The table that needs to be queried looks like this:
ID
UserID
ProductCodes
1
33
9999
2
456
3051
3
456
9999
4
456
3051
4
33
9999
How would I write a SQL query to find out which users have at least one productCodes = '9999' and also have more than 10 productCodes <> '9999'?
You can use GROUP BY and HAVING:
SELECT
UserID
FROM dbo.YourTable
GROUP BY
UserId
HAVING SUM(CASE WHEN ProductCodes = '9999' THEN 1 ELSE 0 END) >= 1
AND COUNT(DISTINCT ProductCodes) >= 11
;
Use Case or Intersect (case is more performant)
SELECT UserID, SUM (case when ProductCodes='9999' then 1 else 0 end) PC9999
, SUM (case when ProductCodes<>'9999' then 1 else 0 end) PCNot9999
FROM dbo.Users
WHERE ProductCodes='9999'
GROUP BY UserID
HAVING SUM (case when ProductCodes='9999' then 1 else 0 end)>0
AND SUM (case when ProductCodes<>'9999' then 1 else 0 end) >10
I ended up going with this. It allows us to get specific with how many times a '9999' product code has been used in comparison with other codes.
SELECT
UserID
FROM Session_Hst
GROUP BY
UserID
HAVING SUM(CASE WHEN ProductCodes = '9999' THEN 1 ELSE 0 END) >= 1
AND COUNT(CASE WHEN ProductCodes <> '9999' THEN 1 ELSE null END ) >= 10
;
Related
I have a table generated from a query in TeraData that looks like this:
User_ID Transaction_Month Number_of_Visits
123 1 1
123 2 2
221 4 1
123 5 2
221 3 5
I am trying to create a Pivot table of sorts that will look like:
User_ID Month_1 Month_2 Month_3 Month_4 ..... Month_12
123
That will store the number of visits in each month column.
Any help would be greatly appreciated.
Thanks.
You can do conditional aggregation:
select user_id,
sum(case when transaction_month = 1 then number_of_visits else 0 end) month_1,
sum(case when transaction_month = 2 then number_of_visits else 0 end) month_2,
...
sum(case when transaction_month = 12 then number_of_visits else 0 end) month_12
from mytable
group by user_id
How to total count?
SELECT
COUNT(CASE WHEN SHP.id = 1 then 1 ELSE NULL END) as "New",
COUNT(CASE WHEN SHP.id = 2 then 5 ELSE NULL END) as "Accepted"
from SHP
RESULT:
NEW Accepted
1 5
But I need a total count
result: 6
I'd do something like this;
SELECT
COUNT(CASE WHEN id = 1 THEN 1 END) as New,
COUNT(CASE WHEN id = 2 THEN 5 END) as Accepted,
COUNT(CASE WHEN id = 1 THEN 1
WHEN id = 2 THEN 5 END) as Total
FROM SHP
This is exactly what the CASE statement should be used for, the logic is very simple. This will avoid having to perform multiple calculations on the same fields.
As a note, the value in your THEN statement isn't used in this instance at all, it's just doing a COUNT of the number rather than performing a SUM. I've also removed the ELSE NULL because this is what the CASE will do by default anyway.
If your intention was to SUM the values then do this;
SELECT
SUM(CASE WHEN id = 1 THEN 1 END) as New,
SUM(CASE WHEN id = 2 THEN 5 END) as Accepted,
SUM(CASE WHEN id = 1 THEN 1
WHEN id = 2 THEN 5 END) as Total
FROM SHP
Example
Assuming you have only two values in your database, 1 and 2, we can create test data like this;
CREATE TABLE #SHP (id int)
INSERT INTO #SHP (id)
VALUES (1),(2)
And use this query;
SELECT
SUM(CASE WHEN id = 1 then 1 END) as New,
SUM(CASE WHEN id = 2 then 5 END) as Accepted,
SUM(CASE WHEN id = 1 THEN 1
WHEN id = 2 THEN 5 END) as Total
FROM #SHP
Gives this result;
New Accepted Total
1 5 6
Try this:
SELECT
COUNT(CASE WHEN SHP.id = 1 then 1 ELSE NULL END) +
COUNT(CASE WHEN SHP.id = 2 then 5 ELSE NULL END) as "Total"
from SHP
You could wrap your query into a subquery and do something like this:
SELECT SUM(New) as New, Sum(Accepted) as Accepted, Sum(New + Accepted) as Total FROM
(SELECT
COUNT(CASE WHEN SHP.id = 1 then 1 ELSE NULL END) as "New",
COUNT(CASE WHEN SHP.id = 2 then 5 ELSE NULL END) as "Accepted"
from SHP) as SubQuery
That's if you don't want to duplicate doing the counts and just adding the two together.
try this
with s1 as(
SELECT
COUNT(CASE WHEN SHP.id = 1 then 1 ELSE 0 END) as "New"
from SHP
),s2 as
(
SELECT
COUNT(CASE WHEN SHP.id = 2 then 5 ELSE 0 END) as "Accepted"
from SHP
)
select sum("New"+ "Accepted") from s1,s2
I need to write query on employee table to fetch the employee with employee ID & how many days he is present absent & half-day for given date range.
Employee
AID EmpID Status Date
1 10 Present 17-03-2015
2 10 Absent 18-03-2015
3 10 HalfDay 19-03-2015
4 10 Present 20-03-2015
5 11 Present 21-03-2015
6 11 Absent 22-03-2015
7 11 HalfDay 23-03-2015
Expected Output will be :
EmpID Present Absent HalfDay
10 2 1 1
11 1 1 1
Can you please help me with the Sql query ?
Here Is the query I tried
SELECT EMP.EMPID,
(CASE WHEN EMP.STATUS = 'Present' THEN COUNT(STATUS) ELSE 0 END) Pres,
(CASE WHEN EMP.STATUS = 'Absent' THEN COUNT(STATUS) ELSE 0 END) ABSENT,
(CASE WHEN emp.status = 'HalfDay' THEN Count(status) ELSE 0 END) HalfDay
FROM EMPLOYEE EMP GROUP BY emp.empid
The COUNT() function tests if the value is NOT NULL. Therefore it will always increment for both sides of a CASE statement like this:
COUNT(CASE Status WHEN 'Present' THEN 1 ELSE 0) AS Present
So we need to use SUM() ...
select empid,
sum(case when status='Present' then 1 else 0 end) present_tot,
sum(case when status='Absent' then 1 else 0 end) absent_tot,
sum(case when status='HalfDay' then 1 else 0 end) halfday_tot
from employee
group by empid
order by empid
/
... or use COUNT() with a NULL else clause. Both produce the same output, perhaps this one is clearer:
SQL> select empid,
2 count(case when status='Present' then 1 end) present_tot,
3 count(case when status='Absent' then 1 end) absent_tot,
4 count(case when status='HalfDay' then 1 end) halfday_tot
5 from employee
6 group by empid
7 order by empid
8 /
EMPID PRESENT_TOT ABSENT_TOT HALFDAY_TOT
---------- ----------- ---------- -----------
10 2 1 1
11 1 1 1
SQL>
Note that we need to use ORDER BY to guarantee the order of the result set. Oracle introduced a hashing optimization for aggregations in 10g which meant GROUP BY rarely returns a predictable sort order.
Replace 0 with null because it would be also come in count and added the where clause for date range, check the example below:
select empID,
count(case when status='Present' then 1 else null end) Present_Days,
count(case when status='Absent' then 1 else null end) Absent_Days,
count(case when status='HalfDay' then 1 else null end) HalfDays
from Employee
where date >= to_date('17mar2015') and date <= to_date('23mar2015')
group by empID
I have a huge database with over 4 million rows that look like that:
Customer ID Shop
1 Asda
1 Sainsbury
1 Tesco
2 TEsco
2 Tesco
I need to count customers that within last 4 weeks had shopped in all 3 shops Tesco Sainsbury and Asda. Can you please advice if its possible to do it with subqueries?
This is an example of a "set-within-sets" subquery. You can solve it with aggregation:
select customer_id
from Yourtable t
where <shopping date within last four weeks>
group by customer_id
having sum(case when shop = 'Asda' then 1 else 0 end) > 0 and
sum(case when shop = 'Sainsbury' then 1 else 0 end) > 0 and
sum(case when shop = 'Tesco' then 1 else 0 end) > 0;
This structure is quite flexible. So if you wanted Asda and Tesco but not Sainsbury, then you would do:
select customer_id
from Yourtable t
where <shopping date within last four weeks>
group by customer_id
having sum(case when shop = 'Asda' then 1 else 0 end) > 0 and
sum(case when shop = 'Sainsbury' then 1 else 0 end) = 0 and
sum(case when shop = 'Tesco' then 1 else 0 end) > 0;
EDIT:
If you want a count, then use this as a subquery and count the results:
select count(*)
from (select customer_id
from Yourtable t
where <shopping date within last four weeks>
group by customer_id
having sum(case when shop = 'Asda' then 1 else 0 end) > 0 and
sum(case when shop = 'Sainsbury' then 1 else 0 end) > 0 and
sum(case when shop = 'Tesco' then 1 else 0 end) > 0
) t
I'm trying to do a full join on two SQL queries, below:
1st Query:
SELECT
ID
,SUM(CASE WHEN reason = 4 THEN 0 ELSE quantity*price END) AS TValue
,COUNT(*) AS CountAll
FROM table1
WHERE Date>=#StartDate AND Date<=#EndDate
GROUP BY ID
2nd Query:
SELECT
ID
,SUM(CASE WHEN reason = 1 THEN 1 ELSE 0 END) AS New
,SUM(CASE WHEN reason = 6 THEN 1 ELSE 0 END) AS Amend
,SUM(CASE WHEN reason = 5 THEN 1 ELSE 0 END) AS Cancel
FROM Table2
WHERE Date2 >=#StartDate AND Date2<= #EndDate
GROUP BY ID
Result from query1
ID CountAll TValue
-------------------------
id1 24 1020
id2 13 2030
id3 4 120
Result from query 2:
ID New Amend Cancel
--------------------------------
id1 12 4 6
id2 7 6 1
id4 2 1 2
Needed output:
ID TValue CountAll New Amend Cancel Total(countall+new+amend+cancel)
----------------------------------------------------------------------------------------
Id1 1020 24 12 4 6 46
Id2 2030 13 7 6 1 27
id3 120 4 0 0 0 4
Id4 0 0 2 1 2 5
I'll post my current solution if requested, but it is pretty far from working.
I've been doing a bit of research and I think I need to either make a union to join the ID'S, or just do a Full Join. (Second day ever doing sql)
Try this,
SELECT *
FROM
(
SELECT ID ,
SUM(CASE WHEN reason = 4 THEN 0 ELSE quantity*price END) AS TValue,
COUNT(*) AS CountAll
FROM table1
WHERE Date>=#StartDate AND Date<=#EndDate
GROUP BY ID
) a FULL JOIN
(
SELECT ID ,
SUM(CASE WHEN reason = 1 THEN 1 ELSE 0 END) AS New ,
SUM(CASE WHEN reason = 6 THEN 1 ELSE 0 END) AS Amend ,
SUM(CASE WHEN reason = 5 THEN 1 ELSE 0 END) AS Cancel
FROM Table2
WHERE Date2 >=#StartDate AND Date2<= #EndDate
GROUP BY ID
) b ON a.ID = b.ID
I would write something like below:
select decode (a.id, null, b.id, a.id) as ID, a.TValue, CountAll, b.new, b.Amend, b.cancel
from (SELECT ID ,SUM(CASE WHEN reason = 4 THEN 0 ELSE quantity*price END)
AS TValue ,COUNT(*) AS CountAll
FROM table1
WHERE Date>=#StartDate AND Date<=#EndDate GROUP BY ID
) a FULL OUTER JOIN
(SELECT ID , SUM(CASE WHEN reason = 1 THEN 1 ELSE 0 END)
AS New ,SUM(CASE WHEN reason = 6
THEN 1 ELSE 0 END) AS Amend ,
SUM(CASE WHEN reason = 5 THEN 1 ELSE 0 END) AS Cancel
FROM Table2 WHERE Date2 >=#StartDate AND Date2<= #EndDate GROUP BY ID
) b
on a.id = b.id
have you tried this...
select isnull (a.id,b.id) as ID, a.TValue, CountAll, b.new, b.Amend, b.cancel
from (SELECT ID ,SUM(CASE WHEN reason = 4 THEN 0 ELSE quantity*price END) AS TValue ,COUNT(*) AS CountAll
FROM table1
WHERE Date>=#StartDate AND Date<=#EndDate GROUP BY ID ) a
FULL OUTER JOIN (SELECT ID , SUM(CASE WHEN reason = 1 THEN 1 ELSE 0 END) AS New ,SUM(CASE WHEN reason = 6 THEN 1 ELSE 0 END) AS Amend , SUM(CASE WHEN reason = 5 THEN 1 ELSE 0 END) AS Cancel
FROM Table2 WHERE Date2 >=#StartDate AND Date2<= #EndDate GROUP BY ID ) b on a.id = b.id