I'm using this for adding commas into number.
val commaNumber = NumberFormat.getNumberInstance(Locale.US).format(floatValue)
floatValue is 8.1E-7 , but commaNumber shows just 0.
How to covert Float to String with comma without Rounding?
For the US locale, the maximumFractionalDigits of the number format is 3, therefore, it will try to format 8.1e-7 with only 3 fractional digits, which makes it 0.000. Since the minimumFractionalDigits is also 0, it tries to remove all the unnecessary 0s, making the final result "0".
You should set maximumFractionalDigits to at least 7 if you want to precisely display the number 8.1e-7.
val numberFormat = NumberFormat.getNumberInstance(Locale.US)
numberFormat.maximumFractionDigits = 7
val commaNumber = numberFormat.format(floatValue)
As for the commas, that is already part of the US locale. It uses grouping, and , is its grouping separator. The commas will be inserted if they are needed.
Related
I have a Population Estimate series with numbers as float64 and I need to convert them to a string with thousands separator (using commas). Using all significant digits (no rounding).
e.g. 12345678.90345 -> 12,345,678.90345
Try applying a comma-float string formatter.
population = population.apply('{:,.5f}'.format)
To achieve the desired formatting, you could use '{:,}'.format.
This will use commas as thousands separator and only output the values that are in your data and not clip or fill to a certain number of digits.
data = data.apply('{:,}'.format)
Not understanding this:
Number returned from DataReader: 185549633.66000035
We have a requirement to maintain the number of decimal places per a User Choice.
For example: maintain 7 places.
We are using:
FormatNumber(dr.Item("Field"), 7, TriState.false, , TriState.True)
The result is: 185,549,633.6600000.
We would like to maintain the 3 (or 35) at the end.
When subtracting two numbers from the resulting query we are getting a delta but trying to show these two numbers out to 6,7,8 digits is not working thus indicating a false delta to the user.
Any advice would be appreciated.
Based on my testing, you must be working with Double values rather than Decimal. Not surprisingly, the solution to your problem can be found in the documentation.
For a start, you should not be using FormatNumber. We're not in VB6 anymore ToTo. To format a number in VB.NET, call ToString on that number. I tested this:
Dim dbl = 185549633.66000035R
Dim dec = 185549633.66000035D
Dim dblString = dbl.ToString("n7")
Dim decString = dec.ToString("n7")
Console.WriteLine(dblString)
Console.WriteLine(decString)
and I saw the behaviour you describe, i.e. the output was:
185,549,633.6600000
185,549,633.6600004
I read the documentation for the Double.ToString method (note that FormatNumber would be calling ToString internally) and this is what it says:
By default, the return value only contains 15 digits of precision although a maximum of 17 digits is maintained internally. If the value of this instance has greater than 15 digits, ToString returns PositiveInfinitySymbol or NegativeInfinitySymbol instead of the expected number. If you require more precision, specify format with the "G17" format specification, which always returns 17 digits of precision, or "R", which returns 15 digits if the number can be represented with that precision or 17 digits if the number can only be represented with maximum precision.
I then tested this:
Dim dbl = 185549633.66000035R
Dim dblString16 = dbl.ToString("G16")
Dim dblString17 = dbl.ToString("G17")
Console.WriteLine(dblString16)
Console.WriteLine(dblString17)
and the result was:
185549633.6600004
185549633.66000035
I am calling
FORMAT(myNum, '#,###') AS myNum
Which works for 123456789 as the output is 123,456,789
Also works for negative numbers
However, 0 is showing up as a blank field.
How do I get 0 to show up as 0? I am also curious as to why 0 is being removed as the query without the format shows 0 in that column's field when there should be a 0.
Note: I do not need any decimals and would prefer to use the above code if at all possible.
If you want to display the 0, if it is zero, you should use:
FORMAT(myNum, '#,###0') AS myNum
According to this Reference:
https://msdn.microsoft.com/en-us/library/ee634206.aspx
0 (zero character)
Digit placeholder. Displays a digit or a zero. If the expression has a digit in the position where the zero appears in the format string, displays the digit; otherwise, displays a zero in that position.
If the number has fewer digits than there are zeros (on either side of the decimal) in the format expression, displays leading or trailing zeros. If the number has more digits to the right of the decimal separator than there are zeros to the right of the decimal separator in the format expression, rounds the number to as many decimal places as there are zeros. If the number has more digits to the left of the decimal separator than there are zeros to the left of the decimal separator in the format expression, displays the extra digits without modification.
# Digit placeholder:
Displays a digit or nothing. If the expression has a digit in the position where the # character appears in the format string, displays the digit; otherwise, displays nothing in that position.
This symbol works like the 0 digit placeholder, except that leading and trailing zeros aren't displayed if the number has fewer digits than there are # characters on either side of the decimal separator in the format expression.
If negative number is from -31 to -1 then I would like represent it into the format 111XXXXX.
I try to do it using "and" bitwise operator:
println("0b00011111 & 0xe0 is ${0b00011111 and 0xe0}")
println("31 & 0xe0 is ${31 and 0xe0}")
println("0b00011111 & 0b11100000 is ${0b00011111 and 0b11100000}")
But the result is always 0. Where did I make the mistake?
It prints 0 because 00011111 and 11100000 always returns 0. The return type of and is Int, so if you want to print it in base 2 with leading zeroes, you have to format it.
To convert it to a String in base 2, you can call the toString method on Int with a radix parameter:
val numberString = (0b00011111 and 0b11100000).toString(2);
This will give you the number in binary format, but without leading zeroes. You need to left-pad with zeroes to get the format you want. I leave that task up to you (hint: padStart) ;)
I would like to format an integer 9 to "09" and 25 to "25".
How can this be done?
You can use either of these options:
The "0" Custom Specifier
value.ToString("00")
String.Format("{0:00}", value)
The Decimal ("D") Standard Format Specifier
value.ToString("D2")
String.Format("{0:D2}", value)
For more information:
Custom Numeric Format Strings
Standard Numeric Format Strings
If its just leading zero's that you want, you can use this:
value.tostring.padleft("0",2)
value.ToString().PadLeft(2, '0'); // C#
If you have 2 digits, say 25 for example, you will get "25" back....if you have just one digit, say 9 for example, you will get "09"....It is worth noting that this gives you a string back, and not an integer, so you may need to cast this later on in your code.
String formate is the best way to do that. It's will only add leading zero for a single length. 9 to "09" and 25 to "25".
String.format("%02d", value)
Bonus:
If you want to add multiple leading zero 9 to "0009" and 1000 to "1000". That's means you want a string for 4 indexes so the condition will be %04d.
String.format("%04d", value)
I don't know the exact syntax. But in any language, it would look like this.
a = 9
aString =""
if a < 10 then
aString="0" + a
else
aString = "" + a
end if