I have a table showing production steps (PosID) for a production order (OrderID) and which machine (MachID) they will be run on; I’m trying to reduce the table to show one record for each order – the lowest position (field “PosID”) that is still open (field “Open” = Y); i.e. the next production step for the order.
Example data I have:
OrderID
PosID
MachID
Open
1
1
A
N
1
2
B
Y
1
3
C
Y
2
4
C
Y
2
5
D
Y
2
6
E
Y
Example result I want:
OrderID
PosID
MachID
1
2
B
2
4
C
I’ve tried two approaches, but I can’t seem to get either to work:
I don’t want to put “MachID” in the GROUP BY because that gives me all the records that are open, but I also don’t think there is an appropriate aggregate function for the “MachID” field to make this work.
SELECT “OrderID”, MIN(“PosID”), “MachID”
FROM Table T0
WHERE “Open” = ‘Y’
GROUP BY “OrderID”
With this approach, I keep getting error messages that T1.”PosID” (in the JOIN clause) is an invalid column. I’ve also tried T1.MIN(“PosID”) and MIN(T1.”PosID”).
SELECT T0.“OrderID”, T0.“PosID”, T0.“MachID”
FROM Table T0
JOIN
(SELECT “OrderID”, MIN(“PosID”)
FROM Table
WHERE “Open” = ‘Y’
GROUP BY “OrderID”) T1
ON T0.”OrderID” = T1.”OrderID”
AND T0.”PosID” = T1.”PosID”
Try this:
SELECT “OrderID”,“PosID”,“MachID” FROM (
SELECT
T0.“OrderID”,
T0.“PosID”,
T0.“MachID”,
ROW_NUMBER() OVER (PARTITION BY “OrderID” ORDER BY “PosID”) RNK
FROM Table T0
WHERE “Open” = ‘Y’
) AS A
WHERE RNK = 1
I've included the brackets when selecting columns as you've written it in the question above but in general it's not needed.
What it does is it first filters open OrderIDs and then numbers the OrderIDs from 1 to X which are ordered by PosID
OrderID
PosID
MachID
Open
RNK
1
2
B
Y
1
1
3
C
Y
2
2
4
C
Y
1
2
5
D
Y
2
2
6
E
Y
3
After it filters on the "rnk" column indicating the lowest PosID per OrderID. ROW_NUMBER() in the select clause is called a window function and there are many more which are quite useful.
P.S. Above solution should work for MSSQL
Related
I have a table in PostgerSQL and I need to make N entries in the table twice and for the first half I need to fill in the partner_id field with the value 1 and the second half with the value partner_id = 2.
i try to `
update USERS_TABLE set user_rule_id = 1;
update USERS_TABLE set user_rule_id = 2 where USERS_TABLE.id > count(*)/2;
`
I depends a lot how precise the number of users have to be that are updated with 1 or 2.
The following would be quite unprecise,a s it doesn't take the exact number of user that already exist8after deleting some rows the numbers doesn't fit anymore.
SELECT * FROM USERS_TABLE
id
user_rule_id
1
1
2
1
3
2
4
2
5
2
SELECT 5
If you have a lot of deleted rows and want still the half of the users, you can choose following approach, which does rely on the id, but at teh actual row number
UPDATE USERS_TABLE1
set user_rule_id = CASE WHEN rn <= (SELECT count(*) FROM USERS_TABLE1)/ 2 then 1
ELSE 2 END
FROM (SELECT id, ROW_NUMBER() OVER( ORDER BY id) rn FROM USERS_TABLE1) t
WHERE USERS_TABLE1.id = t.id;
UPDATE 5
SELECT * FROM USERS_TABLE1
id
user_rule_id
1
1
2
1
3
2
4
2
5
2
SELECT 5
fiddle
In the sample case it it the same result, but when you have a lot of rows and a bunch of the deleted users, the senind will give you quite a good result
How to repeat rows based on column value in snowflake using sql.
I tried a few methods but not working such as dual and connect by.
I have two columns: Id and Quantity.
For each ID, there are different values of Quantity.
So if you have a count, you can use a generator:
with ten_rows as (
select row_number() over (order by null) as rn
from table(generator(ROWCOUNT=>10))
), data(id, count) as (
select * from values
(1,2),
(2,4)
)
SELECT
d.*
,r.rn
from data as d
join ten_rows as r
on d.count >= r.rn
order by 1,3;
ID
COUNT
RN
1
2
1
1
2
2
2
4
1
2
4
2
2
4
3
2
4
4
Ok let's start by generating some data. We will create 10 rows, with a QTY. The QTY will be randomly chosen as 1 or 2.
Next we want to duplicate the rows with a QTY of 2 and leave the QTY =1 as they are.
Obviously you can change all parameters above to suit your needs - this solution works super fast and in my opinion way better than table generation.
Simply stack SPLIT_TO_TABLE(), REPEAT() with a LATERAL() join and voila.
WITH TEN_ROWS AS (SELECT ROW_NUMBER()OVER(ORDER BY NULL)SOME_ID,UNIFORM(1,2,RANDOM())QTY FROM TABLE(GENERATOR(ROWCOUNT=>10)))
SELECT
TEN_ROWS.*
FROM
TEN_ROWS,LATERAL SPLIT_TO_TABLE(REPEAT('hire me $10/hour',QTY-1),'hire me $10/hour')ALTERNATIVE_APPROACH;
I have the task to find out if all columns in a SQL Server table have exact the same value. The table content is created by a stored procedure and can vary in the number of columns. The first column is an ID, the second and the following columns must be compared if the all columns have exact the same value.
At the moment I do not have a clue how to achieve this.
The best solution would be to display only the rows, which have different values in one or multiple columns except the first column with ID.
Thank you so much for your help!!
--> Edit: The table looks this:
ID Instance1 Instance2 Instance3 Instance4 Instance5
=====================================================
A 1 1 1 1 1
B 1 1 0 1 1
C 55 55 55 55 55
D Driver Driver Driver Co-driver Driver
E 90 0 90 0 50
F On On On On On
The result should look like this, only the rows with one or multiple different column values should be display.
ID Instance1 Instance2 Instance3 Instance4 Instance5
=====================================================
B 1 1 0 1 1
D Driver Driver Driver Co-driver Driver
E 90 0 90 0 50
My table has more than 1000 rows and 40 columns
you can achieve this by using row_number()
Try the following code
With c as(
Select id
,field_1
,field_2
,field_3
,field_n
,row_number() over(partition by field_1,field_2,field_3,field_n order by id asc) as rn
From Table
)
Select *
From c
Where rn = 1
row_number with partition is going to show you if the field is repeated by assigning a number to a row based on field_1,field_2,field_3,field_n, for example if you have 2 rows with same field values the inner query is going to show you
rn field_1 field_2 field_3 field_n id
1 x y z a 5
2 x y z a 9
After that on the outer part of the query pick rn = 1 and you are going to obtain a query without repetitions based on fields.
Also if you want to delete repeated numbers from your table you can apply
With c as(
Select id
,field_1
,field_2
,field_3
,field_n
,row_number() over(partition by field_1,field_2,field_3,field_n order by id asc) as rn
From Table
)
delete
From c
Where rn > 1
The best solution would be to display only the rows, which have different values in one or multiple columns except the first column with ID.
You may be looking for a the following simple query, whose WHERE clause filters out rows where all fields have the same value (I assumed 5 fields - id not included).
SELECT *
FROM mytable t
WHERE NOT (
field1 = field2
AND field1 = field3
AND field1 = field4
AND field1 = field5
);
Ok, so hoping I can get some help here after searching with no joy.
So I have a key 'orderno' and each 'orderno' has multiple items. Each item has a status. I want to pull a Q that shows only the orderno's that contain an item that has status of 'x'
So If there are 3 items and only 1 is showing status 'x' I want to see all three items not just the one.
Essentially removing any order/items that do not show the x value.
So table1
orderno / Itemno / Itemstatus
1 1 y
1 2 x
2 1 z
3 1 y
3 2 x
3 3 y
4 1 y
4 1 y
EDIT:
So basically the letters represent open, closed, or inprogress... I want to see only order that have and item closed as well as an item in progress so I can see why the order is only showing partially complete from there. Still probably not making sense here. Grrrr.
I need to return the ORDER# and all item#'s for any order that contains an item with status of 'x'.
SELECT * FROM Order_Table
WHERE orderno IN
(SELECT orderno FROM Order_Table WHERE Itemstatus = 'x')
The Inner query returns all the orders with the status 'x' and the outer one return all details of those orders.
I prefer EXISTS to the IN or JOIN versions. It general faster.
Added a sqlfiddle.
CREATE TABLE table1(orderno INT, Itemno INT, Itemstatus CHAR(1))
INSERT INTO table1 VALUES
(1,1,'y')
,(1,2,'x')
,(2,1,'z')
,(3,1,'y')
,(3,2,'x')
,(3,3,'y')
,(4,1,'y')
,(4,1,'y')
SELECT *
FROM table1 a
WHERE EXISTS(SELECT 1
FROM table1 b
WHERE b.OrderNo = a.OrderNo
AND b.Itemstatus='x')
I have a sql table :
Levels
LevelId Min Product
1 x 1
2 y 1
3 z 1
4 a 1
I need to duplicate the same data into the database by changing only the product Id from 1 2,3.... 40
example
LevelId Min Product
1 x 2
2 y 2
3 z 2
4 a 2
I could do something like
INSERT INTO dbo.Levels SELECT top 4 * fROM dbo.Levels
but that would just copy paste the data.
Is there a way I can copy the data and paste it changing only the Product value?
You're most of the way there - you just need to take one more logical step:
INSERT INTO dbo.Levels (LevelID, Min, Product)
SELECT LevelID, Min, 2 FROM dbo.Levels WHERE Product = 1
...will duplicate your rows with a different product ID.
Also consider that WHERE Product = 1 is going to be more reliable than TOP 4. Once you have more than four rows in the table, you will not be able to guarantee that TOP 4 will return the same four rows unless you also add an ORDER BY to the select, however WHERE Product = ... will always return the same rows, and will continue to work even if you add an extra row with a product ID of 1 (where as you'd have to consider changing TOP 4 to TOP 5, and so on if extra rows are added).
You can generate the product id's and then load them in:
with cte as (
select 2 as n
union all
select n + 1
from cte
where n < 40
)
INSERT INTO dbo.Levels(`min`, product)
SELECT `min`, cte.n as product
fROM dbo.Levels l cross join
cte
where l.productId = 1;
This assumes that the LevelId is an identity column, that auto-increments on insert. If not:
with cte as (
select 2 as n
union all
select n + 1
from cte
where n < 40
)
INSERT INTO dbo.Levels(levelid, `min`, product)
SELECT l.levelid+(cte.n-1)*4, `min`, cte.n as product
fROM dbo.Levels l cross join
cte
where l.productId = 1;
INSERT INTO dbo.Levels (LevelId, Min, Product)
SELECT TOP 4
LevelId,
Min,
2
FROM dbo.Levels
You can include expressions in the SELECT statement, either hard-coded values or something like Product + 1 or anything else.
I expect you probably wouldn't want to insert the LevelId though, but left that there to match your sample. If you don't want that just remove it from the INSERT and SELECT sections.
You could use a CROSS JOIN against a numbers table, for example.
WITH
L0 AS(SELECT 1 AS C UNION ALL SELECT 1 AS O), -- 2 rows
L1 AS(SELECT 1 AS C FROM L0 AS A CROSS JOIN L0 AS B), -- 4 rows
Nums AS(SELECT ROW_NUMBER() OVER(ORDER BY (SELECT NULL)) AS N FROM L1)
SELECT
lvl.[LevelID],
lvl.[Min],
num.[N]
FROM dbo.[Levels] lvl
CROSS JOIN Nums num
This would duplicate 4 times.