooking.tourid) AS NAME,
(SELECT url
FROM tours
WHERE tours.id = tourbooking.tourid) AS Url,
(SELECT TOP 1 NAME
FROM tourimages
WHERE tourimages.tourid = tourbooking.tourid
ORDER BY id ASC) AS ImageName,
(SELECT duration + ' ' + CASE WHEN durationtype = 'd' THEN
'Day(s)' WHEN
durationtype =
'h' THEN 'Hour(s)' END
FROM tours
WHERE tours.id = tourbooking.tourid) AS Duration,
(SELECT Replace(Replace('<a> Adult(s) - <c> Children', '<a>', Sum
(CASE
WHEN [type] = 1 THEN 1
ELSE 0
END)),
'<c>',
Sum(CASE
WHEN [type] = 2 THEN 1
ELSE 0
END))
FROM tourperson
WHERE tourperson.bookingid = tourbooking.id) AS TotalPassengers
,
startdate,
createddate AS BookingDate,
id AS BookingID,
[status],
serviceprice
FROM tourbooking
WHERE memberid = 6)AS innerTable
GROUP BY innerTable.NAME,
innerTable.bookingdate,
innerTable.bookingid,
innerTable.duration,
innerTable.imagename,
innerTable.serviceprice,
innerTable.startdate,
innerTable.status,
innerTable.totalpassengers,
innerTable.url
You select records from tourbooking. One of the columns you select is id. This is probably the table's primary key and thus unique. (If not, you should hurry to change that name.)
You call this ID BookingID, and it is one of the columns you group by. So you get one result record per record in tourbooking. The number of records within such a "group" is of course 1; it is the one record you select and show.
If you built real groups, say a result record per day, then you'd get a real count, e.g. the number of bookings per day.