I have a table that looks like this -
Table screenshot link - https://i.stack.imgur.com/Pztpq.png
I want to add a new column 'Manufacturer_Updated', such that -
If any particular 'Product' has more than 1 (distinct) 'Manufacturer', then the Manufacturer having highest 'Sales' should be populated in the 'Manufacturer_Updated' column for all rows of that particular 'Product'.
Ex - In the above screenshot, Product - 'TOTAL HAIR CARE NA' has 2 different Manufacturer, so in the 'Manufacturer_Updated' column, 'SEXY HAIR CONCEPTS' should appear for both the rows, as it has the higher sales.
Could someone pls help with this query? Thanks in Advance!
Something like this should work:
SELECT Manufacturer, Product, Sales, Manufacturer as Manufacturer_Updated FROM
WHERE amt_of_manufacturers > 1
((SELECT Product, max(Sales) as Sales, count(distinct Manufacturer) as amt_of_manufacturers
FROM your_table
GROUP BY Product) as q1
left join
(SELECT Manufacturer, Sales, Product
FROM your_table
) as q2
ON q1.Sales = q2.Sales
AND q1.Product = q2.Product
) as q3
In the first query (q1), you're retrieving maximum sales per each product along with amount of manufacturers for a specific product (used later in upper query). In the second one (q2) you just need to retrieve Manufacturer (to transform it later to Manufacturer_Updated), Sales and Product (as join keys). After this you only need to filter out all products with single manufacturer.
Alternatively, if you want to keep those, you can remove where amt_of_manufacturers > 1 and replace Manufacturer_Updated in the upper query with the following:
CASE WHEN
amt_of_manufacturers <=1 THEN null
ELSE Manufacturer
END AS Manufacturer_Updated
Related
So I have two tables of sales, budget and actual.
"budget" has two columns: location and sales. For example,
location sales
24 $20000
36 $100300
40 $24700
Total $145000
"actual" has three columns: invoice_number, location, and sales. For example,
invoice location sales
10000 36 $5000
10001 40 $6000
10002 99 $7000
and so forth
Total $110000
In summary, "actual" records transactions at the invoice level, whereas "budget" is done at the location level only (no individual invoices).
I'm trying to create a summary table that lists actual and budget sales side by side, grouped by location. The total of the actual column should be $110000, and $145000 for budget. This is my attempt at it (on pgAdmin/ postgresql):
SELECT actual.location, SUM(actual.sales) AS actual_sales, SUM(budget.sales) AS budget_sales
FROM actual LEFT JOIN budget
ON actual.location = budget.location
GROUP BY actual.location;
I used LEFT JOIN because "actual" has locations that "budget" doesn't have (e.g. location 99).
I ended up with some gigantic numbers ($millions) on both the actual_sales and budget_sales columns, far exceeding the total actual ($110000) or budget sales ($145,000).
Is this because the way I wrote my query is basically asking SQL to join each invoice in "actual" to each line in "budget," therefore duplicating things many times over? If so how should I have written this?
Thanks in advance!
Based on your description, you seem to have duplicates in both tables. There are various ways to solve this problem. Here is one using union all and group by:
select Location,
sum(actual_sales) as actual_sales,
sum(budget_sales) as budget_sales
from ((select a.location, a.sales as actual_sales, null as budget_sales
from actual a
) union all
(select b.location, null, b.sales
from budget b
)
) ab
group by location;
This structure guarantees that each value is counted only once, regardless of the table.
The query looks fine to me. However, it is difficult to find out why the figures are wrong. My suggestion is that you do the sum by location separately for budget and actual into 2 temporary tables, and later put them together using LEFT JOIN.
Yes, you're joining the budget in once for each actual sales row. However, your Actual Sales sum shouldn't have been larger unless there were multiple budget rows for the same location. You should check for that, because it doesn't sound like there should be.
What you need to do in a case like this is sum the actual sales first in a CTE or subquery, then later join the result to the budget. That way you only have one row for each location. This does it for the actual sales. If you really do have more than one row for a location for budget as well, you might need to subquery the budget as well the same way.
Select Act.Location, Act.actual_sales, budget.sales as budget_sales
From
(
SELECT actual.location, SUM(actual.sales) AS actual_sales
FROM actual
GROUP BY actual.location
) Act
left join budget on Act.location = budget.location
Gordon's suggestion is good, an alternative using WITH statements is:
WITH aloc AS (
SELECT location, SUM(sales) FROM actual GROUP BY 1
), bloc AS (
SELECT location, SUM(sales) FROM budget GROUP BY 1
)
SELECT location, a.sum AS actual_sales, b.sum AS budget_sales
FROM aloc a LEFT JOIN bloc b USING (location)
This is equivalent to:
SELECT location, a.sum AS actual_sales, b.sum AS budget_sales
FROM (SELECT location, SUM(sales) FROM actual GROUP BY 1) a LEFT JOIN
(SELECT location, SUM(sales) FROM budget GROUP BY 1) b USING (location)
but I find WITH statements more readable.
The purpose of the subqueries is to get tables into a state where a row means something relevant, i.e. aloc contains a row per location, and hence cause the join to evaluate to what you want.
If anyone can help me figure out where I am going wrong with this SQL that would be great. Please see my attempt to answer it below. I have answer how I think it should be answered but I am very confused by the exam advice below, which says I should use a SUM function? I have googled this and I do not see how a SUM function can help here when I need get the product of two values in this case. Or am I missing something major?
Question: TotalValue is a column in Order relation that contains derived data representing total value (amount) of each order. Write a SQL SELECT statement that computes a value for this column.
My answer:
SELECT Product.ProductPrice * OrderLine.QuantityOrdered AS Total_Value
FROM Product,
OrderLine
GROUP BY Product;
Advice from exam paper:
This is a straightforward question. Tip: you need to use the SUM function. Also, note that you can take the sum of various records set using the GROUP BY clause.
Ok your question became a lot clearer once I clicked on the the hyperlink (blue text).
Each order is going to be made up of a quantity of 1 or more products.
So there could be 3 Product A and 5 Product B etc.
So you have to get the total for each product which is your Price * Quantity, but then you need to add them all together which is where the SUM comes in.
Example:
3 * ProductA Price (e.g. €5) = 15
5 * ProductB Price (e.g. €4) = 20
Total Value = 35
So you need to use the Product, Order and OrderLine tables.
Something like (I haven't tested it):
SELECT SUM(Product.ProductPrice * OrderLine.QuantityOrdered) FROM Product, Order, OrderLine
WHERE Order.OrderID = OrderLine.OrderID
AND Product.ProductID = OrerLine.ProductID
GROUP BY Order.OrderID
This should return rows containing the totalValue for each order - the GROUP BY clause causes the SUM to SUM over each group - not the entire rows.
For a single order you would need add (before the GROUP BY) "AND Order.OrderID = XXXXX" where XXXXX is the actual orders OrderId.
A newbie here. So please be kind :-)
I have 2 Tables namely Item & Item Entries.
Relation is: Item.No = ItemEntries.No.
In Item Entries Table I have Columns as Qty, Entry type, Purchase Amount, Sales Amount
I like to have a report which shows as below,
Item No. | Opening Quantity | Purchase Amount | Sales Amount
To calculate Opening Inventory I summed up the quantity field and the result is as expected. No problem in that. Now From that dataset I like to run a sub query which Calculates/Sum the Purchase amount for an Item that is a part of first dataset and similarly for Sales Amount.
Select(Item No.,Sum(IE.Quantity) As Quantity, Select(......Purchase Amount),Select(....Sales Amount)
I hope I was able to clear my doubts to you guys.
Something like :
SELECT ItemNo, sum(quantity), purchaseAmount, SalesAmount FROM Item i INNER JOIN ItemEntities ie on i.no = ie.no GROUP BY ItemNo, PurchaseAmount, SalesAmount;
I believe (if I understand what you want) that this is the solution to your problem
Select Item.No ,
Sum(IE.Quantity) As Quantity,
(Select(......Purchase Amount)) As ColumnName1 ,
(Select(....Sales Amount)) As ColumnName2
From your need to "sum the purchase amount for an item that is part of the first dataset and similarly for Sales Amount" I think what you're trying to achieve is one row for each item on the Item table with a sum for each of the Qty, Sales Amount and Purchase Amount. If so, then you can simply use a 'group by' clause which groups results together which have matching values for the columns specified.
SELECT I.no, SUM(IE.qty), SUM(IE.purchase_amount), SUM(IE.sales_amount)
FROM item I JOIN item_entries IE
ON I.no = IE.no
GROUP BY I.no;
See the group_by_clause for more details and some examples.
N.B. The join from the item tables isn't strictly required in this example, but if you're producing a report I suspect you might want to get things like a description - in which case you'll need to add those columns to the group by clause too.
You might need the sum of three columns from
ItemEntries table(Qty,PurchaseAmount,SalesAmount) for each Item.No
Select A.No,
Sum(B.Qty),
Sum(B.Purchaseamount),
Sum(B.Salesamount)
From Item A,
Itementries B
Where A.No = B.No
Group By A.No;
Alright so say I have a 'product_catalog', and 'orders' tables. Each order has the product_catalog_id as a foreign key. What I want to return as the query results is the product_code (name of the product associated with a specific product_catalog_id) + a count of how many of each product_code have been ordered. That's easy enough with something like this (Oracle SQL):
SELECT pc.product_code,
COUNT(*) as count
FROM orders o
join product_catalog pc on pc.product_catalog_id = o.product_catalog_id
GROUP BY pc.product_code
ORDER BY count DESC;
but I also want to print various pieces of information from the order table such as total of all monthly charges for that product_code. That would seem easy enough with something like this:
(o.monthly_base_charge*count(*)) as "Monthly Fee"
but the problem is that there have been various monthly fees for the same product_code over time. If I add the above line in and add 'o.monthly_base_charge' to the group by statement, then it will print out a unique row for every variation of pricing for that product_code. How do I get it to ignore those price variations and just add together every entry with that product code?
It is a little unclear what you are asking. My best guess is that you want the sum of the monthly base charge:
SELECT pc.product_code,
COUNT(*) as count,
sum(o.monthly_base_charge) as "Monthly Fee"
FROM orders o join
product_catalog pc
on pc.product_catalog_id = o.product_catalog_id
GROUP BY pc.product_code
ORDER BY count DESC;
I'm not sure if this is exactly what you want. What happens if you have two orders in the same month for the same product?
You may need to do something like this since SQL will not be able to know which monthly base charge to multiply by the count.
SELECT pc.product_code,
COUNT(*) as count,
(min(o.monthly_base_charge)*count(*)) as "Monthly Fee"
FROM orders o
join product_catalog pc on pc.product_catalog_id = o.product_catalog_id
GROUP BY pc.product_code
ORDER BY count DESC;
Or you will need to add o.monthly_base_charge to the group by in order for sql to know how to determine the count()
GROUP BY pc.product_code, o.monthly_base_charge
I've got two tables that I'm trying to grab data from. The first is a 'titles' table, which represents product information (name, unique ID, etc). The second is a 'prices' table which collects price information for various currencies (each product can have multiple historic entries in the prices table).
I've written a fairly long-winded SQL statement to grab the latest price changes across products, but there are some issues that hopefully more experienced users will be able to help me out with:
SELECT
t.id,
t.name,
t.type,
p.value,
(SELECT
value
FROM
prices
WHERE
prices.id = p.id AND
prices.country='US' AND
prices.timestamp < p.timestamp
ORDER BY
prices.timestamp DESC
LIMIT 1) AS last_value
FROM
prices AS p
INNER JOIN
titles AS t
ON
t.row_id = p.id
WHERE
p.country = 'US' AND
(SELECT
value
FROM
prices
WHERE
prices.id = p.id AND
prices.country='US' AND
prices.timestamp < p.timestamp
ORDER BY
prices.timestamp DESC
LIMIT 1) IS NOT NULL
GROUP BY
t.id
ORDER BY
p.timestamp DESC,
last_value DESC
LIMIT 0, 25"
The first issue I've run into is that, while this query works, titles appear multiple times in the same listing. While this is expected, I'd ideally like only the latest price change to be displayed for the title. To solve this, I tried GROUPING by the titles 'id' (note the: GROUP BY t.id above). Unfortunately, while I'd expect the GROUP to respect the ORDER BY (which orders the latest price changes in DESC order), the results seem to remove the latest changes and show the GROUP'd titles with earlier price values.
Secondly, is there any better way to grab the last price of each item (currently I grab the current value, and then run a subquery to grab the 'last_value' - which effectively represents the value before the current price change). At the moment I run two subqueries: one to grab the second to last known price, and again to ensure that a previous price exists in the database (otherwise there's no point in listing the title as having a price change).
Any help would be appreciated!
How about this:
SELECT titles.id, titles.name, titles.type, prices.value, MAX(prices.timestamp)
FROM titles, prices
WHERE prices.row_id = titles.id AND prices.country='US';
Mind you, I don't have MySQL installed so I couldn't try this query.
[Edit:] I think it won't work 'cause it'll always display the last price entered for all the items because it'll always choose the highest timestamp from the prices table, maybe a group by will do, I'm really sleepy now and I can't think straight;
[Edit2:] How about this:
(SELECT max(report_run_date) as maxdate, report_name
FROM report_history
GROUP BY report_name) maxresults
SELECT titles.id, titles.name, titles.type, prices.value,
(SELECT MAX(prices.timestamp) as maxtimestamp FROM prices GROUP BY prices.row_id)
FROM titles, prices
WHERE prices.row_id = titles.id AND prices.country='US';