I am calling
FORMAT(myNum, '#,###') AS myNum
Which works for 123456789 as the output is 123,456,789
Also works for negative numbers
However, 0 is showing up as a blank field.
How do I get 0 to show up as 0? I am also curious as to why 0 is being removed as the query without the format shows 0 in that column's field when there should be a 0.
Note: I do not need any decimals and would prefer to use the above code if at all possible.
If you want to display the 0, if it is zero, you should use:
FORMAT(myNum, '#,###0') AS myNum
According to this Reference:
https://msdn.microsoft.com/en-us/library/ee634206.aspx
0 (zero character)
Digit placeholder. Displays a digit or a zero. If the expression has a digit in the position where the zero appears in the format string, displays the digit; otherwise, displays a zero in that position.
If the number has fewer digits than there are zeros (on either side of the decimal) in the format expression, displays leading or trailing zeros. If the number has more digits to the right of the decimal separator than there are zeros to the right of the decimal separator in the format expression, rounds the number to as many decimal places as there are zeros. If the number has more digits to the left of the decimal separator than there are zeros to the left of the decimal separator in the format expression, displays the extra digits without modification.
# Digit placeholder:
Displays a digit or nothing. If the expression has a digit in the position where the # character appears in the format string, displays the digit; otherwise, displays nothing in that position.
This symbol works like the 0 digit placeholder, except that leading and trailing zeros aren't displayed if the number has fewer digits than there are # characters on either side of the decimal separator in the format expression.
Related
I'm using this for adding commas into number.
val commaNumber = NumberFormat.getNumberInstance(Locale.US).format(floatValue)
floatValue is 8.1E-7 , but commaNumber shows just 0.
How to covert Float to String with comma without Rounding?
For the US locale, the maximumFractionalDigits of the number format is 3, therefore, it will try to format 8.1e-7 with only 3 fractional digits, which makes it 0.000. Since the minimumFractionalDigits is also 0, it tries to remove all the unnecessary 0s, making the final result "0".
You should set maximumFractionalDigits to at least 7 if you want to precisely display the number 8.1e-7.
val numberFormat = NumberFormat.getNumberInstance(Locale.US)
numberFormat.maximumFractionDigits = 7
val commaNumber = numberFormat.format(floatValue)
As for the commas, that is already part of the US locale. It uses grouping, and , is its grouping separator. The commas will be inserted if they are needed.
I was checking if DB pads spaces in a column if the inserted string has fewer characters than the designated length of the column. Example:
lets say size of <column1> is 10 but the value entered is abc - then is it abc_______ which the DB stores where _ represents spaces?
I am asking because I used LTRIM-RTRIM while INSERTing the values and on again fetching the value in the very next minute I got the result as abc_______.
You are using the CHAR or CHARACTER datatype for the column. The CHAR or CHARACTER datatype is a fixed length datatype and is padded with space at the end of the value to fill the column size.
You can use VARCHAR to avoid the padding with spaces at the end of the values.
Note: Make sure you are using CHARACTER_LENGTH on CHARACTER columns to get the correct character length (without padding spaces). The result of LENGTH also includes the padding spaces.
demo on dbfiddle.uk
Need to write a sql function that takes two different integers with the same length (same amount of digits) as arguments: one lower threshold and one upper threshold.
And the function should return a vector with all whole numbers between the two thresholds - but to reduce the array length, your function is supposed to return a wildcard character instead of the digits where possible.
Example: output of the function for a lower threshold L = 3778 and an upper threshold U = 9423
To further clarify, the line in the example showing 941* has one digit replaced by the wild card character and hence represents all values from 9410 - 9419
The line in the example showing 93* has two digits replaced by the wildcard character and represents all values from 9300 - 9399
And so on.
9423
9422
9421
9420
941*
93*
.
378*
3779
3778
When I save data byte[] in SQL Server the value change and add 0x0 in the first of value
the correct value (0xFFD8FFE000104A46)
the incorrect value (0x0FFD8FFE000104A46494600010102004C)
0xF and 0x0F are the same number, both are hexadecimal notations of number 15 decimal. A byte contains two hexadecimal 'digits'. If the left most digit is 0, it doesn't affect the value, just like zero-hundred and fifteen is the same as fifteen. The notation with the leading 0 just prints all the bytes, the one without strips the leading zeros.
Where the 494600010102004C part is coming from I don't know.
I am writing a custom totaling method for a grid view. I am totaling fairly large numbers so I'd like to use a decimal to get the total. The problem is I need to control the maximum length of the total number. To solve this problem I started using float but it doesn't seem to support large enough numbers, I get this in the totals column(1.551538E+07). So is there some formating string I can use in .ToString() to guarentee that I never get more then X characters in the total field? Keep in mind I'm totaling integers and decimals.
If you're fine with all numbers displaying in scientific notation, you could go with "E[numberOfDecimalPlaces]" as your format string.
For example, if you want to cap your strings at, say, 12 characters, then, accounting for the one character for the decimal point and five characters needed to display the exponential part, you could do:
Function FormatDecimal(ByVal value As Decimal) As String
If value >= 0D Then
Return value.ToString("E5")
Else
' negative sign eats up another character '
Return value.ToString("E4")
End If
End Function
Here's a simple demo of this function:
Dim d(5) As Decimal
d(0) = 1.203D
d(1) = 0D
d(2) = 1231234789.432412341239873D
d(3) = 33.3218403820498320498320498234D
d(4) = -0.314453908342094D
d(5) = 000032131231285432940D
For Each value As Decimal in d
Console.WriteLine(FormatDecimal(value))
Next
Output:
1.20300E+000
0.00000E+000
1.23123E+009
3.33218E+001
-3.1445E-001
3.21312E+016
You could use Decimal.Round, but I don't understand the exact question, it sounds like you're saying that if the total adds up to 12345.67, you might only want to show 4 digits and would then show 2345 or do you just mean that you want to remove the decimals?