Want to ignore the row no 2 and 3 which is not have any space based on 2nd table data .
Table 1 like below
No Name
1 kumar unknow raja
2 kumarunknowraja sameple
3 kumartradraja testing
4 kumar trad raja
5 trad
6 unknow
Table 2
Name
unknow
trad
Using this query but l am getting all the records select * from base_tbl where exists (select name from exc_tbl);
Here is an ms sql solution. It is an ugly piece of sql though....
with data(No,Name ) as(
select 1, 'kumar unknow raja' union all
select 2, 'kumarunknowraja sameple' union all
select 3, 'kumartradraja testing' union all
select 4, 'kumar trad raja' union all
select 5, 'trad' union all
select 6, 'unknow'
),
param (name) as (
select 'unknow' union all
select 'trad'
),
data2 (No,Name ) as(
select No,data.Name from data
join param on data.name = param.name
union
select No,data.Name from data
join param on data.name like ('% ' + param.name + '%')
union
select No,data.Name from data
join param on data.name like ('%' + param.name + ' %')
)
select * from data2
order by No
But it gives you what you want:
Related
I try to select from table_1 where ITEM_FIELD_A is not in ITEM_FIELD_B. The Item_FIELD_B value are look as below. I was expecting no COVER_TAPE & SHIPPING_REELS will be selected. But unfortunately, it's not working.
The sql I used to select the table
select * from table_1 where MST.ITEM_FIELD_A not in ITEM_FIELD_B
Question:
In Oracle, is there any function to decode the string. so that the above select statement will not return COVER_TAPE and SHIPPING_REELS??
The IN operator would be used when you wish to compare (or negate) one item in a list such as
WHERE ITEM_FIELD_A NOT IN ('COVER_TAPE', 'SHIPPING_REELS', '')
What you want is the LIKE operator:
WHERE ITEM_FIELD_B NOT LIKE '%' || ITEM_FIELD_A || '%'
Apologies if I got the wildcard wrong, been a while since I last touched Oracle.
Check out below Query:
WITH TAB1 AS
( SELECT 'COVER_TAPE' ITEM_A FROM DUAL
UNION
SELECT 'CARRIER_TAPE' ITEM_A FROM DUAL
UNION
SELECT 'SHIPPING_REELS' ITEM_A FROM DUAL
),
TAB2 AS
(
SELECT 'COVER_TAPE,SHIPPING_REELS' ITEM_B FROM DUAL
)
SELECT ITEM_A, ITEM_B FROM TAB1, TAB2 WHERE INSTR(ITEM_B, ITEM_A) <=0
INSTR will return >0 if same sequence of characters is available.
SQL> with t(x , y) as
2 (
3 select 'A', q'[('A','B','C')]' from dual union all
4 select 'R', q'[('A','B','C','D')]' from dual union all
5 select 'C', q'[('A', 'C','D')]' from dual
6 )
7 select x, y
8 from t where y not like q'[%']'||x||q'['%]'
9 /
X Y
---------- --------------------------------------------------
R ('A','B','C','D')
I have a table and i want to colum joint_no column. The column's values are like these
FW-1
FW-2
.
.
.
FW-13
FW-R1
FW-1A
When i ordered them i get this results
FW-1
FW-10
FW-11
FW-12
FW-13
FW-1A
.
.
FW-R1
I want to get this result after sql query
FW-1
FW-1A
FW-2
FW-3
..
FW-13
FW-R1
can anybody help me?
If you can do it, I'd advise you to renumber the values so that the 'logical' order sticks to the alphabetical order. F-1 will then be updated to F-01, or F-001.
If you cannot do it, add a field that will be populated with the 'ordered' form of your code. You 'll then be able to order by the F-001 column and still display the F-1 value
Otherwise ordering your records will rapidly become your nightmare.
Using Patindex to find the first numeric expression as first sort field, then extracting the numeric part as integer as second sortfield and using the whole string as third sort field you might get the desired result.
Declare #a Table (c varchar(50))
Insert Into #a
Select 'FW-1'
Union Select 'FW-10'
Union Select 'FW-11'
Union Select 'FW-12'
Union Select 'FW-13'
Union Select 'FW-1A'
Union Select 'FW-2'
Union Select 'FW-3'
Union Select 'FW-R1'
Union Select 'FW-A1'
;With CTE as
(Select 1 as ID
Union All
Select ID + 1 from CTE where ID < 100
)
Select * from
(
Select c
,PATINDEX('%[0-9]%',c) as s1
,(Select Cast(
(Select Case
When SUBSTRING(c, ID, 1) LIKE '[0-9]'
Then SUBSTRING(c, ID, 1)
Else ''
End
From (Select * from CTE) AS X(ID)
Where ID <= LEN(c)
For XML PATH(''))
as int)
)
as s2
from
#a
) x
order by
s1,s2,c
With the output:
FW-1 4 1 -1
FW-1A 4 1 -1A
FW-2 4 2 -2
FW-3 4 3 -3
FW-10 4 10 -10
FW-11 4 11 -11
FW-12 4 12 -12
FW-13 4 13 -13
FW-A1 5 1 A1
FW-R1 5 1 R1
If the leading part is not fixed (FW-) you might need to add one additional sort field
Declare #a Table (c varchar(50))
Insert Into #a
Select 'FW-1'
Union Select 'FW-10'
Union Select 'FW-11'
Union Select 'FW-12'
Union Select 'FW-13'
Union Select 'FW-1A'
Union Select 'FW-2'
Union Select 'FW-3'
Union Select 'FW-R1'
Union Select 'FW-A1'
Union Select 'AB-A1'
Union Select 'AB-11'
;With CTE as
(Select 1 as ID
Union All
Select ID + 1 from CTE where ID < 100
)
Select * from
(
Select c
,SubString(c,1,PATINDEX('%[0-9]%',c)-1) as S0
,PATINDEX('%[0-9]%',c) as s1
,(Select Cast(
(Select Case
When SUBSTRING(c, ID, 1) LIKE '[0-9]'
Then SUBSTRING(c, ID, 1)
Else ''
End
From (Select * from CTE) AS X(ID)
Where ID <= LEN(c)
For XML PATH(''))
as int)
)
as s2
from
#a
) x
order by
s0,s1,s2,c
I would like to execute a query that will only show all the string before dash in the particular field.
For example:
Original data: AB-123
After query: AB
You can use substr:
SQL> WITH DATA AS (SELECT 'AB-123' txt FROM dual)
2 SELECT substr(txt, 1, instr(txt, '-') - 1)
3 FROM DATA;
SUBSTR(TXT,1,INSTR(TXT,'-')-1)
------------------------------
AB
or regexp_substr (10g+):
SQL> WITH DATA AS (SELECT 'AB-123' txt FROM dual)
2 SELECT regexp_substr(txt, '^[^-]*')
3 FROM DATA;
REGEXP_SUBSTR(TXT,'^[^-]*')
---------------------------
AB
You can use regexp_replace.
For example
WITH DATA AS (
SELECT 'AB-123' as text FROM dual
UNION ALL
SELECT 'ABC123' as text FROM dual
)
SELECT
regexp_replace(d.text, '-.*$', '') as result
FROM DATA d;
will lead to
WITH DATA AS (
2 SELECT 'AB-123' as text FROM dual
3 UNION ALL
4 SELECT 'ABC123' as text FROM dual
5 )
6 SELECT
7 regexp_replace(d.text, '-.*$', '') as result
8 FROM DATA d;
RESULT
------------------------------------------------------
AB
ABC123
I found this simple
SELECT distinct
regexp_replace(d.pyid, '-.*$', '') as result
FROM schema.table d;
pyID column contains ABC-123, DEF-3454
SQL Result:
ABC
DEF
I have data like this in a table
NAME PRICE
A 2
B 3
C 5
D 9
E 5
I want to display all the values in one row; for instance:
A,2|B,3|C,5|D,9|E,5|
How would I go about making a query that will give me a string like this in Oracle? I don't need it to be programmed into something; I just want a way to get that line to appear in the results so I can copy it over and paste it in a word document.
My Oracle version is 10.2.0.5.
-- Oracle 10g --
SELECT deptno, WM_CONCAT(ename) AS employees
FROM scott.emp
GROUP BY deptno;
Output:
10 CLARK,MILLER,KING
20 SMITH,FORD,ADAMS,SCOTT,JONES
30 ALLEN,JAMES,TURNER,BLAKE,MARTIN,WARD
I know this is a little late but try this:
SELECT LISTAGG(CONCAT(CONCAT(NAME,','),PRICE),'|') WITHIN GROUP (ORDER BY NAME) AS CONCATDATA
FROM your_table
Usually when I need something like that quickly and I want to stay on SQL without using PL/SQL, I use something similar to the hack below:
select sys_connect_by_path(col, ', ') as concat
from
(
select 'E' as col, 1 as seq from dual
union
select 'F', 2 from dual
union
select 'G', 3 from dual
)
where seq = 3
start with seq = 1
connect by prior seq+1 = seq
It's a hierarchical query which uses the "sys_connect_by_path" special function, which is designed to get the "path" from a parent to a child.
What we are doing is simulating that the record with seq=1 is the parent of the record with seq=2 and so fourth, and then getting the full path of the last child (in this case, record with seq = 3), which will effectively be a concatenation of all the "col" columns
Adapted to your case:
select sys_connect_by_path(to_clob(col), '|') as concat
from
(
select name || ',' || price as col, rownum as seq, max(rownum) over (partition by 1) as max_seq
from
(
/* Simulating your table */
select 'A' as name, 2 as price from dual
union
select 'B' as name, 3 as price from dual
union
select 'C' as name, 5 as price from dual
union
select 'D' as name, 9 as price from dual
union
select 'E' as name, 5 as price from dual
)
)
where seq = max_seq
start with seq = 1
connect by prior seq+1 = seq
Result is: |A,2|B,3|C,5|D,9|E,5
As you're in Oracle 10g you can't use the excellent listagg(). However, there are numerous other string aggregation techniques.
There's no particular need for all the complicated stuff. Assuming the following table
create table a ( NAME varchar2(1), PRICE number);
insert all
into a values ('A', 2)
into a values ('B', 3)
into a values ('C', 5)
into a values ('D', 9)
into a values ('E', 5)
select * from dual
The unsupported function wm_concat should be sufficient:
select replace(replace(wm_concat (name || '#' || price), ',', '|'), '#', ',')
from a;
REPLACE(REPLACE(WM_CONCAT(NAME||'#'||PRICE),',','|'),'#',',')
--------------------------------------------------------------------------------
A,2|B,3|C,5|D,9|E,5
But, you could also alter Tom Kyte's stragg, also in the above link, to do it without the replace functions.
Here is another approach, using model clause:
-- sample of data from your question
with t1(NAME1, PRICE) as(
select 'A', 2 from dual union all
select 'B', 3 from dual union all
select 'C', 5 from dual union all
select 'D', 9 from dual union all
select 'E', 5 from dual
) -- the query
select Res
from (select name1
, price
, rn
, res
from t1
model
dimension by (row_number() over(order by name1) rn)
measures (name1, price, cast(null as varchar2(101)) as res)
(res[rn] order by rn desc = name1[cv()] || ',' || price[cv()] || '|' || res[cv() + 1])
)
where rn = 1
Result:
RES
----------------------
A,2|B,3|C,5|D,9|E,5|
SQLFiddle Example
Something like the following, which is grossly inefficient and untested.
create function foo returning varchar2 as
(
declare bar varchar2(8000) --arbitrary number
CURSOR cur IS
SELECT name,price
from my_table
LOOP
FETCH cur INTO r;
EXIT WHEN cur%NOTFOUND;
bar:= r.name|| ',' ||r.price || '|'
END LOOP;
dbms_output.put_line(bar);
return bar
)
Managed to get till here using xmlagg: using oracle 11G from sql fiddle.
Data Table:
COL1 COL2 COL3
1 0 0
1 1 1
2 0 0
3 0 0
3 1 0
SELECT
RTRIM(REPLACE(REPLACE(
XMLAgg(XMLElement("x", col1,',', col2, col3)
ORDER BY col1), '<x>'), '</x>', '|')) AS COLS
FROM ab
;
Results:
COLS
1,00| 3,00| 2,00| 1,11| 3,10|
* SQLFIDDLE DEMO
Reference to read on XMLAGG
In my SQL Server 2005 database, using an SLQ query, does anyone know the best way to group records together by one field, and get a comma-separated list of the values from another?
So if I have:
UserID Code
1 A
1 C5
1 X
2 V3
3 B
3 D
3 NULL
3 F4
4 NULL
I'd get:
UserID Code
1 A,C5,X
2 V3
3 B,D,F4
4 NULL
Thanks for any help.
WITH Data AS (
SELECT 1 UserId, 'A' Code
UNION ALL
SELECT 1, 'C5'
UNION ALL
SELECT 1, 'X'
UNION ALL
SELECT 2, 'V3'
UNION ALL
SELECT 3, 'B'
UNION ALL
SELECT 3, 'D'
UNION ALL
SELECT 3, NULL
UNION ALL
SELECT 3, 'F4'
UNION ALL
SELECT 4, NULL
)
SELECT U.UserId, STUFF((
SELECT ','+Code FROM Data WHERE Data.UserID = U.UserID FOR XML PATH('')
), 1, 1, '') Code
FROM (SELECT DISTINCT UserID FROM Data) U
Just replace the Data CTE with your table name and you're done.
There it´s a complete review of forms to do that in TSQL
http://www.simple-talk.com/sql/t-sql-programming/concatenating-row-values-in-transact-sql/