I want a count but it repeats 1 with every record. Can you please suggest what to do?
SELECT Count(*),
innerTable.*
FROM (SELECT (SELECT NAME
FROM tours
WHERE tours.id = tourbooking.tourid) AS NAME,
(SELECT url
FROM tours
WHERE tours.id = tourbooking.tourid) AS Url,
(SELECT TOP 1 NAME
FROM tourimages
WHERE tourimages.tourid = tourbooking.tourid
ORDER BY id ASC) AS ImageName,
(SELECT duration + ' ' + CASE WHEN durationtype = 'd' THEN
'Day(s)' WHEN
durationtype =
'h' THEN 'Hour(s)' END
FROM tours
WHERE tours.id = tourbooking.tourid) AS Duration,
(SELECT Replace(Replace('<a> Adult(s) - <c> Children', '<a>', Sum
(CASE
WHEN [type] = 1 THEN 1
ELSE 0
END)),
'<c>',
Sum(CASE
WHEN [type] = 2 THEN 1
ELSE 0
END))
FROM tourperson
WHERE tourperson.bookingid = tourbooking.id) AS TotalPassengers
,
startdate,
createddate AS BookingDate,
id AS BookingID,
[status],
serviceprice
FROM tourbooking
WHERE memberid = 6)AS innerTable
GROUP BY innerTable.NAME,
innerTable.bookingdate,
innerTable.bookingid,
innerTable.duration,
innerTable.imagename,
innerTable.serviceprice,
innerTable.startdate,
innerTable.status,
innerTable.totalpassengers,
innerTable.url
You select records from tourbooking. One of the columns you select is id. This is probably the table's primary key and thus unique. (If not, you should hurry to change that name.)
You call this ID BookingID, and it is one of the columns you group by. So you get one result record per record in tourbooking. The number of records within such a "group" is of course 1; it is the one record you select and show.
If you built real groups, say a result record per day, then you'd get a real count, e.g. the number of bookings per day.
Related
I'm not even sure what to call this type of query and that's why the title might be misleading. Here's what I want to do. We have a history table that goes like this
id, mod_date, is_active
1, 2022-06-22:12:00:00, 1
1, 2022-06-22:13:00:00, 0
2, 2022-06-22:12:00:00, 0
3, 2022-07-07:00:00:00, 1
is_active means that the record was made active. For example, row 1 was made active at 2022-06-22:12:00:00 and then was made inactive at 13:00:00.
What I want is to get only the row that was made inactive on a specific day and not made active again on that day. I came up with this query
select distinct(id)
from history
where is_active = 0
and cast(ah.mod_date as date) = '2022-06-22'
It would return 1 and 2. But I only want 2 because 1 was toggled between states. So, I only want to find all of ids that was made inactive on a specific day and never made active again on that day or any of the toggling the same day.
You may phrase this using exists logic:
SELECT *
FROM history h1
WHERE is_active = 0 AND mod_date::date = '2022-06-22' AND
NOT EXISTS (SELECT 1
FROM history h2
WHERE h2.mod_date::date = '2022-06-22' AND
h2.id = h1.id AND h2.is_active = 1);
Count how many times an id has been activated and deactivated in a day. From the result select the ones that have been deactivated once and activated zero times.
with the_historical_table(id, mod_date, is_active) as
(
values
(1, '2022-06-22:12:00:00', 1),
(1, '2022-06-22:13:00:00', 0),
(2, '2022-06-22:12:00:00', 0),
(3, '2022-07-07:00:00:00', 1)
)
select id, mod_date from
(
select id, mod_date::date,
count(*) filter (where is_active = 1) activated,
count(*) filter (where is_active = 0) deactivated
from the_historical_table
group by id, mod_date::date
) t
where activated = 0 and deactivated = 1;
Result:
id
mod_date
2
2022-06-22
What I want is to get only the row that was made inactive on a
specific day and not made active again on that day
partition.: partition by id, mod_date::date order by id, mod_date
ordered set 1 0 1 row 0 the middle row, both lead and lag is 1. You don't want this situation in the partition.
Consider 3 case.
After partition only have one row, is_action = 0 that mean both lead and lag is NULL.
Partition have multi rows.
Partition have multi rows, ordered set multiple 1 followed by multiple 0
demo
The follow code is like compute base on these 3 logic and then union all.
WITH cte AS (
SELECT
*,
lag(is_active, 1) OVER w,
lead(is_active, 1) OVER w,
first_value(is_active) OVER (PARTITION BY id,
mod_date::date ORDER BY id,
mod_date DESC)
FROM test1
WINDOW w AS (PARTITION BY id,
mod_date::date ORDER BY id,
mod_date)) (
SELECT
id,
mod_date,
is_active
FROM
cte
WHERE (lead = 0
OR lead IS NULL)
AND (lag = 1)
AND is_active = 0
ORDER BY
id,
mod_date)
UNION ALL (
SELECT
id,
mod_date,
is_active
FROM
cte
WHERE
lead IS NULL
AND lag IS NULL
AND is_active = 0)
UNION ALL (
SELECT
id,
mod_date,
is_active
FROM
cte
WHERE
lead = 0
AND lag IS NULL
AND is_active = 0
AND first_value != 1)
ORDER BY
id,
mod_date;
Counting number of times a particular level (in transaction data) and then aggregating it the number of times in new variable (under one row per customer)
I have 2 levels to solicitation method, phone and email. I have created 2 new columns which count the number of times phone or email happened per id. Right now I have transaction data and cant figure out how to go about it. the data is on left, what I want is on right. I am okay with both kinds of output on right side.
So far I tried this. returns error
create table d.email as
select ID, email_count
from d.emai
where email_count = (select count (*)
from d.email
group by ID
having SolicitMethod = 'Email' );
quit;
I am not sure what you really want to do, but you can fix the syntax error by making the subquery a correlated subquery:
create table d.email as
select ID, email_count
from d.emai e
where email_count = (select count(*)
from d.email e2
where e2.SolicitMethod = 'Email' and e2.id = e.id
);
I assume the reference in the first from should be d.emai.
The first output can be obtain with this query:
It groups rows by id, and then count how many rows are on each SolicitMethod
SELECT id
, SUM(CASE
WHEN SolicitMethod = 'Email' THEN 1
ELSE 0
END) count_email
, SUM(CASE
WHEN SolicitMethod = 'phone' THEN 1
ELSE 0
END) count_phone
FROM d.email
GROUP BY id
This second output query depends of your dbms and availability of analytics function:
it count on each rows the count of sollicitMethod of each group of id
SELECT id
, SUM(CASE
WHEN SolicitMethod = 'Email' THEN 1
ELSE 0
END)
OVER (partition BY id) count_email
, SUM(CASE
WHEN SolicitMethod = 'phone' THEN 1
ELSE 0
END)
OVER (partition BY id) count_phone
FROM d.email
I have a table called tbl_A with the following schema:
After insert, I have the following data in tbl_A:
Now the question is how to write a query for the following scenario:
Put (1) in front of any employee who was present three days consecutively
Put (0) in front of employee who was not present three days consecutively
The output screen shoot:
I think we should use case statement, but I am not able to check three consecutive days from date. I hope I am helped in this
Thank you
select name, case when max(cons_days) >= 3 then 1 else 0 end as presence
from (
select name, count(*) as cons_days
from tbl_A, (values (0),(1),(2)) as a(dd)
group by name, adate + dd
)x
group by name
With a self-join on name and available = 'Y', we create an inner table with different combinations of dates for a given name and take a count of those entries in which the dates of the two instances of the table are less than 2 units apart i.e. for each value of a date adate, it will check for entries with its own value adate as well as adate + 1 and adate + 2. If all 3 entries are present, the count will be 3 and you will have a flag with value 1 for such names(this is done in the outer query). Try the below query:
SELECT Z.NAME,
CASE WHEN Z.CONSEQ_AVAIL >= 3 THEN 1 ELSE 0 END AS YOUR_FLAG
FROM
(
SELECT A.NAME,
SUM(CASE WHEN B.ADATE >= A.ADATE AND B.ADATE <= A.ADATE + 2 THEN 1 ELSE 0 END) AS CONSEQ_AVAIL
FROM
TABL_A A INNER JOIN TABL_A B
ON A.NAME = B.NAME AND A.AVAILABLE = 'Y' AND B.AVAILABLE = 'Y'
GROUP BY A.NAME
) Z;
Due to the complexity of the problem, I have not been able to test it out. If something is really wrong, please let me know and I will be happy to take down my answer.
--Below is My Approch
select Name,
Case WHen Max_Count>=3 Then 1 else 0 end as Presence
from
(
Select Name,MAx(Coun) as Max_Count
from
(
select Name, (count(*) over (partition by Name,Ref_Date)) as Coun from
(
select Name,adate + row_number() over (partition by Name order by Adate desc) as Ref_Date
from temp
where available='Y'
)
) group by Name
);
select name as employee , case when sum(diff) > =3 then 1 else 0 end as presence
from
(select id, name, Available,Adate, lead(Adate,1) over(order by name) as lead,
case when datediff(day, Adate,lead(Adate,1) over(order by name)) = 1 then 1 else 0 end as diff
from table_A
where Available = 'Y') A
group by name;
I have a table with 3 columns, id, name and vote. They're populated with many registers. I need that return the register with the best balance of votes. The votes types are 'yes' and 'no'.
Yes -> Plus 1
No -> Minus 1
This column vote is a string column. I am using SQL SERVER.
Example:
It must return Ann for me
Use conditional Aggregation to tally the votes as Kannan suggests in his answer
If you really only want 1 record then you can do it like so:
SELECT TOP 1
name
,SUM(CASE WHEN vote = 'yes' THEN 1 ELSE -1 END) AS VoteTotal
FROM
#Table
GROUP BY
name
ORDER BY
VoteTotal DESC
This will not allow for ties but you can use this method which will rank the responses and give you results use RowNum to get only 1 result or RankNum to get ties.
;WITH cteVoteTotals AS (
SELECT
name
,SUM(CASE WHEN vote = 'yes' THEN 1 ELSE -1 END) AS VoteTotal
,ROW_NUMBER() OVER (PARTITION BY 1 ORDER BY SUM(CASE WHEN vote = 'yes' THEN 1 ELSE -1 END) DESC) as RowNum
,DENSE_RANK() OVER (PARTITION BY 1 ORDER BY SUM(CASE WHEN vote = 'yes' THEN 1 ELSE -1 END) DESC) as RankNum
FROM
#Table
GROUP BY
name
)
SELECT name, VoteTotal
FROM
cteVoteTotals
WHERE
RowNum = 1
--RankNum = 1 --if you want with ties use this line instead
Here is the test data used and in the future do NOT just put an image of your test data spend the 2 minutes to make a temp table or a table variable so that people you are asking for help do not have to!
DECLARE #Table AS TABLE (id INT, name VARCHAR(25), vote VARCHAR(4))
INSERT INTO #Table (id, name, vote)
VALUES (1, 'John','no'),(2, 'John','no'),(3, 'John','yes')
,(4, 'Ann','no'),(5, 'Ann','yes'),(6, 'Ann','yes')
,(9, 'Marie','no'),(8, 'Marie','no'),(7, 'Marie','yes')
,(10, 'Matt','no'),(11, 'Matt','yes'),(12, 'Matt','yes')
Use this code,
;with cte as (
select id, name, case when vote = 'yes' then 1 else -1 end as votenum from register
) select name, sum(votenum) from cte group by name
You can get max or minimum based out of this..
This one gives the 'yes' rate for each person:
SELECT Name, SUM(CASE WHEN Vote = 'Yes' THEN 1 ELSE 0 END)/COUNT(*) AS Rate
FROM My_Table
GROUP BY Name
So I'm trying to construct a query in BigQuery that I'm struggling with for a final part.
As of now I have:
SELECT
UNIQUE(Name) as SubscriptionName,
ID,
Interval,
COUNT(mantaSubscriptionIdmetadata) AS SubsPurchased,
SUM(RevenueGenerated) as RevenueGenerated
FROM (
SELECT
mantaSubscriptionIdmetadata,
planIdmetadata,
INTEGER(Amount) as RevenueGenerated
FROM
[sample_internal_data.charge0209]
WHERE
revenueSourcemetadata = 'new'
AND
Status = 'Paid'
GROUP BY
mantaSubscriptionIdmetadata,
planIdmetadata,
RevenueGenerated
)a
JOIN (
SELECT
id,
Name,
Interval
FROM
[sample_internal_data.subplans]
WHERE
id in ('150017','150030','150033','150019')
GROUP BY
id,
Name,
Interval )b
ON
a.planIdmetadata = b.id
GROUP BY
ID,
Interval,
Name
ORDER BY
Interval ASC
The resulting query looks like this
Which is exactly what I'm looking for up to that point.
Now what I'm stuck on this. There is another column I need to add called SalesRepName. The resulting field will either be null or not null. If its null it means it was sold online. If its not null, it means it was sold via telephone. What I want to do is create two additional columns where it says how many were sold via telesales and via online. The sum total of the two columns will always equal the SubsPurchased total.
Can anyone help?
You can include case statements within aggregate functions. Here you could choose sum(case when SalesRepName is null then 1 else 0 end) as online and sum(case when SalesRepName is not null then 1 else 0 end) as telesales.
count(case when SalesRepName is null then 1 end) as online would give the same result. Using sum in these situations is simply my personal preference.
Note that omitting the else clause is equivalent to setting else null, and null isn't counted by count. This can be very useful in combination with exact_count_distinct, which has no equivalent in terms of sum.
Try below:
it assumes your SalesRepName field is in [sample_internal_data.charge0209] table
and then it uses "tiny version" of SUM(CASE ... WHEN ...) which works when you need 0 or 1 as a result to be SUM'ed
SUM(SalesRepName IS NULL) AS onlinesales,
SUM(NOT SalesRepName IS NULL) AS telsales
SELECT
UNIQUE(Name) AS SubscriptionName,
ID,
Interval,
COUNT(mantaSubscriptionIdmetadata) AS SubsPurchased,
SUM(RevenueGenerated) AS RevenueGenerated,
SUM(SalesRepName IS NULL) AS onlinesales,
SUM(NOT SalesRepName IS NULL) AS telesales
FROM (
SELECT SalesRepName, mantaSubscriptionIdmetadata, planIdmetadata, INTEGER(Amount) AS RevenueGenerated
FROM [sample_internal_data.charge0209]
WHERE revenueSourcemetadata = 'new'
AND Status = 'Paid'
GROUP BY mantaSubscriptionIdmetadata, planIdmetadata, RevenueGenerated
)a
JOIN (
SELECT id, Name, Interval
FROM [sample_internal_data.subplans]
WHERE id IN ('150017','150030','150033','150019')
GROUP BY id, Name, Interval
)b
ON a.planIdmetadata = b.id
GROUP BY ID, Interval, Name
ORDER BY Interval ASC