In my SQL Server 2005 database, using an SLQ query, does anyone know the best way to group records together by one field, and get a comma-separated list of the values from another?
So if I have:
UserID Code
1 A
1 C5
1 X
2 V3
3 B
3 D
3 NULL
3 F4
4 NULL
I'd get:
UserID Code
1 A,C5,X
2 V3
3 B,D,F4
4 NULL
Thanks for any help.
WITH Data AS (
SELECT 1 UserId, 'A' Code
UNION ALL
SELECT 1, 'C5'
UNION ALL
SELECT 1, 'X'
UNION ALL
SELECT 2, 'V3'
UNION ALL
SELECT 3, 'B'
UNION ALL
SELECT 3, 'D'
UNION ALL
SELECT 3, NULL
UNION ALL
SELECT 3, 'F4'
UNION ALL
SELECT 4, NULL
)
SELECT U.UserId, STUFF((
SELECT ','+Code FROM Data WHERE Data.UserID = U.UserID FOR XML PATH('')
), 1, 1, '') Code
FROM (SELECT DISTINCT UserID FROM Data) U
Just replace the Data CTE with your table name and you're done.
There it´s a complete review of forms to do that in TSQL
http://www.simple-talk.com/sql/t-sql-programming/concatenating-row-values-in-transact-sql/
Related
Want to ignore the row no 2 and 3 which is not have any space based on 2nd table data .
Table 1 like below
No Name
1 kumar unknow raja
2 kumarunknowraja sameple
3 kumartradraja testing
4 kumar trad raja
5 trad
6 unknow
Table 2
Name
unknow
trad
Using this query but l am getting all the records select * from base_tbl where exists (select name from exc_tbl);
Here is an ms sql solution. It is an ugly piece of sql though....
with data(No,Name ) as(
select 1, 'kumar unknow raja' union all
select 2, 'kumarunknowraja sameple' union all
select 3, 'kumartradraja testing' union all
select 4, 'kumar trad raja' union all
select 5, 'trad' union all
select 6, 'unknow'
),
param (name) as (
select 'unknow' union all
select 'trad'
),
data2 (No,Name ) as(
select No,data.Name from data
join param on data.name = param.name
union
select No,data.Name from data
join param on data.name like ('% ' + param.name + '%')
union
select No,data.Name from data
join param on data.name like ('%' + param.name + ' %')
)
select * from data2
order by No
But it gives you what you want:
Basically the current conditions of the query are
WHERE data_payload_uri BETWEEN
'/organization/team/folder/2021'
AND
'/organization/team/folder/2022'
And this gets all data for the year of 2021.
A sample of the data_payload_uri data looks like this:
/organization/team/folder/20210101/orig
/organization/team/folder/20210102/orig
/organization/team/folder/20210102/orig_v1
/organization/team/folder/20210103/orig
/organization/team/folder/20210104/orig
/organization/team/folder/20210105/orig
/organization/team/folder/20210105/orig_v1
/organization/team/folder/20210105/orig_v2
What I would like to do is only query the rows where up until the last forward-slash, the row is NOT unique.
What this means, is I want to NOT query the rows which ONLY have one orig
/organization/team/folder/20210101/orig
/organization/team/folder/20210103/orig
/organization/team/folder/20210104/orig
but I DO want to query all the other rows
/organization/team/folder/20210105/orig
/organization/team/folder/20210105/orig_v1
/organization/team/folder/20210105/orig_v2
/organization/team/folder/20210102/orig
/organization/team/folder/20210102/orig_v1
What is the best way to do this? Pls let me know if anything is unclear and thank you for any help
You can use the analytic COUNT function:
SELECT *
FROM (
SELECT t.*,
COUNT(DISTINCT data_payload_uri) OVER (
PARTITION BY SUBSTR(data_payload_uri, 1, INSTR(data_payload_uri, '/', -1))
) AS cnt
FROM table_name t
WHERE data_payload_uri >= '/organization/team/folder/2021'
AND data_payload_uri < '/organization/team/folder/2022'
)
WHERE cnt > 1
Which, for the sample data:
CREATE TABLE table_name (id, data_payload_uri) AS
SELECT 1, '/organization/team/folder/20210101/orig' FROM DUAL UNION ALL
SELECT 2, '/organization/team/folder/20210102/orig' FROM DUAL UNION ALL
SELECT 3, '/organization/team/folder/20210102/orig_v1' FROM DUAL UNION ALL
SELECT 4, '/organization/team/folder/20210103/orig' FROM DUAL UNION ALL
SELECT 5, '/organization/team/folder/20210104/orig' FROM DUAL UNION ALL
SELECT 6, '/organization/team/folder/20210105/orig' FROM DUAL UNION ALL
SELECT 7, '/organization/team/folder/20210105/orig_v1' FROM DUAL UNION ALL
SELECT 8, '/organization/team/folder/20210105/orig_v2' FROM DUAL;
Outputs:
ID
DATA_PAYLOAD_URI
CNT
2
/organization/team/folder/20210102/orig
2
3
/organization/team/folder/20210102/orig_v1
2
6
/organization/team/folder/20210105/orig
3
7
/organization/team/folder/20210105/orig_v1
3
8
/organization/team/folder/20210105/orig_v2
3
db<>fiddle here
I have this query
select *
from dbo.EventLogs
where EntityID = 60181615
and EventTypeID in (1, 2, 3, 4, 5)
and NewValue = 'Received'
If 2 and 4 does not exist with NewValue 'Received' it shows this
current results
What I want
Ideally you should maintain somewhere a table containing all possible EventTypeID values. Sans that, we can use a CTE in place along with a left join:
WITH EventTypes AS (
SELECT 1 AS ID UNION ALL
SELECT 2 UNION ALL
SELECT 3 UNION ALL
SELECT 4 UNION ALL
SELECT 5
)
SELECT et.ID AS EventTypeId, el.*
FROM EventTypes et
LEFT JOIN dbo.EventLogs el
ON el.EntityID = 60181615 AND
el.NewValue = 'Received'
WHERE
et.ID IN (1,2,3,4,5);
Is it possible to keep order from a 'IN' conditional clause?
I found this question on SO but in his example the OP have already a sorted 'IN' clause.
My case is different, 'IN' clause is in random order
Something like this :
SELECT SomeField,OtherField
FROM TestResult
WHERE TestResult.SomeField IN (45,2,445,12,789)
I would like to retrieve results in (45,2,445,12,789) order. I'm using an Oracle database. Maybe there is an attribute in SQL I can use with the conditional clause to specify to keep order of the clause.
There will be no reliable ordering unless you use an ORDER BY clause ..
SELECT SomeField,OtherField
FROM TestResult
WHERE TestResult.SomeField IN (45,2,445,12,789)
order by case TestResult.SomeField
when 45 then 1
when 2 then 2
when 445 then 3
...
end
You could split the query into 5 queries union all'd together though ...
SELECT SomeField,OtherField
FROM TestResult
WHERE TestResult.SomeField = 4
union all
SELECT SomeField,OtherField
FROM TestResult
WHERE TestResult.SomeField = 2
union all
...
I'd trust the former method more, and it would probably perform much better.
Decode function comes handy in this case instead of case expressions:
SELECT SomeField,OtherField
FROM TestResult
WHERE TestResult.SomeField IN (45,2,445,12,789)
ORDER BY DECODE(SomeField, 45,1, 2,2, 445,3, 12,4, 789,5)
Note that value,position pairs (e.g. 445,3) are kept together for readability reasons.
Try this:
SELECT T.SomeField,T.OtherField
FROM TestResult T
JOIN
(
SELECT 1 as Id, 45 as Val FROM dual UNION ALL
SELECT 2, 2 FROM dual UNION ALL
SELECT 3, 445 FROM dual UNION ALL
SELECT 4, 12 FROM dual UNION ALL
SELECT 5, 789 FROM dual
) I
ON T.SomeField = I.Val
ORDER BY I.Id
There is an alternative that uses string functions:
with const as (select ',45,2,445,12,789,' as vals)
select tr.*
from TestResult tr cross join const
where instr(const.vals, ','||cast(tr.somefield as varchar(255))||',') > 0
order by instr(const.vals, ','||cast(tr.somefield as varchar(255))||',')
I offer this because you might find it easier to maintain a string of values rather than an intermediate table.
I was able to do this in my application using (using SQL Server 2016)
select ItemID, iName
from Items
where ItemID in (13,11,12,1)
order by CHARINDEX(' ' + Convert("varchar",ItemID) + ' ',' 13 , 11 , 12 , 1 ')
I used a code-side regex to replace \b (word boundary) with a space. Something like...
var mylist = "13,11,12,1";
var spacedlist = replace(mylist,/\b/," ");
Importantly, because I can in my scenario, I cache the result until the next time the related items are updated, so that the query is only run at item creation/modification, rather than with each item viewing, helping to minimize any performance hit.
Pass the values in via a collection (SYS.ODCINUMBERLIST is an example of a built-in collection) and then order the rows by the collection's order:
SELECT t.SomeField,
t.OtherField
FROM TestResult t
INNER JOIN (
SELECT ROWNUM AS rn,
COLUMN_VALUE AS value
FROM TABLE(SYS.ODCINUMBERLIST(45,2,445,12,789))
) i
ON t.somefield = i.value
ORDER BY rn
Then, for the sample data:
CREATE TABLE TestResult ( somefield, otherfield ) AS
SELECT 2, 'A' FROM DUAL UNION ALL
SELECT 5, 'B' FROM DUAL UNION ALL
SELECT 12, 'C' FROM DUAL UNION ALL
SELECT 37, 'D' FROM DUAL UNION ALL
SELECT 45, 'E' FROM DUAL UNION ALL
SELECT 100, 'F' FROM DUAL UNION ALL
SELECT 445, 'G' FROM DUAL UNION ALL
SELECT 789, 'H' FROM DUAL UNION ALL
SELECT 999, 'I' FROM DUAL;
The output is:
SOMEFIELD
OTHERFIELD
45
E
2
A
445
G
12
C
789
H
fiddle
I have following table:
ID Data
1 A
2 A
2 B
3 A
3 B
4 C
5 D
6 A
6 B
etc. In other words, I have groups of data per ID. You will notice that the data group (A, B) occurs multiple times. I want a query that can identify the distinct data groups and number them, such as:
DataID Data
101 A
102 A
102 B
103 C
104 D
So DataID 102 would resemble data (A,B), DataID 103 would resemble data (C), etc. In order to be able to rewrite my original table in this form:
ID DataID
1 101
2 102
3 102
4 103
5 104
6 102
How can I do that?
PS. Code to generate the first table:
CREATE TABLE #t1 (id INT, data VARCHAR(10))
INSERT INTO #t1
SELECT 1, 'A'
UNION ALL SELECT 2, 'A'
UNION ALL SELECT 2, 'B'
UNION ALL SELECT 3, 'A'
UNION ALL SELECT 3, 'B'
UNION ALL SELECT 4, 'C'
UNION ALL SELECT 5, 'D'
UNION ALL SELECT 6, 'A'
UNION ALL SELECT 6, 'B'
In my opinion You have to create a custom aggregate that concatenates data (in case of strings CLR approach is recommended for perf reasons).
Then I would group by ID and select distinct from the grouping, adding a row_number()function or add a dense_rank() your choice. Anyway it should look like this
with groupings as (
select concat(data) groups
from Table1
group by ID
)
select groups, rownumber() over () from groupings
The following query using CASE will give you the result shown below.
From there on, getting the distinct datagroups and proceeding further should not really be a problem.
SELECT
id,
MAX(CASE data WHEN 'A' THEN data ELSE '' END) +
MAX(CASE data WHEN 'B' THEN data ELSE '' END) +
MAX(CASE data WHEN 'C' THEN data ELSE '' END) +
MAX(CASE data WHEN 'D' THEN data ELSE '' END) AS DataGroups
FROM t1
GROUP BY id
ID DataGroups
1 A
2 AB
3 AB
4 C
5 D
6 AB
However, this kind of logic will only work in case you the "Data" values are both fixed and known before hand.
In your case, you do say that is the case. However, considering that you also say that they are 1000 of them, this will be frankly, a ridiculous looking query for sure :-)
LuckyLuke's suggestion above would, frankly, be the more generic way and probably saner way to go about implementing the solution though in your case.
From your sample data (having added the missing 2,'A' tuple, the following gives the renumbered (and uniqueified) data:
with NonDups as (
select t1.id
from #t1 t1 left join #t1 t2
on t1.id > t2.id and t1.data = t2.data
group by t1.id
having COUNT(t1.data) > COUNT(t2.data)
), DataAddedBack as (
select ID,data
from #t1 where id in (select id from NonDups)
), Renumbered as (
select DENSE_RANK() OVER (ORDER BY id) as ID,Data from DataAddedBack
)
select * from Renumbered
Giving:
1 A
2 A
2 B
3 C
4 D
I think then, it's a matter of relational division to match up rows from this output with the rows in the original table.
Just to share my own dirty solution that I'm using for the moment:
SELECT DISTINCT t1.id, D.data
FROM #t1 t1
CROSS APPLY (
SELECT CAST(Data AS VARCHAR) + ','
FROM #t1 t2
WHERE t2.id = t1.id
ORDER BY Data ASC
FOR XML PATH('') )
D ( Data )
And then going analog to LuckyLuke's solution.